Basic Question On Assignment operator

Question

Could any one explain the below solution....
int i=0;
i=i++;
i=i++;
i=i++;
System.out.println(i)// prints 0. how?

Answer 1

First, never, ever write code like that.
If you use i++ in a given statement, then don't use i anywhere else in that statement.
It gives zero because i++ is an expression whose value is that of i before the increment.
If you did
int i = 0;
int j = i++;you'd expect j to hold zero, right?
i = i++ operates like this:
int tmp = i; // tmp = 0, that is, the value of the expression is the value of i before incrementing
i = i + 1; // i = 1, that is, actually perform the increment
i = tmp; // i = 0, tht is assign the value of the expression (which was zero) to i