Applet parsing XML doc with schema

I'm trying to parse (org.apache.xerces.parsers.SAXParser) an xml document and validate it with a schema file. I'm having a little difficulty understanding how the schemaLocation (as specified in the xml file) is used by the parser. I'm trying to use a relative path....but what is it relative to???
In the xml file I specify the schemaLocation as...
xsi:schemaLocation="http://tempuri.org/DeviceDefinition.xsd ./Configuration/DeviceDefinition.xsd"
The directory structure I'm using is...
ProjectX/applet.jar
ProjectX/applet.html
ProjectX/Configuration/DeviceDefinition.xml
ProjextX/Configuration/DeviceDefinition.xsd
It's my understanding that when working with an applet the paths are a relative to the directory where the applet is installed - ProjectX in this case. Yet when I use the above defined schemaLocation I get the following error:
[Fatal Error] :0:0: File "file:///C:/Documents and Settings/dnelson/Desktop/Configuration/DeviceDefinition.xsd" not found.
It seem to be using my user.dir as a starting point for the relative path. Does anyone know why this happens???
What's the proper way to specify the schemaLocation??

xerces hates spaces in uri. so try encoding the url or get rid of the spaces

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Has anybody tried creating and validating a XML doc with XML Schema?

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Still problems serializing xml-docs with xml-parser for java v2.0.2.7

Hi !
I'm using the Oracle XML Parser 2.0.2.7.0 and get some problems when serializing the XMLDocument.
In one class (DOMOut) I parse a xml-file with the oracle.xml.parser.v2.DOMParser, then obtain the XMLDocument and write it to System.out
In another class (DOMIn) I fetch the XMLDocument from System.in, search for a given Element and print it's TextValue (if existing) to System.out
That is where the error occurs.
I get the XMLDocument from System.in but the returning NodeList from doc.getElementsByTagName() is empty. [nl.getLength()==0] even if it shouldn't be.
Look at this code and output:
[DOMOut]
DOMParser parser = new DOMParser();
parser.parse(url);
XMLDocument doc = (XMLDocument)parser.getDocument();
ObjectOutputStream out = new ObjectOutputStream(System.out);
out.writeObject(doc); out.flush();
[DOMIn]
ObjectInputStream in = new ObjectInputStream(System.in);
XMLDocument doc = (XMLDocument)in.readObject();
doc.print(System.out);
NodeList nl = doc.getElementsByTagName("Name");
System.out.println("Length of NodeList: "+nl.getLength());
if (nl.getLength()==0)
System.out.println(argv[0] + ": not in this document!");
else {
XMLNode node = (XMLNode) nl.item(nl.getLength()-1);
System.out.println(node.getNodeName() + ": " + (node.getFirstChild()).getNodeValue());
This is the relevant code.
I javac both classes and then do this:
java DOMOut xmltestfile.xml > xx
java DOMIn Name < xx
And get this as output:
<?xml version = '1.0'?>
<!DOCTYPE course [
<!ELEMENT course (Name,Dept,Instructor,Student)>
<!ELEMENT Name ((#PCDATA)*)*>
<!ELEMENT Dept ((#PCDATA)*)*>
<!ELEMENT Instructor (Name)>
<!ELEMENT Student (Name)*>
]>
<course>
<Name>Calculus</Name>
<Dept>Math</Dept>
<Instructor>
<Name>Jim Green</Name>
</Instructor>
<Student>
<Name>Jack</Name>
<Name>Mary</Name>
<Name>Paul</Name>
</Student>
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Length of NodeList: 0
Name: not in this document!
Has anyone an idea?
If I do all this stuff without serializing it works.
If I do not search for argv[0], but the string "Name" it fails.
If I do search for "*" it works fine!
I'm very confused could anybody please help me a bit??
Stefan.
[[email protected]]

The link has been fixed. You will go to the v2 download page
now. Sorry for the inconvience.
Oracle XML Team
http://technet.oracle.com
Oracle Technology Network
Renilton Oliveira (guest) wrote:
: I didn't find the file for version 2.0.0.0 as well.
: Renilton
: Andrei Filimonov (guest) wrote:
: : I tried to download XML Parser for Java v2 it seems that
only
: v
: : 1.0.1.4 is available. Could you please give an exact URL for
: v2
: : download?
: : Andrei Filimonov
: : Oracle XML Team wrote:
: : : The Oracle XML v2 parser is now available for download
here
: as
: : : an early beta release and is written in Java. It features
: an
: : : improved architecture over the Oracle XML v1 parser and
has
: : : shown better performance on small to large XML documents.
: It
: : : will also be able to format the XML document according to
a
: : : stylesheet, having integrated an XSLT processor.
: : : Version 2 of the XML Parser for Java, besides
incorporating
: an
: : : XSLT processor, has been re-architected from version 1.
This
: : has
: : : resulted in a number of changes to the class names
: especially
: : : those that support Namespaces. See v2changes.txt and
: the .diff
: : : difference files in the sample directory.
: : : Oracle XML Team
: : : http://technet.oracle.com
: : : Oracle Technology Network
null

Validating xml doc using schema

I was wondering if you can the following validation of an xml document using schema:
<parent>
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<parent>the childcountValue equals the number of child node. is this possible using
schema or do do i have to use an application to do this?
thanx in advance

thanx dvohra, but i already know how to validate schema using a parser.
I'm looking for a way in the schema that specified thhat the total number of child elemnt equals to the integer value of the childTotal element. I don't even know if this is possible. If possible, what (tag) would i use. i don't need answer..hint would be nice.
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Problems using XML DB with Schema

Hi,
I am attempting to use Java code running on WebLogic Server 10.3 to insert some XML documents into an Oracle Database (11gr1) and have them ‘shredded’ into columns, as the documentation claims is possible.
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I am able to insert records into the table, using XMLType, but they do not appear to be shredded in such a way that we can perform relational queries on them. References I found on the Oracle web site and others implied that if the XMLType is created with a schema associated, the insert will perform the shredding.
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-=Alan
--- Version of Oracle and validating that the schema is registered.
Connected to:
Oracle Database 11g Enterprise Edition Release 11.1.0.6.0 - Production
With the Partitioning, OLAP, Data Mining and Real Application Testing options
SQL> describe objecthandle;
Name Null? Type
TABLE of SYS.XMLTYPE(XMLSchema "http://foo.org/mySchema" Element "ObjectHandle") STORAGE Object-relational TYPE
"OBJECTHANDLE_TYPE"
--- The XML document I am trying to persist.
<ObjectHandle objectuid="objecthandle_301" serviceURL="URL-Fri Oct 31 17:47:19 EDT 2008" xmlns="http://foo.org/mySchema"/>
--- The most recent error with full stack trace.
java.sql.SQLException: Fail to convert to internal representation
at oracle.jdbc.driver.SQLStateMapping.newSQLException(SQLStateMapping.java:70)
at oracle.jdbc.driver.DatabaseError.newSQLException(DatabaseError.java:112)
at oracle.jdbc.driver.DatabaseError.throwSqlException(DatabaseError.java:173)
at oracle.jdbc.driver.DatabaseError.throwSqlException(DatabaseError.java:229)
at oracle.jdbc.driver.DatabaseError.throwSqlException(DatabaseError.java:403)
at oracle.sql.OPAQUE.<init>(OPAQUE.java:85)
at oracle.xdb.XMLType.toDatum(XMLType.java:492)
at oracle.jdbc.driver.OraclePreparedStatement.setORADataInternal(OraclePreparedStatement.java:7437)
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Thanks - I have been fighting with another problem for the past few days, but am getting back to this now...
I think the second link you sent helped me realize that the particular error came while using the 'thin' driver; I had other problems when I used the OCI driver... I'll try it again and see, now that I'm using a container managed datasource...
I registered the schema in SQL*Plus using the command:
BEGIN
DBMS_XMLSCHEMA.registerURI(
'http://foo.org/mySchema',
'/home/foo/mySchema.xsd',
LOCAL=>TRUE, GENTYPES=>TRUE, GENBEAN=>FALSE, GENTABLES=>TRUE);
END;
Everything created, was created from that command. I did use xdb annotations, but perhaps I didn't use enough of them...
In this simple example (I have more complicated ones) there are only the two attributes; I've been hoping that I would be able to use normal sql statements, e.g.
SELECT * FROM objecthandle WHERE objectuid='objecthandle_301';
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I don't see why you couldn't do that. Bear in mind that you have no idea how long the parsing is going to take, so you couldn't use a progress bar of the kind that says "30% complete... 31% complete...". You would have to use what the API docs for JProgressBar call "indeterminate mode".
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How to parse XML file with namesapce?

Hi,
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Sample Code:
public class XMLFileLoader
var xml:XML = new XML();
var myXML:XML = new XML();
var XML_URL:String = "file:///C:/Documents and Settings/Administrator/Desktop/MyData.xml";
var myLoader:URLLoader = null;
public function XMLFileLoader()
var myXMLURL:URLRequest = new URLRequest(XML_URL);
myLoader= new URLLoader(myXMLURL);
myLoader.addEventListener(Event.COMPLETE,download);
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var ns:Namespace=myXML.namespace("xsi");
for(var prop:String in myXML)
     trace(prop);
//Alert.show(myXML..Parameters);
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The XML Contains the following format.
<Network xmlns="http://www.test.com/2005/test/omc/conf"
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        <Parameters ParameterName="ne_release" OutageType="None"
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</TestDomain>
</Network>
Any sample code how to parse this kind of xml file with namespaces...
Regards,
Purushotham

i have exactly the same problem with KXml2, but using a j2me-polish netbeans project.
i've tried to work around with similar ways like you, but none of them worked. now i've spent 3 days for solving this problem, i'm a bit disappointed :( what is wrong with setting the downloaded kxml2 jar path in libraries&resources?
screenshot

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tempNode XMLDOM.DOMNode;
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Updatexml is reference in Oracle 9i, I'm sorry i should have mentioned that I am using oracle 8i. Is there something you can use in oracle 8i?

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<employee>
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<employeename>Dave</employeename>
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So, what are my options?
All I want to know is, what should I change in the .xsd in order to compose this XML in the structure that I want.
It groups all the employee names (<employeename> tag) under one <employee> tag, instead I want to have individual <employee> tags for each and every <employeename> tags (<employee> tag around <employeename> tag for each and every employee)
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Is it possible to create indexes & use them on xml docs with namespaces?

I have put an XML doc in a BDBXML container which looks like this:
*<ns1:note xmlns:ns1="http://www.testsch.org/ns">*
*<ns1:to>Eric</ns1:to>*
*<ns1:from>Brendan</ns1:from>*
*<ns1:msg>How r u?</ns1:msg>*
*</ns1:note>*
Now, I am creating an index on the element "to", as:
addIndex "ns1" "to" node-element-equality-string
Though the index has been shown as getting created using the listIndexes command, if I lookup that index with the following command:
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*0 objects returned for eager index lookup 'node-element-equality-string'*
Whereas, if I do the whole procedure without the namespaces in the document & the commands, the result is fine:
*1 object returned for eager index lookup 'node-element-equality-string'*
Can someone please tell me whether using namespaces, the indexes can be created or not? If yes, how?
Thanks,
Dev
Edited by: user11871332 on Sep 7, 2009 3:53 PM

Hi Dev,
When using XML, the prefix for the namespace is really just syntactic sugar. The actual namespace in your example is "http://www.testsch.org/ns", and that's the value that you need to use when creating your index:
addIndex "http://www.testsch.org/ns" "to" node-element-equality-stringJohn

Create XML docs with hierarchy of tags and attr defined in databaste tables

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Almost all the Oracle XML utilities I read about, create XML docs based on a SQL query with tag names being columns in the database tables. Any help will be highly appreciated.
Thanks,
Monika

Which database release are you using...
The computed constructors feature of XQuery may help.
-Mark

Parsing XML file with different languages (Xerces)

How do we code or program to an XML file with different
languages , say english and spanish. WHen we parse such a document with the default locale , the presence of special characters throws errors .For eg when I use xerces and use
DOMParser parser = new DOMParser();
try
// Parse the XML Document
parser.parse(xmlFile);
catch (SAXException se)
se.printStackTrace();
org.xml.sax.SAXParseException: An invalid XML character (Unicode: 0xfc) was found in the element content of the document.
System Error: void org.apache.xerces.framework.XMLParser.parse(org.xml.sax.InputSource)
So what locale do we set before we parse ?How to handle this problem

You need an encoding attribute in the xml declaration. If you don't, the parser assumes UTF-8, which are ASCII characters up to 127 - useful (only) for English.
So, something like this would allow you to use characters above 127, ISO-8859-1 is the encoding used by standard PCs.
<?xml version="1.0" encoding="ISO-8859-1"?>
You can find a (offical) list of encodings at:
http://www.iana.org/assignments/character-sets
I'm not sure about mixing various encodings. I think you have to resort external parsed entities, which can have their own encoding, but I think you cannot mix encodings in one XML file.
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Applet parsing XML doc with schema

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