Add site column with ID via Powershell

Hi,
Could somebody please help me with this. I want to create a site column using PS script where i can give the display name, internal name, Field ID etc.
Giving Field ID is important for me. Thanks.
-Prashant

Hi,
It seems like I was writing the correct script but I think i have some different problem.
Scenario:
In my old SP2010 environment, one list template was created using feature (via declarative XML). This list template has two custom columns which were also created via feature. Now in so many site collections users have used that list template to create the
list instances.
In SP2013 environment, I do not have these features installed in the farm and without these customizations installed in SP2013 environment I have upgraded some sites. Now all those list instances which were created using custom list template type are not
opening at all since the feature which was used for creating the list template is missing in this new SP 2013 environment.
So is there any way to fix this problem without installing the features in new environment? I thought if i will add those two site columns again via PS script, it may work but i think its failing because of whole list schema.
-Prashant

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How can I update a Site Column with the content of an array with javascript CSOM?

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console.log(select);
getSiteColumns(select);
}), 'SP.js');
var fieldChoice;
var choices;
var addFields = [];
var slc;
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clientContext = SP.ClientContext.get_current();
if (clientContext != undefined && clientContext != null) {
var web = clientContext.get_web();
fieldChoice = clientContext.castTo(web.get_availableFields().getByTitle(selection), SP.FieldChoice);
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My problem is on the function addItemsToColumns() please help! Thanks in advance.

Let's look at your stylesheet -
<style type="text/css">
body {
background-image: url(assets/images/Business%20Men%20In%20Reception%20Col.2.jpg);
background-repeat: no-repeat;
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margin-right:auto;
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It's a good idea not to use spaces or any punctuation in your filenames when working for the web.
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margin-left:auto;
margin-right:auto;
position: relative;
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font-variant: normal;
margin-left:auto;
margin-right:auto;
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Hello,
Can somebody please suggest me how I can create custom content type with site columns with custom validation to site columns programmatically?
Thanks,
Praveen Kumar Padmakaran

Hi,
From your description, my understanding is that you want to create content type with site column with validation.
You could create a site column, and add some validation to the site column. After you could create a custom content type, please add the site column with validation to the content type. Please refer
to this code below:
static void Main(string[] args)
// replace your url
using (SPSite site = new SPSite("http://sp/sites/sp2013"))
using (SPWeb web = site.OpenWeb())
//define the type of the field
SPFieldType type = SPFieldType.Number;
// create a site column
SPField field = CreateSiteColumn(web, "newTest", type, "");
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fieldNumber.ValidationFormula = "=[newTest]>5";
fieldNumber.ValidationMessage = ">5";
fieldNumber.Update();
SPContentTypeId parentItemCTypeId = web.ContentTypes[0].Id;
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SPContentType contentType = CreateSiteContentType(web, "newContent", parentItemCTypeId, "Custom Content Types");
// add the site column to the content type
AddFieldToContentType(web, contentType, field);
// add fiedl to contenttype
public static void AddFieldToContentType(SPWeb web, SPContentType contentType, SPField field)
if (contentType == null) return;
if (contentType.Fields.ContainsField(field.Title)) return;
SPFieldLink fieldLink = new SPFieldLink(field);
contentType.FieldLinks.Add(fieldLink);
contentType.Update();
// create a custom content type
public static SPContentType CreateSiteContentType(SPWeb web, string contentTypeName,SPContentTypeId parentItemCTypeId, string group)
if (web.AvailableContentTypes[contentTypeName] == null)
SPContentType itemCType = web.AvailableContentTypes[parentItemCTypeId];
SPContentType contentType =
new SPContentType(itemCType, web.ContentTypes, contentTypeName) { Group = @group };
web.ContentTypes.Add(contentType);
contentType.Update();
return contentType;
return web.ContentTypes[contentTypeName];
// create a site column
public static SPField CreateSiteColumn(SPWeb web, string displayName,SPFieldType fieldType, string groupDescriptor)
if (!web.Fields.ContainsField(displayName))
string fieldName = web.Fields.Add(displayName, fieldType, false);
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field.Group = groupDescriptor;
field.Update();
return field;
return web.Fields[displayName];
You could refer to these articles:
C# code to create Site Column, Content Type, and add fields to Content Type
http://spshare.blogspot.jp/2013/10/c-code-to-create-site-column-content.html
How to do custom validation for site column in SharePoint
http://www.c-sharpcorner.com/uploadfile/anavijai/how-to-do-custom-validation-for-site-column-in-sharepoint/
Best Regards,
Vincent Han
TechNet Community Support
Please remember to mark the replies as answers if they help, and unmark the answers if they provide no help. If you have feedback for TechNet Support, contact
[email protected].

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2. ShowInNewForm - False
3. ShowInDisplayForm - True
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Try this
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Feature1 icon in Solution Explorer to modify the Feature ’ s
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< Elements xmlns="http://schemas.microsoft.com/sharepoint/" >
< Field ID="{76C140E1-D827-433B-AD38-257F9594B846}"
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< Field ID="{5F516D92-969C-4661-81B9-C9210E2A2FDC}"
Name="Choice Type"
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Group="Custom group"
Type="Choice"
Required="FALSE" >
< CHOICES >
< CHOICE > Medical < /CHOICE >
< CHOICE > Dental < /CHOICE >
< CHOICE > Vision < /CHOICE >
< CHOICE > Insurance < /CHOICE >
< /CHOICES >
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Column with header data value

Hi All.
I have a control file which i need to add a column with header data value.
example
data file:
123456;201303
santiago;producto1;100
santiago;producto2;200
valparais;producto1;400
valparais;producto3;900
The control file skip the first column and load the three columns on the table, but, now i need to add other column with 201303 value constant of the first record and load it on the table.
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santiago producto1 100 201303
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valparais producto1 400 201303
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Regards!

SCOTT@orcl_11gR2> host type test.dat
123456;201303
santiago;producto1;100
santiago;producto2;200
valparais;producto1;400
valparais;producto3;900
SCOTT@orcl_11gR2> host type test1.ctl
options (load=1)
load data
infile test.dat
replace
into table onecol_onerow
fields terminated by ';'
trailing nullcols
(filler1 filler, newcol)
SCOTT@orcl_11gR2> host type test2.ctl
options (skip=1)
load data
infile test.dat
append
into table test_tab
fields terminated by ';'
trailing nullcols
(col1, col2, col3,
newcol expression "(select newcol from onecol_onerow)")
SCOTT@orcl_11gR2> create table onecol_onerow
2    (newcol number)
3 /
Table created.
SCOTT@orcl_11gR2> create table test_tab
2    (col1   varchar2(15),
3     col2   varchar2(15),
4     col3   number,
5     newcol number)
6 /
Table created.
SCOTT@orcl_11gR2> host sqlldr scott/tiger control=test1.ctl log=test1.log
SQL*Loader: Release 11.2.0.1.0 - Production on Mon May 6 10:46:44 2013
Copyright (c) 1982, 2009, Oracle and/or its affiliates. All rights reserved.
Commit point reached - logical record count 1
SCOTT@orcl_11gR2> select * from onecol_onerow
2 /
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    201303
1 row selected.
SCOTT@orcl_11gR2> host sqlldr scott/tiger control=test2.ctl log=test2.log
SQL*Loader: Release 11.2.0.1.0 - Production on Mon May 6 10:46:45 2013
Copyright (c) 1982, 2009, Oracle and/or its affiliates. All rights reserved.
Commit point reached - logical record count 4
SCOTT@orcl_11gR2> select * from test_tab
2 /
COL1            COL2                  COL3     NEWCOL
santiago        producto1              100     201303
santiago        producto2              200     201303
valparais       producto1              400     201303
valparais       producto3              900     201303
4 rows selected.

Add site column with ID via Powershell

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