A question about arrays (brace yourself this is a long post)

I am working on an assignment that is about generating a random rabbit race by using arrays:
Rabbit Race
Write a program to simulate a race between 4 rabbits (numbered 0 to 3). Initially, all contestants are at the start of the race track (position 0) and must race on a 20 meter track (positions numbered 0 to 19). Each participant has its own technique; some run fast, but are sometimes lazy; while others run slowly but steadily. All rabbits make 1 movement one after the other and the one who arrives at the end of the track before the others, wins the race. Here are the rabbit?s strategies :
At each turn, rabbit 0:
- sleeps (so does not run), 50% of the time;
- runs 4 meters, 30% of the time;
- runs 3 meters, 20% of the time.
At every turn, rabbit 1 runs 2 meters.
At each turn, rabbit 2:
- sleeps, 30% of the time;
- runs 3 meters, 70% of the time.
At each turn, rabbit 3:
- runs 1 meter, 80% of the time;
- runs 10 meters, 20% of the time.
The difficulty in the race is that the track has little slippery hills. So after each movement, rabbits can slide down a hill bringing them either closer to the finishing line, or closer to the starting line. How much they slide and in what direction depends on the slope of the hill at their current position, and how many meters they ran during this turn. Each position (or meter) of the hill has a slope represented by an integer between -3 and +2. If the slope is :
- zero : then, there is no hill at this position and rabbits that reach this position stay there.
- a negative integer : then, there is a declining side of a hill at this position, and all rabbits reaching this position will slide down
to a new position that is closer to the finishing line. The new position will be the current position minus the slope times the number of meters the rabbit ran.
For example, assume a rabbit was in position 10, then ran 5 meters to position 15. If the slope at position 15 is -2, then the new position of the rabbit will be 15 - (-2 x 5) = 25.
- a positive integer : then, there is a rising side of hill at that position, and all rabbits reaching this position will slide down to a new position that is closer to the starting line. The new position will be the current position minus the slope times the number of meters the rabbit ran.
For example, assume a rabbit was in position 10, then ran 5 meters to position 15. If the slope at position 15 is +1, then the new position of the rabbit will be 15 - (+1 x 5) = 10.
Notes on the race:
- Rabbits have 40 turns to reach the finish line. If after 40 turns no one has managed to reach position 19 (or beyond), then the race is cancelled and no winner is declared.
- A rabbit?s position can never go below 0. If, after calculating a rabbit?s position, you arrive at a negative position (ex. position -3), then consider that it is at position 0.
- Consider that any position outside the track (ex. position 0 or position 20) has a slope of 0.
- If a rabbit reaches position 19 (or goes beyond it), it does not immediately win the race. If any other rabbit reaches position 19 (or beyond) during the same turn, then there is a tie.
- If at the same turn, one rabbit reaches position 19, and another reaches a position higher than 19, the second rabbit does not win the race because it went further than the first. They both win.
Ok I know this is long and boring to read but I already completed the majority of the assignment here is my code:
public class Assignment_3 {
    public static void main (String args[])
         int[] position = new int[20];
         int[] slope = new int[20];
         int[] moveRabbit = new int[4];
               moveRabbit[1] = 2;
         int[] currentPosition = new int[4];
         int currentPositionandSlope = 0;
         for (int i=0;i<position.length;i++)
         {     position=i;
          System.out.print(position[i] + " ");
     System.out.println();
     for (int i=0;i<(position.length-5);i++)
     {     slope[i]=(int) (-3 + Math.random()*5);
     for (int i=0;i<position.length;i++)
          System.out.print(slope[i] + " ");
     System.out.println();
     for (int turn=1;turn<=40;turn++)
          int randomNb0 = (int) (Math.random () * 100);
int randomNb2 = (int) (Math.random () * 100);
int randomNb3 = (int) (Math.random () * 100);
          if (randomNb0<=50)
               moveRabbit[0] = 0;
          else if (randomNb<=30)
               moveRabbit[0] = 4;
          else
          moveRabbit[0] = 3;
          if (randomNb2<=30)
               moveRabbit[2] = 0;
          else
          moveRabbit[2] = 3;
          if (randomNb3<=80)
               moveRabbit[3] = 1;
               else
          moveRabbit[3] = 10;
for (int j=0;j<=3;j++)
System.out.println ("Rabbit" + j + " is at position " + position[currentPosition[j]]);
if (slope[currentPosition[j]+moveRabbit[i]] < 0)
     currentPositionandSlope = position[currentPosition[j]+moveRabbit[j]] - (slope[currentPosition[j]+moveRabbit[j]] * moveRabbit[j]);
else if (slope[currentPosition[j]+moveRabbit[i]] > 0)
     currentPositionandSlope = position[currentPosition[j]+moveRabbit[j]] - (slope[currentPosition[j]+moveRabbit[j]] * moveRabbit[j]);
else
     currentPositionandSlope = (currentPosition[j]+moveRabbit[j]);
System.out.println ("it will move by " + moveRabbit[j] + ", but at position " + (position[currentPosition[j]] + moveRabbit[j]) + " there is a slope of " + slope[currentPosition[j] + moveRabbit[j]]);
System.out.println ("so it will slip by " + (position[currentPositionandSlope] - moveRabbit[j]) + " positions, and end up at position " + position[currentPositionandSlope]);
currentPosition[j] += currentPositionandSlope;
*Ok basically my question is that in the assignment there is an example output where the rabbit is at position 21 but the array is only 20 in length and my program crashes if i go beyond the array length.*
The example output is here:
Welcome to the 4 rabbit race:
position: 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19
slopes: 0 0 1 -2 1 0 -1 -1 1 -2 1 0 -1 -1 1 0 0 0 0 0
TURN #1
rabbit 0 is at position 0
it will move by 3, but at position 3 there is a slope of -2
so it will slip by 6 positions, and end up at position 9
rabbit 1 is at position 0
it will move by 2, but at position 2 there is a slope of 1
so it will slip by -2 positions, and end up at position 0
rabbit 2 is at position 0
it will move by 3, but at position 3 there is a slope of -2
so it will slip by 6 positions, and end up at position 9
rabbit 3 is at position 0
it will move by 1, but at position 1 there is a slope of 0
so it will slip by 0 positions, and end up at position 1
TURN #2
rabbit 0 is at position 9
it will move by 0, but at position 9 there is a slope of -2
so it will slip by 0 positions, and end up at position 9
rabbit 1 is at position 0
it will move by 2, but at position 2 there is a slope of 1
so it will slip by -2 positions, and end up at position 0
rabbit 2 is at position 9
it will move by 3, but at position 12 there is a slope of -1
so it will slip by 3 positions, and end up at position 15
rabbit 3 is at position 1
it will move by 1, but at position 2 there is a slope of 1
so it will slip by -1 positions, and end up at position 1
TURN #3
rabbit 0 is at position 9
it will move by 3, but at position 12 there is a slope of -1
so it will slip by 3 positions, and end up at position 15
rabbit 1 is at position 0
it will move by 2, but at position 2 there is a slope of 1
so it will slip by -2 positions, and end up at position 0
rabbit 2 is at position 15
it will move by 3, but at position 18 there is a slope of 0
so it will slip by 0 positions, and end up at position 18
rabbit 3 is at position 1
3
it will move by 10, but at position 11 there is a slope of 0
so it will slip by 0 positions, and end up at position 11
TURN #4
rabbit 0 is at position 15
it will move by 0, but at position 15 there is a slope of 0
so it will slip by 0 positions, and end up at position 15
rabbit 1 is at position 0
it will move by 2, but at position 2 there is a slope of 1
so it will slip by -2 positions, and end up at position 0
*rabbit 2 is at position 18*
*it will move by 3, but at position 21 there is a slope of 0*
*so it will slip by 0 positions, and end up at position 21*
*We have a potential winner...*
rabbit 3 is at position 11
it will move by 1, but at position 12 there is a slope of -1
so it will slip by 1 positions, and end up at position 13
So yeah :) that's basically my question (all this text for a simple question like that lol)
If you've managed to get to the end of my post then any guidance on my code would be appreciated too :)

I'm not going to read that long post. As suggested, produce an SSCCE
and paste in the exact, complete error message, and indicate clearly which line causes it.
I did notice this though:
Ok basically my question is that in the assignment there is an example output where the rabbit
is at position 21 but the array is only 20 in length and my program crashes if i go beyond the array length.Either you're misunderstanding something, or the assignment has a typo. If you have an array of length 20, then the indices are 0..19.
Maybe the instructor is calling index 0 position 1--separating Java's array impelementation details from
colloquial 1-based counting, so that the rabbit starts at "position 1" (index 0) goes through "position 20"
(index 19), and when he's done, he's "at postion 21"--i.e., past the finish line, off the end of the course, etc.
This won't correspond to any index in the array, but can still be considered a logical position in the race. "Oh, he's
at position 21. He's done. There's nothing more to do with the array, as it has no slot corresponding to
this 'done' position."
That's pure speculation on my part. You'll have to ask your instructor or figure out for yourself what's going on.

Similar Messages

Question about arrays

I have a question regarding arrays. I have a contact class and two classes that extend from it a SchoolContact class and FamilyContact class. Right now as my code is I have three diffrernt arrays to hold all the info. Is there a way to store all this info into one array and print out only the School contacts at one time if the user enters that option or print out all the options at one time if the user selects that? my code is below
//The imports below are for I/O
import java.util.*;
import java.io.*;
// Declare a public class
public class CodeExample {
     public static void main(String[] args) {
          // Create scanner
          Scanner sc = new Scanner(System.in);
          //Declare array to hold school contact
          SchoolContact[] schoolContactInfo = new SchoolContact[10];
          FamilyContact[] familyContactInfo = new FamilyContact[10];
          Contact [] contactInfo = new Contact [10];
          // Declare variables
          int menuOption, creditHours, area, prefix, suffix, studentId, studentContactsSoFar = 0, familyContactsSoFar = 0, contactsSoFar = 0;
          double gpa;
          char studentData, familyRelationOption;
          String menuOption2, menuOption3;
          // Get menu to display
          do {
               System.out.println("-----MENU-----");
               System.out.println("1) Enter a Student Contact");
               System.out.println("2) Enter a Family Contact");
               System.out.println("3) Enter a Contact");
               System.out.println("4) Display Student Contacts");
               System.out.println("5) Display Family Contacts");
               System.out.println("6) Display Contacts");
               System.out.println("7) Display All Contacts");
               System.out.println("8) Quit");
               System.out.println("Selection:");
               menuOption = sc.nextInt();
               SchoolContact schoolContact = new SchoolContact();
               FamilyContact familyContact = new FamilyContact();
               Contact contact = new Contact();
               // Implement switch statement to
               switch (menuOption) {
               // If user enters 1 to create contact this will be displayed to user
               case 1:
                    System.out.println("Enter The First Name of The Student");
                    schoolContact.setFirstName(sc.next());
                    System.out.println("Enter The Last Name of The Student");
                    schoolContact.setLastName(sc.next());
                    System.out.println("Enter the Student ID of this person: 900");
                    schoolContact.setStudentId(Integer.parseInt("900" + sc.next()));
                    System.out.println("G)Enter The GPA For This Student");
                    System.out.println("H)Enter The Number Of Completed Credit Hours");
                    menuOption2 = sc.next().toUpperCase();
                    studentData = menuOption2.charAt(0);
                    // Prompts the user for the next choice
                    if (studentData == 'G') {
                         System.out.println("GPA: ");
                         gpa = sc.nextDouble();
                         //create the Data object
                         Data data = new Data();
                         data.setStudentGPA(gpa);
                         //add it to the contact
                         schoolContact.setData(data);
                         else if (studentData == 'H') {
                              System.out.println("Hours: ");
                              creditHours = sc.nextInt();
                              //create the Data object
                              Data data = new Data();
                              data.setStudentCreditHours(creditHours);
                              //add it to the schoolcontact
                              schoolContact.setData(data);
                              else {
                                   System.out.println("Invalid Entry");
                    System.out.println("Enter The Phone Number of This Student");
                    System.out.println("(###)-###-####: ");
                    area = sc.nextInt();
                    prefix = sc.nextInt();
                    suffix = sc.nextInt();
                    //create the phone object
                    Phone_Number studentPhone = new Phone_Number(area, prefix,     suffix);
                    //add it to the Schoolcontact
                    schoolContact.setPhone(studentPhone);
                    //store info in an array
                    schoolContactInfo[ studentContactsSoFar ] = schoolContact;
                    //increase the counter to point to the next free location (if any)
                    studentContactsSoFar++;
                    break;
               case 2:
                    System.out.println("Enter the First Name of The Contact");
                    familyContact.setFirstName(sc.next());
                    System.out.println("Enter The Last Name of The Student");
                    familyContact.setLastName(sc.next());
                    System.out.println("Enter The Relationship of This Contact");
                    System.out.println("A) SISTER");
                    System.out.println("B) BROTHER");
                    System.out.println("C) MOTHER");
                    System.out.println("D) FATHER");
                    System.out.println("E) OTHER");
                    menuOption3 = sc.next();
                    familyRelationOption = menuOption3.charAt(0);
                    if (familyRelationOption == 'A') {
                         System.out.println("Relationship: SISTER ");
                         familyContact.setRelationType(FamilyContact.RelationType.SISTER);
                         else if (familyRelationOption == 'B') {
                         System.out.println("Relationship: BROTHER ");
                         familyContact.setRelationType(FamilyContact.RelationType.BROTHER);
                              else if (familyRelationOption == 'C') {
                                   System.out.println("Relationship: MOTHER ");
                                   familyContact.setRelationType(FamilyContact.RelationType.MOTHER);
                                   else if (familyRelationOption == 'D') {
                                        System.out.println("Relationship: FATHER ");
                                        familyContact.setRelationType(FamilyContact.RelationType.FATHER);
                                        else if (familyRelationOption == 'E') {
                                             System.out.println("Relationship: OTHER ");
                                             familyContact.setRelationType(FamilyContact.RelationType.OTHER);
                    System.out.println("Enter The Phone Number of This Contact");
                    System.out.println("(###)-###-####: ");
                    area = sc.nextInt();
                    prefix = sc.nextInt();
                    suffix = sc.nextInt();
                    //create the phone object
                    Phone_Number familyContactNumber = new Phone_Number(area, prefix,     suffix);
                    //add it to the familyContact
                    familyContact.setPhone(familyContactNumber);
                    //store info in an array
                    familyContactInfo[ familyContactsSoFar ] = familyContact;
                    //increase the counter to point to the next free location (if any)
                    familyContactsSoFar++;
                    break;
               case 3:
                    System.out.println("Enter The First Name of The Contact");
                    contact.setFirstName(sc.next());
                    System.out.println("Enter The Last Name of The Contact");
                    contact.setLastName(sc.next());
                    System.out.println("Enter The Phone Number of This Contact");
                    System.out.println("(###)-###-####: ");
                    area = sc.nextInt();
                    prefix = sc.nextInt();
                    suffix = sc.nextInt();
                    //create the phone object
                    Phone_Number contactNumber = new Phone_Number(area, prefix,     suffix);
                    //add it to the contact
                    contact.setPhone(contactNumber);
                    //store info in an array
                    contactInfo[ contactsSoFar ] = contact;
                    //increase the counter to point to the next free location (if any)
                    contactsSoFar++;
                    break;
               case 4:
                    System.out.println("-----Student Contacts-----");
                    //print each stored contact
                    for( int i = 0 ; i < studentContactsSoFar ; i++ )
                         System.out.println( (i+1) + ". " + schoolContactInfo.toString() + "\n");
                    break;
               case 5:
                    System.out.println("-----Family Contacts-----");
                    //prints each stored contact
                    for( int i = 0 ; i < familyContactsSoFar ; i++ )
                         System.out.println( (i+1) + ". " + familyContactInfo[i].toString() + "\n");
                    break;
               case 6:
                    System.out.println("-----Contacts-----");
                    //prints each stored contact
                    for( int i = 0 ; i < contactsSoFar ; i++ )
                         System.out.println( (i+1) + ". " + contactInfo[i].toString() + "\n");
                    break;
               case 7:
                    System.out.println("Calling Case 7");
                    for( int i = 0 ; i < contactsSoFar ; i++ )
                         System.out.println( (i+1) + ". " + contactInfo[i].toString() + "\n");
                    break;
               case 8:
                    System.out.println("Program Ended");
                    break;
          } while (menuOption != 8);

how would I go in printing the contacts from one array, then the next array and so on?
case 7:
    System.out.println("Calling Case 7");
    for( int i = 0 ; i < studentContactsSoFar ; i++ ) {
        System.out.println( (i+1) + ". " + schoolContactInfo.toString() + "\n");
for( int i = 0 ; i < familyContactsSoFar ; i++ ) {
System.out.println( (i+1) + ". " + familyContactInfo[i].toString() + "\n");
for( int i = 0 ; i < contactsSoFar ; i++ ) {
System.out.println( (i+1) + ". " + contactInfo[i].toString() + "\n");
break;

A few questions about Arrays and Array Methods.

I have 2 dimentional arrays in a number of classes, and I wish to pass them about as variables, however, I can only seem to send int[], rather than int[][]. Gives me some compile errors.
Another thing. How do i get the length of an array?
I've tried: getLength(object), but it's a 2d array (int[][]), and It's having none of it. How do i get the length of a particular side?

An object like int[][] only has a single "length", and that is the length of the first dimension. This object is an array that contains arrays of int, and each of those arrays could have a different length. Your 2D array may happen to be rectangular but that isn't a requirement of Java. So you would have to write your own code to find the lengths of the sides. The first side would be theArray.length, the second side would be theArray[0].length, and like that.

Please do not post questions about Adobe software in this forum

Hello, welcome to the forums.
What you may not realise is that each Adobe product has its own specialist forum, and it's very important to choose the right one. This forum isn't about products, it's about comments on the forums themselves.
So, please go back to http://www.adobe.com/support/forums.html and choose the right forum. But first, make sure you know the name of your product.
When you look at the list of messages in a forum, there is a box above that describing what the forum is for. Take care to read it carefully, or you may put your message in a forum where there are no experts who understand your question. Also, check to see whether there are any "FAQ" (Frequently Asked Questions) sections in the product forum, and search for previous discussions about the question you wish to ask before starting a new one.

this is maybe because users are directly forwarded to this forum when looking for a contact in the otn-contact page. i suggest to change the contact-site and the direct the users to the "forums home" page.
trevi

Hopefully an easy question about arrays

hi there
is there any way of creating an array of objects that is of unspecified size at the time of creating and then add objects as and when they are read from a file?
longer explanation:
i am creating molecule visualization software. the molecule's structure is stored in a text file, ie each line has info on one atom ie 3d coords etc. i'm storing the molecule structure in an object (Molecule.java) which has an array (Structure[]) of atoms (Atom.java). obviously molecules can have any number of atoms in it and you don't know how many until you've gone through the whole file and counted. The only way i can think of doing it is to go through the whole file, coun the atoms, close the file, create the Molecule object with the structure array size of NoOfAtoms and then open the file again and add the atoms as i go through them again. however, i refuse to believe this is the most efficient way of doing it as i have to go throguh the same file twice which brings me back to my original question.
as i said i'm hopeing there is a simple answer
cheers

Use a Collection . Use a Vector, ArrayList or even a Hashtable. You do not need to define the size of these objects and can add and remove Objects from them whenever you want

A question about arrays. Please Help

Ok here is my question lets say i have a multie varible array such as
int[][] thisList = new int[3][64];And I have a number of other arrays that are single variable arrays, and which have data stored in them.
List1[64]
List2[64]
List3[64]is there a way i can store all these three list in the multie varible array?
for example i know i can do this, > Correct me if i am wrong
List1 = List2; where List1 one now contains all the elements that List2 has.
but is there a way i can
us the same format with a multie varible array, to store all three list in it.
such as thisList[1][] = List1; thisList[2][] = List2[]; Thanks

for example i know i can do this, > Correct me if i
am wrong
List1 = List2; where List1 one now
contains all the elements that List2 has.There will be one array. Both the List1 and List2 reference variables will point to that same array.
(By the way, convention in Java is for variables to start with lowercase.)
>
but is there a way i can
us the same format with a multie varible array, to
store all three list in it.
such as thisList[1][] = List1; thisList[2][] =
List2[];
You can do thisList[1] = List1 if thisList is an int[][] and List1 is an int[]. However, that will not copy any ints. It will just do the same as the above--cause the reference thisList[1] to point to the same array object as List1 does.
If you want to copy values from one array to another, use System.arraycopy.

Very simple and quick question about Arrays

Hi,
I have the following code to produce a student grades provessing system. I have got it to store data in the array, i just cant figure out how to add the integers from the row to produce a total. Thats all I want to do create a total from the 6 marks and add a percentage.
Any help would be greatly appreciated.
-------------CODE BELOW----------------------
import java.util.*;
public class newstudent1_2
public static void main (String[]args)
System.out.println ("-----------------------------------------------"); //Decorative border to make the welcome message stand out
System.out.println (" Welcome to Student Exam Mark Software 1.2"); //Simple welcome message
System.out.println ("-----------------------------------------------");
int [][] mark;
int total_mark;
int num_students;
int num_questions = 9;
Scanner kybd = new Scanner(System.in);
System.out.println("How many students?");
num_students =kybd.nextInt();
mark = new int[num_students][num_questions] ;
for (int i=0; i<num_students; i++)
System.out.println("Enter the Students ID");
String student_id;
student_id =kybd.next();
System.out.println("Student "+i);
for( int j=1; j<num_questions; j++)
System.out.println("Please enter a mark for question "+j);
mark[i][j]=kybd.nextInt();
System.out.print("id mark1 mark2 mark3 mark4 mark5 mark6 mark7 mark8");
//This section prints the array data into a table
System.out.println();
for (int i=0; i<num_students; i++)
for( int j=0; j<num_questions; j++)
System.out.print(mark[i][j]+"\t"); //the \t is used to add spaces inbetween the output table
System.out.println();
--------------END OF CODE---------------
Thanks.

I had to do this same sort of thing for a school assignment but i didnt use an array.
import java.text.DecimalFormat;
import TurtleGraphics.KeyboardReader;
public class grade_avg
     public static void main(String[] args)
          int grade, total = 0, count = 0;
          double avg = 0.0;
          KeyboardReader reader = new KeyboardReader();
          DecimalFormat df = new DecimalFormat("0.00");
     for (;;)
               grade = reader.readInt("Please enter a grade: ");
          if (grade > 0)
                    total = total + grade;
                    count ++;
          if (grade == 0)
                    avg = total / count;
                    System.out.println("The average is: " + df.format(avg));
                    System.exit(0);
}output looks like:
Please enter a grade: 100
Please enter a grade: 50
Please enter a grade: 0
The average is: 75.00

I am trying to ask a question about iPhones, but it will not let me post - I get a message similar to this - you are not allowed to change the content. Any help on this matter?

I am trying to ask the following question: Just updated my iPhone5 to V 7.1.2 and can no longer print to my MFC 7860W from this phone. I researched this issue on this forum and found answers from last October/November..... Wary of downloading anything that was posted that long ago. Wondering if there is anyway around this issue, with more recent information? I was able to use this printer in the past by using Brother's iPrint App.
Thanks!!
But when I hit post, I get an error message at the top - "you are not allowed to change this content" Can anyone help me?

I am assuming you got that message when attempting to post an old thread. The old post is probably locked/archived.
FYI, posting on old threads usually yields no responses at all.
I have requested that this post be moved to the iPhone forum where you might get assistance.
Barry

Hello and a question about Arrays

Hello! I am a student working towards a CIS degree, I'm only in my second term, so I have a long way to go still. Next term (starts in November) I'll be starting my first language (Java) so I figured this is a good spot to register and get acquainted with all of you.
Anyway, right now I'm in a programming logic and design class. In this class we use Pseudocode to get the basic constructs of programming down without doing anything language specific. I just read the chapter that introduces Arrays and had a difficult time following it. Could any of you take a minute and give me your definition of what exactly an array is and how it works? Or maybe point me to a link that might help me? I've got the 'jist' of it, but the book jumps right into algorithms using arrays without much explaination as to what they are.
Thanks for any response and for helping a programming "n00b".
-Rawhide

>
Hello! I am a student working towards a CIS
CIS degree, I'm only in my second term, so I have a
long way to go still. Next term (starts in November)
I'll be starting my first language (Java) so I
figured this is a good spot to register and get
acquainted with all of you.
Anyway, right now I'm in a programming logic andThink of an array as a series of boxes. These boxes store data for three
elements. So you would have three boxes that store one element of data.
So 'this' array has a capacity of three. If you want something bigger,
you'd create a array with more boxes, say 10. Then your array has a capacity of 10.
To get to anything from a array, you either need to :
a) go through all the elements of the array
b) or actually know the element you want to retrieve.
The second case is simple enough, you usually just specify the element you want. For example the first element would be zero.(counting starts from zero). The last element would be 9 (10 -1).
The first case requires some knowledge of looping, you'd generally itterate from the first until the last element of the array, in each and every element that you are at, do the stuff you need to do. This will go on until the end of the array is reached.
for(int i=0; i<=arraylength;i++ ) {
do some stuff. like print out to the console.
I'm not giving you any specific java code because you didn't ask for any and you were doing a course that wasn't language specific. So I figured that may be a simpler explanation(was it?) was in order.
Let me know if you need clarification.
and design class. In this class we use Pseudocode to
get the basic constructs of programming down without
doing anything language specific. I just read the
chapter that introduces Arrays and had a difficult
time following it. Could any of you take a minute
and give me your definition of what exactly an array
is and how it works? Or maybe point me to a link that
might help me? I've got the 'jist' of it, but the
book jumps right into algorithms using arrays without
much explaination as to what they are.
Thanks for any response and for helping a programming
"n00b".
-Rawhide

Question about array append

Hi,
I have a for loop and an array outside the for loop. In each iteration some values are sent to the array.
For example, after first loop, I send following data to array:
2 3 4 5
4 5 6 7
after the second loop, other data send to array again and will overwrite the former data in array. How can I append the data to the array?
I try to use "Insert into array.vi", but how to keep the former array's data?
Thanks.

You have quite a few options.
The attached VI (LabVIEW 7.1) shows two possibilities, either building the table (2D string) or building the array (2D DBL).
(NOTES: If this is in a fast FOR loop it is not useful to update the display inside the loop, simply place the output terminals outside the FOR loop, connected to the shift registers on the right. If you know the final array size and it is relatively big, it is more efficient to initialize the shift register with the full sized array (e.g. filled with zeroes or NaNs), then replace array sections as you go in the loop. This avoids array resizing operations.)
LabVIEW Champion . Do more with less code and in less time .
Attachments:
temp_ni_MOD.vi ‏43 KB

Hi, i got some question about arrays.

My question is how do i auto increase the array size for theList[0] to store the over time if the user enter more than 1 employee.
static void showPayInfo(int num1 , int num2)
          for(int coloum = 1 ; coloum <= num2 ; coloum++)
               System.out.print("Enter employee's over time $: ");
               ot = CspInput.readDouble();
               Double = ot;
               getDouble(Double);
static double ot , Double;
     static void getDouble(double Double)
          double[] theList = new double[2];
          theList[0] = ot;
     public static void main(String[] args)
          int a;
          System.out.print("How many employees : " );
          a = CspInput.readInt();
          showPayInfo(1,a);
     }

how to create the list?
import java.util.ArrayList;
class testArrayList {
   public static void main(String[] args) {
     ArrayList<String> list1 = new ArrayList<String>();
     // Populate list
     for (int i = 0; i < 5; i++) {
       list1.add("List item " + i);
     // Show list
     for (int i = 0; i < list1.size(); i++) {
       System.out.println(list1.get(i));
}

Simple newbie question about arrays..

Hello all,
I have two arrays declared like so below the class header:
String Players[];
String Final[];
I have a method like the following:
public String[] CollectPlayers() {
Players[0] = new String(txtPlayer1.getString());
return Players;
I am calling this method like so
Final = CollectPlayers();
Basically not working, giving nullpointerexception, but I feel that I am fundamentally not understanding something, so here is what I want...
A method that returns an array and (ideally) use this method directly in creating a ChoiceGroup, like this...
optBull = new ChoiceGroup("Bully", ChoiceGroup.EXCLUSIVE, CollectPlayers(), arrImage);
Is this possible? Any ideas?
Thanks in advance
poncenby

A few points:
- You almost never need to call new String(String).
- You may want to create an ArrayList (dynamic array) and then call toArray(new Players[0]) if you need it to be a fixed array.
e.g.
final List players = new ArrayList();
public List collectPlayers(List players) {
    List finals = new ArrayList();
    for(int i=0;i<players.size();i++) {
        Player player = (Player) players.get(i);
        finals.add(players.getResult());
    return finals;
players.add(new Player("anne"));
players.add(new Player("bob"));
players.add(new Player("fred"));
List finals = collectPlayers(players);

Question about combos - why does this fire twice?

i make an ItemListener for a combo.
( see below )
when i select an item in the combo the
method my_method() is always called TWICE for
some reason. can somebody tell me
why this is?
class MyItemListener implements java.awt.event.ItemListener {
public void itemStateChanged(ItemEvent e) {
my_method() ;
thanks for any help
owen

OK Ignore what I just said.
Have you looked at the JavaDocs? If not then I recommend that you download them, they're an invaluable source of information. Everything I'm about to tell you is straight from the JavaDocs, I've no experience in using ItemListeners.
The Javadocs say:
addItemListener
public void addItemListener(ItemListener aListener)
Adds an ItemListener.
aListener will receive one or two ItemEvents when the selected item changes.
Then JavaDoc from ItemEvent:
public class ItemEvent
extends AWTEvent
A semantic event which indicates that an item was selected or deselected. This high-level event is generated by an ItemSelectable object (such as a List) when an item is selected or deselected by the user. The event is passed to every ItemListener object which registered to receive such events using the component's addItemListener method.
What you are seeing is an ItemEvent.SELECTED
and a ItemEvent.DESELECTED. I don't know the order in which you'll get them.
Dave

Question about array!

Is there any way to make external array, which could be used by more than one application or flash movie?

The simplest solution is often the best.
If you are only using arrays: use a text file.
Text files can be read into any application and you can use the [split] method with a delimiter to create an array
If you are using both arrays and objects: use JSON
JSON can handle primitive objects which can also be used in any environment beyond Flash
Both solutions involve creating a text file of some sorts. Load the text file with a URLLoader (flash) or as binary (any other) and parse the text as an array or JSON.
Why you dont want to add an 'External Array' to an SWF
In all situations you should consider maintainance and updating. If you create the array in an SWF file, all changes to the array (large or small) will involve you having to re-complie and re-upload the new SWF file. This will get VERY time consuming the larger the project scale. Using a text file is a lot less foot print on processing and file size.

Question about Photoshop Elements, not sure where else to post at.

I am looking to be able to add layers and do some fun type editing for photos to use as backgrounds and media shows. I'm new to this. I am planning to add Photoshop Elements and was just curious if it does enough different stuff from iPhoto 11 to make it worth it as well as enough to avoid purchasing the bigger more expensive Photoshop programs. I am also wondering where to get good tutorials on learning to use it, if so. Any help? Thanks.

PhotoShop Elements will do what you want, and is a good complement to iPhoto. For learning it, I suggest Barbara Brundage's excellent Missing Manual for PhotoShop Elements (Macintosh).
http://oreilly.com/catalog/9780596804961
Adobe also has lots of tutorials on their website.

A question about arrays (brace yourself this is a long post)

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