XML, XSLT and Omniportlet

Question

Hello, I hope I can find some help.
Using 10.1.14.
I'm importing an XML document. I don't know if it's in rowset/row format (don't know what that is).
I use XSL to transform it. When I click "test", I see pretty much what I want. A table tag, a td with a value, a td with another value, this repeats 4 times. This is the number of "item" elements I have. Great. Everything is set to default.
When I view my page, however, this is the response: Error fetching XML data. Or nothing, because I've tried many different configurations of XSL. When I view my page, it never works.
this is my xml:
<?xml version="1.0" encoding="UTF-8"?>
<record name="N/A" type="content">
<item name="Title"><value>Disclosure of Position Reclassifications</value></item>
<item name="Language"><value>eng</value></item>
<item name="Other Language File Name"><value>/sm/srh/prh/cngc/dsc/Reclass_f</value></item>
<item name="Content"><value>
& lt;table border="0" cellspacing="0" cellpadding="0" width="450"& gt;
& lt;tr& gt;
& lt;td colspan="3"& gt;& lt;h2& gt;Disclosure of Position Reclassifications& lt;/h2& gt;& lt;/td& gt;
& lt;/tr& gt;
& lt;/table& gt;
***LOTS OF HTML CLIPPED***
Act& lt;/u& gt;& lt;/i& gt;& lt;/a& gt; does not appear on this web site.& lt;/p& gt;
& lt;/td& gt;
& lt;/tr& gt;
& lt;/table& gt;
</value></item></record>
this is my xsl:
<xsl:transform version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" >
<xsl:template match="record">
<table>
<xsl:for-each select="item">
<tr>
<td><xsl:value-of select="@name"/></td>
<td><xsl:value-of select="value" disable-output-escaping="yes"/></td>
</tr>
</xsl:for-each>
</table>
</xsl:template>
</xsl:transform>

Answer 1

Hi there,
I think missunderstand some basics.
to display XML documents, omniportlet takes in input onlu XML docs like this :
<rowset>
<row>my 1st line</row>
<row>my 2nd line</row>
<row> ... </row>
</rowset>
That means that the XML tags of your document MUST be ROWSET for the group and ROW for each element.
Omniportlet will render the previous XML fragment like this :
<table>
<tr>
<td>my 1st line</td>
<td>my 2ndline</td>
</tr>
<table>
So you got to write your XSL in order to transform your Initial XML in the rowset/row format. Omniportlet will take in charge of the HTML-table rendering.
Otherwise, your XML is not written in a good way. It should have been like this :
<?xml version="1.0" encoding="UTF-8"?>
<record name="N/A" type="content">
<Title>Disclosure of Position Reclassifications</Title>
<Language>eng</Language>
<OtherLanguageFileName>/sm/srh/prh/cngc/dsc/Reclass_f</OtherLanguageFileName>
<Content>
& lt;table border="0" cellspacing="0" cellpadding="0" width="450"& gt;
& lt;tr& gt;
& lt;td colspan="3"& gt;& lt;h2& gt;Disclosure of Position Reclassifications& lt;/h2& gt;& lt;/td& gt;
& lt;/tr& gt;
& lt;/table& gt;
***LOTS OF HTML CLIPPED***
Act& lt;/u& gt;& lt;/i& gt;& lt;/a& gt; does not appear on this web site.& lt;/p& gt;
& lt;/td& gt;
& lt;/tr& gt;
& lt;/table& gt;
</Content></record>I recommand you to have a look at XML tutorials : http://www.w3schools.com/xml/xml_elements.asp
XSL tutorials (if you need) : http://www.w3schools.com/xsl/
I hope this could help you.