4:3 and 16:9 aspect ratio

Question

Ive been producing a video editor using the free tool
AVISYNTH.
But would like to do most of the math processing in director
since its faster.
My problem is, lets say I have an image whose dimensions are
576x409
I want to cut out a part of that image; that portion could
equal 720X480 if enlarged.
So far the only math I can think of is: (the images
width*720)/720..and changing it to 480 for height.
(this although, yields incorrect results for height)
Has anyone dealt with this type of situation..or could
atleast point me in the right direction.
Other math formulas are appreciated as well.
Thank you.
(if I am unclear please specify )

Answer 1

A subtle but very effective convention when creating a
function: set a
local variable to the output of the function at the various
points where
you'd normally use "return"
Then return that local variable at the end of the handler.
Among other
things it allows you to put just one break point on the
return, when
debugging, to easily see the returned value. Plus, for those
who like to
follow the rules, it's what decent coding books teach.
For the most part it makes no difference in performance.
Craig Wollman
Lingo Specialist
Word of Mouth Productions
212-928-9581
www.wordofmouthpros.com
"openspark" <[email protected]> wrote in
message
news:erb7ls$rdg$[email protected]..
> on GetWidthFromHeight(aHeight, aRatio)
> -- INPUT: <aHeight> should be an integer or
floating point number
> -- <aRatio> may be #_4_3 or #_16_9, or a floating
point number
> -- OUTPUT: Returns the width associated with the given
height, as a
> -- floating point number
>
>
> case ilk(aHeight) of
> #float, #integer:
> -- Continue
>
> otherwise:
> return #numberExpected
> end case
>
> case aRatio of
> #_4_3:
> aRatio = 4.0 / 3.0
>
> #_16_9:
> aRatio = 16.0 / 9.0
>
> otherwise:
> case ilk(aRatio) of
> #float, #integer:
> -- Continue
>
> otherwise:
> return #ratioExpected
> end case
> end case
>
> return aHeight * aRatio
> end GetWidthFromHeight
>