Accessing ALL_TAB_COLUMNS from a Procedure

Hi,
I want a help in Accessing ALL_TAB_COLUMNS from a procedure.
I am an getting Error as Insufficient Privileges while Executing the Procedure.
Any help will be Benefitial
Thanks and Regards

You should not really be using SYS.
Is this a general issue with accessing "ALL_" views (i.e. information about other schemas than your own) within procedures? If so perhaps the account needs SELECT ANY DICTIONARY system privilege. although as with any system privilege you should consider the security implications.
If it's specifically ALL_TAB_COLUMNS and not the rest of the dictionary views, then a grant on that view to the owner of the package will do it.

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PROCEDURE PROC_TBLINFO
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AS
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Hi all,
Can I access DBA_TABLES from a PL/SQL block?
Following is the code I tried:
SQL> SHOW USER
USER is "SYSTEM"
SQL> ED
Wrote file afiedt.buf
1 CREATE OR REPLACE PACKAGE BODY BARAKAU
2 AS
3 PROCEDURE UPPER_COLS ( P_USER VARCHAR2, P_TABLE VARCHAR2 ) IS
4 BEGIN
5   -- loop through tables
6   FOR T IN ( SELECT TABLE_NAME FROM DBA_TABLES WHERE TABLE_NAME = NVL(P_TABLE, TABLE_NAME)
7               AND OWNER=UPPER(P_USER) ORDER BY TABLE_NAME) LOOP
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SQL> /
Warning: Package Body created with compilation errors.
SQL> SHOW ERROR
Errors for PACKAGE BODY BARAKAU:
LINE/COL ERROR
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6/36     PL/SQL: ORA-00942: table or view does not exist
8/4      PL/SQL: Statement ignored
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Hi,
SQL> SHOW USER
User is "SYS"
SQL>
Package created
Package body created
No errors for PACKAGE BODY SYS.BARAKAUPackage creation:
CREATE OR REPLACE PACKAGE BARAKAU AS
    PROCEDURE UPPER_COLS(P_USER VARCHAR2,
                         P_TABLE VARCHAR2);
END BARAKAU;
CREATE OR REPLACE PACKAGE BODY BARAKAU AS
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                         P_TABLE VARCHAR2) IS
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        -- loop through tables
        FOR T IN (SELECT TABLE_NAME
                  FROM   DBA_ALL_TABLES
                  WHERE TABLE_NAME = NVL(P_TABLE, TABLE_NAME)
                  AND    OWNER = UPPER(P_USER)
                  ORDER BY TABLE_NAME)
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        END LOOP;
    END UPPER_COLS;
END BARAKAU;
SHOW ERRORSNote: It's not a good idea create specific packages or other objects with users like sys or system...
Regards,

Update Yes/No field in access table through oracle procedure

Hi,
How to update Yes/No field in access table through oracle procedure. all other fields like AutoNumber, Text I can update it. Yes/No field how to update? Please, any one can help me?
Thanks and Regards,
Sudha.

Sudha Teki wrote:
select "fldPost" from tblPHd@ODBCLNKNot quite sure what you mean, but the way you select the column would indicate a case sensitive column name
Look at this example
SQL> create table t
2 ("this" varchar2(10))
3 /
Table created.
SQL> insert into t values ('hello')
2 /
1 row created.
SQL> select *
2    from t
3 /
this
hello
SQL> select this
2    from t
3 /
select this
ERROR at line 1:
ORA-00904: "THIS": invalid identifier
SQL> select "this"
2    from t
3 /
this
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Hi,
I have created an Advanced queue (DBMS_AQ) in my schema and i can successfully enqueue and dequeue messages through a stored proc.
But when i call the same stored proc from an APEX screen, i get the following error.
"ORA-24010: QUEUE APEX_PUBLIC_USER.<Q_name> does not exist."
As AQ admin and even as SYSDBA, the following permissions were given, but still
no luck.
1) DBMS_AQADM.grant_queue_privilege (
privilege => 'ENQUEUE_ANY',
queue_name => 'Q_name',
grantee => 'APEX_PUBLIC_USER',
grant_option => FALSE);
2) DBMS_AQADM.grant_queue_privilege (
privilege => 'DEQUEUE_ANY',
queue_name => 'Q_name',
grantee => 'APEX_PUBLIC_USER',
grant_option => FALSE);
3) DBMS_AQADM.grant_queue_privilege (
privilege => 'ALL',
queue_name => 'Q_name',
grantee => 'PUBLIC',
grant_option => FALSE);
4) Created a public synonym for the queue and tried to access the queue from the screen.
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Hi Scott,
First to answer your questions based on the error i was getting
All 1 , 2 and 3 are the same.
1) The schema assigned to the application is 'XYZ'
2) 'XYZ' is the AQ_administrator
3) Permission was granted to APEX_PUBLIC_USER by connecting as 'XYZ'.
Also in my local XE DB, i tried the same and i am able to access Q from the APEX application created in that Schema.
I did not grant any privilege except that the schema (foo) is the AQ_ADMIN.
schema: foo
workspace: foo (automatically created when i create an app in the schema)
parsing schema: foo
Please find the steps below
Connect As Sysdba
AQ_ADMIN PRIVELEGES
1) GRANT aq_administrator_role TO foo;
2) GRANT execute ON dbms_aq TO foo;
3) GRANT execute ON dbms_aqadm TO foo;
Connect As foo
1) create type image_uploaded_ot as object
sheet_id NUMBER(15));
2) GRANT EXECUTE ON IMAGE_UPLOADED_OT TO PUBLIC;
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3) begin
DBMS_AQADM.CREATE_QUEUE_TABLE (
queue_table => 'image_uploaded_qt',
queue_payload_type => 'image_uploaded_ot'
DBMS_AQADM.CREATE_QUEUE (
queue_name => 'image_uploaded_q',
queue_table => 'image_uploaded_qt'
DBMS_AQADM.START_QUEUE (
queue_name => 'image_uploaded_q'
end;
-- verify if queue exists
4) SELECT name, enqueue_enabled, dequeue_enabled
FROM user_queues;
SELECT name, enqueue_enabled, dequeue_enabled
FROM user_queues;
5) TESTING - ENQUEUE/DEQUEUE
CREATE OR REPLACE PROCEDURE demo_enqueue ( OT_I image_uploaded_ot)
IS
enq_msgid RAW(16);
eopt dbms_aq.enqueue_options_t;
mprop dbms_aq.message_properties_t;
aprop sys.aq$_agent;
pragma autonomous_transaction;
BEGIN
aprop := sys.aq$_agent(NULL, 'foo.image_uploaded_q', 0);
mprop.sender_id := aprop;
dbms_aq.enqueue('foo.image_uploaded_q', eopt, mprop, OT_I, enq_msgid);
COMMIT;
END demo_enqueue;
CREATE OR REPLACE PROCEDURE demo_dequeue IS
deq_msgid RAW(16);
dopt dbms_aq.dequeue_options_t;
mprop dbms_aq.message_properties_t;
payload_t image_uploaded_ot;
q_on_hand PLS_INTEGER;
no_messages EXCEPTION;
pragma exception_init(no_messages, -25228);
pragma autonomous_transaction;
BEGIN
dopt.dequeue_mode := dbms_aq.remove;
dopt.navigation := dbms_aq.first_message;
dopt.visibility := dbms_aq.immediate;
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dbms_aq.dequeue('foo.image_uploaded_q', dopt, mprop, payload_t, deq_msgid);
UPDATE OFFICE
SET OFFICE_NAME = 'TEST'
WHERE OFFICE_ID = payload_t.SHEET_ID;
COMMIT;
EXCEPTION
WHEN others THEN
RAISE;
END;
6) TESTING FROM APEX
created a pl/sql process
declare
test_ot image_uploaded_ot;
begin
test_ot := image_uploaded_ot(1);
demo_enqueue(test_ot);
demo_dequeue();
end;
By looking at the test program above and the answer to the questions. The test prgm satisfies criteria 1 and 2 above and as you had mentioned and confirmed by test prgm, 3 is not required.
I am not sure what privilege is missing in the actual schema.
But atleast a hope that a AQ is accessible from APEX :)
Thanks,
Rakesh

Is there a way to access object from other schema?

1. Is there a way to access object from other schema
Without using synonym/public synonym without prefixing schema owner?
2. If you do not see any object in all_objects by same name owned by connected user or public, can there still be objects hidden from this view? for instance synonyms created by SYSTEM
TIA for help

Well, you missed something somewhere. If there is no
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SQL> CREATE USER a identified by a;
User created.
SQL> GRANT CREATE SESSION to a;
Grant succeeded.
SQL> CREATE USER b identified by b;
User created.
SQL> GRANT CREATE SESSION, CREATE PROCEDURE, CREATE PUBLIC SYNONYM to b;
Grant succeeded.
SQL> connect b/b
Connected.
SQL> CREATE PACKAGE test AS
2     PROCEDURE testit;
3 END;
4 /
Package created.
SQL> CREATE PACKAGE BODY test AS
2 PROCEDURE testit IS
3 BEGIN
4     NULL;
5 END;
6 END;
7 /
Package body created.
SQL> connect a/a
Connected.
SQL> desc b.test
ERROR:
ORA-04043: object b.test does not exist
SQL> connect b/b
Connected.
SQL> GRANT EXECUTE ON test TO a;
Grant succeeded.
SQL> connect a/a
Connected.
SQL> desc b.test;
PROCEDURE TESTIT
SQL> desc test;
ERROR:
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Synonym created.
SQL> connect a/a
Connected.
SQL> desc test
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Connected.
SQL> drop public synonym test;
Synonym dropped.
SQL> GRANT CREATE SYNONYM TO a;
Grant succeeded.
SQL> connect a/a
Connected.
SQL> desc test;
ERROR:
ORA-04043: object test does not exist
SQL> desc b.test
PROCEDURE TESTIT
SQL> CREATE SYNONYM test FOR b.test;
Synonym created.
SQL> desc test;
PROCEDURE TESTIT
SQL> connect b/b
Connected.
SQL> REVOKE EXECUTE ON test FROM a;
Revoke succeeded.
SQL> connect a/a
Connected.
SQL> desc test;
ERROR:
ORA-04043: object "B"."TEST" does not exist
SQL> desc b.test
ERROR:
ORA-04043: object b.test does not exist
SQL> connect b/b
Connected.
SQL> DROP PACKAGE test;
Package dropped.
SQL> CREATE FUNCTION test (p_num IN NUMBER) RETURN NUMBER AS
2 BEGIN
3     RETURN p_num * 10;
4 END;
5 /
Function created.
SQL> GRANT EXECUTE ON test TO a;
Grant succeeded.
SQL> connect a/a
Connected.
SQL> desc test;
FUNCTION test RETURNS NUMBER
Argument Name                  Type                    In/Out Default?
P_NUM                          NUMBER                  INSo, I would go looking for the synonyms.
TTFN
John

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Hi,
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but is concluded while the Stored Procedure is executed
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A 1 3
B 1 5
C 2 10
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E 3 16
F 8 19
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Use Out parameter mode
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2 BEGIN
3        x:= 1;
4        y:= 2;
5 END;
6 .
SQL> /
Procedure created.
SQL> SET SERVEROUTPUT ON
SQL> DECLARE
2   a NUMBER :=3;
3   b NUMBER :=4;
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Dear Experts
I have an SP which gives error " cannot access rows from a non-nested table item ". But here the strange thing is, it works fine with one query. But I write union query with another table, only then it gives error.
CREATE OR REPLACE PROCEDURE SP_MONTHLYSALESUMMARY (
P_TRANSACTIONMONTH VARCHAR2,
P_LEDGERID VARCHAR2,
O_RESULTSET OUT TYPES.CURSORTYPE)
AS
BEGIN
OPEN O_RESULTSET FOR
-- POINT OF SALE
SELECT
L.DESCRIPTION LEDGERNAME,
LS.DESCRIPTION LEDGERSUBGROUPNAME,
C.CORPORATENO
|| E.EMPLOYEENO
|| AF.AFFILIATEMEMBERNO
|| M.MEMBERNO
AS ID,
C.NAME || E.NAME || AF.NAME || M.NAME AS NAME,
SUM(CASE
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AND T.ISCREDITTRANSACTIONMODE = 2
THEN
PB.TAXAMOUNT
ELSE
0
END)
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FROM POINTOFSALEBILL PB
INNER JOIN POINTOFSALEBILLDETAIL PD
ON PB.POINTOFSALEBILL_ID = PD.POINTOFSALEBILL_ID
INNER JOIN TRANSACTIONTYPE TY
ON TY.TRANSACTIONTYPE_ID = PB.TRANSACTIONTYPE_ID
INNER JOIN TRANSACTIONMODE T
ON T.TRANSACTIONMODE_ID = PB.TRANSACTIONMODE_ID
INNER JOIN LEDGER L
ON L.LEDGER_ID = PD.LEDGER_ID
INNER JOIN LEDGERSUBGROUP LS
ON LS.LEDGERSUBGROUP_ID = L.LEDGERSUBGROUP_ID
LEFT JOIN CORPORATE C
ON C.CORPORATE_ID = PB.CORPORATE_ID
LEFT JOIN EMPLOYEE E
ON E.EMPLOYEE_ID = PB.EMPLOYEE_ID
LEFT JOIN AFFILIATEMEMBER AF
ON AF.AFFILIATEMEMBER_ID = PB.AFFILIATEMEMBER_ID
LEFT JOIN MEMBER M
ON M.MEMBER_ID = PB.MEMBER_ID
WHERE TY.ISDEBIT = 1 AND PB.FLAG = 0 AND T.ISROOMNO = 2
AND (P_TRANSACTIONMONTH IS NULL
OR P_TRANSACTIONMONTH =
TO_CHAR (PB.BILLDATE, 'fmMONTH-YYYY'))
AND (P_LEDGERID IS NULL
OR L.LEDGER_ID IN
( (SELECT COLUMN_VALUE
FROM TABLE(GET_ROWS_FROM_LIST1 (
P_LEDGERID,
GROUP BY L.DESCRIPTION,
LS.DESCRIPTION,
C.CORPORATENO
|| E.EMPLOYEENO
|| AF.AFFILIATEMEMBERNO
|| M.MEMBERNO,
C.NAME || E.NAME || AF.NAME || M.NAME,
L.PRINTNO;
END SP_MONTHLYSALESUMMARY;
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REATE OR REPLACE FUNCTION BCLUB1868.GET_ROWS_FROM_LIST1
(L IN LONG DEFAULT NULL, SEP IN VARCHAR2 DEFAULT ',')
RETURN MYVARCHARTABLE1 PIPELINED
AS
L_POS INT := 1;
L_NEXT INT;
L_PART VARCHAR(500);
BEGIN
SELECT INSTR( L, SEP, L_POS) INTO L_NEXT FROM DUAL;
WHILE (L_NEXT>0)
LOOP
SELECT SUBSTR(L, L_POS, L_NEXT - L_POS) INTO L_PART FROM DUAL;
PIPE ROW(L_PART);
SELECT L_NEXT + 1, INSTR( L, SEP, L_POS)
INTO L_POS, L_NEXT FROM DUAL;
END LOOP;
SELECT SUBSTR(L, L_POS) INTO L_PART FROM DUAL;
PIPE ROW(L_PART);
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Request help from you all experts in the forum

Here it is
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P_TRANSACTIONMONTH VARCHAR2,
P_LEDGERID VARCHAR2,
O_RESULTSET OUT TYPES.CURSORTYPE)
AS
BEGIN
OPEN O_RESULTSET FOR
-- Point of sale
SELECT *
FROM ( SELECT L.DESCRIPTION LEDGERNAME,
LS.DESCRIPTION LEDGERSUBGROUPNAME,
C.CORPORATENO
|| E.EMPLOYEENO
|| AF.AFFILIATEMEMBERNO
|| M.MEMBERNO
AS ID,
C.NAME || E.NAME || AF.NAME || M.NAME AS NAME,
SUM(CASE
WHEN PB.EMPLOYEE_ID IS NULL
AND T.ISCREDITTRANSACTIONMODE = 1
THEN
PB.BILLAMOUNT
ELSE
0
END)
MEMBERDEBITAMOUNT,
L.PRINTNO
FROM POINTOFSALEBILL PB
INNER JOIN POINTOFSALEBILLDETAIL PD
ON PB.POINTOFSALEBILL_ID = PD.POINTOFSALEBILL_ID
INNER JOIN TRANSACTIONTYPE TY
ON TY.TRANSACTIONTYPE_ID = PB.TRANSACTIONTYPE_ID
INNER JOIN TRANSACTIONMODE T
ON T.TRANSACTIONMODE_ID = PB.TRANSACTIONMODE_ID
INNER JOIN LEDGER L
ON L.LEDGER_ID = PD.LEDGER_ID
INNER JOIN LEDGERSUBGROUP LS
ON LS.LEDGERSUBGROUP_ID = L.LEDGERSUBGROUP_ID
LEFT JOIN CORPORATE C
ON C.CORPORATE_ID = PB.CORPORATE_ID
LEFT JOIN EMPLOYEE E
ON E.EMPLOYEE_ID = PB.EMPLOYEE_ID
LEFT JOIN AFFILIATEMEMBER AF
ON AF.AFFILIATEMEMBER_ID = PB.AFFILIATEMEMBER_ID
LEFT JOIN MEMBER M
ON M.MEMBER_ID = PB.MEMBER_ID
WHERE TY.ISDEBIT = 1 AND PB.FLAG = 0 AND T.ISROOMNO = 2
AND (P_TRANSACTIONMONTH IS NULL
OR P_TRANSACTIONMONTH =
TO_CHAR (PB.BILLDATE, 'fmMONTH-YYYY'))
AND (P_LEDGERID IS NULL
OR L.LEDGER_ID IN
( (SELECT COLUMN_VALUE
FROM TABLE(GET_ROWS_FROM_LIST1 (
P_LEDGERID,
GROUP BY L.DESCRIPTION,
LS.DESCRIPTION,
C.CORPORATENO
|| E.EMPLOYEENO
|| AF.AFFILIATEMEMBERNO
|| M.MEMBERNO,
C.NAME || E.NAME || AF.NAME || M.NAME,
L.PRINTNO
UNION ALL
-- Guest Registration
SELECT L.DESCRIPTION LEDGERNAME,
LS.DESCRIPTION LEDGERSUBGROUPNAME,
C.CORPORATENO
|| E.EMPLOYEENO
|| AF.AFFILIATEMEMBERNO
|| M.MEMBERNO
AS ID,
C.NAME || E.NAME || AF.NAME || M.NAME AS NAME,
SUM(CASE
WHEN PB.EMPLOYEE_ID IS NULL
AND T.ISCREDITTRANSACTIONMODE = 1
THEN
PB.BILLAMOUNT
ELSE
0
END)
MEMBERDEBITAMOUNT,
L.PRINTNO
FROM GUESTREGISTRATION PB
INNER JOIN GUESTREGISTRATIONDETAIL PD
ON PB.GUESTREGISTRATION_ID = PD.GUESTREGISTRATION_ID
INNER JOIN TRANSACTIONTYPE TY
ON TY.TRANSACTIONTYPE_ID = PB.TRANSACTIONTYPE_ID
INNER JOIN TRANSACTIONMODE T
ON T.TRANSACTIONMODE_ID = PB.TRANSACTIONMODE_ID
INNER JOIN LEDGER L
ON L.LEDGER_ID = PD.LEDGER_ID
INNER JOIN LEDGERSUBGROUP LS
ON LS.LEDGERSUBGROUP_ID = L.LEDGERSUBGROUP_ID
LEFT JOIN CORPORATE C
ON C.CORPORATE_ID = PB.CORPORATE_ID
LEFT JOIN EMPLOYEE E
ON E.EMPLOYEE_ID = PB.EMPLOYEE_ID
LEFT JOIN AFFILIATEMEMBER AF
ON AF.AFFILIATEMEMBER_ID = PB.AFFILIATEMEMBER_ID
LEFT JOIN MEMBER M
ON M.MEMBER_ID = PB.MEMBER_ID
WHERE TY.ISDEBIT = 1 AND PB.FLAG = 0 AND T.ISROOMNO = 2
AND (P_TRANSACTIONMONTH IS NULL
OR P_TRANSACTIONMONTH =
TO_CHAR (PB.BILLDATE, 'fmMONTH-YYYY'))
AND (P_LEDGERID IS NULL
OR L.LEDGER_ID IN
( (SELECT COLUMN_VALUE
FROM TABLE(GET_ROWS_FROM_LIST1 (
P_LEDGERID,
GROUP BY L.DESCRIPTION,
LS.DESCRIPTION,
C.CORPORATENO
|| E.EMPLOYEENO
|| AF.AFFILIATEMEMBERNO
|| M.MEMBERNO,
C.NAME || E.NAME || AF.NAME || M.NAME,
L.PRINTNO)
ORDER BY PRINTNO;
END SP_GRCS;
I have even tried adding L.Ledger_ID in select statement.

Returning recordset from stored procedures

Hi
I am trying to get a stored procedure to return multiple values (i.e. a recordset) and want to access them from JDBC. Is that possible?
Frankie =:>

You can return nested tables and varrays using JDBC. See chapter 10 of the Oracle JDBC Developer's Guide.
http://technet.oracle.com/doc/oracle8i_816/java.816/a81354/toc.htm

I can't access email from my iPhone 3gs since changing email password

Hi all,
iPhone 3s 16GB
iOS version: 6.1.3
ISP Bigpond Cable
I can't access my email from my iPhone 3GS.
This is an iPhone problem, not an ISP problem.
I know this because I can access my email from both my laptop and webmail.
This is occurring here at home via my WiFi network and also a few kilometres away via 3G.
This morning I had to change the password on my Bigpond Cable internet email account.
Whenever I try to access email from my phone I receive the following error:
"Cannot Get Mail"
"The user name or password for "**** *****" is incorrect."
There are two buttons, one captioned Settings the other OK.
Both the user name and password are correct. This happened perhaps 4 or 5 times in the 6+ years I was with Internode and has happened a couple of times in the 20 months that I've been on Bigpond Cable.
I have re-entered my email account and connection details multiple times to no avail.
I have tried deleting the account, then rebooting my phone and creating a new account, but that didn't work.
I tried deleting the account, turning the phone completely off, waiting one minute and then after turning it back on, creating a new account but that didn't work.
I know I am entering the correct settings because before I deleted the account the first time, I took a series of screen captures from the Settings App and I also have the settings from MS Outlook to refer to.
Its as though somewhere in the phone, the old email password is being stored and being used instead of the new one, but I don't know where that could be except in the Settings app, "Mail, Contacts, Calendars" and that is where I am entering the new password.
The only solutions to this problem I found by searching are those that I have already tried and haven't worked for me.
Reverting to the old password is not an option. My account was compromised by Malware, hence the password change and a complete scan of my laptop.
Any ideas?

The problem was resolved by erasing the entire contents of my phone and then restoring it, setting it up as a new phone.

Accessing ALL_TAB_COLUMNS from a Procedure

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