Can any body explain me this query? select 'alter index '||index_name||' monitoring usage' as index_monitor from user_indexes where index_name='EMP';
Initially i've a put an index of emp table in monitoring state..
later i've got this query
select 'alter index '||index_name||' monitoring usage' as index_monitor from user_indexes where index_name='EMP';
can any body explain me what is the meaning of this query...
and how do that query in the strings of projection area works....
i'm totally confused
thank you in advance.
This is referred to as SQL generating SQL. It is most useful when you need to generate SQL statements for all indexes or indexes for one user. After generating the text you then would execute it in SQLPlus or the tool of your choice. If you combine this with a spool statement, SPOOL MyGeneratedScript.SQL you can run it with @MyGeneratedScript in SQLPlus. I combine this into a script which generates the file, calls the editor so you can look it over and then executes it. Here is an example of moving indexes to a different tablespace.
-- UTL_Move_Indexs_To_New_TableSpace_Script.SQL
/* This script will grab all the tables out of the specified source tablespace
** and move them into the specified target tablespace. Ensure the the target
** exists and has sufficient room. You must be logged in as the table owner.
ACCEPT v_source_tablespace_name PROMPT 'Enter source tablespace name: '
ACCEPT v_target_tablespace_name PROMPT 'Enter target tablespace name: '
SET HEADING OFF
SET FEEDBACK OFF
SET TERMOUT OFF
SET ECHO OFF
SPOOL _move_index.SQL
SELECT 'ALTER INDEX '
|| ndx.owner
|| '.'
|| ndx.index_name
|| CHR (10)
|| 'REBUILD '
|| CHR (10)
|| 'TABLESPACE '
|| UPPER ('&v_target_tablespace_name')
|| ';'
sql_statement
FROM dba_indexes ndx
WHERE ndx.tablespace_name = UPPER ('&v_source_tablespace_name')
AND ndx.index_type <> 'LOB'
ORDER BY ndx.owner,
ndx.index_name;
SPOOL OFF
--Edit the move script
EDIT _move_index
--Reset parameters.
SET TERMOUT ON
PAUSE Hit Ctrl+C to ABORT, any key to CONTINUE,
-- Run the move script
SPOOL Move_Indexs_To_New_TableSpace.LOG
@_move_index
SPOOL OFF
--Reset parameters.
SET TERMOUT on
SET FEEDBACK on
SET HEADING on
Marcus Baocn
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09990019711.Hi,
Stock Transfer Between Plants in One Step
Use
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Use
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pl check for more info [STO|http://help.sap.com/saphelp_47x200/helpdata/en/4d/2b90dc43ad11d189410000e829fbbd/content.htm]
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Can any body explain real time confiruration in sd,mm module plssssssss
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SD FLOW AND MM FLOW
Re: reg : document flow for SD and MM ?
http://www.sapgenie.com/abap/tables_sd.htm
Please check this SD online documents.
http://help.sap.com/printdocu/core/Print46c/en/data/pdf/CAARCSD/CAARCSD.pdf
http://help.sap.com/printdocu/core/Print46c/en/data/pdf/MYSAP/SR_SD.pdf
http://help.sap.com/printdocu/core/Print46c/en/data/pdf/BCBMTWFMSD/BCBMTWFMSD.pdf
http://help.sap.com/printdocu/core/Print46c/en/data/pdf/LOLISPLN/LOLISPLN.pdf
Also please check this SD links as well.
Rewards if useful.........
Minal
http://help.sap.com/saphelp_47x200/helpdata/en/92/df293581dc1f79e10000009b38f889/frameset.htm
http://help.sap.com/saphelp_erp2005/helpdata/en/dd/55f33e545a11d1a7020000e829fd11/frameset.htm
http://www.sap-basis-abap.com/sapsd.htm
http://www.sap-img.com/sap-sd.htm
http://www.sapgenie.com/abap/tables_sd.htm
http://searchsap.techtarget.com/featuredTopic/0,290042,sid21_gci961718,00.html
http://www.sapbrain.com/TUTORIALS/FUNCTIONAL/SD_tutorial.html
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http://www.easymarketplace.de/online-pdfs.php
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http://www.sapgenie.com/abap/tables_mm.htm
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http://www.allsaplinks.com/material_management.html
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http://www.sapfriends.com/sapstuff.html
http://help.sap.com/printdocu/core/Print46c/en/data/pdf/PSMAT/PSMAT.pdf
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http://help.sap.com/printdocu/core/Print46c/en/data/pdf/MYSAP/SR_MM.pdf
http://help.sap.com/printdocu/core/Print46c/en/data/pdf/LOMDMM/LOMDMM.pdf
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Hello All
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please have a look on following links. Where I need your support
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hi,
sap gurus,
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09990019711Hi,
I didnt get your question fully, but
Please refer the folowing link
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Can any body explain me what is " silos"
hi
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akhilHi Akhil,
Please go through these links:
1. An information silo is a management system incapable of reciprocal operation with other, related management systems. A bank's management system, for example, is considered a silo if it cannot exchange information with other related systems within its own organization, or with the management systems of its customers, vendors or business partners. "Information silo" is a pejorative expression that is useful for describing the absence of operational reciprocity. Derived variants are "silo thinking", "silo vision", and "silo mentality".
http://en.wikipedia.org/wiki/Information_silo
2. Storage silos are structures for storing bulk materials. Silos are used in agriculture to store grain (see grain elevators) or fermented feed known as silage. Silos are more commonly used for bulk storage of grain, coal, cement, carbon black, wood chips and sawdust.
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http://en.wikipedia.org/wiki/Storage_silo
3. http://blogs.ittoolbox.com/crm/cdi/archives/master-data-silos-and-rocknroll-7686
4. Get in-depth insights into Application Silos!
View as PDF
http://manageengine.adventnet.com/products/applications_manager/application-silos.html
Please rewards if found helpful.
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Alok Sharma -
Can any body please read this and ans me
hi all,
can any body please read this and tell is there any function module or some other thing is available.
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you would have to use the following function modules
CONVERT_TO_LOCAL_CURRENCY
CONVERT_TO_FOREIGN_CURRENCY
regards
Dinesh -
hi,
sap gurus,
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id is timmampalliatgmaildotcom
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balaji.t
09990019711.hi Balaji,
You can find very helpful information at the following address
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vijay -
Can you please explain how this query is fetching the rows?
here is a query to find the top 3 salaries. But the thing is that i am now able to understand how its working to get the correct data :How the data in the alias table P1 and P2 getting compared. Can you please explain in some steps.
SELECT MIN(P1.SAL) FROM PSAL P1, PSAL P2
WHERE P1.SAL >= P2.SAL
GROUP BY P2.SAL
HAVING COUNT (DISTINCT P1.SAL) <=3 ;
here is the data i used :
SQL> select * from psal;
NAME SAL
able 1000
baker 900
charles 900
delta 800
eddy 700
fred 700
george 700
george 700
Regards,
Renu... Please help me in understanding the query.
Your query looks like anything but a Top-N query.
If you run it in steps and analyze the output at the end of each step, then you should be able to understand what it does.
Given below is some brief information on the same:
test@ora>
test@ora> --
test@ora> -- Query 1 - using the non-equi (theta) join
test@ora> --
test@ora> with psal as (
2 select 'able' as name, 1000 as sal from dual union all
3 select 'baker', 900 from dual union all
4 select 'charles', 900 from dual union all
5 select 'delta', 800 from dual union all
6 select 'eddy', 700 from dual union all
7 select 'fred', 700 from dual union all
8 select 'george', 700 from dual union all
9 select 'george', 700 from dual)
10 --
11 SELECT p1.sal AS p1_sal, p1.NAME AS p1_name, p2.sal AS p2_sal,
12 p2.NAME AS p2_name
13 FROM psal p1, psal p2
14 WHERE p1.sal >= p2.sal;
P1_SAL P1_NAME P2_SAL P2_NAME
1000 able 1000 able
1000 able 900 baker
1000 able 900 charles
1000 able 800 delta
1000 able 700 eddy
1000 able 700 fred
1000 able 700 george
1000 able 700 george
900 baker 900 baker
900 baker 900 charles
900 baker 800 delta
900 baker 700 eddy
900 baker 700 fred
900 baker 700 george
900 baker 700 george
900 charles 900 baker
900 charles 900 charles
900 charles 800 delta
900 charles 700 eddy
900 charles 700 fred
900 charles 700 george
900 charles 700 george
800 delta 800 delta
800 delta 700 eddy
800 delta 700 fred
800 delta 700 george
800 delta 700 george
700 eddy 700 eddy
700 eddy 700 fred
700 eddy 700 george
700 eddy 700 george
700 fred 700 eddy
700 fred 700 fred
700 fred 700 george
700 fred 700 george
700 george 700 eddy
700 george 700 fred
700 george 700 george
700 george 700 george
700 george 700 eddy
700 george 700 fred
700 george 700 george
700 george 700 george
43 rows selected.
test@ora>
test@ora>This query joins PSAL with itself using a non equi-join. Take each row of PSAL p1 and see how it compares with PSAL p2. You'll see that:
- Row 1 with sal 1000 is >= to all sal values of p2, so it occurs 8 times
- Row 2 with sal 900 is >= to 9 sal values of p2, so it occurs 7 times
- Row 3: 7 times again... and so on.
- So, total no. of rows are: 8 + 7 + 7 + 5 + 4 + 4 + 4 + 4 = 43
test@ora>
test@ora> --
test@ora> -- Query 2 - add the GROUP BY
test@ora> --
test@ora> with psal as (
2 select 'able' as name, 1000 as sal from dual union all
3 select 'baker', 900 from dual union all
4 select 'charles', 900 from dual union all
5 select 'delta', 800 from dual union all
6 select 'eddy', 700 from dual union all
7 select 'fred', 700 from dual union all
8 select 'george', 700 from dual union all
9 select 'george', 700 from dual)
10 --
11 SELECT p2.sal AS p2_sal,
12 COUNT(*) as cnt,
13 COUNT(p1.sal) as cnt_p1_sal,
14 COUNT(DISTINCT p1.sal) as cnt_dist_p1_sal,
15 MIN(p1.sal) as min_p1_sal,
16 MAX(p1.sal) as max_p1_sal
17 FROM psal p1, psal p2
18 WHERE p1.sal >= p2.sal
19 GROUP BY p2.sal;
P2_SAL CNT CNT_P1_SAL CNT_DIST_P1_SAL MIN_P1_SAL MAX_P1_SAL
700 32 32 4 700 1000
800 4 4 3 800 1000
900 6 6 2 900 1000
1000 1 1 1 1000 1000
test@ora>
test@ora>Now, if you group by p2.sal in the output of query 1, and check the number of distinct p1.sal, min of p1.sal etc. you see that for p2.sal values - 800, 900 and 1000, there are 3 or less p1.sal values associated.
So, the last 3 rows are the ones you are interested in, essentially. As follows:
test@ora>
test@ora> --
test@ora> -- Query 3 - GROUP BY and HAVING
test@ora> --
test@ora> with psal as (
2 select 'able' as name, 1000 as sal from dual union all
3 select 'baker', 900 from dual union all
4 select 'charles', 900 from dual union all
5 select 'delta', 800 from dual union all
6 select 'eddy', 700 from dual union all
7 select 'fred', 700 from dual union all
8 select 'george', 700 from dual union all
9 select 'george', 700 from dual)
10 --
11 SELECT p2.sal AS p2_sal,
12 COUNT(*) as cnt,
13 COUNT(p1.sal) as cnt_p1_sal,
14 COUNT(DISTINCT p1.sal) as cnt_dist_p1_sal,
15 MIN(p1.sal) as min_p1_sal,
16 MAX(p1.sal) as max_p1_sal
17 FROM psal p1, psal p2
18 WHERE p1.sal >= p2.sal
19 GROUP BY p2.sal
20 HAVING COUNT(DISTINCT p1.sal) <= 3;
P2_SAL CNT CNT_P1_SAL CNT_DIST_P1_SAL MIN_P1_SAL MAX_P1_SAL
800 4 4 3 800 1000
900 6 6 2 900 1000
1000 1 1 1 1000 1000
test@ora>
test@ora>
test@ora>That's what you are doing in that query.
The thing is - in order to find out Top-N values, you simply need to scan that one table PSAL. So, joining it to itself is not necessary.
A much simpler query is as follows:
test@ora>
test@ora>
test@ora> --
test@ora> -- Top-3 salaries - distinct or not; using ROWNUM on ORDER BY
test@ora> --
test@ora> with psal as (
2 select 'able' as name, 1000 as sal from dual union all
3 select 'baker', 900 from dual union all
4 select 'charles', 900 from dual union all
5 select 'delta', 800 from dual union all
6 select 'eddy', 700 from dual union all
7 select 'fred', 700 from dual union all
8 select 'george', 700 from dual union all
9 select 'george', 700 from dual)
10 --
11 SELECT sal
12 FROM (
13 SELECT sal
14 FROM psal
15 ORDER BY sal DESC
16 )
17 WHERE rownum <= 3;
SAL
1000
900
900
test@ora>
test@ora>
test@ora>And for Top-3 distinct salaries:
test@ora>
test@ora> --
test@ora> -- Top-3 DISTINCT salaries; using ROWNUM on ORDER BY on DISTINCT
test@ora> --
test@ora> with psal as (
2 select 'able' as name, 1000 as sal from dual union all
3 select 'baker', 900 from dual union all
4 select 'charles', 900 from dual union all
5 select 'delta', 800 from dual union all
6 select 'eddy', 700 from dual union all
7 select 'fred', 700 from dual union all
8 select 'george', 700 from dual union all
9 select 'george', 700 from dual)
10 --
11 SELECT sal
12 FROM (
13 SELECT DISTINCT sal
14 FROM psal
15 ORDER BY sal DESC
16 )
17 WHERE rownum <= 3;
SAL
1000
900
800
test@ora>
test@ora>
test@ora>You may also want to check out the RANK and DENSE_RANK analytic functions.
RANK:
http://download.oracle.com/docs/cd/B19306_01/server.102/b14200/functions123.htm#SQLRF00690
DENSE_RANK:
http://download.oracle.com/docs/cd/B19306_01/server.102/b14200/functions043.htm#SQLRF00633
HTH
isotope -
Can any one help with this query please
I have a table something as below
Things_t
Things Characteristic Char Value
Item 1 Colour Red
Item 1 Packaging
Item 2 Shape Square
Item 2 Brand Spunk
Now i want to reterive an item with none of its char values as Null. Using the query “ select distinct things from things_t where char value is Null ” will fetch the item 1 also together with item 2. i want to fetch a record from thing for which none of the char values are Null such as Item 2. Can you please help me with this query.Try this:
WITH t AS
(SELECT 1 item_id, 17436 chr_id, 14225034 chr_val_id FROM dual UNION
SELECT 1 item_id, 39 chr_id, 14276173 chr_val_id FROM dual UNION
SELECT 1 item_id, 17774 chr_id, NULL chr_val_id FROM dual UNION
SELECT 1 item_id, 265 chr_id, 20502978 chr_val_id FROM dual UNION
SELECT 1 item_id, 16978 chr_id, 797233 chr_val_id FROM dual UNION
SELECT 1 item_id, 13092 chr_id, 5666917 chr_val_id FROM dual UNION
SELECT 1 item_id, 15228 chr_id, 1209758 chr_val_id FROM dual UNION
SELECT 2 item_id, 112 chr_id, 12705342 chr_val_id FROM dual UNION
SELECT 2 item_id, 6945 chr_id, NULL chr_val_id FROM dual UNION
SELECT 2 item_id, 70 chr_id, 12597376 chr_val_id FROM dual UNION
SELECT 2 item_id, 16832 chr_id, NULL chr_val_id FROM dual UNION
SELECT 2 item_id, 7886 chr_id, 9588619 chr_val_id FROM dual UNION
SELECT 2 item_id, 6986 chr_id, 2659351 chr_val_id FROM dual UNION
SELECT 3 item_id, 9531 chr_id, 8910943 chr_val_id FROM dual UNION
SELECT 3 item_id, 9798 chr_id, 8717531 chr_val_id FROM dual UNION
SELECT 3 item_id, 17446 chr_id, 12266441 chr_val_id FROM dual UNION
SELECT 3 item_id, 4830 chr_id, 13683090 chr_val_id FROM dual UNION
SELECT 3 item_id, 9518 chr_id, 834772 chr_val_id FROM dual UNION
SELECT 3 item_id, 11031 chr_id, 20233753 chr_val_id FROM dual UNION
SELECT 3 item_id, 12564 chr_id, 2282478 chr_val_id FROM dual)
SELECT DISTINCT item_id
FROM t
MINUS
SELECT DISTINCT item_id
FROM t
WHERE chr_val_id IS NULLOr this:
SELECT item_id
FROM (SELECT item_id,
MIN(NVL(chr_val_id, -1)) min_chr_val_id
FROM t
GROUP BY item_id)
WHERE min_chr_val_id != -1Edited by: lee200 on Oct 15, 2012 9:22 AM -
Can any body explain this for loop
public void trymethod(){
int i =0;
for ( foo('A'); foo('B')&&(i<2); foo('C')){
i++ ;
foo('D');
static boolean foo(char c) {
System.out.print(c);
return true;
}The program runs fine but If I return a char from 'foo()' it does not compile.The second clause in your for loop declaration uses boolean logic (if this do that, etc). Once foo is returning a character, it's no longer returning a boolean so the result can't have boolean logic applied to it
Don't ask me how to fix it, I have no idea what you're trying to do! -
CAN ANY BODY EXPLAIN ABOUT "PROCESS DEFAULT" IN SSAS PROCESSING OPTIONS
Hi, i am working with SQL Server 2008R2.
working for SSAS Tuning.
I want to Know about "PROCESS DEFAULT" option, whether it calculates the aggregations on Measure groups and Dimensions for both or not.
Please explain me about this Option in detail..
SUPRAJA'S"Default" processing is mainly useful during development, when you tend to change structures of objects of the cube, but the data content does not change. Then it optimizes processing, only processing the parts of the cube affected by the structural
change.
Default processing detects the state of all objects like dimensions, cubes, measure groups, partitions, aggregations. The state can be any of processed, unprocessed, or partly processed. Process default brings the partly or unprocessed objects to processed
state. It does not check if any data has changed on the relational data source, it just checks the state of the objects in the database.
An object can get to unprocessed state in one of the following ways:
If you newly create it.
If you change the objects structure. making sub objects just visible or invisible does not change the structure, nor does renaming sub objects in most cases, but adding or removing sub objects does.
If you explicitly unprocess it (using the Unprocess or Clear process options of the process command).
If you process an object on which the current object depends, and do that in a way that does not keep relations. E. g. if you do a full process of a dimension, all measure groups related to the dimension will get unprocessed. If you do a "Process Update"
of the dimensions, the measure groups stay processed.
Please mark as Answer if this helps! -
Can any body explain me about R/3 delta in to a infocube directly?
Hi Experts,
I think it is not possible to do a delta load from R/3 in to a infocube right? Because Infocube is addition and it will not overwrite the changes like ODS. So if I am doing a delta load from R/3 in to infocube directly; I can only able to do a full load not a delta load right?
Thanks in advance.
Aslam.I am just trying to understand how the cube works with delta laod. For example:
Record 1 in the infocube is $15 for infoobject say expense and this infoobject is mapped to the field expense in r/3.
- now for this same record user changed the value to $20 for the field expense.
- when i do delta to the infocube in bw what happens?
Does the infocube overwrite the value from $15 to $20?
or Does the infocube add $15 to $20 and make it $35?
If it make it to $35 than it is wrong; it should be $20 right?
How it works as it don't have any overwrite functionality?
I think the 0RECORDMODE will take care of the delta load.
Thanks in advance.
Aslam.
Edited by: Asif Aslam on Jan 23, 2008 10:55 PM
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