Average Value Returns as Zero

I'm trying to take a few readings from an oscilloscope. I made a simple VI to test all of the parameters for the oscilloscope and make sure that everything was working before implementing the oscilloscope in a much more elaborate VI. I want to have voltage at a certain level (say, 2 V) then take a reading from the oscilloscope, add that value as a new element in an array. After doing this 100 times the VI will add the average value to a spreadsheet and then increase the voltage (to 2.05 V or something) and take 100 more measurments and average/record them. I was able to take ten sets of 100-sample averages and write them to an array (see notbroken.png) on one file, but when I try to do it in the real program (see broken.png) I check my spreadsheet and each entry is "0.000." Note that I've also created a program that controls the power supply independently and verified that I know how to control it properly; in fact, the only non-zero column is the one which reads the voltage that the program is telling the power supply to output.
I've literally written out each step that my "not broken" program does to find the average value and then done the same for the broken program and I can't find a single discrepancy. Any and all help would be greatly appreciated!
Solved!
Go to Solution.
Attachments:
broken.png ‏53 KB
notbroken.png ‏42 KB

vweltin wrote:
I've literally written out each step that my "not broken" program does to find the average value and then done the same for the broken program and I can't find a single discrepancy. Any and all help would be greatly appreciated!
Here's an exact analysis.
Both of your programs are broken, but the one with the FOR loop iterates only 10 times, thus you get arrays with one nonzero value (the last one) when the loop terminates. (Just because the average is nonzero, does not mean it is correct!)
Your code with the while loop iterates 11 times, but your array only has 10 elements, meaning that in the last iteration you try to replace an element that does not exist and the array remains at all zeroes.
In both programs, there will never be more than one non-zero element in the array.
LabVIEW Champion . Do more with less code and in less time .

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I'm new here so please let me know if I overstep any of the rules or expectations. I merely want to learn more about Java Programming efficiently, and easily. I can ask and discuss these topics with my online prof, but she doesn't have much time.
So right now I'm trying to solve a problem. It's a typical college level computing problem which I've already turned in. So I'm not looking for someone to do my homework for me or something. It's just that the program didn't work. Even though I probably won't get a very good grade for it, I want to
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Finally the class average must be output.
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Randle 54 87 54 98 65 15
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So all the data had to be read from a file and the results output to a file. Also we couldn't use 'global variables'. We had to use the appropriate parameters to pass values to and from methods.
Question 1: What does she mean by 'no global variables'? Maybe she means: don't use "*double test1, test2, test3, test4, test5*;"
Anyway because I'm a slow learner with Java, I end up looking for sample programs that seem to do a similar job as the problem posed. So with this program I decided to adapt a program called Comparison of Class Averages.
//Program: Comparison of Class Averages.
import java.io.*;
import java.util.*;
import java.text.DecimalFormat;
public class DataComparison
public static void main (String[] args) throws
FileNotFoundException, IOException
//Step 1
String courseId1; //course ID for group 1
String courseId2; //course ID for group 2
int numberOfCourses;
DoubleClass avg1 = new DoubleClass(); //average for a course
//in group 1
DoubleClass avg2 = new DoubleClass(); //average for a course
//in group 2
double avgGroup1; //average group 1
double avgGroup2; //average group 2
String inputGroup1;
String inputGroup2;
StringTokenizer tokenizer1 = null;
StringTokenizer tokenizer2 = null;
//Step 2 Open input and output files
BufferedReader group1 =
new BufferedReader(new FileReader("a:\\group1.txt"));
BufferedReader group2 =
new BufferedReader(new FileReader("a:\\group2.txt"));
PrintWriter outfile =
new PrintWriter(new FileWriter("a:\\student.out"));
DecimalFormat twoDecimal =
new DecimalFormat("0.00"); //Step 3
avgGroup1 = 0.0; //Step 4
avgGroup2 = 0.0; //Step 5
numberOfCourses = 0; //Step 6
//print heading: Step 7
outfile.println("Course No Group No Course Average");
inputGroup1 = group1.readLine(); //Step 8
inputGroup2 = group2.readLine(); //Step 9
while((inputGroup1 != null) &&
(inputGroup2 != null)) //Step 10
tokenizer1 = new StringTokenizer(inputGroup1);
courseId1 = tokenizer1.nextToken(); //Step 10a
tokenizer2 = new StringTokenizer(inputGroup2);
courseId2 = tokenizer2.nextToken(); //Step 10b
if(!courseId1.equals(courseId2)) //Step 10c
System.out.println("Data error: Course IDs "
+ "do not match.");
System.out.println("Program terminates.");
outfile.println("Data error: Course IDs "
+ "do not match.");
outfile.println("Program terminates.");
outfile.close();
return;
else //Step 10d
calculateAverage(group1, tokenizer1, avg1); //Step 10d.i
calculateAverage(group2, tokenizer2, avg2); //Step 10d.ii
printResult(outfile,courseId1,1,avg1); //Step 10d.iii
printResult(outfile,courseId2,2,avg2); //Step 10d.iv
avgGroup1 = avgGroup1 + avg1.getNum(); //Step 10d.v
avgGroup2 = avgGroup2 + avg2.getNum(); //Step 10d.vi
outfile.println();
numberOfCourses++; //Step 10d.vii
inputGroup1 = group1.readLine(); //Step 10e
inputGroup2 = group2.readLine(); //Step 10f
}//end while
if((inputGroup1 != null) && (inputGroup2 == null)) //Step 11a
System.out.println("Ran out of data for group 2 "
+ "before group 1.");
else //Step 11b
if((inputGroup1 == null) && (inputGroup1 != null))
System.out.println("Ran out of data for "
+ "group 1 before group 2.");
else //Step 11c
outfile.println("Avg for group 1: " +
twoDecimal.format(avgGroup1 / numberOfCourses));
outfile.println("Avg for group 2: " +
twoDecimal.format(avgGroup2 / numberOfCourses));
outfile.close(); //Step 12
public static void calculateAverage(BufferedReader inp,
StringTokenizer tok,
DoubleClass courseAvg)
throws IOException
double totalScore = 0.0;
int numberOfStudents = 0;
int score = 0;
if(!tok.hasMoreTokens())
tok = new StringTokenizer(inp.readLine());
score = Integer.parseInt(tok.nextToken());
while(score != -999)
totalScore = totalScore + score;
numberOfStudents++;
if(!tok.hasMoreTokens())
tok = new StringTokenizer(inp.readLine());
score = Integer.parseInt(tok.nextToken());
}//end while
courseAvg.setNum(totalScore / numberOfStudents);
}//end calculate Average
public static void printResult(PrintWriter outp,
String courseId,
int groupNo, DoubleClass avg)
DecimalFormat twoDecimal =
new DecimalFormat("0.00");
if(groupNo == 1)
outp.print(" " + courseId + " ");
else
outp.print(" ");
outp.println("\t" + groupNo + "\t "
+ twoDecimal.format(avg.getNum()));
So my adaptation turned out like this:
//Program: Compute individual and class averages from input file.
import java.io.*;
import java.util.*;
public class Exams
public static void main (String[] args)
throws FileNotFoundException
//Step 1
String nameId; //student name ID for list
int numberOfStudents;
DoubleClass avg = new DoubleClass(); //average for a student
//in list
double avgList; //average for list
//Step 2 Open the input and output files
Scanner group1 = new Scanner(new FileReader("c:\\list.txt"));
PrintWriter outfile = new PrintWriter("c:\\student.out");
avgList = 0.0; //Step 3
numberOfStudents = 0; //Step 5
//print heading: Step 6
outfile.println("NameID List Student Average");
calculateAverage(list, avg); //Step 7d.i
printResult(outfile,nameID, avg); //Step 7d.iii
avgList = avgList + avgList.getNum(); //Step 7d.v
outfile.println();
numberOfStudents++; //Step 7d.vii
outfile.printf("Avg for List: %.2f %n",
(avgList / numberOfStudents));
public static void calculateAverage(Scanner inp,
DoubleClass courseAvg)
double totalScore = 0.0;
int numberOfStudents = 0;
int score = 0;
score = inp.nextInt();
courseAvg.setNum(totalScore / numberOfStudents);
}//end calculate Average
public static void printResult(PrintWriter outp,
String nameId,
int groupNo, DoubleClass avg)
if (list == list)
outp.print(" " + nameId + " ");
else
outp.print(" ");
outp.printf("%9d %15.2f%n", list, avg.getNum());
I guess I was trying to find a shortcut that ended up being a long cut. Here's the algorithm I wrote.
Algorithm
1.) Initialize the variables
2.) Get the student name and his/her accompanying 6 exam scores, limiting the number of scores to 6.
3a.) Calculate score of 6 exams for each student using void method called CalculateAverage.
3b.) Use a loop inside the method to read and sum the six scores.
4.) Use value-returning method CalculateGrade to determine and return each student's grade.
5.) Output each student's grade in void main.
6.) Calculate the average score for all students
7.) Output entire class average
And now I'm trying to piece together code to match each step of the algorithm starting from scratch.
So I got the code for outputting each students grade in void:
public static void printGrade(double testScore)
System.out.print("Line 10: Your grade for "
+ "the course is ");
if (testScore >= 90)
System.out.println("A");
else if (testScore >= 80)
System.out.println("B");
else if (testScore >= 70)
System.out.println("C");
else if (testScore >= 60)
System.out.println("D");
else
System.out.println("F");
This code can read the the file with the scores:
Scanner inFile =
new Scanner(new FileReader("a:\\studentlist.txt"));
PrintWriter outFile =
new PrintWriter("a:\\avg.out");
courseGrade = inFile.nextDouble();
studentName=inFile.nextChar();
while (inFile.hasNext())
studentName= inFile.next().charAt(0);
courseGrade= inFile.nextDouble();
I'm just trying to piece this thing together. Any tips would be appreciated. I will return with more pieces to the puzzle soon. As you can tell it's all kind of disorganized, and scatterbrained. Just trying to find some simplification or distillation, or recommendations.
WR

Hello,
Thanks for your reply. So I take it you are more familiar with Object Oriented Programming more than Procedural Based Programming?
Well the teacher insisted I follow the algorithm instead of trying to adapt another program to the problem. But sometimes that approach saves time I've noticed since many of the code examples we study in Java are like 'the golden oldies'.
The student gradebook problem is repeated over and over in different forms. Maybe if I just approached the problem more linearly:
Algorithm
1.) Initialize the variables
String studentId
int numberOfStudents
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double avgGroup: //average for all students2.) Get the student name and his/her accompanying 6 exam scores.
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method calculateAverage
double totalScore //to store the sum of all the scores of each student
int numberOfExams; //to store the number of
int score; //to read and store a course score
double totalScore = 0.0
int numberOfExams = 0;
int score = 0;3b.) Use a loop inside the method to read and sum the six scores.
Using psuedocode (since the variables have been declared and initialized)
i)get the next student score
RIght here my approach of adapting another program to my new program becomes problematic
the pseudocode here is:
ii) while (score != -999):
I.) update totalScore by adding course score read in step i.
II.) increment numberOfExams by 1
III.) Get the nex student score
iii) studentAvg.setNum(totalScore / numberOfExams);
*What is the purpose of the statement while (score != -999)?*
I don't see why they picked -999? Will this loop allow me to read an endless number of student names and theri accompanying number of exams and then find the average for each student?
I'll go into the next algorithmic steps later.
4.) Use value-returning method CalculateGrade to determine and return each student's grade.
5.) Output each student's grade in void main.
6.) Calculate the average score for all students
7.) Output entire class average
Thanks ahead of time for any suggestions, tips.

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Vivek
Please vote or mark your question answered, if my reply helps you

How do I print out the value returned by a method in main??

I'm a total newbie at java, I want to know how I can print out the value returned by this function in the "Main" part of my class:
public int getTotalPrice(int price)
int totalprice=price+(price*0.08);
return totalprice;
I just want to know how to print out the value for total price under "public static void main(String[] args)". thanks in advance,
Brad

Few ways you could do it, one way would be to create an instance of the class and call the method:
public class Test
    public double getTotalPrice(int price)
        double totalprice = price + (price * 0.08);
        return totalprice;
    public static void main(String[] args)
        Test t = new Test();
        System.out.println(t.getTotalPrice(52));
}Or another would be to make getTotalPrice() static and you could call it directly from main.

To display average value in a graph

Hi There,
In one graph I need to display the duration for each week as per the week range selected and a separate average duration value of the weeks selected.
Is it possible to develop a query for above average value and use this query in WAD?
Can anybody help in providing a solution
Thank you
Anima

BI Query data can be fed directly to WAD Charts.
See below.
http://help.sap.com/saphelp_nw04/helpdata/en/0c/95c83956852b51e10000000a114084/content.htm

Assigning value returned from RFC call to a global variable

If I have an RFC call to SAP how can I assign the value returned to a global variable on my data services job?

Hi,
For now, it seems u haven't specified the destination properly. the call function statement must be suffixed with the 'destination' addition to make sure that the function call is an RFC and the particular function be executed at the desired destination.

Average Value Returns as Zero

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