About setting the web.xml for Tomcat

Question

for a project, I use more than one servlet. So i set the
<servlet>
<servlet-name>servlet1</servlet-name>
<servlet-class>servlet1</servlet-class>
<servlet-name>servlet2</servlet-name>
<servlet-class>servlet2</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>servlet1</servlet-name>
<url-pattern>/servlet1</url-pattern>
<servlet-name>servlet2</servlet-name>
<url-pattern>/servlet2</url-pattern>
<servlet-mapping>
but only the last servlet is there for the web server to find and call. I don't know what's the problem. Maybe I don't set other parameters in some files of Tomcat?
Thanks for your reply.

Answer 1

<?xml version="1.0" encoding="ISO-8859-1"?>
<!--
This is the web-app configurations that allow w3prj to work under
Apache Tomcat.
-->
<!DOCTYPE web-app
PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.2//EN"
"http://java.sun.com/j2ee/dtds/web-app_2.2.dtd">
<web-app>
<servlet>
<servlet-name>JDBC</servlet-name>
<servlet-class>TestServlet</servlet-class>
</servlet>
<servlet>
<servlet-name>login</servlet-name>
<servlet-class>LoginServlet</servlet-class>
</servlet>
<servlet>
<servlet-name>worker</servlet-name>
<servlet-class>workerServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>JDBC</servlet-name>
<url-pattern>/TestServlet</url-pattern>
<servlet-name>login</servlet-name>
<url-pattern>/LoginServlet</url-pattern>
<servlet-name>worker</servlet-name>
<url-pattern>/worker</url-pattern>
</servlet-mapping>
</web-app>