11G Interval Partitioning range based on number

All the Oracle documentation states that interval partitioning can be range partitioned on a column that is NUMBER or DATE datatype, but the examples all show just for a DATE column and for a monthly interval.
I need an interval by year, where the partition column is NUMBER and contains 4 digit numbers for year like 2010.
.Does anyone have a working example for creating an interval partitioned table on a NUMBER datatype column?

Please do not refer people to the old, non-maintained psoug site. I have asked this several times in the past.
You do people no favor sending them to the old site contains as it contains inaccurate information I am unable to access and fix.
The new site is www.morganslibrary.org.
And I am a bit of an expert on the subject ... as I am "Morgan."
Thank you.

Similar Messages

  • 11g interval partitioning and global index maintenance

    hi gurus,
    in 11g interval partitioning system can automatically manage the creation of new partitions based on data.
    in this case do we need to manage global indexes?
    in earlier versions, we have to update global indexes whenever there is a partition maintenance operation.
    please suggest.
    thanks,
    charles

    user570138 wrote:
    in earlier versions, we have to update global indexes whenever there is a partition maintenance operation.In 10gR2 you don't need to update/rebuild a global index after adding a partition to the base table.
    So it should be the same when using interval partitioning.
    Regards
    Maurice

  • Oracle 11g interval partitioning - meaningfull partition-names

    Hello,
    On 11g, when creating interval partitions, the partitions get automatically created just fine. Very nice feature. But is it possible to supply meaningfull names to them?
    Now they get names SYS_nnn, but I would like to name them for instance SALES_2007.
    Here is one example on how to use interval partitioning:
    http://download.oracle.com/docs/cd/B28359_01/server.111/b32024/part_admin.htm#BAJHFFBE
    And here is the syntax guide:
    http://download.oracle.com/docs/cd/B28359_01/server.111/b28286/statements_7002.htm#sthref7644
    I don't see how to accomplish meaningfull names (automatically!). Do you?

    No I don't think it is possible. This is what is written in Oracle documentation..
    http://download.oracle.com/docs/cd/B28359_01/server.111/b32024/partition.htm#CACHFHHF
    >
    The range partitioning key value determines the high value of the range partitions, which is called the transition point, and the database creates interval partitions for data beyond that transition point.
    >

  • How to search data dictionary for interval partitions?

    Oracle 11.2.0.3
    When I query DBA_PART_TABLES.PARTITIONING_TYPE it says 'range'. I want to be able to differential an interval from other range based partitions in the data dictionary?
    used this example. shows 'range'
    http://www.rittmanmead.com/2008/09/investigating-oracle-11g-interval-partitioning/
    Oracle Docs list 'SYSTEM' as a partitioning_type which I thought would be intervals.
    ALL_PART_TABLES
    [code]
      1   CREATE TABLE interval_sales
      2          ( prod_id        NUMBER(6)
      3          , cust_id        NUMBER
      4          , time_id        DATE
      5          , channel_id     CHAR(1)
      6          , promo_id       NUMBER(6)
      7          , quantity_sold  NUMBER(3)
      8          , amount_sold    NUMBER(10,2)
      9          )
    10       PARTITION BY RANGE (time_id)
    11       INTERVAL(NUMTOYMINTERVAL(1, 'MONTH'))
    12         ( PARTITION p0 VALUES LESS THAN (TO_DATE('1-1-2005', 'DD-MM-YYYY')),
    13           PARTITION p1 VALUES LESS THAN (TO_DATE('1-1-2006', 'DD-MM-YYYY')),
    14           PARTITION p2 VALUES LESS THAN (TO_DATE('1-7-2006', 'DD-MM-YYYY')),
    15*          PARTITION p3 VALUES LESS THAN (TO_DATE('1-1-2007', 'DD-MM-YYYY')) )
    SQL>/
    Table created.
    Elapsed: 00:00:00.01
    SQL> select partitioning_type from user_part_tables where table_name = 'INTERVAL_SALES';
    PARTITION
    RANGE
    [/code]

    CREATE TABLE junk1
       ( id         NUMBER )
       PARTITION BY RANGE (id)
       INTERVAL(5)
         ( PARTITION p0 VALUES LESS THAN (5),
           PARTITION p1 VALUES LESS THAN (10),
           PARTITION p2 VALUES LESS THAN (15),
           PARTITION p3 VALUES LESS THAN (20) )
    CREATE TABLE junk2
       ( id         NUMBER )
       PARTITION BY RANGE (id)
         ( PARTITION p0 VALUES LESS THAN (5),
           PARTITION p1 VALUES LESS THAN (10),
           PARTITION p2 VALUES LESS THAN (15),
           PARTITION p3 VALUES LESS THAN (20) )
    select owner, table_name, partitioning_type, interval
      from dba_part_tables
    where table_name in ('JUNK1', 'JUNK2')
    OWNER                          TABLE_NAME                     PARTITIONING_TYPE INTERVAL           
    GREGS                          JUNK1                          RANGE             5                  
    GREGS                          JUNK2                          RANGE                 
    2 rows selected.

  • Range partiotion using interval partitioning

    Hi all,
    I am trying to create a partitioned table so that a number (which date converted to number ) partition is created on inserting a new row for release_date column.
    But please note that release_date column is having number data type (as per design) and people want to create an interval based partition on this.
    Any work around for this?
    They want data type NOT to be altered.
    create table product(
    prod_id number,
    prod_code varchar2(3),
    release_date number)
    partition by range(release_date)
    interval(NUMTOYMINTERVAL (1,'MONTH'))
    (partition p0 values less than (20120101))
    Thanks in advance

    >
    I am trying to create a partitioned table so that a number (which date converted to number ) partition is created on inserting a new row for release_date column.
    But please note that release_date column is having number data type (as per design) and people want to create an interval based partition on this.
    >
    You can't use interval partitioning on the NUMBER column but you can add a VIRTUAL column based on it that uses DATE datatype.
    create table product(
    prod_id number,
    prod_code varchar2(3),
    release_date number,
    rel_date DATE as (to_date(to_char(release_date), 'yyyymmdd')) VIRTUAL
    partition by range(rel_date)
    interval(NUMTOYMINTERVAL (1,'MONTH'))
       partition p0 values less than (to_date('20120101', 'yyyymmdd'))
    )The virtual column is a metadata only column (i.e. no data is stored for it).
    NOTE: you will need to modify your queries to use the 'REL_DATE' column in order to get partition pruning:
    insert into product (prod_id, prod_code, release_date) values (1,'abc', 20110502)
    insert into product (prod_id, prod_code, release_date) values (1,'abc', 20120502)
    -- this query does NOT prune
    select * from product where release_date < 20120101
    |   0 | SELECT STATEMENT    |         |     1 |    38 |     4   (0)| 00:00:01 |       |       |
    |   1 |  PARTITION RANGE ALL|         |     1 |    38 |     4   (0)| 00:00:01 |    1 |1048575|
    |*  2 |   TABLE ACCESS FULL | PRODUCT |     1 |    38 |     4   (0)| 00:00:01 |    1 |1048575|
    -- this query DOES prune
    select * from product where rel_date < to_date('20120101', 'yyyymmdd')
    |   0 | SELECT STATEMENT       |         |     1 |    38 |     3   (0)| 00:00:01 |       |       |
    |   1 |  PARTITION RANGE SINGLE|         |     1 |    38 |     3   (0)| 00:00:01 |     1 |     1 |
    |*  2 |   TABLE ACCESS FULL    | PRODUCT |     1 |    38 |     3   (0)| 00:00:01 |     1 |     1 |

  • Trying to convert Interval Partitioned Table to Range..Exchange Partition..

    Requirement:
    Replace Interval partitioned Table by Range Partitioned Table
    DROP TABLE A;
    CREATE TABLE A
       a              NUMBER,
       CreationDate   DATE
    PARTITION BY RANGE (CreationDate)
       INTERVAL ( NUMTODSINTERVAL (30, 'DAY') )
       (PARTITION P_FIRST
           VALUES LESS THAN (TIMESTAMP ' 2001-01-01 00:00:00'));
    INSERT INTO A
         VALUES (1, SYSDATE);
    INSERT INTO A
         VALUES (1, SYSDATE - 30);
    INSERT INTO A
         VALUES (1, SYSDATE - 60);I need to change this Interval Partitioned Table to a Range Partitioned Table. Can I do it using EXCHANGE PARTITION. As if I use the conventional way of creating another Range Partitioned table and then :
    DROP TABLE A_Range
    CREATE TABLE A_Range
    a NUMBER,
    CreationDate DATE
    PARTITION BY RANGE (CreationDate)
       (partition MAX values less than (MAXVALUE));
    Insert  /*+ append */  into A_Range Select * from A; --This Step takes very very long..Trying to cut it short using Exchange Partition.Problems:
    I can't do
    ALTER TABLE A_Range
      EXCHANGE PARTITION MAX
      WITH TABLE A
      WITHOUT VALIDATION;
    ORA-14095: ALTER TABLE EXCHANGE requires a non-partitioned, non-clustered table
    This is because both the tables are partitioned. So it does not allow me.
    If I do instead :
    create a non partitioned table for exchanging the data through partition.
      Create Table A_Temp as Select * from A;
       ALTER TABLE A_Range
      EXCHANGE PARTITION MAX
      WITH TABLE A_TEMP
      WITHOUT VALIDATION;
      select count(*) from A_Range partition(MAX);
    -Problem is that all the data goes into MAX Partition.
    Even after creating a lot of partitions by Splitting Partitions, still the data is in MAX Partition only.
    So:
    -- Is it that we can't Replace an Interval Partitioned Table by Range Partitioned Table using EXCHANGE PARTITION. i.e. We will have to do Insert into..
    -- We can do it but I am missing something over here.
    -- If all the data is in MAX Partition because of "WITHOUT VALIDATION" , can we make it be redistributed in the right kind of range partitions.

    You will need to pre-create the partitions in a_range, then exchange them one by one from a to a tmp then then to arange. Using your sample (thanks for proviing the code by the way).
    SQL> CREATE TABLE A
      2  (
      3     a              NUMBER,
      4     CreationDate   DATE
      5  )
      6  PARTITION BY RANGE (CreationDate)
      7     INTERVAL ( NUMTODSINTERVAL (30, 'DAY') )
      8     (PARTITION P_FIRST
      9         VALUES LESS THAN (TIMESTAMP ' 2001-01-01 00:00:00'));
    Table created.
    SQL> INSERT INTO A VALUES (1, SYSDATE);
    1 row created.
    SQL> INSERT INTO A VALUES (1, SYSDATE - 30);
    1 row created.
    SQL> INSERT INTO A VALUES (1, SYSDATE - 60);
    1 row created.
    SQL> commit;
    Commit complete.You can find the existing partitions form a using:
    SQL> select table_name, partition_name, high_value
      2  from user_tab_partitions
      3  where table_name = 'A';
    TABLE_NAME PARTITION_NAME HIGH_VALUE
    A          P_FIRST        TO_DATE(' 2001-01-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA
    A          SYS_P44        TO_DATE(' 2013-01-28 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA
    A          SYS_P45        TO_DATE(' 2012-12-29 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA
    A          SYS_P46        TO_DATE(' 2012-11-29 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIAYou can then create table a_range with the apporopriate partitions. Note that you may need to create additional partitions in a_range because interval partitioning does not create partitions that it has no data for, even if that leaves "holes" in the partitioning scheme. So, based on the above:
    SQL> CREATE TABLE A_Range (
      2     a NUMBER,
      3     CreationDate DATE)
      4  PARTITION BY RANGE (CreationDate)
      5     (partition Nov_2012 values less than (to_date('30-nov-2012', 'dd-mon-yyyy')),
      6      partition Dec_2012 values less than (to_date('31-dec-2012', 'dd-mon-yyyy')),
      7      partition Jan_2013 values less than (to_date('31-jan-2013', 'dd-mon-yyyy')),
      8      partition MAX values less than (MAXVALUE));
    Table created.Now, create a plain table to use in the exchanges:
    SQL> CREATE TABLE A_tmp (
      2     a              NUMBER,
      3     CreationDate   DATE);
    Table created.and exchange all of the partitions:
    SQL> ALTER TABLE A
      2    EXCHANGE PARTITION sys_p44
      3    WITH TABLE A_tmp;
    Table altered.
    SQL> ALTER TABLE A_Range
      2    EXCHANGE PARTITION jan_2013
      3    WITH TABLE A_tmp;
    Table altered.
    SQL> ALTER TABLE A
      2    EXCHANGE PARTITION sys_p45
      3    WITH TABLE A_tmp;
    Table altered.
    SQL> ALTER TABLE A_Range
      2    EXCHANGE PARTITION dec_2012
      3    WITH TABLE A_tmp;
    Table altered.
    SQL> ALTER TABLE A
      2    EXCHANGE PARTITION sys_p46
      3    WITH TABLE A_tmp;
    Table altered.
    SQL> ALTER TABLE A_Range
      2    EXCHANGE PARTITION nov_2012
      3    WITH TABLE A_tmp;
    Table altered.
    SQL> select * from a;
    no rows selected
    SQL> select * from a_range;
             A CREATIOND
             1 23-NOV-12
             1 23-DEC-12
             1 22-JAN-13John

  • SD number range based on company codes

    Dear all,
    We have two company codes in one client.We want to create  separate SD number ranges based on company codes.Is there any possibilities to do this.Please advice.
    Regards,
    Abdul jabbar

    Abdul,
    If you have  different doc types for two company codes then you can maintain different number ranges in standard for two company codes.
    If you have same doc types for two company codes then you have to go for enhancement.
    1. Create one ztable: Maintain the entries like below.
    company code
    SD document categ.
    Document type
    Sequence Number
    Prefix code
    Object name
    Number range number
    2XX1
    C
    ZXXX
    1
    A01
    Z_XXX_X1
    01
    2XX1
    C
    ZXXX
    1
    A01
    Z_XXX_X1
    01
    2XX1
    C
    ZXXX
    1
    A01
    Z_XXX_X1
    01
    2XX1
    C
    ZXXX
    1
    A01
    Z_XXX_X1
    01
    2XX1
    H
    ZXXX
    1
    A01
    Z_XXX_X1
    01
    2XX1
    H
    ZXXX
    1
    A01
    Z_XXX_X1
    01
    2XX1
    H
    ZXXX
    1
    A01
    Z_XXX_X1
    01
    2XX1
    H
    ZXXX
    1
    A01
    Z_XXX_X1
    01
    2XX1
    H
    ZXXX
    1
    A01
    Z_XXX_X1
    01
    2XX1
    J
    ZXXX
    1
    A02
    Z_XXX_X1
    02
    2XX1
    J
    ZXXX
    1
    A02
    Z_XXX_X1
    02
    2XX1
    J
    ZXXX
    1
    A02
    Z_XXX_X1
    02
    2XX1
    J
    ZXXX
    1
    A02
    Z_XXX_X1
    02
    2XX1
    J
    ZXXX
    1
    A02
    Z_XXX_X1
    02
    2XX1
    K
    ZXXX
    1
    A01
    Z_XXX_X1
    01
    2XX1
    K
    ZXXX
    1
    A01
    Z_XXX_X1
    01
    2XX1
    L
    ZXXX
    1
    A01
    Z_XXX_X1
    01
    2XX1
    M
    ZXXX
    1
    A05
    Z_XXX_X1
    05
    2XX1
    M
    ZXXX
    1
    A05
    Z_XXX_X1
    05
    2XX1
    M
    ZXXX
    1
    A05
    Z_XXX_X1
    05
    2XX1
    N
    ZXXX
    1
    A05
    Z_XXX_X1
    05
    2XX1
    N
    ZXXX
    1
    A04
    Z_XXX_X1
    04
    2XX1
    O
    ZXXX
    1
    A03
    Z_XXX_X1
    03
    2XX1
    O
    ZXXX
    1
    A03
    Z_XXX_X1
    03
    2XX1
    O
    ZXXX
    1
    A03
    Z_XXX_X1
    03
    2XX1
    O
    ZXXX
    1
    A03
    Z_XXX_X1
    03
    2XX1
    O
    ZXXX
    1
    A03
    Z_XXX_X1
    03
    2XX1
    P
    ZXXX
    1
    A04
    Z_XXX_X1
    04
    2XX1
    S
    ZXXX
    1
    A03
    Z_XXX_X1
    03
    2XX1
    S
    ZXXX
    1
    A03
    Z_XXX_X1
    03
    2XX1
    S
    ZXXX
    1
    A03
    Z_XXX_X1
    03
    2XX1
    T
    ZXXX
    1
    A02
    Z_XXX_X1
    02
    2XX1
    T
    ZXXX
    1
    A02
    Z_XXX_X1
    02
    2XX2
    C
    ZXXX
    1
    A06
    Z_XXX_X1
    06
    2XX2
    C
    ZXXX
    1
    A06
    Z_XXX_X1
    06
    2XX2
    C
    ZXXX
    1
    A06
    Z_XXX_X1
    06
    2XX2
    C
    ZXXX
    1
    A06
    Z_XXX_X1
    06
    2XX2
    H
    ZXXX
    1
    A06
    Z_XXX_X1
    06
    2XX2
    H
    ZXXX
    1
    A06
    Z_XXX_X1
    06
    2XX2
    H
    ZXXX
    1
    A06
    Z_XXX_X1
    06
    2XX2
    H
    ZXXX
    1
    A06
    Z_XXX_X1
    06
    2XX2
    H
    ZXXX
    1
    A06
    Z_XXX_X1
    06
    2XX2
    J
    ZXXX
    1
    A07
    Z_XXX_X1
    07
    2XX2
    J
    ZXXX
    1
    A07
    Z_XXX_X1
    07
    2XX2
    J
    ZXXX
    1
    A07
    Z_XXX_X1
    07
    2XX2
    J
    ZXXX
    1
    A07
    Z_XXX_X1
    07
    2XX2
    J
    ZXXX
    1
    A07
    Z_XXX_X1
    07
    2XX2
    K
    ZXXX
    1
    A06
    Z_XXX_X1
    06
    2XX2
    K
    ZXXX
    1
    A06
    Z_XXX_X1
    06
    2XX2
    L
    ZXXX
    1
    A06
    Z_XXX_X1
    06
    2XX2
    M
    ZXXX
    1
    A10
    Z_XXX_X1
    10
    2XX2
    M
    ZXXX
    1
    A10
    Z_XXX_X1
    10
    2XX2
    M
    ZXXX
    1
    A10
    Z_XXX_X1
    10
    2XX2
    N
    ZXXX
    1
    A10
    Z_XXX_X1
    10
    2XX2
    N
    ZXXX
    1
    A09
    Z_XXX_X1
    09
    2XX2
    O
    ZXXX
    1
    A08
    Z_XXX_X1
    08
    2XX2
    O
    ZXXX
    1
    A08
    Z_XXX_X1
    08
    2XX2
    O
    ZXXX
    1
    A08
    Z_XXX_X1
    08
    2XX2
    O
    ZXXX
    1
    A08
    Z_XXX_X1
    08
    2XX2
    O
    ZXXX
    1
    A08
    Z_XXX_X1
    08
    2XX2
    P
    ZXXX
    1
    A09
    Z_XXX_X1
    09
    2XX2
    S
    ZXXX
    1
    A08
    Z_XXX_X1
    08
    2XX2
    S
    ZXXX
    1
    A08
    Z_XXX_X1
    08
    2XX2
    S
    ZXXX
    1
    A08
    Z_XXX_X1
    08
    2XX2
    T
    ZXXX
    1
    A07
    Z_XXX_X1
    07
    2XX2
    T
    ZXXX
    1
    A07
    Z_XXX_X1
    07
    2. In SNRO Maitain the number Ranges interval
    First system take the number range interval and searches for the entry in ztable and prefix the code as per the ztable enteries.
    By this u can differentiate the number ranges by company code.
    Revert back to the forum if need any clarification.
    Thank$
    Hidayath

  • Range interval partitioning with null value

    Hello,
    I have question, how can I create table with partition and after that I will insert null value in the partition key like this kind of
    range interval partitioning with null value.
    I have Oracle 11g.
    Thanks
    Mohammed

    user13777053 wrote:
    Thank you, but my question is about range interval not for range?http://docs.oracle.com/cd/E11882_01/server.112/e25523/partition.htm#VLDBG00220
    A MAXVALUE literal can be defined for the highest partition. MAXVALUE represents a virtual infinite value that sorts higher than any other possible value for the partitioning key, *including the NULL value.*
    So since you're trying to partition by interval (which doesn't support a MAXVALUE clause) you're out of luck.
    There's probably fancy hacks and what not you could try to implement, but i'm not about to recommend any of those here :)
    Cheers,

  • Interval Partition naming Issue (Oracle 11g R2 )

    I need help on identifying latest partition:
    I am using Interval Partition for my table,which creates partition every month end based on inserted data.
    When oracle creates partition assigning its own name but users have automated reports using partition names like Table_name_YYYYMM.
    I tested following ways to identify partition then renamed,worked fine but in long run do i get any problems ?
    or any other way to identify the latest partition ?
    1)Using max partition position :
    select partition_name from dba_tab_partitions a where partition_position = (select max(partition_position)
    from user_tab_partitions b where a.table_name=b.table_name
    and b.table_name = 'INTRVL_PARTITION');
    2)Using Sub Object max creation date :
    SELECT SUBOBJECT_NAME FROM dba_objects
    WHERE OBJECT_TYPE='TABLE PARTITION'
    AND OWNER='ABCD'
    AND OBJECT_NAME='INTRVL_PARTITION'
    AND CREATED=(SELECt MAX(CREATED) FROM DBA_OBJECTS
    WHERE OBJECT_TYPE='TABLE PARTITION'
    AND OWNER='ABCD'
    AND OBJECT_NAME='INTRVL_PARTITION');
    Thanks in advance .
    Edited by: user607128 on Mar 2, 2012 7:09 AM

    Your initial question said you were already using interval partitioning.
    >
    I am using Interval Partition for my table
    now users asking to convert Range to Interval Partition and keeping existing partitions same name.
    >
    So is your issue that you want to use interval partitining for a table now is now using range partitioning? Why are your users driving this change? That should be a decision made by the DBA and technical management since the difference is mainly on of management.
    Though there is one BIG difference that is data related. With interval partitioning if data (even erroneous data) is inserted for a partition that does not exist Oracle will create one. So if you have an insert statement that inserts 12 records for the year '2038' you will get 12 new partitions even though the data may be bogus.
    Now your management problem is detecting the problem, deleting the data (or fixing the date to move it to the right partition) and then dropping the partitions and storage.
    With 'interval' partitioning you had better be absolutely sure your data is clean in terms of the partitioning key values.
    That said, you can use table redefinition or just create a new interval partitioned table and do partition exchanges with the existing partitions to move the data.

  • Existing Range partition to Interval Partition

    I have an Range and list partition tables on Oracle 11g with some records and have to move the
    range and List partition tables to interval partitions. I tried for the range partition
    table with following query,
    SQL> alter table F_PTP_PAYMENTS set interval (numtoyminterval(3,'MONTH'));
    alter table F_PTP_PAYMENTS set interval (numtoyminterval(3,'MONTH'))
    ERROR at line 1:
    ORA-14759: SET INTERVAL is not legal on this table.
    it doesnt worked out.
    Can you please help me to create the interval partitions.

    ORA-14759: SET INTERVAL is not legal on this table.
    Cause: ALTER TABLE SET INTERVAL is only legal on a range partitioned table with a single partitioning column. Additionally this table cannot have a maxvalue partition.
    Action: Use SET INTERVAL only on a valid table
    mark answered post as helpful / correct*

  • Range interval partitioning

    Hi,
    Using Oracle 11.20.3
    We wish to have a range-hash composite partitioned table, one partition for each month.
    However, want to esnure are always a partition tehrfore would like to use range interval partitioning.
    Have a few questions, if have partition say 201301 to 201312 but get somew rosw which have value in date in June 2014 would it create
    a new partition for each month i.e 201401, 201402 etc or just one for 201406?
    Wanyt esnure system can cope automatically with following scenario
    Daty1 have partitions 201301 to 201312
    Day2 get record for 201406 (June 2014)
    Day 3 get record for 201403 (March 2014)
    We have no control of the range of dates we could get but don't want tpo have to manually create partitions fro all tehse dates in advance - want system to handled it automatically.
    Also can you simply rename the system generated partition names to something more meaningful later.

    >
    Using Oracle 11.20.3
    We wish to have a range-hash composite partitioned table, one partition for each month.
    However, want to esnure are always a partition tehrfore would like to use range interval partitioning.
    Have a few questions, if have partition say 201301 to 201312 but get somew rosw which have value in date in June 2014 would it create
    a new partition for each month i.e 201401, 201402 etc or just one for 201406?
    Wanyt esnure system can cope automatically with following scenario
    Daty1 have partitions 201301 to 201312
    Day2 get record for 201406 (June 2014)
    Day 3 get record for 201403 (March 2014)
    We have no control of the range of dates we could get but don't want tpo have to manually create partitions fro all tehse dates in advance - want system to handled it automatically.
    >
    Do NOT be afraid of breaking Oracle by actually trying things yourself.
    DROP TABLE emp_part
    CREATE TABLE emp_part (empno number(4), ename varchar2(10),
    deptno number(2), created_date DATE default sysdate)
      partition by range (created_date)
         SUBPARTITION BY HASH(deptno) subpartitions 4
    ( partition p_prior_to_2014 values less than (to_date('01-01-2014', 'mm-dd-yyyy')));Add some data for 2014 and see for yourself what happens.
    >
    Also can you simply rename the system generated partition names to something more meaningful later.
    >
    Yes - assuming you mean more meaninful to a human. Oracle doesn't care what the name is.
    And you can just as easily manipulate the partition (delete, insert, drop truncate) regardless of the name since you don't need to use the name to do those things.
    You either know the date for the partition you want to work with or you don't. If you know then just tell Oracle and it will work with the correct partition. If you don't believe me try it with the sample code I gave you. Add some data to get a couple of interval partitions created and then drop one of them using Oracle's extended partition syntax. See this example in the 'Dropping Interval Partitions in the VLDB and Partitioning Guide
    http://docs.oracle.com/cd/B28359_01/server.111/b32024/part_admin.htm#i1007479
    >
    The following example drops the September 2007 interval partition from the sales table. There are only local indexes so no indexes will be invalidated.
    ALTER TABLE sales DROP PARTITION FOR(TO_DATE('01-SEP-2007','dd-MON-yyyy'));
    >
    That code doesn't require the partition name. You just need to specify a date that falls IN the partition that you want to drop. You have to do that whether you know the name of the partition or not. Don't 'gunk up' your system with code to rename things unless there is some real need to.

  • Range - Interval Partition and List Subpartition.

    Hi
    I am trying to create the Range(Interval) Partition with List Sub partition (dynamically). Here the LOCATION_CD List is Dynamic. Basically Location_CD is Country name. e.g USA, IND,GER.....
    Below Works good...
    CREATE TABLE TEMP
    SEQUENCE_ID NUMBER,
    RESERVATION_DATE TIMESTAMP,
    LOCATION_CD VARCHAR2(5)
    PARTITION BY RANGE (RESERVATION_DATE)
    INTERVAL (NUMTOYMINTERVAL(1,'MONTH'))
    SUBPARTITION BY LIST(LOCATION_CD)
    SUBPARTITION TEMPLATE
    ( SUBPARTITION CD_01 VALUES ('USA'),
    SUBPARTITION CD_02 VALUES ('IND'),
    SUBPARTITION CD_03 VALUES ('GER')
    PARTITION TEMP values LESS THAN (TO_DATE('01-JAN-2000','DD-MON-YYYY'))
    Today there are 3 Countries but going forward it can be more or less.
    I like the Interval Range Partition concept, where the new partition is automatically gets added.
    But at the same time can the new list sub partition be added ? If this doesn't work...can we have another alternative approach or partition technique ?
    Please suggest.
    Thanks
    Jitesh R.

    Why didn't you just perform two inserts and answer the question yourself?
    orabase> CREATE TABLE T (
      2  SEQUENCE_ID      NUMBER,
      3  RESERVATION_DATE TIMESTAMP,
      4  LOCATION_CD      VARCHAR2(5))
      5  PARTITION BY RANGE (RESERVATION_DATE)
      6  INTERVAL (NUMTOYMINTERVAL(1,'MONTH'))
      7  SUBPARTITION BY LIST(LOCATION_CD)
      8  SUBPARTITION TEMPLATE (
      9  SUBPARTITION CD_01 VALUES ('USA'),
    10  SUBPARTITION CD_02 VALUES ('IND'),
    11  SUBPARTITION CD_03 VALUES ('GER')) (
    12  PARTITION root values LESS THAN (TO_DATE('01-JAN-2000','DD-MON-YYYY')));
    Table created.
    orabase> insert into t values (1, TO_DATE('02-JAN-2000'), 'USA');
    1 row created.
    orabase> select partition_name, subpartition_name
      2  from user_tab_subpartitions
      3  where table_name = 'T';
    PARTITION_NAME                 SUBPARTITION_NAME
    ROOT                           ROOT_CD_03
    ROOT                           ROOT_CD_02
    ROOT                           ROOT_CD_01
    SYS_P84                        SYS_SUBP83
    SYS_P84                        SYS_SUBP82
    SYS_P84                        SYS_SUBP81
    6 rows selected.
    orabase>  insert into t values (1, TO_DATE('02-JAN-2000')+400, 'USA');
    1 row created.
    orabase> select partition_name, subpartition_name
      2  from user_tab_subpartitions
      3  where table_name = 'T';
    PARTITION_NAME                 SUBPARTITION_NAME
    SYS_P88                        SYS_SUBP85
    SYS_P88                        SYS_SUBP86
    SYS_P88                        SYS_SUBP87
    SYS_P84                        SYS_SUBP81
    SYS_P84                        SYS_SUBP82
    SYS_P84                        SYS_SUBP83
    ROOT                           ROOT_CD_01
    ROOT                           ROOT_CD_02
    ROOT                           ROOT_CD_03
    9 rows selected.

  • 11g new feature "Partition pruning based on bloom filtering" is what?

    While idly reading the Oracle 11g Database New Features I stumbled upon the following - BEGIN QUOTE:
    1.11.1.2 Enhanced Partition Pruning Capabilities
    Partition pruning now uses bloom filtering instead of subquery pruning. While subquery pruning was activated on a cost-based decision and consumed internal (recursive) resources, pruning based on bloom filtering is activated all the time without consuming additional resources.
    END QUOTE
    I haven't found any other references to bloom filtering in the manuals, and very few via google and MetaLink. So I am left wondering what the above paragraph actually means?
    Best regards,
    Hans Henrik Krohn

    Hi Hans
    The problem of subquery pruning is that part of the SQL statement is executed twice. Therefore, a cost-based decision is necessary to decide if it makes to do it or not...
    To avoid this double execution they introduced join-filter pruning (which takes advantage of a bloom filter). Since this new method has a very small overhead, it makes always sense to use it if pruning can be used. With it you will see execution plans like the following one.
    | Operation                           | Name    | Pstart| Pstop |
    | HASH JOIN                           |         |       |       |
    |  PART JOIN FILTER CREATE            | :BF0000 |       |       |
    |   TABLE ACCESS BY GLOBAL INDEX ROWID| T       | ROWID | ROWID |
    |    INDEX UNIQUE SCAN                | T_PK    |       |       |
    |  PARTITION RANGE JOIN-FILTER        |         |:BF0000|:BF0000|
    |   TABLE ACCESS FULL                 | T       |:BF0000|:BF0000|
    -----------------------------------------------------------------HTH
    Chris

  • Alter range partition table to Interval partitioning table.

    Hi DBA's,
    I have a very big range partitioned table.
    Recently we have upgraded our database to 11gR2 which has a feautre called interval partitioning.
    Now i want to modify that existing range partitioned table to Interval Partitioning.
    can we alter the range partitioned table to interval partitioning table?
    I googled for the syntax but i didn't find it, can any one help[ me out on this?
    Thanks.

    If you ignore the "alter session set NLS_CALENDAR=PERSIAN;" during create/alter, everything else seems to work.
    When you set the "alter session..." during inserts, the rows gets inserted into the correct partitions.
    Only thing is when you look at HIGH_VALUE, you need to convert from the default GREGORIAN to PERSIAN.

  • Range interval partitioning - ability to set tablespace?

    Hi,
    We have a range partitioned table, considering making it a range-interval partitioned one.
    I know can query/identify partitions by using syntax to the range to which the partition relates.
    If set to range interval, wht tablespace are new ones created in, is it the default tablespace of the database or can you ensure they are automatcially created in specific tablespace.
    Is there any way of setting name to be something more meaninful automatically rather than having to write sql to query data dictionary to do this?
    Many Thanks

    There are no undocumented features in Oracle.
    What did the documentation tell, apart from it isn't possible?
    Sybrand Bakker
    Senior Oracle DBA

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