A little change in my tree path function

Question

Hello, I have a tree that receive this XML as data, and I want to know what is the path of one node, for example if I do click in Documentation I want to receive INBOX.Drafts.Flex.Documentation. I have a function to do that but I get that. [email protected] But id on't want the first node([email protected]). Here the xml and my function. What I have to change to get  INBOX.Drafts.Flex.Documentation?
<?xml version="1.0" encoding="UTF-8"?>
<Cuentas>
  <Cuenta id="cuenta1" label="[email protected]">
    <node label="INBOX" id="(2)">
      <node label="Drafts" />
      <node label="Flex" id="(49)">
        <node label="Codigo" />
        <node label="Documentacion" />
      </node>
      <node label="Sent" />
      <node label="Trash" />
    </node>
  </Cuenta>
  <Cuenta id="cuenta2" label="[email protected]">
    <node label="INBOX">
      <node label="Name">
        <node label="Surname" />
      </node>
      <node label="Carpeta1" id="(37)">
        <node label="Carpeta11" />
      </node>
      <node label="Trash" />
    </node>
  </Cuenta>
</Cuentas>
public function getRuta():String {
             var item:Object = newTree.selectedItem;
              ruta=item.@label
              while (true){
                   if (newTree.getParentItem(item) != null){
                       item=newTree.getParentItem(item)
                    ruta = item.@label + "." + ruta;
                   }else {break;}
               return ruta;
I think that the difference is small but I don't know how can I do. I have to say that the xml is not always the same, sometimes have 3 fathers, or 5 fathers or... I want something dinamic.
Thanks!

Answer 1

I want to know how can I change this if and say. If have parent && the parent isn't the 'root' or the node. I don't know how say the second condition.
if (newTree.getParentItem(item) != null) && ......
The second condition is because I don't want put the label of the main of the node ([email protected]) in the ruta String.
Thanks!