Adding of two files occurances

Hi ,
I am adding two files to one and sending to receiver in this if I get N as occurance of file1 and M as occurance of file2 then I need to get N+M occurance for received file
for exaple if I have 2 occurance and file 1 and 3 occurance for file 2 at this time I need to get 5 as occurance for receiver file
for this please guid how to achive this logic
regards
Krishna

Hi,
Since in your case there are 2 source files coming, so you need to use a BPM with 2 receivers for the 2 source files, one each in one of the branches of a fork, i.e you need a fork step with 2 branches. Then after the fork step , you need to insert a transformation step where you have to do the required message mapping.
After the message mapping, insert a send step which will send the output of the message mapping to the intended receiver.
In the message mapping, you need to have 2 source structures for the 2 source files i.e. there should be 2 source message types in the message mapping. Then you need to use the count node function for both the source messages to count the number of occurrences of the parent node in each of them, and then use the add node function to count the total number of occurrences of the target node and map this to the target side's parent node.
After that, simple map the child node of both the source structures directly to the child node in the target side.
MT1
<Node1>
<child1>
MT_TARGET
                                                     <NODE>
                                                       <child>
                                                                                MT2
<Node2>
        <child2>
Map both <child1> and <child2>   with the same child as shown above for <child1> of MT1 of source
That's it. Hope this helps you
Thanks
Biswajit
Edited by: 007biswa on Feb 14, 2011 12:16 PM
Edited by: 007biswa on Feb 14, 2011 12:17 PM

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