Accessibility/Visibility of java types

Question

I have a problem concerning the visibility of some inherited methods from a parent class. I am calling a method in the child class, but that method is implemented in the parent class, but calls a second protected method which is declared abstract in the parent class. This protected abstract method is implemented in the children. I am unable to access the protected method even though the subclass inherits it. As per the java tutorial this is expected. Is there a way to make this method call work?
For example,
package one;
public abstract class A
public void mainMethod()
System.out.println("Executing mainMethod: Class A");
subMethod();
protected abstract static void subMethod();
package two;
public class B extends A
protected static void subMethod()
System.out.println("Executing subMethod: Class B");
package two;
public class C extends A
protected static void subMethod()
System.out.println("Executing subMethod: Class C");
package test;
public class Test
public static void main(String args[])
C c = new C();
c.mainMethod();
}

Answer 1

Sorry the example in the previous post has an error.
The static modifier should not be in the abstract method.
package one;
public abstract class A
public void mainMethod()
System.out.println("Executing mainMethod: Class A");
subMethod();
protected abstract void subMethod();
package two;
public class B extends A
protected void subMethod()
System.out.println("Executing subMethod: Class B");
package two;
public class C extends A
protected void subMethod()
System.out.println("Executing subMethod: Class C");
package test;
public class Test
public static void main(String args[])
C c = new C();
c.mainMethod();
}