Query to get Biennium
How to get the query to get out put in the biennium column as below for corresponding year
year Biennium
2000 2000-2001
2001 2000-2001
2002 2002-2003
2003 2002-2003
and so on
Or simply:
WITH t AS (
SELECT 2000 yr FROM dual UNION ALL
SELECT 2001 FROM dual UNION ALL
SELECT 2002 FROM dual UNION ALL
SELECT 2003 FROM dual
SELECT yr YEAR,
(TRUNC(yr / 2) * 2) || '-' || (TRUNC(yr / 2) * 2 + 1 )BIENNIUM
FROM t
YEAR BIENNIUM
2000 2000-2001
2001 2000-2001
2002 2002-2003
2003 2002-2003
SQL>
SY.
Similar Messages
-
Query help : Query to get values SYSDATE-1 18:00 hrs to SYSDATE 08:00 hrs
Hi Team
I want the SQl query to get the data for the following comparison : -
Order Created is a Date Column , and i want to find out all the values from (SYSDATE-1) 18:00 hours to SYSDATE 08:00 hours
i.e.
(SYSDATE-1) 18:00:00 < Order.Created < SYSDATE 08:00:00.
RegardsHi, Rohit,
942281 wrote:
If i want the data in the below way i.e.
from (SYSDATE-1) 18:00 hours to SYSDATE 17:59 hours ---> (SYSDATE-1) 18:00:00 < Order.Created < SYSDATE 07:59:00.If you want to include rows from exactly 18:00:00 yesterday (but no earlier), and exclude rows from exatly 08:00:00 today (or later), then use:
WHERE ord_dtl.submit_dt >= TRUNC (SYSDATE) - (6 / 24)
AND ord_dtl.submit_dt < TRUNC (SYSDATE) + (8 / 24)
So can i use the below format : -
ord_dtl.submit_dt BETWEEN trunc(sysdate)-(6/24) and trunc(sysdate)+(7.59/24) . Please suggest . .59 hours is .59 * 60 * 60 = 2124 seconds (or .59 * 60 = 35.4 minutes), so the last time included in the range above is 07:35:24, not 07:59:59.
If you really, really want to use BETWEEN (which includes both end points), then you could do it with date arithmentic:
WHERE ord_dtl.submit_dt BETWEEN TRUNC (SYSDATE) - (6 / 24)
AND TRUNC (SYSDATE) + (8 / 24)
- (1 / (24 * 60 * 60))but it would be simpler and less error prone to use INTERVALs, as Karthick suggested earlier:
WHERE ord_dtl.submit_dt BETWEEN TRUNC (SYSDATE) - INTERVAL '6' HOUR
AND TRUNC (SYSDATE) + INTERVAL '8' HOUR
- INTERVAL '1' SECONDEdited by: Frank Kulash on Apr 17, 2013 9:36 AM
Edited by: Frank Kulash on Apr 17, 2013 11:56 AM
Changed "- (8 /24)" to "+ (8 /24)" in first code fragment (after Blushadown, below) -
Need to create report query to get latest open and last closed period for given application
Hi All,
I need to create a report query to get below result displayed in report output.
1) - Application name
2) - Ledger name
-o/ -Operating Unit
3) - Last Closed Period
4) - Current Open Period
5) - Date Closed – Last Closed Period
6) - Date Open – Current Open Period
I tr I tried to create the query below is the same. Please let me know if it looks fine.
SELECT *
FROM (SELECT fav.application_name ,
hou.name Operating_Unit_Name,
gl.name Ledger_name,
gl.latest_opened_period_name,
gps.period_name Period_Name,
DECODE(gps.closing_status, 'O', 'Open', 'C', 'Closed') status,
gps.last_update_date Last_status_modified_date
FROM gl_period_statuses gps,
gl_sets_of_books gsob,
fnd_application_vl fav,
hr_operating_units hou,
gl_ledgers gl
WHERE gps.period_name = gps.period_name
AND gps.closing_status ='C'
AND fav.application_short_name =
NVL('&p_application_short_name', fav.application_short_name)
AND gps.application_id = fav.application_id
AND gsob.set_of_books_id = gps.set_of_books_id
AND hou.set_of_books_id = gps.set_of_books_id
AND gl.ledger_id = gsob.set_of_books_id
AND hou.organization_id=NVL('&p_operating_unit',hou.organization_id)
AND gl.ledger_id=NVL('&p_ledger_id',gl.ledger_id)
ORDER BY gps.last_update_date desc )WHERE ROWNUM = 1
UNION ALL
SELECT *
FROM (SELECT fav.application_name Application_Name,
hou.name Operating_Unit_Name,
gl.name Ledger_name,
gl.latest_opened_period_name,
gps.period_name Period_Name,
DECODE(gps.closing_status, 'O', 'Open', 'C', 'Closed') status,
gps.last_update_date Last_status_modified_date
FROM gl_period_statuses gps,
gl_sets_of_books gsob,
fnd_application_vl fav,
hr_operating_units hou,
gl_ledgers gl
WHERE gps.period_name = gps.period_name
AND gps.closing_status = 'O'
AND fav.application_short_name =
NVL('&p_application_short_name', fav.application_short_name)
AND gps.application_id = fav.application_id
AND gsob.set_of_books_id = gps.set_of_books_id
AND hou.set_of_books_id = gps.set_of_books_id
AND gl.ledger_id = gsob.set_of_books_id
AND hou.organization_id=NVL('&p_operating_unit',hou.organization_id)
AND gl.ledger_id=NVL('&p_ledger_id',gl.ledger_id)
ORDER BY gps.last_update_date desc)
WHERE ROWNUM = 1It is within the table I believe (I'm not a DBA or a developer) since I created a BLOB column and then used the file browse feature to allow users to attach a resume to the table in order to be able to perform a search of the attached documents.
I'm just having a hard time pointing the link in the search results report to the document in the blob column.
The information on that page is great if you're trying to create a link to the document on the initial report.
But I created a query using Oracle Text to run a report that does a boolean search of the attached word documents in the table.
When it displays the search results, it doesn't create a link to the document and I can't figure out how to do it.
Here's a link the the instructions I used to create the initial search report with Oracle Text, mind you I only created the index and query, I didn't add in all the link data since they're using documents on websites and I'm using documents in a table.
http://www.oracle.com/technology/products/database/application_express/pdf/apex_text_application_v1.6.pdf
If you can help me with this I'd really appreciate it.
Thanks again.
Greg
Edited by: gjones77 on Dec 2, 2008 8:14 AM -
Query to get the data of all the columns in a table except any one column
Can anyone please tell how to write a query to get the data of all the columns in a table except one particular column..
For Example:
Let us consider the EMP table.,
From this table except the column comm all the remaining columns of the table should be listed
For this we can write a query like this..
Select empno, ename, job, mgr, sal, hiredate, deptno from emp;
Just to avoid only one column, I mentioned all the remaining ( 7 ) columns of the table in the query..
As the EMP table consists only 8 columns, it doesn't seem much difficult to mention all the columns in the query,
but if a table have 100 columns in the table, then do we have to mention all the columns in the query..?
Is there any other way of writing the query to get the required result..?
Thanks..Your best best it to just list all the columns. Any other method will just cause more headaches and complicated code.
If you really need to list all the columns for a table because you don't want to type them, just use something like...
SQL> ed
Wrote file afiedt.buf
1 select trim(',' from sys_connect_by_path(column_name,',')) as columns
2 from (select column_name, row_number() over (order by column_id) as column_id
3 from user_tab_cols
4 where column_name not in ('COMM')
5 and table_name = 'EMP'
6 )
7 where connect_by_isleaf = 1
8 connect by column_id = prior column_id + 1
9* start with column_id = 1
SQL> /
COLUMNS
EMPNO,ENAME,JOB,MGR,HIREDATE,SAL,DEPTNO
SQL> -
How to modify the query to get the output in a single row
Hi All,
Below is the query i have written it works fine
select DISTINCT right(left(CTACCT,13),4) AS LocationNum,
tODS_GLBalance.FiscalYearId AS FiscalYearId,
tODS_GLBalance.FiscalMonthOfYearId AS FiscalMonthOfYearId,
--tods_GLMetadata.Metric,
Case when
tods_GLMetadata.Metric = 'Gross Margin'
Then SUM(Balance)
Else 0
END AS GrossMargin,
Case when
tods_GLMetadata.Metric = 'Occupancy'
Then SUM(Balance)
Else 0
END AS Occupancy,
Case when
tods_GLMetadata.Metric = 'Payroll Dollars'
Then SUM(Balance)
Else 0
END AS Payroll,
Case when
tods_GLMetadata.Metric = 'CF Sales'
Then SUM(Balance)
Else 0
END AS OperatingSales,
Case when
tods_GLMetadata.Metric = 'Operations'
Then SUM(Balance)
Else 0
END AS OperatingExpenses
-- 0 as payroll
from ods.[JJill].[tODS_GLBalance]
inner join ods.Staging.tODS_INF_GLPCT ON tODS_GLBalance.PageNum = tODS_INF_GLPCT.CTPAGE
inner join ods.JJill.tods_GLMetadata ON tods_GLMetadata.AcctDescription = tODS_INF_GLPCT.CTDESC
where
(tODS_GLBalance.FiscalYearId = 2012) and
(tODS_GLBalance.FiscalMonthOfYearId = 2) and
(right(left(CTACCT,13),4)= 3020)
group by
right(left(CTACCT,13),4),
tODS_GLBalance.FiscalYearId,
tODS_GLBalance.FiscalMonthOfYearId,
tods_GLMetadata.Metric
This is the sample output,
LocationNum FiscalYearId FiscalMonthOfYearId GrossMargin Occupancy Payroll OperatingSales OperatingExpenses
3020 2012 2 -112477.00 0.00 0.00 0.00 0.00
3020 2012 2 0.00 0.00 0.00 -158288.94 0.00
3020 2012 2 0.00 0.00 0.00 0.00 5625.44
3020 2012 2 0.00 0.00 24185.79 0.00 0.00
3020 2012 2 0.00 31075.53 0.00 0.00 0.00
But, i am expecting the output to be something like this
LocationNum FiscalYearId FiscalMonthOfYearId GrossMargin Occupancy Payroll OperatingSales OperatingExpenses
3020 2012 2 -112477.00 31075.53 24185.79 -158288.94 5625.44
Can someone please help me with changing my query to get the desired output?
Please let me know if you have any questions.
ThanksTry this:
SELECT DISTINCT
RIGHT(LEFT(CTACCT,13),4) AS LocationNum, tODS_GLBalance.FiscalYearId AS FiscalYearId, tODS_GLBalance.FiscalMonthOfYearId AS FiscalMonthOfYearId,
SUM(CASE WHEN tods_GLMetadata.Metric = 'Gross Margin' THEN Balance ELSE 0 END ) AS GrossMargin,
SUM(CASE WHEN tods_GLMetadata.Metric = 'Occupancy' THEN Balance ELSE 0 END ) AS Occupancy,
SUM(CASE WHEN tods_GLMetadata.Metric = 'Payroll Dollars' THEN Balance ELSE 0 END ) AS Payroll,
SUM(CASE WHEN tods_GLMetadata.Metric = 'CF Sales' THEN Balance ELSE 0 END ) AS OperatingSales,
SUM(CASE WHEN tods_GLMetadata.Metric = 'Operations' THEN Balance ELSE 0 END ) AS OperatingExpenses
FROM ods.[JJill].[tODS_GLBalance]
INNER JOIN ods.Staging.tODS_INF_GLPCT
ON tODS_GLBalance.PageNum = tODS_INF_GLPCT.CTPAGE
INNER JOIN ods.JJill.tods_GLMetadata
ON tods_GLMetadata.AcctDescription = tODS_INF_GLPCT.CTDESC
WHERE tODS_GLBalance.FiscalYearId = 2012
AND tODS_GLBalance.FiscalMonthOfYearId = 2
AND RIGHT(LEFT(CTACCT,13),4) = 3020
GROUP BY right(left(CTACCT,13),4), tODS_GLBalance.FiscalYearId, tODS_GLBalance.FiscalMonthOfYearId, tods_GLMetadata.Metric -
Query to get all active customers in oracle apps
Hi All,
I want to grab all active customers account number, customer name, email address, tel number. Could any one give me the query to get it.
Thanks,
Red.Hi,
Please refer to this document, and see if it helps.
Note: 68046.1 - SQL Scripts To Extract Information Relating To A Particular Customer
https://metalink2.oracle.com/metalink/plsql/ml2_documents.showDocument?p_database_id=NOT&p_id=68046.1
Regards,
Hussein -
Need help in SQL query to get only distinct records
Hi all.
I am new to oracle SQL and i want to write a query to get only distinct values from 2 tables.
for example i hade 2 tables table1(employee_id,employee_no,grade) and another table2 with same structure.
for example data in table1 is
Employeeid employeeno Grade
1 101 A
1 101 B
1 101 E
1 101 D
and data in table 2 is
Employeeid employeeno Grade
1 101 A
1 101 B
1 101 E
i want to display only the fourth row like the data that doesnt exist in table2 i,e (1 101 D)
I had too much records in both tables and i jst want to see the records that is in table 1 not in table 2 only.
employeeid and employeeno are the same in both tables
I hope u understand my query. I user left outer join and right outer join bt it displays all the results that and matching and unmatching. I want jst unmatched records.
Any help is highly Appreciated.
Thanx in Advance.
I am using oracle 10G on windowsTry MINUS:
http://download.oracle.com/docs/cd/B19306_01/server.102/b14200/queries004.htm#i2054381
SQL> -- generating sample data:
SQL> with t1 as (
2 select 1 employeeid, 101 employeeno, 'A' grade from dual union
3 select 1, 101, 'B' from dual union
4 select 1, 101, 'E' from dual union
5 select 1, 101, 'D' from dual
6 )
7 , t2 as (
8 select 1 employeeid, 101 employeeno, 'A' grade from dual union
9 select 1, 101, 'B' from dual union
10 select 1, 101, 'E' from dual
11 )
12 --
13 -- actual query:
14 --
15 select employeeid
16 , employeeno
17 , grade
18 from t1
19 minus
20 select employeeid
21 , employeeno
22 , grade
23 from t2;
EMPLOYEEID EMPLOYEENO G
1 101 D
1 row selected. -
Steps of abap query--- to get the reports
steps of abap query -
to get the reportsHi Deva,
For step by step procedure to create an ABAP query you can refer to the following links
http://www.thespot4sap.com/Articles/SAP_ABAP_Queries_Introduction.asp
http://allaboutsap.blogspot.com/2007/09/sap-query-step-by-step.html -
Query to get the hierarchical results
Hi,
Please help me in writing a Query to get the hierarchical results. I want a result like follows...
course-----groupname---TotalMembers---NotStarted---INProgress---Completed
Course1---country1--------12---------------6----------3-------------3
Course1-----state11-------12---------------6----------3-------------3
Course1------District111--10---------------5----------0-------------0
Course1--------City1111----0---------------0----------0-------------0
Course1--------City1112----1---------------0----------0-------------1
Course1--------City1113----6---------------3----------2-------------1
Course1---country2--------12---------------6----------3-------------3
Course1----state21--------12---------------6----------3-------------3
Course1------District211--10---------------5----------0-------------0
Course1--------City2111----0---------------0----------0-------------0
Course1--------City2112----1---------------0----------0-------------1
Course1--------City2113----6---------------3----------2-------------1
Course2---country1--------12---------------6----------2-------------3
Course2----state11--------12---------------6----------2-------------3
Course2------District111--10---------------5----------0-------------0
Course2--------City1111----0---------------0----------0-------------0
Course2--------City1112----1---------------0----------0-------------1
Course2--------City1113----6---------------3----------1-------------2
Course2---country2--------12---------------6----------3-------------3
Course2-----state21-------12---------------6----------3-------------3
Course2------District211--10---------------5----------0-------------0
Course2--------City2111----0---------------0----------0-------------0
Course2--------City2112----1---------------0----------0-------------1
Course2--------City2113----6---------------3----------2-------------1
These are the Tables available to me.
(I have just given some examle data in tables, to get the idea)
"Groups" Table (This table gives the information of the group)
GROUPID-----NAME-------PARENTID
1---------Universe--------1
2---------country1--------1
3---------state11---------2
4---------District111-----3
5---------City1111--------4
6---------City1112--------4
7---------City1113--------4
8---------country2--------1
9---------state21---------8
10--------District211-----9
11--------City2111--------10
12--------City2112--------10
13--------City2113--------10
"Users" Table (This table provides the user information)
userID----FIRSTNAME---LASTNAME
user1-----------Jim-------Carry
user2-----------Tom-------lee
user3-----------sunny-----boo
user4-----------mary------mall
"User-Group" Tables (This table provides the relation between the groups
and the members)
GROUPID---userID
3-------------user1
3-------------user2
3-------------user4
4-------------user5
5-------------user6
5-------------user7
user_score (This table provides the user scores of different courses)
USERID----course-----STATUS
user1------course1-----complete
user1------course2-----NotStarted
user2------course1-----NotStarted
user2------course2-----complete
user3------course1-----complete
user3------course2-----InProgress
user4------course2-----complete
user4------course1-----NotStarted
I will explain the first four lines of the above result.
Course1---country1--------12---------------6----------4-------------2
Course1-----state11-------12---------------6----------4-------------2
Course1------District111--10---------------5----------3-------------2
Course1--------City1111----0---------------0----------0-------------0
Course1--------City1112----1---------------0----------0-------------1
Course1--------City1113----6---------------3----------2-------------1
# "city1111" group has 0 members
# "city1112" group has 1 member (1 member completed the course1)
# "city1113" group has 6 members(3 members notStarted,2 members
InProgress,1 member completed the course1)
# "District111" is the parent group of above three groups, and has 3
members.(2 members NotStarted,1 member InProgress the course1). But this
group has child groups, so the scores of this group has to rollup the
child groups scores also. Thats why it has 2+3+0+0=6 members Not
Started,1+2+0+0=3 members InProgress,0+0+1+1=2 members completed.
# "state11" group also same as the above group.
I am able to get the group hierarchy by using "Connect By" like follows
"select name,groupid,parentid from groups_info start with groupid=1 connect by parentid = prior groupid;"
But i want to get the result as i have mentioned in the begining of this discussion.
I am using oracle 8i (oracle8.1.7).
Thank you for any help
Srinivas MThis may not be exactly what you want,
but it should be fairly close:
SET LINESIZE 100
SET PAGESIZE 24
COLUMN groupname FORMAT A20
SELECT INITCAP (user_score.course) "course",
groupnames.name "groupname",
COUNT (*) "TotalMembers",
SUM (NVL (DECODE (UPPER (user_score.status), 'NOTSTARTED', 1), 0)) "NotStarted",
SUM (NVL (DECODE (UPPER (user_score.status), 'INPROGRESS', 1), 0)) "InProgress",
SUM (NVL (DECODE (UPPER (user_score.status), 'COMPLETE', 1), 0)) "Completed"
FROM user_score,
user_group,
(SELECT ROWNUM rn,
name,
groupid
FROM (SELECT LPAD (' ', 2 * LEVEL - 2) || name AS name,
groupid
FROM groups
START WITH groupid = 1
CONNECT BY PRIOR groupid = parentid)) groupnames
WHERE user_score.userid = user_group.userid
AND user_group.groupid IN
(SELECT groupid
FROM groups
START WITH groupid = groupnames.groupid
CONNECT BY PRIOR groupid = parentid)
GROUP BY user_score.course, groupnames.name, groupnames.rn
ORDER BY user_score.course, groupnames.rn
I entered the minimal test data that you
provided and a bit more and got this result
(It was formatted as you requested,
but I don't know if it will display properly
on this post, or wrap around):
course groupname TotalMembers NotStarted InProgress Completed
Course1 Universe 6 2 0 4
Course1 country1 5 2 0 3
Course1 state11 5 2 0 3
Course1 District111 2 0 0 2
Course1 City1112 1 0 0 1
Course1 City1113 1 0 0 1
Course1 country2 1 0 0 1
Course1 state21 1 0 0 1
Course1 District211 1 0 0 1
Course1 City2113 1 0 0 1
Course2 Universe 5 1 1 3
Course2 country1 4 1 1 2
Course2 state11 4 1 1 2
Course2 District111 1 0 1 0
Course2 City1113 1 0 1 0
Course2 country2 1 0 0 1
Course2 state21 1 0 0 1
Course2 District211 1 0 0 1
Course2 City2113 1 0 0 1
Here is the test data that I used, in case
anyone else wants to play with it:
create table groups
(groupid number,
name varchar2(15),
parentid number)
insert into groups
values (1,'Universe',null)
insert into groups
values (2,'country1',1)
insert into groups
values (3,'state11',2)
insert into groups
values (4,'District111',3)
insert into groups
values (5,'City1111',4)
insert into groups
values (6,'City1112',4)
insert into groups
values (7,'City1113',4)
insert into groups
values (8,'country2',1)
insert into groups
values (9,'state21',8)
insert into groups
values (10,'District211',9)
insert into groups
values (11,'City2111',10)
insert into groups
values (12,'City2112',10)
insert into groups
values (13,'City2113',10)
create table user_group
(groupid number,
userid varchar2(5))
insert into user_group
values (3,'user1')
insert into user_group
values (3,'user2')
insert into user_group
values (3,'user4')
insert into user_group
values (4,'user5')
insert into user_group
values (5,'user6')
insert into user_group
values (5,'user7')
insert into user_group
values (7,'user8')
insert into user_group
values (13,'user9')
insert into user_group
values (11,'use11')
insert into user_group
values (6,'use6')
create table user_score
(userid varchar2(5),
course varchar2(7),
status varchar2(10))
insert into user_score
values ('use6','course1','complete')
insert into user_score
values ('user9','course1','complete')
insert into user_score
values ('user9','course2','complete')
insert into user_score
values ('user8','course1','complete')
insert into user_score
values ('user8','course2','InProgress')
insert into user_score
values ('user1','course1','complete')
insert into user_score
values ('user1','course2','NotStarted')
insert into user_score
values ('user2','course1','NotStarted')
insert into user_score
values ('user2','course2','complete')
insert into user_score
values ('user3','course1','complete')
insert into user_score
values ('user3','course2','InProgress')
insert into user_score
values ('user4','course2','complete')
insert into user_score
values ('user4','course1','NotStarted') -
Query to get total counts in the given scenario
Hi,
I am using Oracle 10g
I have a table A with following data
AgId Trm CD S
1000 100010 12-JAN A
1000 100019 20-MAR A
1000 100019 20-JUL D
1001 100011 25-JAN A
1001 100011 20-FEB D
1001 100011 23-MAR A
1001 100012 31-JAN A
1002 100013 14-FEB A
1002 100013 05-APR D
1002 100015 02-MAY A
1003 100014 03-MAR A
1003 100014 25-MAR D
1004 100016 22-MAY A
1004 100017 21-JUN A
1004 100018 01-JUL A
1005 100020 21-MAY D
1005 100020 21-JUL A
1005 100020 11-AUG D
Here the overall status of AgId '1000' is A as he is having atleast 1 Trm active
Similarly, status of AgId '1001' is A
status of AgId '1002' is A
But,status of AgId '1003' is D as his trm is disconnected after activation(according to date column'CD')
Then, status of AgId '1004' is A
and finally status of AgId '1005' is D again as his trm deactivated, activated and deactivated at last
So, considering these criteria can any one give me a query to get total no of AgId's who are 'Active' and similarly for 'Deactive'Hi,
when you put some code please enclose it between two lines starting with {noformat}{noformat}
i.e.:
{noformat}{noformat}
CREATE TABLE ... etc.
{noformat}{noformat}
Also do not forget to put correct statements. Your insert were missing semicolon at the end.
Coming back to your problem, I assum that the current status of any trm is the latest status so I have done what follows:
{code:sql}
SELECT agid
, trm
, cd
, s
, ROW_NUMBER () OVER (PARTITION BY agid, trm ORDER BY cd) rn
, COUNT (*) OVER (PARTITION BY agid, trm) rn_tot
FROM a
ORDER BY agid, trm, cd;
Output:
AGID TRM CD S RN RN_TOT
1000 100010 12-JAN-12 A 1 1
1000 100019 20-MAR-12 A 1 2
1000 100019 20-JUL-12 D 2 2
1001 100011 25-JAN-12 A 1 3
1001 100011 20-FEB-12 D 2 3
1001 100011 23-MAR-12 A 3 3
1001 100012 31-JAN-12 A 1 1
1002 100013 14-FEB-12 A 1 2
1002 100013 05-APR-12 D 2 2
1002 100015 02-MAY-12 A 1 1
1003 100014 03-MAR-12 A 1 2
1003 100014 25-MAR-12 D 2 2
1004 100016 22-MAY-12 A 1 1
1004 100017 21-JUN-12 A 1 1
1004 100018 01-JUL-12 A 1 1
1005 100020 21-MAY-12 D 1 3
1005 100020 21-JUL-12 A 2 3
1005 100020 11-AUG-12 D 3 3I have used to columns rn and rn_tot to find the latest entry for a specific agid, trm
Using the query above I have done the following:
WITH mydata AS
SELECT agid
, trm
, cd
, s
, ROW_NUMBER () OVER (PARTITION BY agid, trm ORDER BY cd) rn
, COUNT (*) OVER (PARTITION BY agid, trm) rn_tot
FROM a
SELECT agid
, CASE WHEN SUM (CASE s WHEN 'A' THEN 1 END) > 0 THEN 'A' ELSE 'D' END s
FROM mydata
WHERE rn = rn_tot
GROUP BY agid;
Output:
AGID S
1000 A
1001 A
1002 A
1003 D
1004 A
1005 D
{code}
Which is listing the agid and its status if at least there is one trm with final status 'A' for that agid.
To sum up everything you can do simply like this:
{code:sql}
WITH mydata AS
SELECT agid
, trm
, cd
, s
, ROW_NUMBER () OVER (PARTITION BY agid, trm ORDER BY cd) rn
, COUNT (*) OVER (PARTITION BY agid, trm) rn_tot
FROM a
totdata AS
SELECT agid
, CASE WHEN SUM (CASE s WHEN 'A' THEN 1 END) > 0 THEN 'A' ELSE 'D' END s
FROM mydata
WHERE rn = rn_tot
GROUP BY agid
SELECT S, COUNT(*) cnt
FROM totdata
GROUP BY S;
Output:
S CNT
D 2
A 4
{code}
Regards.
Al -
Oracle query to get all occurences of a text in a string
Hi
Does anybody know how to write a query to get all occurences of a text in a string in different rows of the table
For eg:
I have a string <aa>bb</aa><aa>cc</aa><aa>ddd</aa>
I have to find every occurence of <aa> and get the data between <aa> and </aa>
So the output should be
bb
cc
ddd
I think this can be done by using a regular expression but I dont know how.
Can anyone help me?
Thanks in advance.user2360027 wrote:
BluShadow,
The query gives correct results if i only have <aa></aa>
What if i have <ff></ff>?
Example:
<aa>bb</aa><aa>cc</aa><aa>ddd</aa><ff>dsd</ff>
I want to have the following (dsd should not be there in the result)
bb
cc
dddThis is a new requirement and not what you asked for in your original post. Perhaps you should tell us exactly what you are trying to achieve and what database version you are using to save us guessing.
To crokitta,
This version will deal with multiple rows..
SQL> ed
Wrote file afiedt.buf
1 with t as (select '<aa>bb</aa><aa>cc</aa><aa>ddd</aa>' as x from dual union all
2 select '<aa>xx</aa><aa>yy</aa>' from dual)
3 -- end of test data
4 select x, vals
5 from (
6 select x, regexp_replace(REGEXP_SUBSTR (x, '>[^<]+', 1, lvl),'[<>]') as vals
7 from t
8 ,(select level lvl from dual connect by level <= (select max(length(regexp_replace(x,'[^>]*'))/2) from t))
9 )
10 where vals is not null
11* order by 1,2
SQL> /
X VALS
<aa>bb</aa><aa>cc</aa><aa>ddd</aa> bb
<aa>bb</aa><aa>cc</aa><aa>ddd</aa> cc
<aa>bb</aa><aa>cc</aa><aa>ddd</aa> ddd
<aa>xx</aa><aa>yy</aa> xx
<aa>xx</aa><aa>yy</aa> yy
SQL> -
Can I get a query to get the output data like 4th column instead of 3rd col
Can I get a query to get the output data like 4th column instead of 3rd column ?
SQL> select emp.deptno, empno, rownum from emp, dept where emp.deptno=dept.deptno;
DEPTNO EMPNO ROWNUM
10 7782 *1* *1*
10 7839 *2* *2*
10 7934 *3* *3*
20 7369 *4* *1*
20 7876 *5* *2*
20 7902 *6* *3*
20 7788 *7* *4*
20 7566 *8* *5*
30 7499 *9* *1*
30 7698 *10* *2*
30 7654 *11* *3*
30 7900 *12* *4*
30 7844 *13* *5*
30 7521 *14* *6*
14 rows selected.SQL> select emp.deptno, emp.empno,
2 row_number() over(order by emp.deptno, emp.empno) rn,
3 row_number() over(partition by emp.deptno order by emp.empno) dept_rn
4 from emp, dept
5 where emp.deptno=dept.deptno
6 order by emp.deptno, emp.empno;
DEPTNO EMPNO RN DEPT_RN
10 7782 1 1
10 7839 2 2
10 7934 3 3
20 7369 4 1
20 7566 5 2
20 7788 6 3
20 7876 7 4
20 7902 8 5
30 7499 9 1
30 7521 10 2
30 7654 11 3
30 7698 12 4
30 7844 13 5
30 7900 14 6
14 rows selected.Regards,
Dima -
Query to get the blocker and holder info
Hi All,
I have framed the following query to get the blocker and holder info.I intend to use this query in a auto-generated mail which executes every 15 mins
I have put an outer join on the holder because the holder query might have been executed at the time the auto mail configuration fires this query
I am not a dba and was apprehensive is there is some mistake in the logic of my query. I was also expecting to join v$sql_bind_capture using sql_hash_value and sql_address just the way in which I have joined v$sqlarea
Looking forward to your kind help in vetting the below query
Select distinct waiting_session,
dba_waiters.holding_session,
decode(to_char(session_waiting_info.STATE),'0','waiter is currently waiting','-2','duration of last wait by waiter is unknown','-1','waiter waited for a short time',' waiter waited long time') "waiters waiting state",
decode(session_waiting_info.WAIT_TIME,0,'waiter waiting') "waiters last wait time",
decode(to_char(session_holding_info.STATE),'0','holder is currently waiting','-2','duration of last wait by holder is unknown','-1','holder waited for a short time','holder waited long time') "holders waiting state",
decode(session_holding_info.WAIT_TIME,0,'waiter waiting') "holders last wait time",
sql_waiting_info.sql_text "query of the waiter",
sql_holding_info.sql_text "query of the holder",
session_waiting_info.STATUS "waiting STATUS",
session_holding_info.STATUS "holding STATUS",
session_waiting_info.process "waiting process",
session_waiting_info.PROGRAM "waiting PROGRAM",
session_holding_info.process "holding process",
session_holding_info.PROGRAM "holding PROGRAM",
session_waiting_info.ROW_WAIT_OBJ# "waiting object",
session_waiting_info.ROW_WAIT_ROW# "waiting row",
session_holding_info.ROW_WAIT_OBJ# "holding object",
session_holding_info.ROW_WAIT_ROW# "holding row",
session_waiting_info.BLOCKING_SESSION_STATUS "waiting session status",
session_holding_info.BLOCKING_SESSION_STATUS "holding session status",
session_waiting_info.username "holding os username",
session_holding_info.username "waiting os username",
session_waiting_info.MACHINE "waiting MACHINE",
session_waiting_info.TERMINAL "waiting TERMINAL",
session_holding_info.MACHINE "holding MACHINE",
session_holding_info.TERMINAL "holding TERMINAL",
session_waiting_info.TYPE "waiting TYPE",
session_holding_info.TYPE "holding TYPE"
from dba_waiters,
v$session session_holding_info,
v$session session_waiting_info,
v$sqlarea sql_waiting_info,
v$sqlarea sql_holding_info
Where dba_waiters.waiting_Session = session_waiting_info.sid
and dba_waiters.holding_Session = session_holding_info.sid
And session_waiting_info.sql_hash_value = sql_waiting_info.hash_value
And session_waiting_info.sql_address = sql_waiting_info.address
and session_holding_info.sql_hash_value = sql_holding_info.hash_value(+)
And session_holding_info.sql_address = sql_holding_info.address(+)
and dba_waiters.mode_held <> 'None'
Regards,
Vishal
Edited by: user11924113 on Feb 18, 2011 2:39 AMQuery to track the holder and waiter info
People who reach this place for a similar problem can use the above link to find their answer
Regards,
Vishal -
Query to get InfoObject(ReportObject) from specific Folder
Hi,
I am using XI Release 2.I am having one report object in two folders with the same name.
example: I am having one report object named TestReport that exist in folder ALL as well as folder TEMPORARY in CMS.
Following query i am using:
"SELECT TOP 1 * FROM CI_INFOOBJECTS WHERE SI_PROGID = 'CrystalEnterprise.Report'").append(" AND SI_INSTANCE=0 AND SI_NAME='").append(TestReport ).append("'");
but it always returns the report object from folder ALL while i want to have report Object from folder TEMPORARY
Reporrt Path: path://InfoObjects/Root Folder/Temporary/
Can anyone help me out with the query to get the report object from specific folder?
Thanks
Prakhar Paharia
Edited by: prakhar paharia on Mar 10, 2009 3:43 PM
Edited by: prakhar paharia on Mar 10, 2009 3:44 PM
Edited by: prakhar paharia on Mar 10, 2009 4:17 PMHello Prakhar,
You are querying the the CI_INFOOBJECTS table for crystal reports that have the name TestReport.
If a crystal with name TestReport exists in folder ALL and another crystal with name TestReport exists in folder TEMPORARY , you should get two INFOOBJECTs with your query!
Look at your query :
SELECT TOP 1 means select one entity.
I guess this is the reason for your problem.
bernd
Edited by: BerndB on Mar 12, 2009 8:42 AM -
Query to get users using a Form
Hi All
I would like to build a query to get all users who is having access to a form. I could get the cases
where there is no submenus. But how can I handles cases were submenus also there. Please help. I have checked
the other posts in this forum. But none is giving a possibility of giving single query for this.
Kindly help.
Version 12.1.3
Thanks,I guess my question was confusing.
I build a query like this to getthe information, but it will work only if the function is attached directly to the main menu. It will not work incase of submentus.
SELECT distinct usr.user_name FROM
FND_FORM_VL form,
FND_FORM_FUNCTIONS_VL func,
FND_MENU_ENTRIES_VL menu_l,
FND_MENUS_VL menu_h,
FND_RESPONSIBILITY_VL resp,
FND_USER_RESP_GROUPS_DIRECT usr_resp,
FND_USER usr
WHERE func.form_id = form.form_id
AND menu_l.FUNCTION_ID = func.FUNCTION_ID
and menu_h.MENU_ID = menu_l.menu_id
and form.form_name = :FORM_NAME
and resp.MENU_ID = menu_h.menu_id
and usr_resp.responsibility_id = resp.responsibility_id
and usr.user_id = usr_resp.user_id ;
Maybe you are looking for
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We have a case where we have to call the SO change BAPI twice in rapid succession on the same SO. It would be nice if we could avoid this, but we can't, so let's assume that redesigning the code is not an answer to the problem. In our dev instance,
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I sent a mail that exceeded the maximum size of the recipients mailbox. When the mail-delivery message came back, my system HD was full and the incoming mail could not be stored. After I got my Mac back running, the mail-delivery-error-message keeps
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