XSLT Transformation returns blank page

Question

Hi,
apologies for the NOOB Question.
I'm trying to prepare an XSQL demonstration for work and have hit a problem, which I'm sure is just a configuration issue.
Using JDeveloper 10.1.3.3.0 I have created an XSQL page which returns a few rows.
I've written an XSL stylesheet to transform the data into an html page.
However, the browser is just showing a blank page.
I've tried the following:
1.) Calling the XSQL page with the '?xml-stylesheet=none' parameter.
The browser displays the unprocessed data correctly, so there's no problem with the XSQL itself.
2.) Saving the output from the webpage as a seperate xml file and applying the stylesheet to it
(by adding the line <?xml-stylesheet type="text/xsl" href="bhwtest1.xsl"?> to the saved output, and opening in the browser.
This works fine and shows that the stylesheet works OK.
I've also tried opening the stylesheet directly in the browser to check that the path that I specify to the stylesheet is valid. This also works, so
the path to the stylesheet is correct.
Any ideas what I can try next?
Thanks for your suggestions,
Ben

Answer 1

XSLT file
<?xml version="1.0" encoding='windows-1252'?>
<?xml-stylesheet type="text/xsl"
href="D:\JDev10\jdev\mywork\BHWApplication1\BHWProject1\bhwtest1.xsl" ?>
<page xmlns:xsql="urn:oracle-xsql" connection="ossdev_07t">
<xsql:query>
SELECT u.user_id AS user_id, u.user_name AS username, email_address AS email
FROM fnd_user u
WHERE email_address IS NOT NULL
and user_id > 3
</xsql:query>
</page>
Stylesheet
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output encoding="ISO-8859-1" method="html" />
<xsl:template match="/page">
<table border="1">
<tr><td><b>User Name</b></td>
<td><b>Email Address</b></td>
</tr>
<xsl:for-each select="ROWSET/ROW">
<tr>
<td>
<xsl:value-of select="./USERNAME"/>
</td>
<td>
mailto:<xsl:value-of select="EMAIL"/>
</td>
</tr>
</xsl:for-each>
</table>
</xsl:template>
</xsl:stylesheet>