By Default All Value Into Select List,If Select % In select List

Question

Hi ,
i have created application process to extract state name in select list based on city name.
Now i need if i don't have city name and i have select % into City Name select List then All State Name Should Come into Select List.
Right Now if i select % into select List then It show me Blank In to state Name Select List.
How can i extract All State Name if i select % Into Select List.
My Application Process
BEGIN
  OWA_UTIL.mime_header ('text/xml', FALSE);
  HTP.p ('Cache-Control: no-cache');
  HTP.p ('Pragma: no-cache');
  OWA_UTIL.http_header_close;
htp.prn('<data>');
   HTP.prn ('<select>');
   FOR c IN (select S.NAME,S.CODE from STATE_MAS S,CITY_MAS C where C.STATE_CODE=S.CODE AND C.CODE =:SELECT5)
LOOP
  HTP.prn ('<option value="' || c.CODE || '">' || c.NAME || '</option>');
   END LOOP;
   HTP.prn ('</select>');
htp.prn('</data>');
END;My City Name Table
CREATE TABLE  "CITY_MAS"
   (     "CODE" VARCHAR2(3) NOT NULL ENABLE,
     "NAME" VARCHAR2(1000) NOT NULL ENABLE,
     "STATE_CODE" VARCHAR2(3) NOT NULL ENABLE
        )My State Name Table
CREATE TABLE  "STATE_MAS"
   (     "CODE" VARCHAR2(3) NOT NULL ENABLE,
     "NAME" VARCHAR2(50) NOT NULL ENABLE
/How can i do this.
Thanks
Edited by: 805629 on Jan 25, 2011 2:06 AM

Answer 1

select S.NAME,S.CODE from STATE_MAS S join CITY_MAS C on (C.STATE_CODE=S.CODE)If you join two table you must have some equal data between this tables. and define it on your sql. Else you join will be cartesian join. if you dont want use this sql then create view
create view TEST1 as (
select S.NAME,S.CODE from STATE_MAS S,CITY_MAS C where C.STATE_CODE=S.CODE
select * from test1 where  C.CODE =:SELECT5 OR :SELECT5 = '%' Edited by: Adigozalov Gurban on Jan 25, 2011 3:46 PM