Attendance Report Select Statement Help

Question

Hello , 
i am working on the a Report for Attendance , for each employee , i want to show the report for a Date Range , i want to show 
all days even if he is absent , the table structure for getting the attendance is just one Table , where i take the min time and max time for the employee 
i want to show it as the below : 
Date    Time In     Time Out 
1-1     7:45            16:00 
1-2     7:05            16:48 
1-3     Null      Null 
1-4     8:00            14:00 
i have created a table TCalendar with all Dates and want to join it with the Transactions Table 
Select UserID ,FirstName + ' ' + LastName as [Employee Name],  Convert(Varchar,min(OccurDateTime),108) as MinDate, Convert(Varchar,max(OccurDateTime),108) as maxDate
  , Department , Rank , Cast(ISNull(Datediff(mi,min(OccurDateTime),max(OccurDateTime)),'') as Decimal(4,0)) / 60 as [Total Hours] , DATENAME(DW,max(OccurDateTime))+ ' ' +  CONVERT(varchar, Record_Day, 106) as Date
from
  TTransactionLog1 T Full Outer Join TCalendar C On C.Record_Day = T.OccurDateTime
  where OccurDateTime between '2015-01-01' and '2015-01-06' and UserID <> '' and UserID = 'AKHG1030'
group by CONVERT(varchar, OccurDateTime, 106), UserID , FirstName , LastName , Department , Rank 
The Results currently show like this 
UserID Employee Name
MinDate maxDate
        Total Hours
Date
AKHG1030 Osama Ashraf
07:44:37 12:27:07
4.716666
NULL
AKHG1030 Osama Ashraf
11:08:18 15:49:12
4.683333
NULL
AKHG1030 Osama Ashraf
07:43:00 15:31:30
7.800000
NULL
AKHG1030 Osama Ashraf
07:27:35 18:56:22
11.483333
NUL
need your Help 

Answer 1

I think this is what you're aiming for:
DECLARE @transactions TABLE (ID INT IDENTITY, empID INT, datetime DATETIME)
INSERT INTO @transactions (empID, datetime)
VALUES (1, '2015-01-01 07:44:37'),(1, '2015-01-01 12:27:07'),(1, '2015-01-02 11:08:18'),(1, '2015-01-02 15:49:12'),(1, '2015-01-03 07:43:00'),(1, '2015-01-03 15:31:30'),(1, '2015-01-05 07:27:35'),(1, '2015-01-05 18:56:22')
DECLARE @employees TABLE (ID INT, firstName VARCHAR(30), lastName VARCHAR(30), userID VARCHAR(8))
INSERT INTO @employees (ID, firstName, lastName, userID)
VALUES (1, 'Osama', 'Ashraf', 'AKHG1030')
SELECT c.today, e.ID, MIN(datetime) AS inTime, MAX(datetime) AS outTime, DATEDIFF(MINUTE,MIN(datetime),MAX(datetime))/60.0 AS hours
FROM toolbox.dbo.calendar c
FULL JOIN @employees e
on e.id = e.id
LEFT OUTER JOIN @transactions t
ON c.today = CAST(t.datetime AS DATE)
WHERE c.today BETWEEN '2015-01-01' AND '2015-01-05'
GROUP BY c.today, e.ID
ORDER BY c.today
I created mock ups of a transactions table which holds the transactions data, and an employee ID column and an employee table which holds employee data.
I am using my calendar table/functions which you can read about here:
http://social.technet.microsoft.com/wiki/contents/articles/29260.tsql-calendar-functions-and-tables.aspx.
We full joined the employee table (creating a cartesian product between the date and all employees) so we always show every employee for every date. Then, we left outer join the transaction table to find the records for that date. We aggregate the min and
max, and use them in a date add to find the total number of hours between them. I'ved used minutes and devided by 60.0 (to force the decimal) to give partial hours.
hth.