Calculating hours in numerical formats between 2 business days, calculated column

Hi there,
I need to calculate how many hours are between 2 days only including business days, outputting in numerical format (ex. 7.3).
I've been using this formula to output how many weekdays are between 2 days.
=IF(AND((WEEKDAY(CompletedTimeStamp,2))<(WEEKDAY(,2)),((WEEKDAY(Created,2))-(WEEKDAY(CompletedTimeStamp,2)))>1),(((DATEDIF(Created,CompletedTimeStamp,"D")+1))-(FLOOR((DATEDIF(Created,CompletedTimeStamp,"D")+1)/7,1)*2)-2),(((DATEDIF(Created,CompletedTimeStamp,"D")+1))-(FLOOR((DATEDIF(Created,CompletedTimeStamp,"D")+1)/7,1)*2)))
The problem with this is if the 2 dates are on the same day, it outputs "1". I need it to output the amount of hours then / by 24 to give me ".7" instead.
Is there anything I can do to convert this current formula to give me hours instead of days?
Thanks,
Terence

The DATEDIF is rounding to the nearest day.
Try this:
=IF(AND((WEEKDAY(CompletedTimeStamp,2))<(WEEKDAY(,2)),((WEEKDAY(Created,2))-(WEEKDAY(CompletedTimeStamp,2)))>1),(((CompletedTimeStamp-Created+1))-(FLOOR((CompletedTimeStamp-Created+1)/7,1)*2)-2),(((CompletedTimeStamp-Created+1))-(FLOOR((CompletedTimeStamp-Created+1)/7,1)*2)))
-1
Then above will return fractions of days, i.e. 5.5 days. Multiply this by 24 for hours.
I think there is a extra "+1" in the above example somewhere, so I added a minus 1 to get back the correct value.
Hi.. Mike.. I am trying to use this calcuation.. its renndering "time being used 3.3".. I need it to calcuate a work day as 8 hrs so if
Start Date= 9/12/2014 9:00am
End Date= 9/16/2014 5:00 pm
should be 3 (8 hr work days) any way I can fix this?
Thanks in advance for your help.
Mike Smith TechTrainingNotes.blogspot.com

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To Whom It May Concern:
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Hello,
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Thanks,

Hi, Please take a look and tweak accordingly. Best of luck.
--Assuming data dimension table something like the following
--tblDateDim (DT date primary key,
flagHoliday bit,
flagWeekday bit
CREATE FUNCTION fnBusinessDays (
@StartDate DATE,
@EndDate DATE
RETURNS INT
AS
BEGIN
DECLARE @Days INT ;
SELECT @Days = count(*)
FROM tblDateDim --// date dimension
WHERE
( DT BETWEEN @StartDate AND @EndDate) --// dt is date column in the table.
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Post Author: dusty
CA Forum: WebIntelligence Reporting
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Post Author: jsanzone
CA Forum: WebIntelligence Reporting
Dusty,
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Calculate "Business Days" and account for holidays

I have played with Date math based on what I have found for documentation, and adding an arbitrary number of days is pretty easy. But what about adding an arbitrary number of business days? I found a web site that talks about "Next business day",
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and calculated from a Friday should produce the date of the next Wednesday. And calculated from Friday Sept 4, 2015 (Friday before Labor Day) should produce Thursday Sept 10, 2015.
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for weekends. ;)

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Calculating Business Days(Start_dt - End_dt)

Hi Friends,
Could anyone of you help me to find out the business days(Excluding Saturdays and Sundays) between two dates.
The difference should be calculated of both the Start_dt and End_dt values truncated. The result should be calculated and stored according to business days, it means weekend days are to be ignored.
create table sample (id number,start_dt date,end_dt date). The table values are as follows;
ID ; start_dt ; End_dt
1 ; 08-02-2012 ; 15-02-2012
2 ; 30-12-2011 ; 15-02-2012
My output should be;
ID ; start_dt ; End_dt ; Expected Business Days (Excluding Weekends)
1 ; 08-02-2012 ; 15-02-2012 ; 4
2 ; 30-12-2011 ; 15-02-2012 ; 33
Please note that, the Start Date and End Date can be any date from any year. Please help me on this.
Regards,
Williams.
Edited by: Williams on Feb 8, 2012 6:28 PM
Edited by: Williams on Feb 8, 2012 6:29 PM

Here's my first cut at it.
SQL> WITH sample AS
2 (
3     SELECT 1 AS id, TO_DATE('08-02-2012','DD-MM-YYYY') AS start_dt, TO_DATE('15-02-2012','DD-MM-YYYY') AS end_dt FROM DUAL UNION ALL
4     SELECT 2 AS id, TO_DATE('30-12-2011','DD-MM-YYYY') AS start_dt, TO_DATE('15-02-2012','DD-MM-YYYY') AS end_dt FROM DUAL
5 )
6 /* END SAMPLE DATA */
7 SELECT id
8       , start_dt
9       , end_dt
10       , COUNT(*)
11 FROM   sample
12 JOIN   ( /* Exclude Weekends */
13           SELECT dt
14           FROM ( /* Generate a range that includes all days */
15                   SELECT min_start_dt + (LEVEL - 1) AS dt
16                        , TO_CHAR
17                          ( min_start_dt + (LEVEL - 1)
18                          , 'fmDAY'
19                          , 'NLS_DATE_LANGUAGE=AMERICAN'
20                          ) AS dy
21                   FROM   ( SELECT MIN(start_dt) AS min_start_dt
22                                 , MAX(end_dt)   AS max_end_dt
23                            FROM   sample
24                          )
25                   CONNECT BY LEVEL <= max_end_dt - min_start_dt + 1
26                 )
27           WHERE dy NOT IN ('SATURDAY','SUNDAY')
28         ) dys ON dys.dt BETWEEN start_dt AND end_dt
29 GROUP BY id
30         , start_dt
31         , end_dt
32 /
        ID START_DT            END_DT                COUNT(*)
         2 12/30/2011 00:00:00 02/15/2012 00:00:00         34
         1 02/08/2012 00:00:00 02/15/2012 00:00:00          6
2 rows selected.I got different results then you though. Can you say why your counts are what they are?

Calculation of Business day in OBIEE

Hi,
How to calculate the business day in OBIEE by excluding both weekends and public holidays.
Please guide me

If you want the "nth business day," here is something I prepared.
Understanding the Concept in Layman Terms
The first step to deriving the calculation is looking at a calendar. For our example, we will calculate the 6th business day of each month.
1) Observation One: When the first day of the month is Saturday, the 6th business day occurs when “today’s date minus the first-day-of-the month equals 9.”
2) Observation Two: When the first day of the month is Sunday, the 6th business day occurs when the above calculation equals 8.
3) Observation Three: When the first day of the month is Monday – Friday, the 6th business day occurs when the above calculation equals 7.
Building the SQL
Below are the SQL statements that correspond to the above observations:
4) When the first day of the month is Saturday…
DAYOFWEEK(TIMESTAMPADD(SQL_TSI_DAY,DAYOFMONTH(CURRENT_DATE)*-1,CURRENT_DATE)) = 6 AND DAYOFMONTH(CURRENT_DATE)-DAYOFMONTH(TIMESTAMPADD(SQL_TSI_DAY,1,TIMESTAMPADD(SQL_TSI_DAY,DAYOFMONTH(CURRENT_DATE)*-1,CURRENT_DATE))) = 9
5) When the first day of the month is Sunday…
DAYOFWEEK(TIMESTAMPADD(SQL_TSI_DAY,DAYOFMONTH(CURRENT_DATE)*-1,CURRENT_DATE)) = 7 AND DAYOFMONTH(CURRENT_DATE)-DAYOFMONTH(TIMESTAMPADD(SQL_TSI_DAY,1,TIMESTAMPADD(SQL_TSI_DAY,DAYOFMONTH(CURRENT_DATE)*-1,CURRENT_DATE))) = 8
6) When the first day of the month is Monday – Friday…
DAYOFWEEK(TIMESTAMPADD(SQL_TSI_DAY,DAYOFMONTH(CURRENT_DATE)*-1,CURRENT_DATE)) NOT IN (6,7) AND DAYOFMONTH(CURRENT_DATE)-DAYOFMONTH(TIMESTAMPADD(SQL_TSI_DAY,1,TIMESTAMPADD(SQL_TSI_DAY,DAYOFMONTH(CURRENT_DATE)*-1,CURRENT_DATE))) = 7
Putting the SQL Statements Together
When any of the above conditions are true (“OR” between each condition), then (THEN) “today” is the 6TH business day; otherwise (ELSE) it is not the 6th business day. Below is the final SQL:
CASE WHEN
DAYOFWEEK(TIMESTAMPADD(SQL_TSI_DAY,DAYOFMONTH(CURRENT_DATE)*-1,CURRENT_DATE)) = 6 AND DAYOFMONTH(CURRENT_DATE)-DAYOFMONTH(TIMESTAMPADD(SQL_TSI_DAY,1,TIMESTAMPADD(SQL_TSI_DAY,DAYOFMONTH(CURRENT_DATE)*-1,CURRENT_DATE))) = *9*
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Modifying the Query for the nth Business Day
To modify the above SQL for the nth business day, change the numbers in bold to the appropriate values.

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Hello,
I had a calculated column on a library that took two dates and found the difference between them in business days, but I am not sure how to subtract business days from a date...for instance I get a start date from a form and I need to
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I've always resorted to Javascript/JQuery for that kind of function. I found an old fashioned loop worked the best for me - it supports going forward or backwards. I key it off of a change in a starting date, or sometimes a status change. My actual production
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newDate = getNextDate(newDate, -3);
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I have two questions:
1. Does anyone know a better formula for calculating business days in totals?
I am currently using the formula in https://www.sdn.sap.com/irj/sdn/go/portal/prtroot/docs/library/uuid/701a52c3-6b1e-2b10-21b3-a6e101be1a0f
I tailored to my needs. However, there are still a lot of manual maintenance every year.
2. I have many reports that need the formula. It is very consuming to update the formula in each report. Does anyone know a better way to do it?
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numbervar days;
datevar date1 := minimum({?My Parameter});
datevar date2 := maximum({?My Parameter});
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totext(days,0);
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Need Help Calculating Business Days AND omitting Holidays...

Post Author: dkotenoglou
CA Forum: Formula
Thanks to the people here I was able to get a nice formula to help me calculate the amount of business days between two days.//Crystal syntax
Local DateTimeVar d1 := ;
Local DateTimeVar d2 := ;
DateDiff ("d", d1, d2) -
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Post Author: V361
CA Forum: Formula
If you have CR XI, there is another example as well, in the sample reports, look at feature examples, custom functions.rpt   this code is from that example.
Function cdDateAddSkipHolidays (nWorkingDays As Number, startDateTime As DateTime) As DateTime    'the result = startDateTime + nWorkingDays + nHolidays (including weekends)    'the algorithm below also works when nWorkingDays is negative
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