Assigning the file path to a text field

I assume this is simple, but I can't figure it out...
I want to be able to print out the the file name on my form -- preferably the full path to the PDF file, e.g. N:\MyFolder\MySubfolder\MyFormName.PDF
I have been looking at the GetAttribute command but I can't seem to find the file name and path in the XML object model.

The filename and path are not stored in the XML.
The command event.target.path will return the full path and file name to you. The command event.target.documentFilename will return just the filename - no Path.

Similar Messages

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    Hello,
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    P2_FILE_PATH will become empty. But in the session, i can find the blob value. but not the "d:\abc.gif "
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    Thanks in advance.
    Regards,
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    Hello Archana,
    You can't do what you want because of some HTML security restrictions – nothing to do with APEX. As you found out, You can capture the value of this item. You can't set it. After submitting the page, the browser is the one to clear the item.
    The only workaround is to work with AJAX and not submit the page until the end of the user input phase.
    Regards,
    Arie.

  • Getting the file path from a File browse button

    Hi,
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  • Issue with Getting the file path from InputFile component

    Hi,
    One of our requirement is like below:
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    MC

    Hi Mahesh,
    I have manage to store the file path from the InputFile component in Jdev 11g. I found the file upload script from this forum and manage to alter it so that i could save the file path to the database. But my problem is to retrieve it back to view as a document. Hope this will help you :)
    This is an example of what I have manage to save to my DB :
    (CLOB) //192.168.238.53/c$/Research/Docs/0906160744/EyeCandyLog.txt
    In my form, I save the file path first before I update the other fields. My code is something like this :
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    // Add event code here...
    InputStream in;
    FileOutputStream out;
    if(tanda == 0){
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    // final Context context = getInitialContext();
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    id = rS01Proposal.dptProposalid();
    tanda = tanda + 1;
    System.out.println("tanda"+ tanda);
    } catch (Exception ex) {
    ex.printStackTrace();
    System.out.println("id"+id);
    proposal = id.substring(6);
    System.out.println("proposal"+proposal);
    UploadedFile file = (UploadedFile)valueChangeEvent.getNewValue();
    String fileUploadLoc = "//192.168.238.53/c$/Research/Docs/"+id+"/";//The place where file will saved
    //create upload directory
    boolean exists = (new File(fileUploadLoc)).exists();
    if (!exists) {
    (new File(fileUploadLoc)).mkdirs();
    if (file != null && file.getLength() > 0) {
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    FacesMessage message =
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    columnL = valueChangeEvent.getComponent().getClientId(context);
    column = columnL.substring(9);
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    columnLengkap = "RS01"+column.toUpperCase();
    System.out.println("columnLengkap"+columnLengkap);
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    out = new FileOutputStream(fileUploadLoc + "" + file.getFilename());
    in = file.getInputStream();
    *for (int bytes = 0; bytes < file.getLength(); bytes++) {*
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    out.close();
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    e.printStackTrace();
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    String byteLength = file != null ? "" + file.getLength() : "0";
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    filename + " (" + byteLength + " bytes)",
    null);
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    a = fileUploadLoc+file.getFilename();
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    try {
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    RS01Proposal rS01Proposal = (RS01Proposal)new InitialContext().lookup("Phase2-RS01Proposal#sr.model.RS01Proposal");
    rS01Proposal.updateDoc(id,proposal,columnLengkap,a);
    flagInsert = flagInsert + 1;
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  • How to set the file path dynamically based on sytem, username, and date

    Hi All,
    My requirement is upload the data into one  structure like xyz that is related to t.code MCSZ.
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    PATH IS: /sapif
    file name is xy789 load .txt
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    how can i set the file path for this.
    shall i put hard code file path?
    because i have to writecode in user-exit.
    plz tell me how to set the file path based ons syetem, username, date
    Thanks in advance
    Ram.A

    Concatenate the field SY-SYSID, SY-UNAME and SY-DATUM for the file path

  • Enable and Disable the file paths

    Hai i have two file paths one logical file path and other is physical file path.
    I took two radio buttons.
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    When i select the 1st radio button then 1st file path is in enable and second file path in disable mode similarly for the second radio button also.
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    With Regards,
    Prasad.Tallapudi.

    i answered in your other post....here is the code again....
    SELECTION-SCREEN BEGIN OF BLOCK B1 WITH FRAME TITLE TEXT-001.
    PARAMETERS: logfile type string default 'Z_DATALOAD',
    FILE(128) TYPE C DEFAULT 'nittest.txt' LOWER CASE.
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    SELECTION-SCREEN BEGIN OF BLOCK B2 WITH FRAME TITLE TEXT-001.
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          if screen-name = 'LOGFILE'.
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            if screen-name = 'FILE'.
              screen-input = '1'.
              endif.
              modify screen.
          endloop.
          endif.
    if the problem gets solved...please close both the posts

  • F4 for the file path

    Hello Everybody,
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    Hi Anushka,
    refer sample code:
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    PARAMETERS : rb_pc  RADIOBUTTON GROUP r1 DEFAULT 'X'
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                                         MODIF ID rb2,
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                                                           "File Directory
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          mode             = c_mode
          title            = text-006
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               WITH sy-msgv1 sy-msgv2 sy-msgv3 sy-msgv4.
        flg_pre = c_x.
      ENDIF.
    ENDFORM.                    " f1000_browse_presentation_file
    *&      Form  f1001_browse_appl_file
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      DATA:  lcl_directory  TYPE char128.
      lcl_directory  = p_direct.
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          filemask         = c_mask
        IMPORTING
          serverfile       = p_f2
        EXCEPTIONS
          canceled_by_user = 1
          OTHERS           = 2.
      IF sy-subrc <> 0.
       MESSAGE e000(zmm) WITH text-039.
       flg_app = 'X'.
      ENDIF.
    ENDFORM.                    " f1001_browse_appl_file
    Reward points if this Helps.
    Manish

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