Average Pay Days

Hi Experts,
I need a keyfig "Avg. Pay Days" which is a formula of avg(Days w/o payment) for FI-AP report in BI, which gets data from FBL1N report in r/3.
Avg. Pay Days = avg(Days w/o payment)
Can anyone pls help me how to get the above value of count of days.
Is there any r/3 field which gets the data for Days w/o payment?
Thanks in advance.
Sai Chand.S

Hi Adriana,
Here is a way to automatically update the Average Delay field on the BP Master Data under the Payment Terms tab. If you install this storproc it will make it very easy to report on the Average Days to Pay since it will simply be OCRD.AvrageLate without having to do any subqueries or anything.
Here is the link: [http://www.tellme747.com/?p=312]
It doesn't filter for the 6 months or the COD scenarios but it is very simple to do.
Let me know if you need any further assistance,
Mike

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I think what you are meeting with is Monthly End Accrual (MEA) senario.
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Hi,
I made a query to calculate the average number of days of payment for a customer using the journal transactions:
+SELECT AVG((DateDiff(DD, JDT1.DueDate, JDT1.MthDate)))
FROM OJDT INNER JOIN JDT1 ON OJDT.TransId = JDT1.TransId LEFT JOIN ORCT ON OJDT.TransId = ORCT.TransId
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Hi,
I don't have BOE to try your query. To solve the problem, you need to separate your query to two to deal with different type first. After you got the correct result, you can combine them.
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Iam having a problem with the cal day average my scenario is as follows:
Iam executing a report based on the Cal day where for ex:01.01.2010 - 10.02.2010 iam gettin the data which contains aggregated data for the above selection criteria thats ok with me, But i need to add another column where i can get the Cal day average since in the selection criteria i have selcted for 40 days i want the total aggreated value/40 as my average per day.
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Hi,
To find day difference using function module refer below thread,
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To Dos vs Events for Bill Pay Reminders

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Hi All,
I have a requirement to calculate average quantities/day based on variable entry.
Date : variable ( range, mandatory)
Based on the user entry , the report should display quantity
average quantity on mondays ,
average quantity on Tuesday ,
average quantity on Wednesday ,
average quantity on Thursday ,
average quantity on Friday ,
for ex : march 01,2010 - march 15,2010 ( user entry)
in that date period we have three mondays (1,8,15)
the report should display average quantity for mondays and so on for otherdays..
any suggestions on how to proceed...
srinivas
Edited by: srinivas reddy on Mar 15, 2010 10:02 AM

Hi,
I dont know if others have a better solution, but if I were to suggest something, it would be to create a an infoobject to store the days, include it in your infocube.
The based on the date, it will populate the day in your infocube. Include this new infoobject into the report, then create restricted key figures using the new day infoobject to restrict.
Hope you could follow what I suggested and its useful for you.
regards,
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Hour-by-hour day usage extraction

Hey SQLers,
I have a large table that shows the total nr. of connections to my_software (let's call it like this) during 1 month. I would like to create an one-day average view of connections from 00:00 to 23:59; and see the connection pattern to my_software during this past month.
EDIT The date column is defined as: 'YYYY:MM:DD H24:MI:SS'
My SQL skills are not sufficient for this, and I wonder if anyone could point me to the right directions? I believe this must not be very complex, but I'm struggling with the implementation of 'average' in SQL.
Thanks!
M.
Edited by: mcasanovas on Sep 2, 2011 6:04 AM

Hi,
mcasanovas wrote:
I believe I didn't explain myself correctly. I am sorry for that. Whenever you post a problem, post a little sample data (CREATE TABLE and INSERT statements) and the results you want from that data.
Always say which version of Oracle you're using.
Simplify as much as possible. Fior example, you might only include times before 03:00 AM, but explain that your real data (and results) will go all the way to midnight.
Each row of the table is one connection, and I've got plenty. One of the columns is the date+hour, and it indicates the exact moment of the acces. In a more practical way, I need to be able to create a graph that shows the average per-hour (from 00 to 23) for the whole month. The result of the select should be something like:
--AVERAGE CONNECTIONS DAY
acces_time average_connections
00:00 550
01:00 340
22:00 1200
23:00 1130
Where the first row is the average nr. of connections at 00:00 during the whole month.Let's say there were 31 days in the month. Are you saying that you'd want output like this is, for example, there were
500 connections between 00:00 on 15 of those days,
550 connections between 00:00 on 1 day, and
600 connections between 00:00 on 15 days?
Here's one way:
WITH     parameters     AS
     SELECT     DATE '2011-08-01'     AS start_date
     ,     31               AS total_days
     FROM     dual
SELECT       TO_CHAR (connection_time, 'HH":00"')     AS hour
,       COUNT (*) / total_days          AS avg_connections
FROM            table_x
CROSS JOIN     parameters
WHERE       connection_time >= start_date
AND       connection_time < start_date + total_days
GROUP BY TO_CHAR (connection_time, 'HH":00"')
ORDER BY hour
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This assumes that connection_time is a DATE, not a string. There is no reason to store dates in string columns.

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I figured it out:
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Hi,
I'm trying to have numbers calculating an average based on the actual day of the year.
I have a table with a lot of data for a lot of days within the year and would like to know the current average per day. I think I have to have one cell that gives me the current day of the year and another with the total amount of all the data I enter in the table and a third cell that gives me the average of it.
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Hi Henning,
My assumptions differ slightly from kharisma's.
I've assumed you want an average based on the days for which there has been activity. For example if this were the average daily sales of a shop open Monday to Friday, there would be no data for Saturdays or Sundays. Similarly, the data table could record the earnings of a casual worker—some days the worker could receive payment from multiple employers, other days he might be unavailable for employment (or remain unhired).
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Regards,
Barry

Average Pay Days

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