AT end of... some issues in using them

Question

Hi ALL,
I am having a req where i have to calculate the no of empty bin for each 3 and 4 row combination.... and each combination will be moved to flat file.
so i tried to use AT end of ( field) ....
as below:
   loop at it_lagp into wa_lagp.
      move wa_lagp-lgnum to wa_final-lgnum.
       timestamp
      move wa_lagp-lgber to wa_final-lgber.
      move wa_lagp-lptyp to wa_final-lptyp.
      if wa_lagp-lgber is not INITIAL and wa_lagp-lptyp is INITIAL.
        at end of lgber.
          cnt = cnt + 1.
          move cnt to wa_final-count.
          append wa_final to it_final.
          clear : cnt.
        endat.
      ELSEIF wa_lagp-lgber is INITIAL and wa_lagp-lptyp is not INITIAL.
        at end of lptyp.
          cnt = cnt + 1.
          move cnt to wa_final-count.
          append wa_final to it_final.
          clear : cnt.
        endat.
      else.
        at end of lgber.
          at end of lptyp.
            cnt = cnt + 1.
            move cnt to wa_final-count.
            append wa_final to it_final.
            clear : cnt.
          endat.
        endat.
      endif.
    endloop.
The prblm is at the bolded ones... as we see 3rd row is having 0001 which ll not end so the statement is not working for me.. i want taht it should consider both 3rd(lgber) and 4th (lptyp) row... and count..
1     5051
2     5051     0001
3     5051     0001
4     5051     0001
5     5051     0001
6     5051     0001     E060
7     5051     0001     E075
8     5051     0001     E075
9     5051     0001     E090
10     5051     0001     E090
11     5051     0001     E090
12     5051     0001     E090
13     5051     0001     E090
14     5051     0001     E090

Answer 1

Hi,
     Write AT END on the last field ...
Ex: ITAB is an internal table with the given data ...
itab-a = '5051'.
append itab.
clear  itab.
itab-a = '5051'.
itab-b = '0001'.
append itab.
append itab.
append itab.
append itab.
clear  itab.
itab-a = '5051'.
itab-b = '0001'.
itab-c = 'E060'.
append itab.
clear  itab.
itab-a = '5051'.
itab-b = '0001'.
itab-c = 'E075'.
append itab.
append itab.
clear  itab.
itab-a = '5051'.
itab-b = '0001'.
itab-c = 'E090'.
append itab.
append itab.
append itab.
append itab.
append itab.
append itab.
clear  itab.
*loop thru itab as ....
loop at itab.
  v_count = v_count + 1.
  at end of c.
    read table itab index sy-tabix.
    itab-d = v_count.
    modify itab index sy-tabix.  <-- pass the values to another internal table
    clear v_count.
  endat.
endloop.
loop at itab.
    write :/1 itab-a,
            10 itab-b,
            20 itab-c,
            30 itab-d.
endloop.
output from the above:
5051                                 1
5051     0001
5051     0001
5051     0001
5051     0001                        4
5051     0001      E060              1
5051     0001      E075
5051     0001      E075              2
5051     0001      E090
5051     0001      E090
5051     0001      E090
5051     0001      E090
5051     0001      E090
5051     0001      E090              6
Regards,
Srini.