Basic Help on Servlets

Question

Hi,
I have installed JDK1.4.0_01 and Tomcat 4.1.
In my basic Servlet Example, I have created the following directory structure --
TOMCAT_HOME\webapps\testing\index.html
TOMCAT_HOME\webapps\testing\src\TestServlet.java
TOMCAT_HOME\webapps\testing\WEB-INF\web.xml
TOMCAT_HOME\webapps\testing\WEB-INF\classes\TestServlet.class
The HTML Takes some input from a Text box and on Submit, calls the Servlet.
The problem I am facing is that, everytime the Submit is invoked, it gives HTTP 404 Servlet Not found Error.
My entries in server.xml ---
<Context path="/testing" docBase="testing" debug="0" reloadable="true">
     <Logger className="org.apache.catalina.logger.FileLogger"
          prefix="localhost_testing_log." suffix=".txt"
          timestamp="true"/>
</Context>
My entries in web.xml ---
<?xml version="1.0" encoding="ISO-8859-1"?>
<!DOCTYPE web-app
PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
"http://java.sun.com/dtd/web-app_2_3.dtd">
<web-app>
<servlet>
<servlet-name>TestServlet</servlet-name>
<servlet-class>TestServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>TestServlet</servlet-name>
     <url-pattern>/testing</url-pattern>
</servlet-mapping>
</web-app>
In the POST tage in the index.html, I am calling ---
<form action="TestServlet" method="POST">
</form>
http://localhost:8080/testing displays index.html appropriately.
But, on SUBMIT, HTTP 404 Error is displayed.
Expecting Help!
Thanks in Advance

Answer 1

According to your servlet mapping , the url to run your servlet is :
http://localhost:8080/testing/testing !!! because of <url-pattern>/testing</url-pattern>
so change it to :
<url-pattern>/TestServlet</url-pattern>