Bash script "open terminal and launch command

I need a script to do this:
launch a terminal, from this change working directory and then launch a command; the terminal have to remain opened after the command execution.
Something like:
$terminal cd $dir && $command
If I open a terminal and I do:
cd $dir && $command
it works
If I do a .sh script with this:
xterm -hold -e cd $dir && $command
or
terminal -H -x cd $dir && $command
when I launch it (the script) it doesn't work.
Last edited by buntolo (2012-01-05 23:44:52)

karol wrote:
xterm -hold -e "cd ~/test/ && ls"
works too.
I don't know what $command do you mean, but this will list th ~/test directory.
It works also for me.
With urxvt and xfce4-terminal don't work.
But xterm is too minimalist, is there an advanced terminal based on it?
And I don't unerstand why it doesn't work for xfce4-terminal but for it does for xterm...
man xfce4-terminal:
-H, --hold
Causes the terminal to be kept around after the child command has terminated
-e, --command=command
Execute command inside the terminal
man xterm:
-hold
Turn on the hold resource, i.e., xterm will not immediately destroy its window when the shell command completes. It will wait until you use the window manager to destroy/kill the window, or if you use the menu entries that send a signal, e.g., HUP or KILL.
-e program [ arguments ... ]
This option specifies the program (and its command line arguments) to be run in the xterm window. It also sets the window title and icon name to be the basename of the program being executed if neither -T nor -n are given on the command line. This must be the last option on the command line.
What the ...?
Is only my opinion that there aren't differences between:
terminal -H -e "cd $dir && $command"
and
xterm -hold -e "cd $dir && $command"
Last edited by buntolo (2012-01-06 13:11:58)

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