BPC 7.5 NW - IF stament in Formule for Transformation File ?

Question

Hi, i try load data from 0PROFIT_CTR to BPC reading PDF "How To Import Master Data and Hierarchies into BPC 7.5 from SAP NW BW".
Then use this assing:
*MAPPING
ID=ID
RESPONSABLE=0RESP_USER
BPC=*IF(ID(2:2)=*STR(I) then *STR(I);*IF(ID(2:2)=*STR(D) AND ID(4:4)=*STR(Z) then *STR();*STR(D)))
PAIS=*IF(ID(1:1)=*STR(C) then *STR(CHILE);*STR(PERU))
In Validate get Error for Field BPC : The number in parentheses is incorrect, check your formula
*IF(ID(2:2)=*STR(I) then *STR(I);*IF(ID(2:2)=*STR(D) AND ID(4:4)=*STR(Z) then *STR();*STR(D)))
This line working good :
PAIS=*IF(ID(1:1)=*STR(C) then *STR(CHILE);*STR(PERU))
Examples value for 0PROFIT_CTR is :
CD1Z0101
CD101C01
PI1CA001
CI1CA001
I look sintaxis and is good number in parentheses.
Any idea the problem ?

Answer 1

I test this :
BPC=*IF(ID(2:2)=*STR(D) AND ID(4:4)=*STR(Z) then *STR();*STR(D))
And GET error :
*IF formula is not valid, check your formula
Maybe problem is in "AND" stament ?
This is part the previous code posted :
BPC=*IF(ID(2:2)=*STR(I) then *STR(I);*IF(ID(2:2)=*STR(D) AND ID(4:4)=*STR(Z) then *STR();*STR(D)))
But here get error :
The number in parentheses is incorrect, check your formula
Any idea how use "AND" stament or correct sintaxis in this line :
BPC=*IF(ID(2:2)=*STR(I) then *STR(I);*IF(ID(2:2)=*STR(D) AND ID(4:4)=*STR(Z) then *STR();*STR(D)))
Thank you.