XML one to many

Question

Hello:
Given the following XML document:
<?xml version="1.0" encoding="UTF-8"?>
<People>
     <Person Gender="Male">
          <Name>
               <First>Clint</First>
               <Last>Eastwood</Last>
          </Name>
          <Address>
               <Street>Cowboy Court</Street>
               <Number>1234</Number>
               <City>Raleigh</City>
               <State>NC</State>
               <Zip>27615</Zip>
          </Address>
     </Person>
     <Person Gender="Female">
          <Name>
               <First>Lucy</First>
               <Last>Lou</Last>
          </Name>
          <Address>
               <Street>Holly Way</Street>
               <Number>4589</Number>
               <City>Cary</City>
               <State>NC</State>
               <Zip>27876</Zip>
          </Address>
     </Person>
     <Person Gender="Male">
          <Name>
               <First>Mark</First>
               <Last>Manly</Last>
          </Name>
          <Address>
               <Street>Studly Drive</Street>
               <Number>9909</Number>
               <City>Greensboro</City>
               <State>NC</State>
               <Zip>27900</Zip>
          </Address>
     </Person>
</People>
How could a create an XSLT (.xsl) file that would generate a seperate XML document for each
"Person" element? Everything I've read transforms one input document to one output.
I saw a reference to " xsl:result-document ", but that is only available in version 2 of XSLT.
I don't think the Java transform api supports version 2.
Thanks for your help.

Answer 1

here is the code that uses JDOM
I ran the test using your XML and result comes out like this
<?xml version="1.0" encoding="UTF-8"?>
<Person Gender="Male">
  <Name>
    <First>Clint</First>
    <Last>Eastwood</Last>
  </Name>
  <Address>
    <Street>Cowboy Court</Street>
    <Number>1234</Number>
    <City>Raleigh</City>
    <State>NC</State>
    <Zip>27615</Zip>
  </address>
</Person>
<?xml version="1.0" encoding="UTF-8"?>
<Person Gender="Male">
  <Name>
    <First>Mark</First>
    <Last>Manly</Last>
  </Name>
  <Address>
    <Street>Studly Drive</Street>
    <Number>9909</Number>
    <City>Greensboro</City>
    <State>NC</State>
    <Zip>27900</Zip>
  </address>
</Person>
public static void breakXML(String filename, String elementname)
          Element root = null;
          try
               root = loadXMLFile(filename);     //load xml file
               List children = root.getChildElements(elementname);
               for (int i = 0; i < children.size(); i++)
                    Element child = (Element)children.get(i);
                    child.detach();
                    Document doc = new Document(child);
                    //finally output to a file as your choice
                    XMLOutputter writer = new XMLOutputter(Format.getPrettyFormat());
     //                    OutputStream out = new FileOutputStream("dummy.txt");
                    writer.output(doc, System.out);
     //                    out.flush();
     //                    out.close();
          catch (Exception e)
               e.printStackTrace();
         public static Element loadXMLFile(String filename)
          Element element = null;
          InputStream in = null;
          if (!(new File(filename).exists()))
             System.err.println("file name can not be null");
          try
               SAXBuilder builder = new SAXBuilder(false);
               Document doc = builder.build(in = new FileInputStream(filename));
               element = doc.getRootElement();
          catch(Exception e)
            e.printStackTrace();
          finally
            try {
                if (null != in) in.close();
            } catch (IOException ignored) { }
          return element;
     public static void main(String[] s)
          breakXML("testxml.txt", "Person");
     }-----------