Adding two special double numbers

Adding two double numbers.
say, 12543.34 and 42895.00 am getting in the decimal part .3999999.
Now I want .34 instead .399999 and how??
Can any body help me ??

Read this (or search the forums--this question is asked at least once a day):
http://docs.sun.com/source/806-3568/ncg_goldberg.html

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Adding two random generated numbers together?

I'm writing a program for a class in which we have to simulate a two die rolling. So I got the computer to generate to random numbers, and now I need to add them to get the rolled die's sum. This info will then be organized into a chart. But I have no idea how to add to randomly generted numbers together, can anybody help me??
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import java.util.Scanner;
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You can't call the variable "final" as that's a Java keyword. Try something like "sum" or "total".
(Also consider just using a single Random object and calling it twice to obtain the value for each of the dice.. And don't (cast) for the fun of it or as a talisman to ward off compiler messages.)

Adding two double numbers is a problem

Hi friends..
when we try to add the two double numbers say,
119.52, 10.00
here we should get 129.52
but it is giving as 129.51999999999998
Here i want to round this to two digits after decimal point
if i round the above value i will get 129.52 and the problem will be solved.
But we don't know exactly on what basis we are getting the sum as 129.51999999999998.
Assume that, tomorrow when we are adding some other numbers we may got like
129.51444444444448
when we round this we get 129.51
but actually we have to get 129.52.
If anyone know why the system is giving that wrong sum amount, please give solution to avoid this.
To solve this problem, i tried by converting the double numbers to integers and adding these integers and finally converting the sum into double...like
if
d1= 119.52
d2=10
int x = (int)(119.52*100.00);
int y = (int)(10.00*100.00);
int z = x + y;
double d = (double)(z)/100;
This is working for this case...
But when we are applying this approch to other numbers it is giving problem....
i.e, if i convert like below
int x = (int)(72.46*100.00);
this should give x=7246
but it is giving x=7245
What is the solution for this problem...please give immediate reply.....

Assume that, tomorrow when we are adding some other
numbers we may got like129.51444444444448
That isn't going to happen. The numerical computations are deterministic. The problem lies in your understanding of how numbers work.
This has been repeated before so if you want more detail I suggest you search the forums for discussion on precision and double.
Computers store numbers in binary. The number you are trying to represent is a decimal number. This produces an error in precision.
The same problem exists in decimal notation. Decimal notation can not accurately represent one divided by three (in decimal 0.33333333.....).

Problme while adding double numbers.

Hi,
I am trying to get a series of double numbers by adding some constant value to a double number.
so when i try to add .01 to 10.04 i am getting the result as 10.0499999.. instead of 10.05
is there any work around for this problem.
Thanks

Can Someone tell me please what is going on?
Trying to add simple double numbers but the result is really surprising.
double postage = 0.72 ;
double total = 0.18;
double totalamt = postage + total;
System.out.println(totalamt);
Result: 0.8999999999999999 INSTEAD OF 0.9

Problem with the addition of double numbers

when we try to add the two double numbers say,
119.52, 10.00
here we should get 129.52
but it is giving as 129.51999999999998
This is happening only for sum numbers.
Here i want to round this to two digits after decimal point
if i round the above value i will get 129.52 and the problem will be solved.
But we don't know exactly on what basis we are getting the sum as 129.51999999999998.
Assume that, tomorrow when we are adding some other numbers we may got like
129.51444444444448
when we round this we get 129.51
but actually we have to get 129.52.
If anyone know why the system is giving that wrong sum , please give solution to avoid this.
In My application , i want the exact sum amount so if i add some numbers i should get exact sum.
like 119.52+10=129.52
i want exactly this. How to get this.

As another poster said, this is a topic worth reading up on, as there are subtleties involved in this kind of imprecise math. A couple of points to get you started though...
* Java's double type has a precision of something like 16 (20? 24?) decimal places. (You should be able to find the correct number in the lang. spec., or someone may be kind enough to post it here.) I don't remember the formal definition, but what this means, approximately, is that any number that can be represented will be accurate to within +/-0.5*10^-16 of its value. That is, if the actual value is 2e5, then the absolute value of the error in the representation will be less than 0.5e-11. (I might be off be a factor of 2 and/or an order of magnitude here, but you get the general idea.) The good news is, no value will be in error by more than that amount. The bad news is, any value could be in error by up to that amount. These are the two key points.
* Compare the precision implicit in your data and needed in your results to that of Java, along with the number of intermediate calculations you'll do to get a final result. For instance, if you're doing financial calcs in the tens of billions of dollars, and you need accuracy to the penny, that's one part in 10^-12. Assuming any given value is off by no more than one part in 10^-16, and assuming all errors are in the same direction, if you do 10^4 cumulative additions, you'll be off by a penny. Again, these are rough, and I may have missed something, but this is the kind of thing to look at to determine how the inherent imprecision will affect you.
* Don't round any intermediate results. Keep the precision you have. However, when you're comparing (as jschell demonstrated) make a copy of the value and round that copy before doing the comparison. Use the first two points above to determine whether that rounding will meet your needs for precision. Same goes for displaying.
* Finally, if the 10^-16 (or whatever it was) precision of a double is not sufficient, you can get arbitrary precision with BigDecimal. There are a couple of caveats, however. 1) It's a lot slower than using primitives ans 2) Arbitrary precision does not mean infinite precision. You can specify as many decimal places as you want (subject to time and memory constraints), but you even if you specify 1,000 decimal places, you can still be off by 5 in the 1001st place.

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Boolean double is in range of two other doubles.

First, I apologize if this is in wrong forum, seems I can never decide which forum I should ask my questions in and I get jumped on, so if this is wrong I am sorry.
I have been searching every where for a boolean range checker to tell me if a user input (double) is in between two double numbers. Where can I find something on how to do this? Searches I have done have turned up nothing. I do not want someone to do it for me, I want to learn.
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Adding two special double numbers

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