Why can't I use regular expressions?
I'm trying to use a regular expression but it won't work. :-{ When I try to compile my bling.java file, it doesn't work. It chokes on the following line...
import java.util.regex.*;
The error message I get is...
bling.java:7: cannot resolve symbol
symbol : class regex
location: package util
import java.util.regex;
^
1 error
From my understanding, all I need is a newer version of the SDK.
If I do a "java -version", I get...
java version "1.4.2"
Java(TM) 2 Runtime Environment, Standard Edition (build 1
Java HotSpot(TM) Client VM (build 1.4.2-b28, mixed mode)
--------------------------
Here's an update... I change my source code and it still bombs. Take a look. Help is appreciated.
// file : bling.java
import java.util.regex.*;
class bling {
public static void main(String[] args) {
System.out.println("Hello!");
bling.java:2: package java.util.regex does not exist
import java.util.regex.*;
^
1 error
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Trying to use regular expressions to convert names to Title Case
I'm trying to change names to their proper case for most common names in North America (esp. the U.S.).
Some examples are in the comments of the included code below.
My problem is that *retName = retName.replaceAll("( [^ ])([^ ]+)", "$1".toUpperCase() + "$2");* does not work as I expect. It seems that the toUpperCase method call does not actually do anything to the identified group.
Everything else works as I expect.
I'm hoping that I do not have to iterate through each character of the string, upshifting the characters that follow spaces.
Any help from you RegEx experts will be appreciated.
{code}
* Converts names in some random case into proper Name Case. This method does not have the
* extra processing that would be necessary to convert street addresses.
* This method does not add or remove punctuation.
* Examples:
* DAN MARINO --> Dan Marino
* old macdonald --> Old Macdonald <-- Can't capitalize the 'D" because of Ernst Mach
* ROY BLOUNT, JR. --> Roy Blount, Jr.
* CAROL mosely-BrAuN --> Carol Mosely-Braun
* Tom Jones --> Tom Jones
* ST.LOUIS --> St. Louis
* ST.LOUIS, MO --> St. Louis, Mo <-- Avoid City Names plus State Codes
* This is a work in progress that will need to be updated as new exceptions are found.
public static String toNameCase(String name) {
* Basic plan:
* 1. Strategically create double spaces in front of characters to be capitalized
* 2. Capitalize characters with preceding spaces
* 3. Remove double spaces.
// Make the string all lower case
String retName = name.trim().toLowerCase();
// Collapse strings of spaces to single spaces
retName = retName.replaceAll("[ ]+", " ");
// "mc" names
retName = retName.replaceAll("( mc)", " $1");
// Ensure there is one space after periods and commas
retName = retName.replaceAll("(\\.|,)([^ ])", "$1 $2");
// Add 2 spaces after periods, commas, hyphens and apostrophes
retName = retName.replaceAll("(\\.|,|-|')", "$1 ");
// Add a double space to the front of the string
retName = " " + retName;
// Upshift each character that is preceded by a space
// For some reason this doesn't work
retName = retName.replaceAll("( [^ ])([^ ]+)", "$1".toUpperCase() + "$2");
// Remove double spaces
retName = retName.replaceAll(" ", "");
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Edited by: FuzzyBunnyFeet on Jan 17, 2011 10:56 AM
Edited by: FuzzyBunnyFeet on Jan 17, 2011 10:57 AMHopefully someone will still be able to provide a RegEx solution, but until that time here is a working method.
Also, if people have suggestions of other rules for letter capitalization in names, I am interested in those too.
* Converts names in some random case into proper Name Case. This method does not have the
* extra processing that would be necessary to convert street addresses.
* This method does not add or remove punctuation.
* Examples:
* CAROL mosely-BrAuN --> Carol Mosely-Braun
* carol o'connor --> Carol O'Connor
* DAN MARINO --> Dan Marino
* eD mCmAHON --> Ed McMahon
* joe amcode --> Joe Amcode <-- Embedded "mc"
* mr.t --> Mr. T <-- Inserted space
* OLD MACDONALD --> Old Macdonald <-- Can't capitalize the 'D" because of Ernst Mach
* old mac donald --> Old Mac Donald
* ROY BLOUNT,JR. --> Roy Blount, Jr.
* ST.LOUIS --> St. Louis
* ST.LOUIS,MO --> St. Louis, Mo <-- Avoid City Names plus State Codes
* Tom Jones --> Tom Jones
* This is a work in progress that will need to be updated as new exceptions are found.
public static String toNameCase(String name) {
* Basic plan:
* 1. Strategically create double spaces in front of characters to be capitalized
* 2. Capitalize characters with preceding spaces
* 3. Remove double spaces.
// Make the string all lower case
String workStr = name.trim().toLowerCase();
// Collapse strings of spaces to single spaces
workStr = workStr.replaceAll("[ ]+", " ");
// "mc" names
workStr = workStr.replaceAll("( mc)", " $1 ");
// Ensure there is one space after periods and commas
workStr = workStr.replaceAll("(\\.|,)([^ ])", "$1 $2");
// Add 2 spaces after periods, commas, hyphens and apostrophes
workStr = workStr.replaceAll("(\\.|,|-|')", "$1 ");
// Add a double space to the front of the string
workStr = " " + workStr;
// Upshift each character that is preceded by a space and remove double spaces
// Can't upshift using regular expressions and String methods
// workStr = workStr.replaceAll("( [^ ])([^ ]+)", "$1"toUpperCase() + "$2");
StringBuilder titleCase = new StringBuilder();
for (int i = 0; i < workStr.length(); i++) {
if (workStr.charAt(i) == ' ') {
if (workStr.charAt(i+1) == ' ') {
i += 2;
while (i < workStr.length() && workStr.charAt(i) == ' ') {
titleCase.append(workStr.charAt(i++));
if (i < workStr.length()) {
titleCase.append(workStr.substring(i, i+1).toUpperCase());
} else {
titleCase.append(workStr.charAt(i));
return titleCase.toString();
{code} -
Searching for a substring using Regular Expression
I have a lengthy String similar to repetetion of the one below
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import java.io.Console;
import java.util.regex.Pattern;
import java.util.regex.Matcher;
public class RegexTestHarness {
public static void main(String[] args){
Console console = System.console();
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System.exit(1);
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boolean found = false;
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matcher.group(), matcher.start(), matcher.end());
found = true;
if(!found){
console.format("No match found.%n");
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I say "for the most part" because I am compiling Patterns with the case insensitivity flag. This appears to do horrible, horrible things. Take a look at the following code, modified from uncle_alice's example:
String[] str = {"#test#hello", "#tes", "blargblarg", "", "#test#", "S"};
String rgx = "#[A-Za-z0-9]+#";
Pattern pc = Pattern.compile(rgx);
Pattern pi = Pattern.compile(rgx, Pattern.CASE_INSENSITIVE);
for (String s : str)
System.out.println(" For string: "+s);
for (Pattern p : new Pattern[]{pc, pi}) // once for each pattern
Matcher m = p.matcher(s);
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} else
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For string: #test#hello
No match; hitEnd = false
No match; hitEnd = true
For string: #tes
No match; hitEnd = true
No match; hitEnd = true
For string: blargblarg
No match; hitEnd = false
No match; hitEnd = true
For string:
No match; hitEnd = true
No match; hitEnd = true
For string: #test#
Matched '#test#'; hitEnd = false
Matched '#test#'; hitEnd = false
For string: S
No match; hitEnd = false
No match; hitEnd = trueIt would seem that, with the case-insensitive flag set, hitEnd always returns true unless a match is found. Why is this? I find it quite confusing.
I can adjust my design to accomodate if this problem cannot be circumvented; however, I'd like to understand what has going wrong here. :)
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Using regular expressions in java
Does anyone of you know a good source or a tutorial for using regular expressions in java.
I just want to look at some examples....
Thanksthanks a lot... i have one more query
Boundary matchers
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\A The beginning of the input
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Changeparticular characters in a string by using regular expressions ...
Hello Everyone,
I am trying to write a function by using oracles regular expression function REGEXP_REPLACE but I could not succed till now.
My problem as follows, I have a text in a column for example let say 'sdfsdf Sdfdfs Sdfd' I want replace all s and S characters with X and make the text look like 'XdfXdf XdfdfX Xdfd'.
Is it possible by using regular expressions in oracle ?
Can you give me some clues ?
Thank youSSU wrote:
Hello Everyone,
I am trying to write a function by using oracles regular expression function REGEXP_REPLACE but I could not succed till now.
My problem as follows, I have a text in a column for example let say 'sdfsdf Sdfdfs Sdfd' I want replace all s and S characters with X and make the text look like 'XdfXdf XdfdfX Xdfd'.
Is it possible by using regular expressions in oracle ?
Can you give me some clues ?
Thank you
SQL> SELECT
2 regexp_replace('sdfsdf Sdfdfs Sdfd','s|S','X') from dual;
REGEXP_REPLACE('SD
XdfXdf XdfdfX XdfdRegards,
Achyut -
Using regular expressions for validating time fields
Similar to my problem with converting a big chunk of validation into smaller chunks of functions I am trying to use Regular Expressions to handle the validation of many, many time fields in a flexible working time sheet.
I have a set of FormCalc scripts to calculate the various values for days, hours and the gain/loss of hours over a four week period. For these scripts to work the time format must be in HH:MM.
Accessibility guidelines nix any use of message box pop ups so I wanted to get around this by having a hidden/visible field with warning text but can't get it to work.
So far I have:
var r = new RegExp(); // Create a new Regular Expression Object
r.compile ("^[00-99]:\\] + [00-59]");
var result = r.test(this.rawValue);
if (result == true){
true;
form1.flow.page.parent.part2.part2body.errorMessage.presence = "visible";
else (result == false){
false;
form1.flow.page.parent.part2.part2body.errorMessage.presence = "hidden";
Any help would be appreciated!Date and time fields are tricky because you have to consider the formattedValue versus the rawValue. If I am going to use regular expressions to do validation I find it easier to make them text fields and ignore the time patterns (formattedValue). Something like this works (as far as my very brief testing goes) for 24 hour time where time format is HH:MM.
// form1.page1.subform1.time_::exit - (JavaScript, client)
var error = false;
form1.page1.subform1.errorMsg.rawValue = "";
if (!(this.isNull)) {
var time_ = this.rawValue;
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error = true;
else {
var regExp = /^([01]?[0-9]|2[0-3]):[0-5][0-9]$/;
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error = true;
if (error == true) {
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Using regular expressions for validation in i18n
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Matching substrings between square brackets using regular expressions
Hello,
I am new at Java and have a problem with regular expressions. Let me describe the issue in 3 steps:
1.- I have an english sentence. Some words of the sentence stand between square brackets, for example "I [eat] and [sleep]"
2- I would like to match strings that are in square brackets using regular expressions (java.util.regex.*;) and here is the code I have written for the task
+Pattern findStringinSquareBrackets = Pattern.compile("\\[.*\\]");+
+ Matcher matcherOfWordInSquareBrackets = findStringinSquareBrackets.matcher("I [eat] and [sleep]");+
+//Iteration in the string+
+ while ( matcherOfWordInSquareBrackets.find() )+
+{+
+ System.out.println("Patter found! :"+ outputField.getText().substring(matcherOfWordInSquareBrackets.start(), matcherOfWordInSquareBrackets.end())+""); +
+ }+
3- the result I have after running the code described in 2 is the following: *Patter found!: [eat] and [sleep]*
That is to say that not only words between square brackets are found but also the substring "and". And this is not what I want.
What I would like to have as a result is:
*Patter found!: [eat]*
*Patter found!: [sleep]*
That is to say I want to match only the words between the square brackets and nothing else.
Does somebody know how to do this? Any help would be great.
Best regards,
AbouYou can find the words by looping through the sentence and then return the substring within the indexes.
int start=0;
int end=0;
for(int i=0; i<string.length(); i++)
if(string.substring(i,i+1).equals("[");
start=i;
if(start!=0)
if(string.substring(i,i+1).equlas("]");
end=i;
return string.substring(start,end+1);
}something like that. This code will only find the firt word however. I do not know much about regex so I cannot help anymore.
Edited by: elasolova on Jun 16, 2009 6:45 AM
Edited by: elasolova on Jun 16, 2009 6:46 AM -
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Checking valid e-mail's using Regular expressions
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I desperately need some help here. I need to develop a generic method that wiull use regular expressions and patterns to validate an e-mail.
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import java.util.regex.*;
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Hi All,
I have a requirement to update a column which is having values like below code.
based on the conditinos I need to update from ‘E’ to ‘Z’. Few positions I need to update and remaining positions I need leave as it is.
How I can achive this requirement by using regular expression regexp_replace.
Actual value --> 'AEAAAEAA EE AA EE AA EE EEEAA AA AA '
After update --> 'AZAAAZAA EE AA EE AA EE EEEAA AA AA 'below is my requirement. I am adding the conditions dynamically as per the conditions. I dont know the position of the E. If 'E' is in any position I need to update with 'Z' if that 'E' satisfy the condition.
I dont want to update all the E's to Z's.
I want to update specific E's which satisfy the condition.
IF l_kwhhilow >= 1 THEN
l_where := l_where||' SUBSTR(OVERRIDEFIELD,1,1) = ''E'' OR ';
l_exp := l_exp||'Z';
ELSE
l_exp := l_exp||'\1';
END IF;
IF l_kwhilow >= 1 THEN
l_where := l_where||' SUBSTR(OVERRIDEFIELD,2,1) = ''E'' OR ';
l_exp := l_exp||'Z';
ELSE
l_exp := l_exp||'\2';
END IF;
IF l_kvahilow >= 1 THEN
l_where := l_where||' SUBSTR(OVERRIDEFIELD,3,1) = ''E'' OR ';
l_exp := l_exp||'Z';
ELSE
l_exp := l_exp||'\3';
END IF;
IF l_kvarhilow >= 1 THEN
l_where := l_where||' SUBSTR(OVERRIDEFIELD,4,1) = ''E'' OR ';
l_exp := l_exp||'Z';
ELSE
l_exp := l_exp||'\4';
END IF;
IF l_todkwh1hilow >= 1 THEN
l_where := l_where||' SUBSTR(OVERRIDEFIELD,5,1) = ''E'' OR ';
l_exp := l_exp||'Z';
ELSE
l_exp := l_exp||'\5';
END IF;
IF l_todkwh2hilow >= 1 THEN
l_where := l_where||' SUBSTR(OVERRIDEFIELD,6,1) = ''E'' OR ';
l_exp := l_exp||'Z';
ELSE
l_exp := l_exp||'\6';
END IF;
l_exp := ''''||l_exp||'''';
l_exp1 := '\1\2\3\4'||l_exp1;
IF l_todkw1hilow >= 1 THEN
l_where := l_where||' SUBSTR(OVERRIDEFIELD,11,1) = ''E'' OR ';
l_exp1 := l_exp1||'Z';
ELSE
l_exp1 := l_exp1||'\5';
END IF;
IF l_todkw2hilow = 1 THEN
l_where := l_where||' SUBSTR(OVERRIDEFIELD,12,1) = ''E'' OR ';
l_exp1 := l_exp1||'Z';
ELSE
l_exp1 := l_exp1||'\6';
END IF;
l_exp1 := ''''||l_exp1||'''';
IF i give 10 in the regexp_replace it is not working.
SET OVERRIDEFIELD = REGEXP_REPLACE(SUBSTR(overridefield,1,6), ''(.)(.)(.)(.)(.)(.)'','||l_exp||')'||
' ||REGEXP_REPLACE(SUBSTR(overridefield,7,6), ''(.)(.)(.)(.)(.)(.)'','||l_exp1||')'||
' ||SUBSTR(overridefield,13)'||
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