Best Two in Three Numbers

Question

Hi i had written a logic for finding out two best nos out of three.
But i think i m using BAD logic,
any good guess than this??
int a, b, c, max1, max2;
a = 10;
b = 20;
c = 30;
max1 = a > b ? (a > c ? a : b) : (b > c ? b : c);
if(max1 == a )
   max2 = b > c ? b : c;
else if(max1 == b )
   max2 = a > c ? a : c;
else if(max1 == a )
   max2 = a > b ? a : b;
System.out.println("Max1 = " + max1 + "  MAx2 = " + max2);Can there be any other logic than this??
--Bhupendra Mahajan

Answer 1

Assuming that max1 and max2 don't need ordering, it is sufficient to reject the least:if (a>=b) {
  max1 = a;
  max2 = b > c ? b : c;
} else {
  max1 = b;
  max2 = a > c ? a : c;
}Pete