Batch Applications in Java

I have to write programs in Java which will run as a nightly process (same as COBOL in mainframe) without any user inputs. First question is: Is it a good idea to do this. Eg: I will give an example of a real life situation. Let us take a banking application. Every night after the bank is closed the system has to spin through every checking accounts (millions) and do some transactions, cleanups maintenenace so that next day when the bank is up and running the accounts are ready. Normally these kind of processes will be in COBOL. Please give me input and will appreciate your ideas. Is it better to do this in C++ ??? :)
Thanks

* Java as many libs useful for batch (like XML APi, JMail, log4j etc ...)
* you can do a "big" program that execute some tasks depending on args. A part of your code is common. With several batch you have to duplicate it.
* if your batch are very different and don't use same code, no need to do a program.
* the use of Java is platform independent, so if your server change, no need to recompil the code !
* java is an Oriented Object Language, so if you don't have an Object Model ...
* if all your other program of your Information System is in Java why not keep it heterogen ?
* shell script is faster than java if you know use it !
it depend on project, I use a java program to do my batch because all my architecture is in java and because i need send/receive mail, acces ftp/http and i use an object model to generate report etc ... but if you just want to write a csv file from your database you don't need to use other thing than shell script .
think about global architecture, future of your application ... good luck !

Similar Messages

Batch application: As EJB or standalone?

Hi,
We are trying to develop some batch applications using java language.
I was asked to evaluate the differences between running them as standalone java programs or as an EJB inside an Application Server.
Any idea? Which is the best way?

Good question. I'm currently in a similar planning process (I'm still in a pretty early stage), and so far, I've come up with the following notes:
pro non-ejb:
- on EJB you cannot have multiple threads for a single EJB
- File I/O is also restricted on EJB
pro ejb:
- location transparency; you can basically run it everywhere
- on app server, possibility of ressource sharing (e.g. JDBC connection pooling)
misc:
- future ejb specs might contain timers (schedulers) so that you can schedule the jobs without programming the scheduler; not available at the moment in general, although some vendors might support this (weblogic ??)

How to create a Batch file for java application ?

HI,
How to create a Batch file for java application ?
And whats the use of creating batch file ?
Thanks in advance

[http://static.springsource.org/spring-batch/]
Assuming you want to develop a batch application rather than actually just create a .bat file ..

HOw to create a Batch file for java application and whats the use of this ?

HI,
How to create a Batch file for java application ?
And whats the use of creating batch file ?
Thanks in advance

First of all, you're OT.
Second, you can find this everywhere in the net.
If you got a manifest declaring main class (an classpath if needed), just create a file named whatever.bat, within same directory of jar file, containing:
javaw -jar ./WhateverTheNameOfYourJarIs.jar %*By the way, assuming a Windows OS, you can just double click the jar file (no batch is needed).
Otherwise use:
javaw -cp listOfJarsAndDirectoriesSeparedBySemiColon country/company/application/package/className %*Where 'country/company/application/package/' just stands for a package path using '/' as separator instead of '.'
Don't specify the .class extension.
Javaw only works on Windows (you asked for batch, I assumed .BAT, no .sh), in Linux please use java.exe (path may be needed, Windows doesn't need it 'cause java's executables are copied to system32 folder in order to be always available, see PATH environment variable if you don't know what I'm talking about) and use ':' as classpath (cp) separator.
The '%***' tail is there in order to pass all parameters, it only works on Windows, refer to your shell docs for other OSs (something like $* may work).
This way you have a command you can call to launch your code (instead of opening NetBeans just to see your app working). You could schedule tasks on it or just call it in any command prompt (hope you know what it is 'cause there have been people in this very same forum with no clue about it, if not just hold the 'Windows button' and press 'R', then type 'cmd' and run it).
Finally add dukes and give 'hem away.
Bye.

Java.io.filepermission error while executing a batch file from java prog

Hi,
i want run a java program which executes a batch file, both are in a jar file. while am trying this using webstart it shows error:access denied java.io.filepermission <<ALL FILES>>execute. why this happens how to rectify this.
By
Vinod

Clearly, it would be a security vulnerability to be able to do such a thing from the web w/o user granting trust to the application.
Java Web Start applications run in the Java SE secure sandbox unless they have been granted all-permissions by the user:
1.) sign all jar files.
2.) add <security><all-permissions/></security> to the jnlp file.
The user would then be prompted to grant trust to the applications.
/Andy

Hibernate/IBatis/JPA for batch applications

We are planning on developing a batch application. Performace is a very critical part in this. Wanted to get some feed back upon which is the best framework for batch applications.
This application would not have too many inserts/updates. It will have selects mainly.
Can somebody suggest which framework is good Hibernate/Ibatis/JPA ?
Thanks in advance
Gautam

Uppalapati wrote:
duffymo wrote:
"batch" usually means "transactional" to me. Why would a batch be mainly SELECTs? Makes no sense.
Most people wouldn't use Java/JDBC for batch. Better to use the tools that are optimized for your relational database in most cases.
sorry by stating that a little unclear. It is basically a stand-alone application. It reads messages as they comeby and process the messages. The processing of the messages require a lot of validations to be done (which are dependent upon a lot of parameters in the database and these would require selects). and finally based upon a few criteria's we write the data to the database. Are the validations static, read-only reference data? If so, you can read it once and cache it. Unless the SELECTs are truly dynamic and need to be made every time, perhaps you can save yourself some network traffic that way.
Caching with Hibernate might make a difference, depending on how dynamic the validations are.
and my reason for stating that it would have lots of selects is for the validation purpose and some inserts for updating the status.
duffymo wrote:
JPA and Hibernate will both require that you have an object model to map to your schema. Do you have that? If not, don't use either of those.
I have an object model to map with and which is the reason why we are considering Hibernate/Jpa.OK, that's better.
Either one will do, then. The advantage of JPA is that you don't have to commit to Hibernate, since TopLink and JDO will do as well. You can also use Glassfish or any other Java EE app server that supports EJB3 as well.
How well do you know Hibernate and/or JPA? The other consideration is your level of skill. Choose the one you know best. Assess the risk if you're just learning and this is a critical project.
Do you know that JDBC itself can't do the job?
What other reasons do you have for going this way?
%

Launching applications from java code

I have found a solution to launch applications from java.I thought this will be useful for programmers who want to open a
1. Browser
2. Player
3. Files etc.
There are 2 solutions :
I)To use a known application :
eg: to open windows media player
String[] cmd = new String[3];
cmd[0] = "cmd.exe";
cmd[1] = "/C";
cmd[2] = "START MPLAYER2.exe "+mediaURL+" /PLAY /CLOSE /FULLSCREEN";
//eg: mediaURL = "\"D:/project/songs/track1.mp3\""
// /PLAY /CLOSE /FULLSCREEN this option can be used only for windows media player
// for any other application use cmd[2] as START apl.exe //apl can be any windows application
Process p = Runtime.getRuntime().exec(cmd);
II) To use a default application:
Runtime.getRuntime().exec("rundll32 url.dll,FileProtocolHandler " + url);
// url can be any url
ref: [http://forums.sun.com/thread.jspa?threadID=5203313|http://forums.sun.com/thread.jspa?threadID=5203313]
[http://www.ericphelps.com/batch/rundll/|http://www.ericphelps.com/batch/rundll/]
Edited by: veda_sishta on ? ?????, ???? ??:?? ???????
Edited by: veda_sishta on ? ?????, ???? ??:?? ???????

To post code, use the code tags -- [code]Your Code[/code] will display asYour CodeOr use the code button above the editing area and paste your code between the {code}{code} tags it generates.
And make up your mind what file type you're having a problem with. Maybe .asx doesn't have a file association on your computer.
This works just fine for .m3u:import java.awt.Desktop;
import java.io.File;
import java.io.IOException;
public class Playlist {
   public static void main(String[] args) {
      try {
         Desktop.getDesktop().
               open(new File("E:/Music/Playlists/test.m3u"));
      } catch (IOException ex) {
         ex.printStackTrace();
}db
edit Did you try searching the net for the error you got? ("Invalid menu handle")
Edited by: Darryl.Burke

'Unable to Launch Application Error' - Java Web Start Running Under MS IIS.

I am attempting to render the following .jnlp in MS IE:
<?xml version="1.0" encoding="utf-8"?>

<jnlp
   codebase="http://localhost/LottoMadness/"
   href="LottoMadness.jnlp">
   <information>
     <title>LottoMadness Application</title>
     <vendor>Rogers Cadenhead</vendor>
     <homepage href="http://localhost/LottoMadness/"/>
     <icon href="lottobigicon.gif"/>
   </information>
   <resources>
     <j2se version="1.5"/>
     <jar href="LottoMadness.jar"/>
   </resources>
   <application-desc main-class="LottoMadness"/>
</jnlp>I've deployed the .jnlp, .gif, and .jar to MS IIS, running locally on my PC.
When I attempt to render the .jnlp in IE I obtain an 'Application Error' window stating 'Unable to Launch Application'. Clicking details gives me:
com.sun.deploy.net.FailedDownloadException: Unable to load resource: http://localhost/LottoMadness/LottoMadness.jnlp
     at com.sun.deploy.net.DownloadEngine.actionDownload(Unknown Source)
     at com.sun.deploy.net.DownloadEngine.getCacheEntry(Unknown Source)
     at com.sun.deploy.net.DownloadEngine.getResourceCacheEntry(Unknown Source)
     at com.sun.deploy.net.DownloadEngine.getResourceCacheEntry(Unknown Source)
     at com.sun.deploy.net.DownloadEngine.getResource(Unknown Source)
     at com.sun.deploy.net.DownloadEngine.getResource(Unknown Source)
     at com.sun.javaws.Launcher.updateFinalLaunchDesc(Unknown Source)
     at com.sun.javaws.Launcher.prepareToLaunch(Unknown Source)
     at com.sun.javaws.Launcher.launch(Unknown Source)
     at com.sun.javaws.Main.launchApp(Unknown Source)
     at com.sun.javaws.Main.continueInSecureThread(Unknown Source)
     at com.sun.javaws.Main$1.run(Unknown Source)
     at java.lang.Thread.run(Unknown Source)I have configured MS IIS for Web Start, by setting the Extension/Content Type fields to .jnlp and application/x-java-jnlp-file.
(The .jnlp is basically from 'Programming with Java in 24 Hours', as this is the book I am learning Java from.)

AndrewThompson64 wrote:
I am not used to seeing references to a local server that do not include a port number.
E.G. http://localhost:8080/LottoMadness/
I have deployed the following HTML (HelpMe.html) to the web server:
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<html>
<head>
     <title>Untitled</title>
</head>
<body>
Help Me!
</body>
</html>When I attempt to render the URL in IE, I see the page just fine. The URL is use is:
http://localhost/LottoMadness/HelpMe.htmlSo, I think my web server setup and usage is ok.
>
As an aside, what happens if (your MS IIS is running and) you click a direct link to..
[http://localhost/LottoMadness/LottoMadness.jnlp|http://localhost/LottoMadness/LottoMadness.jnlp]
When I click this link I get the error and exception I cited in my previous post.

Not getting application in Java Web Start

Hello Sir,
I wanted to run an application using Java Web Start. So, I created a jnlp file and i have mentioned the necessary jar files and the main class file. when I clicked on the jnlp file, the application is running in the Server using Java Web Start and its shortcuts are creates on the desktop and in the startmenu. I am able to run the application by clicking on the shortcut in the server. But I am unable to Download the application in the Java Web Start. It is not showing any Error Messages and the application is not running in the cleint machines.
The contents of the jnlp file is as follows.
<?xml version="1.0" encoding="utf-8"?>

<jnlp
spec="1.0+"
codebase="http://dev01/Dummy/New"
href="SimpleClass.jnlp">
<information>
<title>SimpleClass Demo Application</title>
<vendor>xxx</vendor>

<description>SimpleClass Demo </description>
<description kind="short">A demo of Class A and Class B Dependencies in java Web Start.</description>


<offline-allowed/>
</information>
<security>
<all-permissions/>
</security>
<resources>
<j2se version="1.4.0"/>
<jar href="ClassLib.jar"/>
</resources>
<application-desc main-class="A"/>
</jnlp>
So, please Tell me how to solve this problem.
Thanking you
R.Venkatesh
MakeLogic
www.makelogic.com
[email protected]

Here is an example of my JNLP file that works.
<?xml version="1.0" encoding="utf-8"?>

<jnlp spec="1.0+" codebase="http://application:8080/application/" href="passport.jnlp">
<information>
    <title>Passport</title>
    <vendor>WIM Consulting</vendor>
    <homepage href="http://www.wim.ca"/>
    <description>application Passport.</description>
    <description kind="short">Passport</description>
    <icon href="WIMicon.gif" width="32" height="32"/>
    <icon href="WIMsplash.jpg" kind="splash"/>
    <offline-allowed/>
</information>
<security>
    <all-permissions/>
</security>
<resources>
    <j2se version="1.4+"/>
    <jar href="passport.jar"/>
    <jar href="jars/kunststoff.jar"/>
    <jar href="jars/ldapsec.jar"/>
    <jar href="jars/localedata.jar"/>
    <jar href="jars/mysql-connector-java-3.0.6-stable-bin.jar"/>
</resources>
<application-desc main-class="ca.wim.passport.startup"/>
</jnlp>I am not sure what the problem is.
"I am unable to Download the application in the Java Web Start"
If webstart in not actually downloading the jar - is the jar in the correct location?
Is the server named dev01 and the directory structure actually /Dummy/New?
Note: you do need to set up the mine type JNLP on your server,
In my case the location of the JNLP file and main jar file passport is in the following directory.
c:\Inetpub\WIMRoot\application
The additional jars are in
c:\Inetpub\WIMRoot\application
I hope this may give you some clue
rykk

Installation Problem inSAP NetWeaver Application Server, Java EE 5 Edition

Hi All,
I have dowloaded the package from SDN but as I tried to Install it into my system,i got the following error;the log is like below:
(Mar 1, 2007 4:54:56 PM), Install, com.sap.installshield.maxdb.maxdb_call_sdbinst, err, An error occurred and product installation failed. Look at the log file D:\sapdb\JP1\log.txt for details.
(Mar 1, 2007 4:54:56 PM), Install, com.sap.installshield.maxdb.maxdb_call_sdbinst, err, ProductException: (error code = 601; message="Thu Mar 01 16:54:56 IST 2007 An Error happened during the Change of the MaxDB Database passwords. Check end of Logfile C:/DOCUME1/SAP/LOCALS1/Temp/MaxDBSAPNWPREV.log")
STACK_TRACE: 22
ProductException: (error code = 601; message="Thu Mar 01 16:54:56 IST 2007 An Error happened during the Change of the MaxDB Database passwords. Check end of Logfile C:/DOCUME1/SAP/LOCALS1/Temp/MaxDBSAPNWPREV.log")
     at com.sap.installshield.maxdb.maxdb_call_sdbinst.install(maxdb_call_sdbinst.java:247)
     at com.installshield.product.service.product.PureJavaProductServiceImpl.installProductAction(Unknown Source)
     at com.installshield.product.service.product.PureJavaProductServiceImpl$InstallProduct.getResultForProductAction(Unknown Source)
     at com.installshield.product.service.product.InstallableObjectVisitor.visitComponent(Unknown Source)
     at com.installshield.product.service.product.InstallableObjectVisitor.visitInstallableComponents(Unknown Source)
     at com.installshield.product.service.product.InstallableObjectVisitor.visitProductBeans(Unknown Source)
     at com.installshield.product.service.product.PureJavaProductServiceImpl$InstallProduct.install(Unknown Source)
     at com.installshield.product.service.product.PureJavaProductServiceImpl.installProduct(Unknown Source)
     at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
     at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source)
     at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source)
     at java.lang.reflect.Method.invoke(Unknown Source)
     at com.installshield.wizard.service.LocalImplementorProxy.invoke(Unknown Source)
     at com.installshield.wizard.service.AbstractService.invokeImpl(Unknown Source)
     at com.installshield.product.service.product.GenericProductService.installProduct(Unknown Source)
     at com.installshield.product.service.product.PureJavaProductServiceImpl.installAssembly(Unknown Source)
     at com.installshield.product.service.product.PureJavaProductServiceImpl.access$900(Unknown Source)
     at com.installshield.product.service.product.PureJavaProductServiceImpl$Installer.execute(Unknown Source)
     at com.installshield.wizard.service.AsynchronousOperation.run(Unknown Source)
     at java.lang.Thread.run(Unknown Source)
But the same package got installed on another system having the same system parameters.
Pls guide.
Thanks in advance

Hi,
welcome to SDN!
To your problem: did you make sure the master password you set during installation is less than 9 charachters as discussed in the Installation Troubleshooting?
P.S. I'm moving this thread to the forum dedicated to the SAP NetWeaver Application Server, Java EE 5 Edition.

I want to create a Ajax based Chating application using java .

hi . I want to create an chating Application , and ajax based chatting application using java as my server side language ..i have some idea about it .. but one thing that i m not understanding is that how i will communicate with other users because each user has its own session so what i will do to send one messge to all the users ???? . i m new to JavaEE and i have chosen this as my semester project .. i need some help regarding this .

First get it working without AJAX.

Executing batch file from Java stored procedure hang

Dears,
I'm using the following code to execute batch file from Java Stored procedure, which is working fine from Java IDE JDeveloper 10.1.3.4.
public static String runFile(String drive)
String result = "";
String content = "echo off\n" + "vol " + drive + ": | find /i \"Serial Number is\"";
try {
File directory = new File(drive + ":");
File file = File.createTempFile("bb1", ".bat", directory);
file.deleteOnExit();
FileWriter fw = new java.io.FileWriter(file);
fw.write(content);
fw.close();
// The next line is the command causing the problem
Process p = Runtime.getRuntime().exec("cmd.exe /c " + file.getPath());
BufferedReader input = new BufferedReader(new InputStreamReader(p.getInputStream()));
String line;
while ((line = input.readLine()) != null)
result += line;
input.close();
file.delete();
result = result.substring( result.lastIndexOf( ' ' )).trim();
} catch (Exception e) {
e.printStackTrace();
result = e.getClass().getName() + " : " + e.getMessage();
return result;
The above code is used in getting the volume of a drive on windows, something like "80EC-C230"
I gave the SYSTEM schema the required privilege to execute the code.
EXEC DBMS_JAVA.grant_permission('SYSTEM', 'java.io.FilePermission', '<<ALL FILES>>', 'read ,write, execute, delete');
EXEC DBMS_JAVA.grant_permission('SYSTEM', 'SYS:java.lang.RuntimePermission', 'writeFileDescriptor', '');
EXEC DBMS_JAVA.grant_permission('SYSTEM', 'SYS:java.lang.RuntimePermission', 'readFileDescriptor', '');
GRANT JAVAUSERPRIV TO SYSTEM;
I have used the following to load the class in Oracle 9ir2 DB:
loadjava -u [system/******@orcl|mailto:system/******@orcl] -v -resolve C:\Server\src\net\dev\Util.java
CREATE FUNCTION A1(drive IN VARCHAR2) RETURN VARCHAR2 AS LANGUAGE JAVA NAME 'net.dev.Util.a1(java.lang.String) return java.lang.String';
variable serial1 varchar2(1000);
call A1( 'C' ) into :serial1;
The problem that it hangs when I execute the call to the function (I have indicated the line causing the problem in a comment in the code).
I have seen similar problems on other forums, but no solution posted
[http://oracle.ittoolbox.com/groups/technical-functional/oracle-jdeveloper-l/run-an-exe-file-using-oracle-database-trigger-1567662]
I have posted this in JDeveloper forum ([t-853821]) but suggested to post for forum in DB.
Can anyne help?

Dear Peter,
You are totally right, I got this as mistake copy paste. I'm just having a Java utility for running external files outside Oracle DB, this is the method runFile()
I'm passing it the content of script and names of file to be created on the fly and executed then deleted, sorry for the mistake in creating caller function.
The main point, how I claim that the line in code where creating external process is the problem. I have tried the code with commenting this line and it was working ok, I made this to make sure of the permission required that I need to give to the schema passing security permission problems.
The function script is running perfect if I'm executing vbs script outside Oracle using something like "cscript //NoLogo aaa1.vbs", but when I use the command line the call just never returns to me "cmd.exe /c bb1.bat".
where content of bb1.bat as follows:
echo off
vol C: | find /i "Serial Number is"
The above batch file just get the serial number of hard drive assigned when windows formatted HD.
Same code runs outside Oracle just fine, but inside Oracle doesn't return if I exectued the following:
variable serial1 varchar2(1000);
call A1( 'C' ) into :serial1;
Never returns
Thanks for tracing teh issue to that details ;) hope you coul help.

How to get the current path of my application in java ?

how to get the current path of my application in java ?
thanks

To get the path where your application has been installed you have to do the following:
have a class called "what_ever" in the folder.
then you do a litte:
String path=
what_ever.class.getRessource("what_ever.class").toString()
That get you a string like:
file:/C:/Program Files/Cool_program/what_ever.class
Then you process the result a little to remove anything you don't want:
path=path.substring(path.indexOf('/')+1),path.lastIndexOf('/'))
//Might be a little error here but you should find out //quickly if it's the case
And here you go, you have a nice
C:/Program Files/Cool_program
which is the path to your application.
Hooray

Creating a Gnutella downloading application in Java

Hi I am trying to create an application in Java that is able to simplly download a file from a remote host using the Gnutella (peer-2-peer) protocol. The application accepts 3 arguments:
1 host (IP address or hostname)
2 port (the remote gnutella application is listening on)
3 ss1hash (unique code for the desired file)
Gnutella file transfers work by sending HTTP get request headers to the remote host, which includes the information from the arguments.
This is the application i have created so far...:
import java.io.*;
import java.net.*;
public class GnuttDownloader{
        public static void main(String[] args) throws IOException{
                String host;
                int port;
                host = args[0];
                port = Integer.parseInt(args[1]);
                String sha1Hash;
                sha1Hash = args[2];
                Socket socket=null;
                System.out.println("Starting Downloader...");
                try {
                      socket = new Socket(host, port);
                  // Send request to get root
                  // Be sure to end string with two sets of carriage
                  // return - newline characters.
                  OutputStream outputStream =
                      socket.getOutputStream();
                  PrintWriter out = new PrintWriter(outputStream);
                 out.print ("GET /uri-res/N2R?" + sha1Hash + " HTTP/1.1\r\n"
                            + "User-Agent: Limewire/3.3.5\r\n"
                            + "Host: " + host + ":" + port + "\r\n"
                            + "Connection: Keep-Alive\r\n"
                            + "Range: bytes=0-\r\n\r\n");
                  out.flush();
                  // Fetch response
           InputStream inputStream =
             socket.getInputStream();
           InputStreamReader inputStreamReader =
             new InputStreamReader(inputStream);
           BufferedReader in =
             new BufferedReader(inputStreamReader);
           String response;
           while ((response = in.readLine()) != null) {
             System.out.println(response);
           System.out.print("ARGUMENTS:\nHost: " + host + "\n"
   + "port: " +port + "\nFile's sha1 code: " + sha1Hash);
           // Close everything
           out.close();
           in.close();
           socket.close();
         } catch (IOException e) {
           System.err.println("Problems talking to " + host + " on port:" + port);
           e.printStackTrace();
     }I have not implemented the file reading/saving part yet, but the application should at least give me a response such as:
HTTP/1.1 200 OK
Server: Gnutella
Content-type: application/binary
Content-length: 4356789
this should verify that it accepts my request, and i should expect a file to be delivered about 4MB long. However this does not happen.
The application manages to connect to a remote host i.e. if I specify a host on my LAN (192.168.0.3) running LimeWire 3.3.5, but instead of receiving the above response, I receive the follwing:
HTTP/1.1 400 Malformed Request
Server: LimeWire/3.3.5
Content-Type: text/plain
Content-Length: 17
Connection: close
Malformed Request
Therefore, i know it is connecting and sending the header, but it seems that it is not understanding the actual header that I send. I can't see anything wrong with it, is there anything that I am doing wrong? Has anyone done anyting like this?Can anyone help me here?
Thanks in advance.

If anyone can help here please????????????????????????????????

How to call a VB application from Java

Hi,
does anybody know how to call a VB application from java.
Would appreciate if you can provide me with an example.
thanks

try exec()ing the cad program with the name of the file as a command line parameter...
Runtime.getRuntime().exec("CADProg.exe Test.prt");
i have no clue if this will work but it seems like it's worth a try.

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