Replacing a set of characters from a string in oracle sql query

I want to replace a set of characters ( ~ ! @ # $ % ^ * / \ + : ; | < > ? _ ,) from a STRING in sql
select 'TESTING ! ABC 123 #'
FROM DUAL;
What is the best way to do it? Please provide examples also.

What is your expected output... The query I posted just removes them, it never replaces them with spaces..your string already has space.. if you want to remove space as well .. try this...
SELECT TRANSLATE ('TESTING ! ABC 123 #', '-~!@#$%^*/\+:;|<>?_, ', ' ') FROM DUAL;
Output:
--TESTINGABC123
Else post your expected output..
Cheers,
Manik.

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Removing non-alpha-numeric characters from a string

How can I remove all non-alpha-numeric characters from a string? (i.e. only alpha-numerics should remain in the string).

Or even without a loop ?
Extract from the help for the Search and Replace String function :
Right-click the Search and Replace String function and select Regular Expression from the shortcut menu to configure the function for advanced regular expression searches and partial match substitution in the replacement string.
Extract from the for the advanced search options :
[a-zA-Z0-9] matches any lowercase or uppercase letter or any digit. You also can use a character class to match any character not in a given set by adding a caret (^) to the beginning of the class. For example [^a-zA-Z0-9] matches any character that is not a lowercase or uppercase letter and also not a digit.
Message Edité par JB le 05-06-2008 01:49 PM
Attachments:
Example_VI_BD4.png ‏2 KB

Removing characters from a String (concats, substrings, etc)

This has got me pretty stumped.
I'm creating a class which takes in a string and then returns the string without vowels and without even numbers. Vowels and even characters are considered "invalid." As an example:
Input: "hello 123"
Output: "hll 13"
The output is the "valid" form of the string.
Within my class, I have various methods set up, one of which determines if a particular character is "valid" or not, and it is working fine. My problem is that I can't figure out how to essentially "erase" the invalid characters from the string. I have been trying to work with substrings and the concat method, but I can't seem to get it to do what I want. I either get an OutOfBoundsException throw, or I get a cut-up string that just isn't quite right. One time I got the method to work with "hello" (it returned "hll") but when I modified the string the method stopped working again.
Here's what I have at the moment. It doesn't work properly for all strings, but it should give you an idea of where i'm going with it.
public String getValidString(){
          String valid = str;
          int start = 0;
          for(int i=0; i<=valid.length()-1; i++){
               if(isValid(valid.charAt(i))==false){
                         String sub1 = valid.substring(start, i);
                         while(isValid(valid.charAt(i))==false)
                              i++;
                         start=i;
                         String sub2 = valid.substring(i, valid.length()-1);
                         valid = sub1.concat(sub2);
          return valid;
     }So does anybody have any advice for me or know how I can get this to work?
Thanks a lot.

Thansk for the suggestions so far, but i'm not sure how to implement some of them into my program. I probably wasn't specific enough about what all I have.
I have two classes. One is NoVowelNoEven which contains the code for handling the string. The other is simply a test class, which has my main() method, used for running the program.
Here's my class and what's involved:
public class NoVowelNoEven {
//data fields
     private String str;
//constructors
     NoVowelNoEven(){
          str="hello";
     NoVowelNoEven(String string){
          str=string;
//methods
     public String getOriginal(){
          return str;
     public String getValidString(){
          String valid = str;
          int start = 0;
          for(int i=0; i<=valid.length()-1; i++){
               if(isValid(valid.charAt(i))==false){
                         String sub1 = valid.substring(start, i);
                         while(isValid(valid.charAt(i))==false)
                              i++;
                         start=i;
                         String sub2 = valid.substring(i, valid.length()-1);
                         valid = sub1.concat(sub2);
          return valid;
     public static int countValidChar(String string){
          int valid=string.length();
          for(int i=0; i<=string.length()-1; i++){
               if(isNumber(string.charAt(i))==false){
                    if((upperVowel(string.charAt(i))==true)||lowerVowel(string.charAt(i))){
                         valid--;}
               else if(even(string.charAt(i))==true)
                    valid--;
          return valid;
     private static boolean even(char num){
          boolean even=false;
          int test=(int)num-48;
          if(test%2==0)
               even=true;
          return even;
     private static boolean isNumber(char chara){
          boolean number=false;
          for(int i=0; i<=9; i++){
               if((int)chara-48==i){
                    number=true;
          return number;
     private static boolean isValid(char chara){
          boolean valid=true;
          if(isNumber(chara)==true){
               if(even(chara)==true)
                    valid=false;
          if((upperVowel(chara)==true)||(lowerVowel(chara)==true))
               valid=false;
          return valid;
}So in my test class i'd have something like this:
public class test {
public static void main(String[] args){
     NoVowelNoEven test1 = new NoVowelNoEven();
     NoVowelNoEven test2 = new NoVowelNoEven("hello 123");
     System.out.println(test1.getOriginal());
     //This prints hello   (default constructor string is "hello")
     System.out.println(test1.countValidChar(test1.getOriginal()));
     //This prints 3
     System.out.println(test1.getValidString());
     //This SHOULD print hll
}

Removing non english characters from my string input source

Guys,
I have problem where I need to remove all non english (Latin) characters from a string, what should be the right API to do this?
One I'm using right now is:
s.replaceAll("[^\\x00-\\x7F]", "");//s is a string having chinese characters.
I'm looking for a standard Solution for such problems, where we deal with multiple lingual characters.
TIA
Nitin

Nitin_tiwari wrote:
I have a string which has Chinese as well as Japanese characters, and I only want to remove only Chinese characters.
What's the best way to go about it?Oh, I see!
Well, the problem here is that Strings don't have any information on the language. What you can get out of a String (provided you have the necessary data from the Unicode standard) is the script that is used.
A script can be used for multiple languages (for example English and German use mostly the same script, even if there are a few characters that are only used in German).
A language can use multiple scripts (for example Japanese uses Kanji, Hiragana and Katakana).
And if I remember correctly, then Japanese and Chinese texts share some characters on the Unicode plane (I might be wrong, 'though, since I speak/write neither of those languages).
These two facts make these kinds of detections hard to do. In some cases they are easy (separating latin-script texts from anything else) in others it may be much tougher or even impossible (Chinese/Japanese).

Removing characters from a String

Hi!
I have a large String that has some unwanted characters in it that I want to remove. Here is an example:
AA1lbmNvZGVkUGFy\015\012YW1zdAACW0JbABBlbm5MQ2Is there any method I can use to remove the characters \015\012 from the String. I looked at the method String.replace(char, char); but this is unsuitable because I can only remove one charater at a time an I may have this character occuring legitimately elsewhere in my String. Would it be possible in some way to traverse the String and identify the pattern of \015\012 and remove that.
I'd appreciate any help,
Thanks
Chris

Specifically, str = str.replaceAll("\\\\01[25]", "");The replaceAll method is only available in v1.4.0 or later.

Removing Non-Ascii Characters from a String

Hi Everyone,
I would like to remove all NON-ASCII characters from a large string. For example, I am taking text from websites and would like to remove all the strange arabic and asian characters. How can I accomplish this?
Thank you in advance.

I would like to remove all NON-ASCII characters from a large string. I don't know if its a good method but try this:
str="\u6789gj";
output="";
for(char c:str.toCharArray()){
if((c&(char)0xff00)==0){
output=output+c;
System.out.println(output);
all the strange arabic and asian characters.Don't call them so.... I am an Indian Muslim ;-) ....
Thanks!

Remove $%&* characters from a String

Hi,
I have the following program that is supposed to detect a subsequence from a String (that contains $ signs) and remove it. This is a bit tricky, since because of $ signs, the replaceAll method for String does not work. When I use replaceAll for removing the part of the String w/ no $ signs, replaceAll works perfectly, but my code needs to cover the $ signs as well.
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If anyone has any idea on this, I would greatly appreciate it!
Looking forward to your help!
public class StringDivider {
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         String removeSymbols = "$d $e $f";
         int startIndex = symbols.indexOf(removeSymbols);
         int endIndex = startIndex + removeSymbols.length()-1;
         for(int i=startIndex;i<endIndex+1;i++)
              if(symbols.charAt(i)=='$')
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                   //delete $ signs from the specific sequence only (as opposed to all the $ signs)
         System.out.println(symbols);
}

A little modification on the last version:
This one's more accurate.
public class StringDivider {
     public static void main(String [] args){
          String symbols = "$a $b $c $d $e $f $g $h $i $j $k l m n o p";
              String removeSymbols = "$d $e $f $g";
              if(symbols.indexOf(removeSymbols)!=-1)
                   if(removeSymbols.indexOf("$")!=-1)
                        removeSymbols = removeSymbols.replace('$', ' ').trim();
                        removeSymbols = removeSymbols.replaceAll("[ ]+", " ");
                        String [] symbolsWithoutSpecialChars = removeSymbols.split(" ");
                        for(int i=0;i<symbolsWithoutSpecialChars.length;i++)
                             symbols = symbols.replaceAll("[\\$]*"+symbolsWithoutSpecialChars, "");
                         symbols = symbols.replaceAll("[ ]+", " ");
               else
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          symbols = symbols.trim();
          System.out.println(symbols);

Can't get an array of characters from a string!

If I have a string eg "Hello World", how do I get an array containing the characters eg. [H,e,l,l,o, ,W,o,r,l,d]
Can any one help me please?

Or to get the chars you want from a String object you can do this:
String helloString = new String("Hello World");
char[] helloArray = helloString.toCharArray();

How can I remove all non alpha/space characters from a string

Subject changed by moderator. Please use a meaningful subject in future.
Hi all,
Can anyone tell me.
how to get only alphabets & spaces from the string..
suppose..
raj*&{]afhajk ajkf_+#fkh jah jka7767jk hhha
I need only
rajafhajk ajkf fkh jah jkajk hhha
thanks..
Rajeev
Edited by: Matt on Feb 17, 2009 3:36 PM

This will work.
CONSTANTS:
sm2big(52) VALUE
    'aAbBcCdDeEfFgGhHiIjJkKlLmMnNoOpPqQrRsStTuUvVwWxXyYzZ'.
DATA:
str_out(60),
str_in(60) VALUE
'raj*&{]afhajk ajkf_+^#^fkh jah jka7767jk hhha',
my_len          TYPE i,
pos1            TYPE i,
pos2            TYPE i.
START-OF-SELECTION.
COMPUTE my_len = strlen( str_in ).
CLEAR pos1.
CLEAR pos2.
WHILE pos1 LT my_len.
    IF str_in+pos1(1) co sm2big
    OR str_in+pos1(1) EQ ' '.
      str_out+pos2(1) = str_in+pos1(1).
      pos2 = pos2 + 1.
    ENDIF.
    pos1 = pos1 + 1.
ENDWHILE.
WRITE:/ 'String In', str_in.
WRITE:/ 'String Out', str_out.
and the output
String In      raj*&{]afhajk ajkf_+^#^fkh jah jka7767jk hhha
String Out   rajafhajk ajkffkh jah jkajk hhha

Remove all non-number characters from a string

hi
How i can remove all non-number characters from a column ? for example , i have a column that contains data like
'sd3456'
'gfg87s989'
'45/45fgfg'
'4354-df4456'
and i want to convert it to
'3456'
'87989'
'4545'
'43544456'
thx in adv

Or in 9i,
Something like this ->
satyaki>
satyaki>with vat
2 as
3    (
4      select 'sd3456' cola from dual
5      union all
6      select 'gfg87s989' from dual
7      union all
8      select '45/45fgfg' from dual
9      union all
10      select '4354-df4456' from dual
11    )
12 select translate(cola,'abcdefghijklmnopqrstuvwxyz-/*#$%^&@()/?,<>;:{}[]|\`"',' ') res
13 from vat;
RES
3456
87989
4545
43544456
Elapsed: 00:00:00.00
satyaki>
{code}
I checked this with minimum test cases. It will be better if you checked it with other cases.
Regards.
Satyaki De.

Return selected number of characters from a string

How do you select a certain number of charaters from a string?
For example:
I have a string that contains 51-108
I want to separate the string into two strings one containing 51 and another one containing 108.

A StringTokenizer will do it.
StringTokenizer strtok = new StringTokenizer(yourString, "-");

Error "Conversion failed when converting date and/or time from character string" to execute one query in sql 2008 r2, run ok in 2005.

I have a table-valued function that run in sql 2005 and when try to execute in sql 2008 r2, return the next "Conversion failed when converting date and/or time from character string".
USE [Runtime]
GO
/****** Object: UserDefinedFunction [dbo].[f_Pinto_Graf_P_Opt] Script Date: 06/11/2013 08:47:47 ******/
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
CREATE FUNCTION [dbo].[f_Pinto_Graf_P_Opt] (@fechaInicio datetime, @fechaFin datetime)
-- Declaramos la tabla "@Produc_Opt" que será devuelta por la funcion
RETURNS @Produc_Opt table ( Hora datetime,NSACOS int, NSACOS_opt int)
AS
BEGIN
-- Crea el Cursor
DECLARE cursorHora CURSOR
READ_ONLY
FOR SELECT DateTime, Value FROM f_PP_Graficas ('Pinto_CON_SACOS',@fechaInicio, @fechaFin,'Pinto_PRODUCTO')
-- Declaracion de variables locales
DECLARE @produc_opt_hora int
DECLARE @produc_opt_parc int
DECLARE @nsacos int
DECLARE @time_parc datetime
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SET @produc_opt_hora = (SELECT * FROM f_Valor (@fechaFin,'Pinto_PRODUC_OPT'))
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/************ BUCLE WHILE QUE SE VA A MOVER A TRAVES DEL CURSOR ************/
WHILE (@@fetch_status <> -1)
BEGIN
IF (@@fetch_status = -2)
BEGIN
-- Terminamos la ejecucion
BREAK
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FETCH NEXT FROM cursorHora INTO @time_parc,@nsacos
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You can search the forums for that error message and find previous discussions - they all boil down to the same problem. Somewhere in your query that calls this function, the code invoked implicitly converts from string to date/datetime. In general,
this works in any version of sql server if the runtime settings are correct for the format of the string data. The fact that it works in one server and not in another server suggests that the query executes with different settings - and I'll assume for
the moment that the format of the data involved in this conversion is consistent within the database/resultset and consistent between the 2 servers.
I suggest you read Tibor's guide to the datetime datatype (via the link to his site below) first - then go find the actual code that performs this conversion. It may not be in the function you posted, since that function also executes other functions.
You also did not post the query that calls this function, so this function may not, in fact, be the source of the problem at all.
Tibor's site

Extracting the partial string from the string in oracle

Hello Friends,
I have a string like this
var str = '/G/CNH/CNHCornerstone/currentCode/data/Working/Images/ModelImages/png/7402203E-607D-E111-9CA5-005056875BD6.png'
I want to extract only 7402203E-607D-E111-9CA5-005056875BD6 from the string .
Please let me know how to implement this ..
thanks/kumar
Edited by: kumar73 on Apr 10, 2012 12:34 PM

hope this works
set serveroutput on
declare
str1 varchar(4000);
str2 varchar(4000);
begin
str1 := '/G/CNH/CNHCornerstone/currentCode/data/Working/Images/ModelImages/png/7402203E-607D-E111-9CA5-005056875BD6.png';
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output
string 1 : /G/CNH/CNHCornerstone/currentCode/data/Working/Images/ModelImages/png/7402203E-607D-E111-9CA5-005056875BD6.png
string 2 : 7402203E-607D-E111-9CA5-005056875BD6.png
PL/SQL procedure successfully completed

How to pass a string value from XL sheet cell to SQL query.

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I am using SQL query in XL sheet to fetch some data. for that i am using ODBC connection. Now I want to pass a string from XL sheet Cell value in the where clause of Select statement, Please let me know how to do this.
Below is My code:
nge("A4").Select
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What does "XL" (whatever that is) have to do with Crystal Reports which is what you are obviously working with have to do with the Oracle database?
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Oracle SQL query for getting specific special characters from a table

Hi all,
This is my table
Table Name- Table1
S.no    Name
1          aaaaaaaa
2          a1234sgjghb
3          a@3$%jkhkjn
4          abcd-dfghjik
5          bbvxzckvbzxcv&^%#
6          ashgweqfg/gfjwgefj////
7          sdsaf$([]:'
8          <-fdsjgbdfsg
9           dfgfdgfd"uodf
10         aaaa bbbbz#$
11         cccc dddd-/mnm
The output has to be
S.no    Name
3          a@3$%jkhkjn
5          bbvxzckvbzxcv&^%#
7          sdsaf$([]:'
8          <-fdsjgbdfsg
10         aaaa bbbbz#$
It has to return "Name" column which is having special characters,whereas some special chars like -, / ," and space are acceptable.
The Oracle query has to print columns having special characters excluding -,/," and space
Can anyone help me to get a SQL query for the above.
Thanks in advance.

You can achieve it in multiple ways. Here are few.
SQL> with t
2 as
3 (
4 select 1 id, 'aaaaaaaa' name from dual union all
5 select 2 id, 'a1234sgjghb' name from dual union all
6 select 3 id, 'a@3$%jkhkjn' name from dual union all
7 select 4 id, 'abcd-dfghjik' name from dual union all
8 select 5 id, 'bbvxzckvbzxcv&^%#' name from dual union all
9 select 6 id, 'ashgweqfg/gfjwgefj////' name from dual union all
10 select 7 id, 'sdsaf$([]:''' name from dual union all
11 select 8 id, '<-fdsjgbdfsg' name from dual union all
12 select 9 id, 'dfgfdgfd"uodf' name from dual union all
13 select 10 id, 'aaaa bbbbz#$' name from dual union all
14 select 11 id, 'cccc dddd-/mnm' name from dual
15 )
16 select *
17    from t
18   where regexp_like(translate(name,'a-/" ','a'), '[^[:alnum:]]');
        ID NAME
         3 a@3$%jkhkjn
         5 bbvxzckvbzxcv&^%#
         7 sdsaf$([]:'
         8 <-fdsjgbdfsg
        10 aaaa bbbbz#$
SQL> with t
2 as
3 (
4 select 1 id, 'aaaaaaaa' name from dual union all
5 select 2 id, 'a1234sgjghb' name from dual union all
6 select 3 id, 'a@3$%jkhkjn' name from dual union all
7 select 4 id, 'abcd-dfghjik' name from dual union all
8 select 5 id, 'bbvxzckvbzxcv&^%#' name from dual union all
9 select 6 id, 'ashgweqfg/gfjwgefj////' name from dual union all
10 select 7 id, 'sdsaf$([]:''' name from dual union all
11 select 8 id, '<-fdsjgbdfsg' name from dual union all
12 select 9 id, 'dfgfdgfd"uodf' name from dual union all
13 select 10 id, 'aaaa bbbbz#$' name from dual union all
14 select 11 id, 'cccc dddd-/mnm' name from dual
15 )
16 select *
17    from t
18   where translate
19         (
20            lower(translate(name,'a-/" ','a'))
21          , '.0123456789abcdefghijklmnopqrstuvwxyz'
22          , '.'
23         ) is not null;
        ID NAME
         3 a@3$%jkhkjn
         5 bbvxzckvbzxcv&^%#
         7 sdsaf$([]:'
         8 <-fdsjgbdfsg
        10 aaaa bbbbz#$
SQL>

Replacing a set of characters from a string in oracle sql query

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