BASH: iterate through an array passed in

Question

I have the following function that does not iterate through the array I want to be able to do some maanipulation on each element in the array[@] Any ideas whats wrong with the below for loop ????
function foo() {
name =$1
array=( "$2" )
for i in `seq 0 $(( ${#array[@]} - 1 ))`; do
echo "$i: ${array}"
echo "./prog $name ${array[i]}"
done
NAME ="BLAH"
arrayP+=("TEST") ;
arrayP+=("TESTB")
arrayP+=("TESTC")
foo $NAME "${arrayP[@]}"
Edited by: user618557 on 19-May-2011 12:57

Answer 1

Your code needs a small correction in order to work, at least when I tried:
foo "${name}" "${array[@]}"
should read
foo "${name}" "${arrayP[@]}"However, I would use a different approach, which is perhaps also not as ugly:
#!/bin/bash
foo() {
   name="$1"
   for i in $2; do
   set -- $i
   echo "$name $*"
done
name="BLAH"
arrayP+=("TEST")
arrayP+=("TESTB")
arrayP+=("TESTC")
foo "$name" "${arrayP[*]}"gives:
$ ./allarray
BLAH TEST
BLAH TESTB
BLAH TESTCI used this also in the previous thread BASH 3.2.25 multidemsional arrays which however, apparently wasn't helpful.