Can't find the error on this small code :S

Question

Hi , i've just compiled this code and i can't find what is wrong! :(
The compiler is ok, but the output print its not what i was expect.
If u insert 121 (capicua) the answer is: This number its not a capicua :S
what is wrong?
thanks!!
Note: Don't create another code plz.
import java.io.*;
public class Capicua {
     public static void main (String[] args) throws Exception {
          int digit, num;
          int inverted = 0;
               BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
               System.out.print(" Insert number: ");
               num=Integer.parseInt(br.readLine().trim());
               while(num > 0) {
               digit = num % 10;
               num = num /10;
               inverted = inverted * 10 + digit;
               if(num == inverted) {
                    // to be capicua the number inserted must
                    //be equals to the inverted
                    System.out.println("Its Capicua!");      
               }else{
                    System.out.println("This number is not a Capicua!");
}

Answer 1

Please use code tags (see button above posting box) when posting code. It makes it much easier to read.
So, it appears that capicua means palindrome--the number reads the same backwards and forwards. Is that correct?
There are ways of doing this without converting the 121 to a number, but I won't explain that unless you want.
I think your problem is this line:
if (num == inverted)
You have changed "num" within your while loop. Therefore, num is no longer the original input 121.
Try adding println statements like this to watch what happens:
while(num > 0) {
  digit = num % 10;
  num = num /10;
  inverted = inverted * 10 + digit;
  System.out.println("digit = " + digit);
  System.out.println("num = " + num);
  System.out.println("inverted = " + inverted);
}