Bash script to terminated upon logout,

Hi all,
I have created a bash script - which start recording a camera device for security purpose, but I need the script to finish when the security user is logging out.
Any idea on how to do that?

sweetthdevil wrote:
Hi again,
sorry it took some time but I haven't had the time to look yet,
Back to the topic, I added the "pkill mencoder" at the begining of the file but it doesn't seem to work (because when shutting down the pc, the avi file created is broken - the index)
Any suggestion?
Difficult to say like this. If you kill mencoder by hand (not with the logout script); does this work properly? Maybe you have to wait that men,coder actualy exit before continuing:
PID=$(grep mencoder)
kill $PID
wait $PID
(work only if there is a single mencoder process).
But how did you start mencoder? (o processes receive a HUP signal if the terminal from which it has been opened is closed).
Last edited by olive (2011-03-04 00:58:30)

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  • Bash script for checking link status

    So I'm doing some SEO work I've been tasked with checking a couple hundred thousand back links for quality.  I found myself spending a lot of time navigating to sites that no longer existed.  I figured I would make a bash script that checks if the links are active first.  The problem is my script is slower than evolution.  I'm no bash guru or anything so I figured maybe I would see if there are some optimizations you folks can think of.  Here is what I am working with:
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    while read line
    do
    #pull page source and grep for domain
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    done < <(cat links.txt)
    Can you guys think of another way of doing this that might be quicker?  I realize the bottleneck is curl (as well as the speed of the remote server/dns servers) and that there isn't really a way around that.  Is there another tool or technique I could use within my script to speed up this process?
    I will still have to go through the active links one by one and analyze by hand but I don't think there is a good way of doing this programmatically that wouldn't consume more time than doing it by hand (if it's even possible).
    Thanks

    I know it's been awhile but I've found myself in need of this yet again.  I've modified Xyne's script a little to work a little more consistently with my data.  The problem I'm running into now is that urllib doesn't accept IRIs.  No surprise there I suppose as it's urllib and not irilib.  Does anyone know of any libraries that will convert an IRI to a URI?  Here is the code I am working with:
    #!/usr/bin/env python3
    from threading import Thread
    from queue import Queue
    from urllib.request import Request, urlopen
    from urllib.error import URLError
    import csv
    import sys
    import argparse
    parser = argparse.ArgumentParser(description='Check list of URLs for existence of link in html')
    parser.add_argument('-d','--domain', help='The domain you would like to search for a link to', required=True)
    parser.add_argument('-i','--input', help='Text file with list of URLs to check', required=True)
    parser.add_argument('-o','--output', help='Named of csv to output results to', required=True)
    parser.add_argument('-v','--verbose', help='Display URLs and statuses in the terminal', required=False, action='store_true')
    ARGS = vars(parser.parse_args())
    INFILE = ARGS['input']
    OUTFILE = ARGS['output']
    DOMAIN = ARGS['domain']
    REMOVED = 'REMOVED'
    EXISTS = 'EXISTS'
    NUMBER_OF_WORKERS = 50
    #Workers
    def worker(input_queue, output_queue):
    while True:
    url = input_queue.get()
    if url is None:
    input_queue.task_done()
    input_queue.put(None)
    break
    request = Request(url)
    try:
    response = urlopen(request)
    html = str(response.read())
    if DOMAIN in html:
    status = EXISTS
    else:
    status = REMOVED
    except URLError:
    status = REMOVED
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    input_queue.task_done()
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    input_queue = Queue()
    output_queue = Queue()
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    for i in range(NUMBER_OF_WORKERS):
    t = Thread(target=worker, args=(input_queue, output_queue))
    t.daemon = True
    t.start()
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    number_of_urls = 0
    with open(INFILE, 'r') as f:
    for line in f:
    input_queue.put(line.strip())
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    input_queue.put(None)
    #Write URL and Status to csv file
    with open(OUTFILE, 'a') as f:
    c = csv.writer(f, delimiter=',', quotechar='"')
    for i in range(number_of_urls):
    url, status = output_queue.get()
    if ARGS['verbose']:
    print('{}\n {}'.format(url, status))
    c.writerow((url, status))
    output_queue.task_done()
    input_queue.get()
    input_queue.task_done()
    input_queue.join()
    output_queue.join()
    The problem seems to be when I use urlopen
    response = urlopen(request)
    with a URL like http://www.rafo.co.il/בר-פאלי-p1
    urlopen fails with an error like this:
    Exception in thread Thread-19:
    Traceback (most recent call last):
    File "/usr/local/Cellar/python3/3.3.0/Frameworks/Python.framework/Versions/3.3/lib/python3.3/threading.py", line 639, in _bootstrap_inner
    self.run()
    File "/usr/local/Cellar/python3/3.3.0/Frameworks/Python.framework/Versions/3.3/lib/python3.3/threading.py", line 596, in run
    self._target(*self._args, **self._kwargs)
    File "./linkcheck.py", line 35, in worker
    response = urlopen(request)
    File "/usr/local/Cellar/python3/3.3.0/Frameworks/Python.framework/Versions/3.3/lib/python3.3/urllib/request.py", line 160, in urlopen
    return opener.open(url, data, timeout)
    File "/usr/local/Cellar/python3/3.3.0/Frameworks/Python.framework/Versions/3.3/lib/python3.3/urllib/request.py", line 473, in open
    response = self._open(req, data)
    File "/usr/local/Cellar/python3/3.3.0/Frameworks/Python.framework/Versions/3.3/lib/python3.3/urllib/request.py", line 491, in _open
    '_open', req)
    File "/usr/local/Cellar/python3/3.3.0/Frameworks/Python.framework/Versions/3.3/lib/python3.3/urllib/request.py", line 451, in _call_chain
    result = func(*args)
    File "/usr/local/Cellar/python3/3.3.0/Frameworks/Python.framework/Versions/3.3/lib/python3.3/urllib/request.py", line 1272, in http_open
    return self.do_open(http.client.HTTPConnection, req)
    File "/usr/local/Cellar/python3/3.3.0/Frameworks/Python.framework/Versions/3.3/lib/python3.3/urllib/request.py", line 1252, in do_open
    h.request(req.get_method(), req.selector, req.data, headers)
    File "/usr/local/Cellar/python3/3.3.0/Frameworks/Python.framework/Versions/3.3/lib/python3.3/http/client.py", line 1049, in request
    self._send_request(method, url, body, headers)
    File "/usr/local/Cellar/python3/3.3.0/Frameworks/Python.framework/Versions/3.3/lib/python3.3/http/client.py", line 1077, in _send_request
    self.putrequest(method, url, **skips)
    File "/usr/local/Cellar/python3/3.3.0/Frameworks/Python.framework/Versions/3.3/lib/python3.3/http/client.py", line 941, in putrequest
    self._output(request.encode('ascii'))
    UnicodeEncodeError: 'ascii' codec can't encode characters in position 5-8: ordinal not in range(128)
    I'm not too familiar with how character encoding works so I'm not sure where to start.  What would be a quick and dirty way (if one exists) to get URLs like this to play nicely with python's urlopen?

  • ???? how to launch bash script in cron ????

    with help from people in this forum, I successfully debugged the syntax in a shell script I wrote (my syntactical faux pas had to do with sending a multi-line mail message from a bash script).
    I can manually launch my script from Terminal's command line, and it works perfectly (well, at least it does exactly what I told it to do:). I try to launch it via cron, and it doesn't appear to ever launch.
    In /var/cron/tabs/root, the pertinent line of text reads:
    00 22 * * * /usr/local/customShellScripts/script.sh
    so it is supposed to launch daily at 10PM.
    Other jobs listed in /var/cron/tabs/root do run, because I get emails to my postfix admin account saying that they do. However, none of those other jobs are shell scripts; they are stuff like:
    24 06 * * 5 /usr/sbin/diskutil verifyVolume /
    The directory listing for /var/cron/tabs/root reads:
    $ ls /var/cron/tabs
    total 4
    drwxr-xr-x 3 root wheel 102 Mar 25 18:53:28 2006 .
    drwxr-xr-x 3 root wheel 102 Mar 20 17:13:47 2005 ..
    -rw-r--r-- 1 root wheel 1040 Mar 31 20:28:10 2006 root
    The directory listing for script.sh reads:
    $ ls /usr/local/customShellScripts/
    total 24
    drwxr-xr-x 6 root wheel 204 Mar 31 18:31:27 2006 .
    drwxr-xr-x 11 root wheel 374 Mar 5 12:26:23 2006 ..
    -rw-r--r-- 1 root wheel 6148 Feb 4 14:13:22 2006 .DS_Store
    -rwxr-xr-x 1 root wheel 8058 Mar 31 20:27:50 2006 script.sh
    for debug, the first two lines of script.sh read:
    #!/bin/sh
    /usr/bin/touch /foo
    but the file /foo never gets created. I tried using just "touch /foo" and that didn't work either.
    Also, since the script has a lot of calls to "echo," "expr," "date," "cut," "awk," etc., if I ever get cron to execute the script past the shebang line, do I have to preface all those calls with their full path? Or can I do something like in the old /etc/crontab file, where they defined a path variable up front
    PATH=/etc:/bin:/sbin:/usr/bin:/usr/sbin
    and the script will be smart enough to look in those directories for the appropriate executables?
    But, getting back to the first problem, I am obviously overlooking something very basic, which is not surprising since I'm self-taught (and I guess, Apple Unix Discussions forum taught) at this unix thing and shell scripting. So, can anybody bail me out here...again?
    2001 Quicksilver G4   Mac OS X (10.4.5)  

    Hey Reese
    You bailed me out, dude! Apparently, my difficulties stemmed from me trying to directly edit /var/cron/tabs/root with pico. Never seemed to bother the other stuff, but it did this time. I am totally inept with vi, the default editor for crontab -e, which is why I had cheated before, and directly edited the /var/cron/tabs/root, el.al., so I had to find out how to
    export EDITOR='pico'
    in my .bashrc
    After having done that, no problem, except for a latent programming logic bug that has reared its ugly head (my script is doing some date manipulation with today's and yesterday's date, and my script crashed and burned on the month change and with stuff related to single-digit date sequence numbers <10).
    But, hey, I learned how to reset my default editor, so as to make life easier for me when it comes time to dorking with crontab files, and I learned that when the crontab file says "DO NOT EDIT THIS FILE - edit the master and reinstall," it means it!
    Thanx for the troubleshooting hint.

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