Working w/ regular expressions
Hi all,
I'm having trouble figuring out what regular expression to use to parse my output. I want to capture a block of text that starts with a tab (\t) and ends with a line containing the word "error code."
For example, if my output is the following: ( [\tab] denotes ASCII tab character)
[\tab]Some command
Anytext
Anytext
blah blah error code is 0
[\tab]Some other command
[\tab]Yet another command
Anytext
blah blah error code is 1
I would like subsequent calls to matcher.find() to find these two blocks:
[\tab]Some command
Anytext
Anytext
blah blah error code is 0
and
[\tab]Yet another command
Anytext
blah blah error code is 1
I thought the regular expression should be something like
"[\t](.*\n)+.*error code.*"
but the above regular expression returns the entire text intead of the two "blocks" that I want. I know that Java returns the longest match for the expression but I don't know how to exclude "error code" in the middle...
"[\t](.*\n)+(.*error code.*){1}" ???
Any help is greatly appreciated.
Thanks,
KK
..but I'm not sure what is the purpose of the second part (?:\\n|\\Z).
Would someone care to explain this too me?This non-capturing group is for final delimiter, it means "last character is a Line Feed char or end of input reached", just to prevent error if last line is an error line without Line Feed char.
A good reference about groups are at JRegex documentation/examples:
http://jregex.sourceforge.net/.
Good news for you: the minimal regular expression that solves your problem.
import java.io.*;
import java.util.*;
import java.util.regex.*;
public class ParseTest {
public static void main(String[] args) throws Exception {
String Output =
"\t\tgcc -someoption file0\n"
+ "\t\tgcc -someoption file1\n"
+ "\t\tgcc -someoption file2\n"
+ "\t\tgcc -someoption file3\n"
+ "some error message\n"
+ "some more error message\n"
+ "make: 1254-004 The error code from the last command is 1.\n"
+ "make: 1254-005 Ignored error code 1 from last command.\n"
+ "\t\tgcc -someoption file4\n"
+ "\t\tgcc -someoption file5\n"
+ "error message\n"
+ "more error message\n"
+ "make: 1254-004 The error code from the last command is 1.\n"
+ "make: 1254-005 Ignored error code 1 from last command.\n"
+ "\t\tgcc -someoption file6\n"
+ "\t\tgcc -someoption file7\n"
+ "last error message\n"
+ "make: 1254-005 Ignored error code 1 from last command.";
System.out.println(Output+"\n");
final String
// Regular Expression pattern to find only commands with error messages.
// $1 = command
// $2 = error message
re = "\\t+(.+)\\n([^\\t]+[^\\t\\n])(?:\\n|$)";
Pattern p = Pattern.compile(re);
System.out.println("Pattern:\n"+p.pattern());
Matcher m = p.matcher(Output);
for (int j=1; m.find(); j++) {
System.out.println("\nMatching "+j+":\n");
System.out.println("--------------------------------");
System.out.println(m.group(1));
System.out.println("--------------------------------");
System.out.println(m.group(2));
System.out.println("--------------------------------");
Regards.
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"ColdFusion supplies four functions that work with regular expressions" should be "ColdFusion supplies six functions that work with regular expressions,"
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Originally posted by:
Luckbox72
The problem is not the Regex. I have tested 3 or 4 different
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validation?
Bear in mind that by default validation does not occur until
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How this regular expression work in detail
Who can tell me how does the following regular expression work step by step, thanks!
string input = "PRIVATE11xxPRIVATE22xx123PRIVATE33";
string pattern = @"(?<Pvt>PRIVATE)?(?(Pvt)(\d+)|([^\d]+))";
string publicDocument = null, privateDocument = null;
foreach (Match match in Regex.Matches(input, pattern))
if (match.Groups[1].Success)
privateDocument += match.Groups[1].Value + "\n";
else
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Console.WriteLine("Private Document:");
Console.WriteLine(privateDocument);
Console.WriteLine("Public Document:");
Console.WriteLine(publicDocument);Hi Sincos,
sure:
Your regular expression has two main blocks:
1. (?<Pvt>PRIVATE)?
That means find a string PRIVATE with zero or one repetition. This is a named capture group with the name "Pvt" to access it later
2. (?(Pvt)(\d+)|([^\d]+))
That's a conditional Expression with a yes and no clause. So let's split this one up:
The first part (Pvt) means whether the string "PRIVATE" was found or not.
When it was found, this gets active: (\d+)
When it was not found, this gets active: ([^\d]+)
So let's look at those two:
(\d+) means a numbered capture Group. So one or more numbers
([^\d]+) means any character that is not in [\d], so not a number, with one or more repetitions
Ok. So your regex ends up with three groups:
1 Group: Numbered Group for [\d+]
2 Group: Numbered Group for [^\d+]
3 Group: Named Group for the string "PRIVATE"
Now let's look at your input string "PRIVATE11xxPRIVATE22xx123PRIVATE33"
With that one you'll have four matches:
1st match "PRIVATE11"
1 Group: "11"
2 Group: -
3 Group (Pvt): "PRIVATE"
2nd match "xxPRIVATE" (String private was not found, so [^\d+] is used (any character not a number))
1 Group: -
2 Group: "xxPRIVATE"
3 Group (Pvt): -
3rd match "xx" (String private was not found, so [^\d+] is used (any character not a number))
1 Group: -
2 Group: "xx"
3 Group (Pvt): -
4th match "PRIVATE33"
1 Group: 33
2 Group: -
3 Group (Pvt): "PRIVATE"
Now let's look at your code:
foreach (Match match in Regex.Matches(input, pattern))
if (match.Groups[1].Success)
privateDocument += match.Groups[1].Value + "\n";
else
publicDocument += match.Groups[2].Value + "\n";
The Groups-Property of the Match contains 4 values. At index 0 there's the match itself. Index 1, 2 and 3 contain the
three groups I've described above. So first you check if match.Groups[1].Success. That group is the first Group that stands for [\d+]. That group is succeeded when the string PRIVATE was found and it is followed by a number. With your Input string
the first and fourth match are succeeded for that one. Then you're adding that Number to your privateDocument-string-variable.
In the else-block you're adding the Groups[2].Value to the publicDocument-string-variable. That's the second group that stands for [^\d+]. So it is used for matches 2 and 3 with the two strings "xxPRIVATE" and "xx".
That's it.
I would recommend you to install a tool to play around with Regex. My favourite is Expresso. You can download it here:
http://www.ultrapico.com/expressodownload.htm
Thomas Claudius Huber
"If you can't make your app run faster, make it at least look & feel extremly fast"
My latest Pluralsight-courses:
XAML Layout in Depth
Windows Store Apps - Data Binding in Depth
twitter: @thomasclaudiush
homepage: www.thomasclaudiushuber.com -
Regular Expression replacement not working
I am trying to use a regular expression to replace non-ascii characters on a file, and I'm afraid I've reached the end of my regex knowledge.
Here is the specific code
'Set the Regular Expression paramaters
Set RegEx = CreateObject("VBScript.Regexp")
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RegEx.IgnoreCase = True
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If I understand regular expressions correctly the pattern of "[^\u0000-\u007F]" should replace any character that is not an ascii character, and then replace it with a space (which I understand is "\u0020"). What am I doing wrong?Simply use
ReplacedText = RegEx.Replace(FileText, " ")
Regards, Hans Vogelaar (http://www.eileenslounge.com)
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