ARRAYLIST comarision failing.

Question

Hi,
I am expecting wen arraylist is null any of the cases then then other arraylist sud come in noMatchList.
but now its is coming blank[].can u figure it out and solve..
import java.util.ArrayList;
import java.util.LinkedHashMap;
import java.util.List;
public class Demo3 {
public static void main(String[] args) {
ArrayList<String> al = new ArrayList<String>();
al.add("1");al.add("2");al.add("3");al.add("4");al.add("6");
ArrayList<String> a2 = new ArrayList<String>();
// a2.add("1");a2.add("6");//a2.add("3");a2.add("4");a2.add("6");
ArrayList<String> a3 = new ArrayList<String>();
//a3.add("1");a3.add("2");a3.add("33");a3.add("44");a3.add("5");
ArrayList<String> a4 = new ArrayList<String>();
a4.add("1");a4.add("2");a4.add("33");a4.add("44");a4.add("5");
ArrayList<String> a5 = new ArrayList<String>();
a5.add("1");a5.add("2");a5.add("33");a5.add("44");a5.add("5");
ArrayList<String> a6 = new ArrayList<String>();
a6.add("1");a6.add("2");a6.add("3300");a6.add("44");a6.add("500");
ArrayList<String> a8 = new ArrayList<String>();
a8.add("1");a8.add("2");a8.add("33");a8.add("44");a8.add("51231111");
ArrayList<String> a9 = new ArrayList<String>();
a9.add("1");a9.add("2");a9.add("33");a9.add("44");a9.add("51231111");
LinkedHashMap<String,ArrayList<String>> lhm = new LinkedHashMap<String,ArrayList<String>>();
lhm.put("rule1", al);lhm.put("rule2", a2);lhm.put("rule3", a3);
// lhm.put("rule4", a4);
// lhm.put("rule5", a5);
// lhm.put("rule6", a6); // lhm.put("rule9", a9);
// lhm.put("rule8", a8);
System.out.println("lhm value " + lhm);
StringBuilder match = new StringBuilder();
String[] a= new String[0];
a = lhm.keySet().toArray(a);
for(int i=0;i<a.length;i++){
for(int j = 0;j<a.length -1;j++){
if(j!= i){
ArrayList<String> x1 = lhm.get(a);
ArrayList<String> x2 = lhm.get(a[j]);
if(x1.containsAll(x2) && x2.containsAll(x1) && !(x1.isEmpty() || x2.isEmpty())){
if(!match.toString().contains(a[i])){
match.append(a[i]+",");
if(!match.toString().contains(a[j])){
match.append(a[j]+",");
match.append(":");
StringBuilder noMatch = new StringBuilder();
for(int i=0;i<a.length;i++){
for(int j = 0;j!= i &&j<a.length -1;j++){
ArrayList<String> x1 = lhm.get(a[i]);
ArrayList<String> x2 = lhm.get(a[j]);
if(!(x1.containsAll(x2) && x2.containsAll(x1))){
if(!(x1.isEmpty() || x2.isEmpty())){
if(!match.toString().contains(a[i]) && !noMatch.toString().contains(a[i])){
noMatch.append(a[i]+",");
if(!match.toString().contains(a[j]) && !noMatch.toString().contains(a[j])){
noMatch.append(a[j]+",");
//For Matched (Grouping done here)
List<List<String>> matchList = spitTheString(match.toString());
List<List<String>> noMatchList = spitTheString(noMatch.toString());
private static List<List<String>> spitTheString(String match){
String[] strings = match.toString().split(":");
List<List<String>> finalList = new ArrayList<List<String>>();
StringBuilder builder = null;
for(String string:strings){
String[] strings2 = string.split(",");
builder = new StringBuilder();
List<String> list = new ArrayList<String>();
for(int i = 0;i < strings2.length;i++){
if(strings2[i].length() != 0){
builder.append(strings2[i]);
if(i < strings2.length -1)
builder.append(",");
if(builder.length() != 0){
list.add(builder.toString());
finalList.add(list);
return finalList;

Answer 1

codingMonkey wrote:
Please use code tags when posting code. You can do this using the CODE button above the forum editor. Few people will bother to read unformatted code.This time I did bother to read the unformatted code, specifically to learn a new language. However I am not entirely sure what the language I learnt is called, so lets call it "non-english".
To the OP what exactly is the problem here? I have gone over your code and I notice a few things. Firstly you only add 3 ArrayList<String> into your map, one of which is non empty, the other two are empty. Secondly you have two sets of for loops, the first for loop appends matches, the second appends non matches. In both cases you will only add a match or a non match if in either situation both ArrayLists are non empty. Further more in the situation where 2/3 of your ArrayLists are empty, then no string will ever be built, because the conditional expression of empty in both cases is true > (!true) > false. This is why you have two empty StringBuilders if you even bothered to check.
Mel