3 Tier Relational DB's and Dynamic Tables

Question

I have three tables which I shall, for ease, call A, B and C.
B is relational to A
C is relational to B
A1 - B1 - C1
C2
B2 - C3
C4
A2
A3 - B3 - C5
B4
B5 - C6
C7
C8
I have no trouble creating recordset links for one or the
other
SELECT A.*, B.*
FROM A INNER JOIN B ON A.AID = B.BAID
WHERE etc... etc......
Similarly, I can create a recordset for the secondary link..
SELECT B.*, C.*
FROM B INNER JOIN C ON B.BID = C.CBID
WHERE etc... etc......
What I am trying to acheive however is a recordset with a 3
tier relationship and I can't figure the syntax.
Somthing like...
SELECT A.*, B.*, C.*
FROM A INNER JOIN B ON A.AID = B.BAID, B INNER JOIN C ON
B.AID = C.BAID
WHERE etc... etc...... (This doesn't work!)
This would then result in a dynamic table with (B and C) in
the same row as it propogates.
Eventually, what I want to achieve is a simple attachment
symbol on each row of B, based on something like....
<?php if (C,TotalRecords <> NULL) { ?>
<a href="/linkedattachments.php?BID=<?php echo
$row_recordsetB['BID']; ?>" target="_blank">
<img src="fileicon.gif" alt="Click to see
attachments"></a>
<?php } ?>
Am I going about this the right way? Is this even clear?
lol

Answer 1

"RichardODreamweaver" <[email protected]>
wrote in message
news:[email protected]...
> I have three tables which I shall, for ease, call A, B
and C.
>
> B is relational to A
>
> C is relational to B
>
> A1 - B1 - C1
> C2
> B2 - C3
> C4
> A2
> A3 - B3 - C5
> B4
> B5 - C6
> C7
> C8
>
>
> I have no trouble creating recordset links for one or
the other
>
> SELECT A.*, B.*
> FROM A INNER JOIN B ON A.AID = B.BAID
> WHERE etc... etc......
>
> Similarly, I can create a recordset for the secondary
link..
>
> SELECT B.*, C.*
> FROM B INNER JOIN C ON B.BID = C.CBID
> WHERE etc... etc......
>
> What I am trying to acheive however is a recordset with
a 3 tier
> relationship
> and I can't figure the syntax.
>
> Somthing like...
>
> SELECT A.*, B.*, C.*
> FROM A INNER JOIN B ON A.AID = B.BAID, B INNER JOIN C ON
B.AID = C.BAID
> WHERE etc... etc...... (This doesn't work!)
that's almost right
SELECT A.*, B.*, C.*
FROM ((A INNER JOIN B ON A.AID = B.BAID) INNER JOIN C ON
B.AID = C.BAID)
WHERE etc... etc......
I've added parentheses to show how the next join will operate
on the first,
the first join results in a relation of table a and b,
you then join this "virtual table" to the third.
> This would then result in a dynamic table with (B and C)
in the same row
> as it
> propogates.
>
> Eventually, what I want to achieve is a simple
attachment symbol on each
> row
> of B, based on something like....
For the count to work with records that have no children you
have to employ
a LEFT join to return records from the RIGHT table even if no
record on the
LEFT side matches.
SELECT A.*, B.*, COUNT(c.CAID) AS CAID_COUNT
FROM ((A INNER JOIN B ON A.AID = B.BAID) LEFT JOIN C ON B.AID
= C.BAID)
WHERE etc... etc......
> <?php if (C,TotalRecords <> NULL) { ?>
> <a href="/linkedattachments.php?BID=<?php echo
$row_recordsetB['BID']; ?>"
> target="_blank">
> <img src="fileicon.gif" alt="Click to see
attachments"></a>
> <?php } ?>
>
> Am I going about this the right way? Is this even clear?
lol
>