Calculating average of selected values

Hello all,
I would like to put the following question in relation to bex queries:
We have a condition in our query to select the 5 top values and the 5 bottom ones. But there are 33 values. When we calculate the average value (result of the query), we can do it in a way the query displays  the average of those 10 values displayed. But innerly the average value stored is the average of the 33 values (all) and in SEM that's the value we see (not the average of the 10 values selected.)
And now, the question:
Is there a possibility to obtain from SEM the average of the 10 values displayed?
Thank you very much,
Carlos Hinestrosa

Hi Nick,
Petri Net Method
Researchers of Petri Nets from 1962 to about 1990 developed the main ideas (including the basic graphics notations) of the “thought process” I used. One of the literature I read on Petri Nets is the textbook (except for the chapters on Grafcet),
David and Alla (1992). Petri Nets and Grafcet: Tools for Modeling Discrete Event Systems. New York: Prentice Hall.
If you want to research the topic on your own, there is a bibliography on Petri Nets.
Missed Requirement
It occurred to me that we missed the possibility that a user can select a non-zero value given that a non-zero value is currently selected (T14 – T19) for each of the six fields. Here is the diagram with this requirement.
Since we agree on the general interpretation of the diagram, I am combining several graphics to create a new, more concise diagram. Of course, this is a cryptic diagram to someone who do not agree with the earlier diagram.
Additional Requirement
We can also include the cumulative sum of the non-zero values selected by the user (P8), similar to the cumulative number of non-zero values selected (P6). In this case, a document-level variable for the cumulative sum should be defined, and updated along with counter. When the computation for the average is needed, the cumulative sum is already available and the average is computed by dividing the cumulative sum by the number of non-zero values selectes: m(P8) / m(P6) .
If we do this, we would have done something very interesting: there are no for-loops in the code.
Regards,
John

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