3D plot - select coordinates
Hello,
I would like to know if there is a way to know the coordinates on a 3D surface plot in LabVIEW. Actually I know one way but I would like to know if there is another. The way I know is: right click on the 3D plot and then click on ´Properties of 3D plot´. Then click on ´Cursor´ and finally set the X, Y and Z positions to the desired point on the plot. I have attached a few images showing this. I have also in the Blockdiagramm a PropertyNode that shows the selected coordinates.
OK. Now, my question is...Is there a way to select a point just clicking on the graphic?? (without right clicking and selecting ´Properties´ and so on).
Thank you very much in advance,
Claudia
Attachments:
3Dplot.jpg 132 KB
Properties.jpg 254 KB
Property-Node.jpg 23 KB
Hello ClaudiaRamos,
I did some research and wrote a small VI to test these cursor things.
Unfortunately, I just could do it like you. I am afraid, it is not possible to click in the 3D diagram and have the x, y and z value output.
(Come to think about it: how should the computer know where you click? The mouse is not a 3D input device and there can be more than one point in the 3D room you could "mean" with your click - which one should the computer take?)
Also, I have a question: should the point you select be on the surface of you graph, or anywhere in the diagram?
I think the way we are trying just selects any point, regardless if it is on the surface of the plot, or not.
I am sorry I cannot give you a solution at this point now.
Best regards!
Christopher W.
Intern Application Engineering | NI Certified LabVIEW Associate Developer (CLAD) | NI Germany
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These 10 points are constantly moving (data from a Leap Motion hand tracker)
I have attached a screen shot of simple VI and example data
How would i go about gaphing this?Hi coqwas,
That's a pretty interesting project you have there.
I guess there is 2 types of 3D graph which you can find (use quick drop if you have to): 3D Line Graph and Active X 3D Curve Graph. You can find some examples on 3D graphs in NI Example Finder as well (Open LabVIEW >> Help >> Find Examples... >> Search key word "3D graph").
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Hi
I am trying to do a fairly simple state space task with Control Design and Simulation toolbox, however I am quite new at using this toolbox and need some help :-)
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Message Edited by SCMAJA on 10-16-2009 11:21 AM
LabVIEW 8.6 / 2009 / 2010
Vision Development Module 8.6 / 2009 / 2010
VBAI 3.6 / 2010
Attachments:
2 DOF robot with ramp input, polar coordinates plot, state space.vi 49 KBHello Simon,
The error comes from your Ramp Input. Since your system is MIMO, you would need to feed in a vector input to the system.
I've changed your VI and attached here~!
Andy Chang
National Instruments
LabVIEW Control Design and Simulation
Attachments:
MIMO Robot VI.vi 76 KB -
Good day to all,
First of all, I am so new in programming.
I just learn about a week (Java Language).
I already have a code that shows the coordinates of selected area.
But the output in the text file is x,y,x,y,x,y...
I want the output to be x,x,x... and y,y,y... in new line.
Example:
In the code, the output is:
578,337,529,488,512,526,478,512,486,464,484,464,480,475,477,475,479,458,477,458,472,462,47 2,458,476,442,484,420,519,363,528,355,554,334
What I want is:
578,529,512,489,478,486,484,480,477,479,477,472,472,476,484,519,528,554
337,488,526,517,512,464,464,475,475,458,458,462,458,442,420,363,355,334
I mean the x coordinates are on first line and y are on the second line.
Here is my code:
#target Photoshop
var data=mapa_seleccion(activeDocument,data)
function mapa_seleccion(doc,out){
var hs = doc.historyStates;
preferences.rulerUnits = Units.PIXELS;
doc.selection.makeWorkPath(1);
var p = doc.pathItems["Work Path"];
var a = new Array();
var t = 0;
var l = p.subPathItems.length;
for ( k = 0; k < l; k++) {
var n = p.subPathItems[k].pathPoints.length;
a[k] = new Array (n);
for ( i = 0; i < n; i++){
a[k][i] = new Array();
a[k][i]=p.subPathItems[k].pathPoints[i].anchor;
var t = 0;
for ( k = 0; k < l; k++) {
var n = a[k].length;
var s = 0;
for ( i = 0; i < n; i++){
var j = (i+1)%n;
s+=(a[k][i][0]*a[k][j][1]);
s-=(a[k][i][1]*a[k][j][0]);
s/=2;
t+=s;
doc.activeHistoryState = hs[hs.length-2];
out=new Array()
out.mapa=a
out.area=parseFloat(t/doc.resolution/doc.resolution*2.54*2.54).toFixed(2) //conv ierte a cm2
return out
alert(data.mapa[0]);
//data.mapa[0];
if ($.os.search(/windows/i) != -1)
fileLineFeed = "windows";
else
fileLineFeed = "macintosh";
var fileName = app.activeDocument.name
var fileOut = new File('~/Desktop/coords.txt');
fileOut.linefeed = fileLineFeed;
fileOut.open("w", "TEXT", "");
fileOut.writeln(data.mapa[0]);
fileOut.close();
Thanks to muyshangai for the codes.
And thank you guys in advancevar data=mapa_seleccion(activeDocument,data);
function mapa_seleccion(doc,out){
var hs = doc.historyStates;
preferences.rulerUnits = Units.PIXELS;
doc.selection.makeWorkPath(1);
var p = doc.pathItems["Work Path"];
var a = new Array();
var t = 0;
var l = p.subPathItems.length;
for ( k = 0; k < l; k++) {
var n = p.subPathItems[k].pathPoints.length;
a[k] = new Array (n);
for ( i = 0; i < n; i++){
a[k][i] = new Array();
a[k][i]=p.subPathItems[k].pathPoints[i].anchor;
var t = 0;
for ( k = 0; k < l; k++) {
var n = a[k].length;
var s = 0;
for ( i = 0; i < n; i++){
var j = (i+1)%n;
s+=(a[k][i][0]*a[k][j][1]);
s-=(a[k][i][1]*a[k][j][0]);
s/=2;
t+=s;
doc.activeHistoryState = hs[hs.length-2];
out=new Array()
out.mapa=a
out.area=parseFloat(t/doc.resolution/doc.resolution*2.54*2.54).toFixed(2) //conv ierte a cm2
return out
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alert(data.mapa.toSource());
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var xArray = [];
var yArray = [];
for(var i=0;i<data.mapa[0].length;i++){
xArray.push(data.mapa[0][i][0]);
yArray.push(data.mapa[0][i][1]);
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fileLineFeed = "windows";
}else{
fileLineFeed = "macintosh";
var fileName = app.activeDocument.name
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fileOut.linefeed = fileLineFeed;
fileOut.open("w", "TEXT", "");
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fileOut.writeln(xArray);
fileOut.writeln(yArray);
fileOut.close(); -
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for (int t = 1; t <= p.SubPathItems[u].PathPoints.Count; t++)
PathPoint w = p.SubPathItems[u].PathPoints[t];
object[] my = ((object[])w.Anchor);
int myx = Convert.ToInt32(my[0]);
int myy = Convert.ToInt32(my[1]);
but it's not working as I have no experience with PS scripts. I've saved it as .jsx and tried to load it but it throws errors like it can't set a variable of the "PathItem" type and such. The script is obviously not completed, after it executes i need a way to obtain the outputted coordinates (text file, area, output window..)
Can anyone help me out ?
Thanks beforehand#target Photoshop
var data=mapa_seleccion(activeDocument,data)
function mapa_seleccion(doc,out){
var hs = doc.historyStates;
preferences.rulerUnits = Units.PIXELS;
doc.selection.makeWorkPath(1);
var p = doc.pathItems["Work Path"];
var a = new Array();
var t = 0;
var l = p.subPathItems.length;
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var n = p.subPathItems[k].pathPoints.length;
a[k] = new Array (n);
for ( i = 0; i < n; i++){
a[k][i] = new Array();
a[k][i]=p.subPathItems[k].pathPoints[i].anchor;
var t = 0;
for ( k = 0; k < l; k++) {
var n = a[k].length;
var s = 0;
for ( i = 0; i < n; i++){
var j = (i+1)%n;
s+=(a[k][i][0]*a[k][j][1]);
s-=(a[k][i][1]*a[k][j][0]);
s/=2;
t+=s;
doc.activeHistoryState = hs[hs.length-2];
out=new Array()
out.mapa=a
out.area=parseFloat(t/doc.resolution/doc.resolution*2.54*2.54).toFixed(2)//convierte a cm2
return out
//You can get the area of the selection with:
alert(data.area)
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data.mapa[0] // for the first subpathitem
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As my x axis is having labels as 06:00:00-07:00:00,07:00:00-08:00:00,..........
Below is image of my application
f Chart1.Series(0).Name = "Daily Data" Then
'Chart1.Series(0).XValueType = ChartValueType.Time
Chart1.Series(0).Points(result.PointIndex).XValue.ToString()
'xval = xval.AddHours(Chart1.Series(0).Points(result.PointIndex).XValue)
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Else
If result.ChartElementType <> ChartElementType.Nothing Then
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Chart examples.
I think you need to tell the chart to use datetime for the labels but I am not sure how and I am not too good with them but that is why I do this to learn things. I would just look in the chart examples from the link I show. That is how I answer most of
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Also, most times when you make a simple example you will find the problem or at least understand it better.
So take a look and come back if you cant get it I then I will try too. -
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Please see my code and helpme out pls
//Making Circle here
gridx=20;
gridy=20;
num=0;
for (var i=0;i < 10;i++)
for (var j=0;j < 10;j++)
dot.duplicateMovieClip("dot"+num,num);
mc=this["dot"+num];
mc._x=gridx*i;
mc._y=gridy*j;
num++;
dot._visible=0;
// here i make plain circle, but problam is my all circle
open in fornt side, i want to that all my circle in background
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this.createEmptyMovieClip("test_mc"+i,
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this["test"+i]._visible = false;
// here i make fill circle mc, all hide with this code, but
problam is all circle come in background
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so add them as properties of the selection clip
sel.starty = _ymouse;
this.onEnterFrame = function() {
with(sel){
clear();
lineStyle( 1, 000000, 100 );
moveTo(sel.startx, sel.starty);
lineTo(_xmouse, starty);
lineTo(_xmouse, _ymouse);
lineTo(sel.startx, _ymouse);
lineTo(sel.startx, sel.starty);
_root.onMouseUp = function() {
_root.select(sel.startx,sel.starty,sel._xmouse,sel._ymouse);
// call the selection function
removeMovieClip(sel);
this.onEnterFrame = undefined;
_root.select =
function(x1:Number,y1:Number,x2:Number,y2:Number){
// in case you dragged the selection box from right to left
or bottom to top, we need
// to work out the top left and bottom right coordinates..
var sx = Math.min(x1,x2);
var ex = Math.max(x1,x2);
var sy = Math.min(y1,y2);
var ey = Math.max(y1,y2);
for(var item in this){ // loop through all items in the
_root
if(typeof(this[item])=="movieclip"){ // if the current item
is a movieclip..
this[item]._visible = isInside(this[item],sx,sy,ex,ey);
function
isInside(mc:MovieClip,x1:Number,y1:Number,x2:Number,y2:Number):Boolean{
// check whether the selection coordinates enclose the mc
coordinates
return (x1<=mc._x && x2>=mc._x+mc._width
&& y1<=mc._y && y2>=mc._y+mc._height);
// here u can find selection option, selection option is
wroking, but same problam, it work in background, & hide my all
MC (that Plain Circle also) and highlight only which we select
// Some brif here:
i want to create plain circle in background, after that some
one want to slecte that palin circle highlight that circle only
with fill circle ( for better explaination see my fla file which is
attach here
Please see this
Pls pls help me out
thanks
praful damaniafor better explaination pls see my fla file which is attache
there & I have some quation about it as under
1) here i make fill circle mc, all hide with this code, but
problam is all circle come in background
2) here i make fill circle mc, all hide with this code, but
problam is all circle come in background
3) here u can find selection option, selection option is
wroking, but same problam, it work in background, & hide my all
MC (that Plain Circle also) and highlight only which we select
i want to create plain circle in background, after that some
one want to slecte that palin circle highlight that circle only
with fill circle
thanks for reply
Praful Damania
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Can UWL are simontanously configure for two different sap systems ? How ?
Hi, I am new in portal. Can any one tell me how to configure UWL . We have r/3 system as well as crm system. i want to show both UWL for both the system on one page. Please give ans in steps by steps. Please suggest me steps for that. Regards, Gurpri