Case Expression in when clause

I am doing a query to filter out depto 20 and inside the case deptno 30 only if sal = 1500. Its working fine. I just want to do this without end=1? is there any way.
select * from scott.emp where deptno not in (20)
and case when deptno = 30
AND sal = 1500
THEN 0
ELSE 1
end=1
I am getting error when I remove end=1
ORA-00918: column ambiguously defined
please help me..

Hi,
A lot of guys would say:
SELECT *
FROM    scott.emp
WHERE   deptno <> 20
AND     ( deptno <> 30
        OR sal    <> 1500
        );Whenever you use CASE, whether in the WHERE clause or anywhere else, the CASE expression must return a value of some SQL datatype, like NUMBER or VARCHAR2. There is no boolean data type in SQL, so you can't say:
WHERE   CASE ... ENDIf you're using CASE in the WHERE clause, you have to say something like
WHERE   CASE ... END = 'Okay'or
WHERE   CASE ... END NOT IN (0)As G illlustrated, you can hide the CASE statement in a subquery, and use the value it returns in the main query, if you prefer that.

Similar Messages

Case expression in where clause

I have requirement to select a columns based on condition Datacode should (when the column id=1 THEN 'GILL' ELSE WHEN ID=11 THEN IT Should be 'HEL'
how can i write in case statment
AND DATA_CD =CASE WHEN ID=1 THEN 'GIL'
WHEN ID=11 THEN 'HEL'
END ) my question is above code is corrrect for where clause?
what happens to the ELSE PART?
Please clarify
S

oraclehema wrote:
I have requirement to select a columns based on condition Datacode should (when the column id=1 THEN 'GILL' ELSE WHEN ID=11 THEN IT Should be 'HEL'
how can i write in case statment
AND DATA_CD =CASE WHEN ID=1 THEN 'GIL'
WHEN ID=11 THEN 'HEL'
END ) my question is above code is corrrect for where clause?
what happens to the ELSE PART?It is for you to tell what happens to the ELSE part.
If the ID is not 1 or 11, then your AND condition fails and probably your query will not retrieve any records for you (Assuming this query is not a part of OR condition, because there is no query provided.).
Because, without ELSE, the default shall be set to NULL and since you used "DATA_CD =", NULL shall not equate with it resulting in failure of condition. Hence, I would suggest you to add some default value in the ELSE part.

Missing Expression Error When Case Statment is used as field

I have tried to write an expression that will calculate how many days ago a request was submitted and return a user defined value if the calculation falls within the criteria in the case statment. The SQL View for the Query I am using is shown below:
SELECT A.F_POSN_REQUEST_ID, A.F_REQ_ECP_STATUS, TO_CHAR(A.REQUEST_DTTM,'YYYY-MM-DD-HH24.MI.SS."000000"'), TO_CHAR(A.F_REQ_ST_DT,'YYYY-MM-DD-HH24.MI.SS."000000"'), TO_CHAR(A.F_REQ_ECP_ST_DT,'YYYY-MM-DD-HH24.MI.SS."000000"'), TO_CHAR(A.F_REQ_ECP_PROC_DT,'YYYY-MM-DD-HH24.MI.SS."000000"'), CASE WHEN(sysdate - TO_DATE(SUBSTR( TO_CHAR(A.F_REQ_ST_DT,'YYYY-MM-DD-HH24.MI.SS."000000"'),1,16),'YYYY-MM-DD-HH24.MI'))>60 THEN '>60' ELSE(CASE WHEN(sysdate - TO_DATE(SUBSTR( TO_CHAR(A.F_REQ_ST_DT,'YYYY-MM-DD-HH24.MI.SS."000000"'),1,16),'YYYY-MM-DD-HH24.MI')) >30 AND <=60 THEN '30 - 60' ELSE(CASE WHEN(sysdate - TO_DATE(SUBSTR( TO_CHAR(A.F_REQ_ST_DT,'YYYY-MM-DD-HH24.MI.SS."000000"'),1,16),'YYYY-MM-DD-HH24.MI'))>=15 AND <=30 THEN '15 - 30' ELSE(CASE WHEN(sysdate - TO_DATE(SUBSTR( TO_CHAR(A.F_REQ_ST_DT,'YYYY-MM-DD-HH24.MI.SS."000000"'),1,16),'YYYY-MM-DD-HH24.MI'))<15 THEN 'Less Than 15' ELSE NULL END)END)END)END))
FROM PS_F_POSN_REQUEST A
WHERE A.F_REQ_ECP_STATUS IN ('I','O','P')
GROUP BY A.F_POSN_REQUEST_ID, A.F_REQ_ECP_STATUS, TO_CHAR(A.REQUEST_DTTM,'YYYY-MM-DD-HH24.MI.SS."000000"'), TO_CHAR(A.F_REQ_ST_DT,'YYYY-MM-DD-HH24.MI.SS."000000"'), TO_CHAR(A.F_REQ_ECP_ST_DT,'YYYY-MM-DD-HH24.MI.SS."000000"'), TO_CHAR(A.F_REQ_ECP_PROC_DT,'YYYY-MM-DD-HH24.MI.SS."000000"')When I try to run the query I get Message=ORA-00936: missing expression (50,380)
Any suggestions you could provide to help me clear this error would be greatly appreciated.
Edited by: 992737 on Mar 8, 2013 9:07 AM

Hi,
Welcome to the forum!
I think you want something like this:
CASE
    WHEN a.f_req_st_dt < TRUNC (SYSDATE) - 60 THEN '>60'
    WHEN a.f_req_st_dt < TRUNC (SYSDATE) - 30 THEN '30.1-60'
    WHEN a.f_req_st_dt < TRUNC (SYSDATE) - 15 THEN '15.1-30'
    WHEN a.f_req_st_dt < TRUNC (SYSDATE)       THEN '15 or less'
ENDNested CASE expressions aren't needed very much. Each WHEN clause is evaluated only if all the ealier ones have failed. For example, when testing to see if a row is in the 301.-60 range above (that is, the 2nd WHEN clause), there's no need to see if the difference is greater than or equal to 60; it wouldn't be evaluating that clause if the 1st WHEN condition was TRUE.
This assumes that a.f_req_st_dt is a TIMESTAMP or DATE; either datatype can be compared with DATEs, such as SYSDATE-60, so there's no need to conevert them to strings, and then convert them back into DATEs.
I hope this answers your question.
If not, post a little sample data (CREATE TABLE and INSERT statements, relevant columns only) for all tables involved, and also post the results you want from that data.
Simplify the problem as much as possible. Show only the parts that you don't already know how to do.
Explain, using specific examples, how you get those results from that data.
Always say which version of Oracle you're using (e.g., 11.2.0.2.0).
See the forum FAQ {message:id=9360002}
Never write, let alone post, unformatted code. Indent the code to show the exent and structure of clauses (SELECT, FROM, etc.), and complex expressions (such as CASE). The forum FAQ explains how to use \ tags when posting formatted text on this site.

How to use the CASE Expression in Where Cluase?

Hi All,
I'm trying to use the CASE Expression in the Where Clause at some trigger on the Form?
I've tried this Code:
Declare
N Number;
begin
SELECT COUNT(E.EMP_SID)
     INTO N
     FROM EMPLOYEES E, RANKS R
     WHERE CASE WHEN R.qualification_sid = 1104 AND E.rank_sid = 8 THEN
     (TO_DATE(E.RANK_DATE, 'DD-MM-RR')+(365*M.spe_per)+1)
     ELSE
     (TO_DATE(E.RANK_DATE, 'DD-MM-RR')+(365*M.mili_yea_per)+1)
     END
     BETWEEN TO_DATE('01-07-2011', 'DD-MM-RR') AND TO_DATE('31-07-2011', 'DD-MM-RR');
END;
When I run this code as a normal query at any SQL editor it works successfully, But When I Compile it at some trigger on the Form it gives me this error:
Encountered the symbol "CASE" when expecting one of the following:
( - + mod ......
Heeey how to specify the previous code to be shown as code in the thread?
Note: I'm using Forms 6i

OK I tried it and worked but for one condition:
WHERE DECODE (E.qualification_sid, 1104,
     (TO_DATE(E.RANK_DATE, 'DD-MM-RR')+(365*M.spe_per)+1),
     (TO_DATE(E.RANK_DATE, 'DD-MM-RR')+(365*M.mili_yea_per)+1))
     BETWEEN TO_DATE('01-07-2011', 'DD-MM-RR') AND TO_DATE('31-07-2011', 'DD-MM-RR')
But how to put two conditions for the same Expression:
WHERE DECODE ((E.qualification_sid, 1104) AND (E.RANK_SID, 8),
     (TO_DATE(E.RANK_DATE, 'DD-MM-RR')+(365*M.spe_per)+1),
     (TO_DATE(E.RANK_DATE, 'DD-MM-RR')+(365*M.mili_yea_per)+1))
     BETWEEN TO_DATE('01-07-2011', 'DD-MM-RR') AND TO_DATE('31-07-2011', 'DD-MM-RR')
The previous code gives me this error: missing right parenthesis

Case statement in where clause ??

Hello gurus,
Can we use case statements in where clause ?? Any example will be great!
And also i would like to know, besides CASE and DECODE statements, Is there any way we can use IF ELSE statements in SELECT clause or in WHERE clause ?
Thank you!!

Hi,
user642297 wrote:
Hoek,
Thanks for the reply
Whatever you return from 'then' should match your criteria.I didnt get this part...can you elaborate this part ?? Thank you!!Remember what a CASE expression does: it returns a single value in one of the SQL data types (or NULL).
You're probably familiar with conditions such as
WHERE   col = 1Inthe example above, col could be replaced by any kind of expression: a function call, and operation (such as "d * 24") or a CASE expression, which is exactly what Hoek posted:
where case
         when col = 6 then 1
         when col = 9 then 1
       end = 1;I think what Hoek meant about mnatching was this: since the CASE expression is being compared to a NUMBER, then every THEN clause (as well as the ELSE, if there is one) should return the same data type. You can't have one THEN clause return a NUMBER, and another one in the same CASE expression return a DATE, like this:
where case
         when col = 6 then 1
         when col = 9 then SYSDATE     -- WRONG! Raises ORA-00932: inconsistent datatypes
       end = 1;
By the way, it's rare when a CASE expression really helps in a WHERE clause. CASE is great for doing conitional stuff in places where you otherwise can't (in the ORDER BY clause, for example), but the WHERE clause was designed for conditions.
Hoek was just trying to give a simple example. If you really wanted those results, it would be simpler to say:
where col = 6
or     col = 9and simpler still to say
where col IN (6, 9)

Case statement within where clause

How can i write a case statement within Where clause of SQL statement.
Ex:
If sysdate is less than Dec 31 of 2009 then run the query for 2009 else run the query for 2010.
belwo query is not working. Please let me know how can i write a case statement within where clause.
Select * from table
where
Case
when to_char(sysdate,'yyyymmdd')<=20091231 then tax_year=2009
else tax_year=2010
End

Hi,
You can get the results you want like this:
Select *
from      table
where   tax_year = Case
                  when to_char(sysdate,'yyyymmdd') <= 20091231
                  then 2009
                  else 2010
             End
;A CASE expression returns a single value in one of the SQL data types, such as a NUMBER, VARCHAR2 or DATE. There is no boolean type in SQL.

Case Expression syntax

Hi,
I am writing the below program.
when case_not_found exception raises
can any one help me....
declare
i integer := 10;
l_result NUMBER;
begin
   l_result:= CASE i
                 WHEN 1 THEN 2
                   WHEN 2 THEN 3
                     END CASE;
EXCEPTION
WHEN CASE_NOT_FOUND THEN
    dbms_output.put_line(nvl(l_result,200));
end;Regards,
Rajesh

A case statement, when does not find an Appropriate match, raises a CASE_NOT_FOUND Exception.
On the contrary, the Case Expression, returns a NULL Value.
Since, you used a Case Statement, use the ELSE clause to return some value, say NULL, and the select statement will nto fail.
Modify it this way:
declare
i integer := 10;
l_result NUMBER;
begin
   l_result:= CASE i
                 WHEN 1 THEN 2
                   WHEN 2 THEN 3
                 else NULL
                     END;
EXCEPTION
WHEN CASE_NOT_FOUND THEN
    dbms_output.put_line(nvl(l_result,200));
end;Extract for Oracle Documentation
+"If the ELSE clause is omitted, the system substitutes a default action. For a CASE statement, the default when none of the conditions matches is to raise a CASE_NOT_FOUND exception. For a CASE expression, the default is to return NULL."+
Read For more info on Case Expression and Case Statement
Edited by: Purvesh K on Dec 13, 2012 12:26 PM

CASE STATEMENTS AND CASE EXPRESSIONS IN ORACLE9I PL/SQL

제품 : PL/SQL
작성날짜 : 2001-11-13
CASE STATEMENTS AND CASE EXPRESSIONS IN ORACLE9I PL/SQL
=======================================================
PURPOSE
아래의 자료는 Case 문에서 oracle 8.1.7과 Oracle 9i의 New Feature로 8.1.7에서는
sqlplus 에서만 가능했고, 9i 부터는 pl/sql 까지 가능하다.
Explanation
1. Oracle 8.1.7 Feature
Oracle 8.1.7 에서 Case 문은 Decode 문과 유사하지만, 기존의 decode 문을 쓰는 것보다
더 많은 확장성과 Logical Power와 좋은 성능을 제공한다. 주로 나이와 같이 category 별로
나눌때 주로 사용하고 Syntex는 아래와 같다.
CASE WHEN <cond1> THEN <v1> WHEN <cond2> THEN <v2> ... [ELSE <vn+1> ] END
각각의 WHEN...THEN 절의 argument 는 255 까지 가능하고 이 Limit를 해결하려면
Oracle 8i Reference를 참조하면 된다.
The maximum number of arguments in a CASE expression is 255, and each
WHEN ... THEN pair counts as two arguments. To avoid exceeding the limit of 128 choices,
you can nest CASE expressions. That is expr1 can itself be a CASE expression.
Case Example : 한 회사의 모든 종업원의 평균 봉급을 계산하는데 봉급이 $2000보다 작은경우
2000으로 계산을 하는 방법이 pl/sql을 대신하여 case function을 사용할 수 있다.
SELECT AVG(CASE when e.sal > 2000 THEN e.sal ELSE 2000 end) FROM emp e;
Case Example : 나이를 column으로 가지고 있는 customer table을 예로 들어보자.
SQL> SELECT
2 SUM(CASE WHEN age BETWEEN 70 AND 79 THEN 1 ELSE 0 END) as "70-79",
3 SUM(CASE WHEN age BETWEEN 80 AND 89 THEN 1 ELSE 0 END) as "80-89",
4 SUM(CASE WHEN age BETWEEN 90 AND 99 THEN 1 ELSE 0 END) as "90-99",
5 SUM(CASE WHEN age > 99 THEN 1 ELSE 0 END) as "100+"
6 FROM customer;
70-79 80-89 90-99 100+
4 2 3 1
1 SELECT
2 (CASE WHEN age BETWEEN 70 AND 79 THEN '70-79'
3 WHEN age BETWEEN 80 and 89 THEN '80-89'
4 WHEN age BETWEEN 90 and 99 THEN '90-99'
5 WHEN age > 99 THEN '100+' END) as age_group,
6 COUNT(*) as age_count
7 FROM customer
8 GROUP BY
9 (CASE WHEN age BETWEEN 70 AND 79 THEN '70-79'
10 WHEN age BETWEEN 80 and 89 THEN '80-89'
11 WHEN age BETWEEN 90 and 99 THEN '90-99'
12* WHEN age > 99 THEN '100+' END)
SQL> /
AGE_G AGE_COUNT
100+ 1
70-79 4
80-89 2
90-99 3
Example
2. Oracle 9i Feature
Oracle 9i부터는 pl/sql에서도 case문을 사용할 수 있으면 이것은
복잡한 if-else 구문을 없애고, C언어의 switch문과 같은 기능을 한다.
아래의 9i pl/sql Sample 및 제약 사항을 보면 아래와 같다.
Sample 1:
A simple example demonstrating the proper syntax for a case
statement
using a character variable as the selector. See the section entitled
'Restrictions' at the end of this article for details on which PLSQL
datatypes may appear as a selector in a case statement or
expression.
- - - - - - - - - - - - - - - - Code begins here - - - - - - - - - - - -
set serveroutput on
declare
achar char(1) := '&achar';
begin
case achar
when 'A' then dbms_output.put_line('The description was Excellent');
when 'B' then dbms_output.put_line('The description was Very Good');
when 'C' then dbms_output.put_line('The description was Good');
when 'D' then dbms_output.put_line('The description was Fair');
when 'F' then dbms_output.put_line('The description was Poor');
else dbms_output.put_line('The description was No such Grade');
end case;
end;
- - - - - - - - - - - - - - - - Code ends here - - - - - - - - - - - -
Sample 2:
A simple example demonstrating the proper syntax for a case
expression
using a character variable as the selector. See the section entitled
'Restrictions' at the end of this article for details on which PLSQL
datatypes may appear as a selector in a case statement or
expression.
- - - - - - - - - - - - - - - - Code begins here - - - - - - - - - - - -
set serveroutput on
declare
achar char(1) := '&achar';
description varchar2(20);
begin
description :=
case achar
when 'A' then 'Excellent'
when 'B' then 'Very Good'
when 'C' then 'Good'
when 'D' then 'Fair'
when 'F' then 'Poor'
else 'No such grade'
end;
dbms_output.put_line('The description was ' || description);
end;
- - - - - - - - - - - - - - - - Code ends here - - - - - - - - - - - -
NOTE: The above simple samples demonstrate two subtle differences in the
syntax
required for case statements and expressions.
1) A case STATEMENT is terminated using the 'end case' keywords; a
case
EXPRESSION is terminated using only the 'end' keyword.
2) Each item in a case STATEMENT consists of one or more
statements, each
terminated by a semicolon. Each item in a case expression
consists of
exactly one expression, not terminated by a semicolon.
Sample 3:
Sample 1 demonstrates a simple case statement in which the selector
is
compared for equality with each item in the case statement body.
PL/SQL
also provides a 'searched' case statement as an alternative; rather
than
providing a selector and a list of values, each item in the body of
the
case statement provides its own predicate. This predicate can be any
valid boolean expression, but only one case will be selected.
- - - - - - - - - - - - - - - - Code begins here - - - - - - - - - - - -
set serveroutput on
declare
achar char(1) := '&achar';
begin
case
when achar = 'A' then dbms_output.put_line('The description was
Excellent');
when achar = 'B' then dbms_output.put_line('The description was Very
Good');
when achar = 'C' then dbms_output.put_line('The description was
Good');
when achar = 'D' then dbms_output.put_line('The description was
Fair');
when achar = 'F' then dbms_output.put_line('The description was
Poor');
else dbms_output.put_line('The description was No such Grade');
end case;
end;
- - - - - - - - - - - - - - - - Code ends here - - - - - - - - - - - -
Sample 4:
This sample demonstrates the proper syntax for a case expression of
the
type discussed in Sample 3 above.
- - - - - - - - - - - - - - - - Code begins here - - - - - - - - - - - -
set serveroutput on
declare
achar char(1) := '&achar';
description varchar2(20);
begin
description :=
case
when achar = 'A' then 'Excellent'
when achar = 'B' then 'Very Good'
when achar = 'C' then 'Good'
when achar = 'D' then 'Fair'
when achar = 'F' then 'Poor'
else 'No such grade'
end;
dbms_output.put_line('The description was ' || description);
end;
- - - - - - - - - - - - - - - - Code ends here - - - - - - - - - - - -
Sample 5:
This sample demonstrates the use of nested case statements. It is
also
permissable to nest case expressions within a case statement (though
it
is not demonstrated here), but nesting of case statements within a
case
expression is not possible since statements do not return any value.
- - - - - - - - - - - - - - - - Code begins here - - - - - - - - - - - -
set serveroutput on
declare
anum1 number := &anum1;
anum2 number := &anum2;
answer number;
begin
case anum1
when 1 then case anum2
when 1 then answer := 10;
when 2 then answer := 20;
when 3 then answer := 30;
else answer := 999;
end case;
when 2 then case anum2
when 1 then answer := 15;
when 2 then answer := 25;
when 3 then answer := 35;
else answer := 777;
end case;
else answer := 555;
end case;
dbms_output.put_line('The answer is ' || answer);
end;
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Sample 6:
This sample demonstrates nesting of case expressions within another
case
expression. Note again the absence of semicolons to terminate both
the
nested case expression and the individual cases of those
expressions.
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set serveroutput on
declare
anum1 number := &anum1;
anum2 number := &anum2;
answer number;
begin
answer :=
case anum1
when 1 then case anum2
when 1 then 10
when 2 then 20
when 3 then 30
else 999
end
when 2 then case anum2
when 1 then 15
when 2 then 25
when 3 then 35
else 777
end
else 555
end;
dbms_output.put_line('The answer is ' || answer);
end;
- - - - - - - - - - - - - - - - Code ends here - - - - - - - - - - - -
Although PL/SQL anonymous blocks have been used in all of the examples
so far,
case statements and expressions can also be used in procedures,
functions, and
packages with no changes to the syntax.
The following samples are included for completeness and demonstrate the
use of
case statements and/or expressions in each of these scenarios.
Sample 7:
This sample demonstrates use of a case statement in a stored
procedure.
Note that this sample also demonstrates that it is possible for each
of
the items in the case body to consist of more than one statement.
- - - - - - - - - - - - - - - - Code begins here - - - - - - - - - - - -
set serveroutput on
create or replace procedure testcasestmt ( anum IN number ) is
begin
case
when anum = 1 then dbms_output.put_line('The number was One');
dbms_output.put_line('In case 1');
when anum = 2 then dbms_output.put_line('The number was Two');
dbms_output.put_line('In case 2');
when anum = 3 then dbms_output.put_line('The number was Three');
dbms_output.put_line('In case 3');
when anum = 4 then dbms_output.put_line('The number was Four');
dbms_output.put_line('In case 4');
when anum = 5 then dbms_output.put_line('The number was Five');
dbms_output.put_line('In case 5');
else dbms_output.put_line('The description was Invalid input');
dbms_output.put_line('In the else case');
end case;
end;
exec testcasestmt(&anum);
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Sample 8:
This sample demonstrates the use of a case statement in a stored
package.
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set serveroutput on
create or replace package testpkg2 is
procedure testcasestmt ( anum IN number );
function testcasestmt_f ( anum IN number ) return number;
end testpkg2;
create or replace package body testpkg2 is
procedure testcasestmt ( anum IN number ) is
begin
case
when anum = 1 then dbms_output.put_line('The number was One');
dbms_output.put_line('In case 1');
when anum = 2 then dbms_output.put_line('The number was Two');
dbms_output.put_line('In case 2');
when anum = 3 then dbms_output.put_line('The number was Three');
dbms_output.put_line('In case 3');
when anum = 4 then dbms_output.put_line('The number was Four');
dbms_output.put_line('In case 4');
when anum = 5 then dbms_output.put_line('The number was Five');
dbms_output.put_line('In case 5');
else dbms_output.put_line('The description was Invalid input');
dbms_output.put_line('In the else case');
end case;
end;
function testcasestmt_f ( anum IN number ) return number is
begin
case
when anum = 1 then dbms_output.put_line('The number was One');
dbms_output.put_line('In case 1');
when anum = 2 then dbms_output.put_line('The number was Two');
dbms_output.put_line('In case 2');
when anum = 3 then dbms_output.put_line('The number was Three');
dbms_output.put_line('In case 3');
when anum = 4 then dbms_output.put_line('The number was Four');
dbms_output.put_line('In case 4');
when anum = 5 then dbms_output.put_line('The number was Five');
dbms_output.put_line('In case 5');
else dbms_output.put_line('The description was Invalid input');
dbms_output.put_line('In the else case');
end case;
return anum;
end;
end testpkg2;
exec testpkg2.testcasestmt(&anum);
variable numout number
exec :numout := testpkg2.testcasestmt_f(&anum);
print numout
- - - - - - - - - - - - - - - - Code ends here - - - - - - - - - - - -
Sample 9:
This sample demonstrates the use of a case expression in a stored
package.
- - - - - - - - - - - - - - - - Code begins here - - - - - - - - - - - -
set serveroutput on
create or replace package testpkg is
procedure testcase ( anum IN number );
function testcase_f ( anum IN number ) return number;
end testpkg;
create or replace package body testpkg is
procedure testcase ( anum IN number ) is
anumber number := anum;
anothernum number;
begin
anothernum :=
case
when anumber = 1 then anumber + 1
when anumber = 2 then anumber + 2
when anumber = 3 then anumber + 3
when anumber = 4 then anumber + 4
when anumber = 5 then anumber + 5
else 999
end;
dbms_output.put_line('The number was ' || anothernum);
end;
function testcase_f ( anum IN number ) return number is
anumber number := anum;
anothernum number;
begin
anothernum :=
case
when anumber = 1 then anumber + 1
when anumber = 2 then anumber + 2
when anumber = 3 then anumber + 3
when anumber = 4 then anumber + 4
when anumber = 5 then anumber + 5
else 999
end;
dbms_output.put_line('The number was ' || anothernum);
return anothernum;
end;
end testpkg;
variable numout number
exec testpkg.testcase(&anum);
exec :numout := testpkg.testcase_f(&anum);
print numout
- - - - - - - - - - - - - - - - Code ends here - - - - - - - - - - - -
제약 사항
다음의 databasetype은 case 문에서 지원되지 않는다.
BLOB
BFILE
VARRAY
Nested Table
PL/SQL Record
PL/SQL Version 2 tables (index by tables)
Object type (user-defined type)
All of these types except for object types face a similar restriction
even for if statements (i.e. they cannot be compared for equality directly) so this is unlikely to change for these types. Lack of support for object types is simply an implementation restriction which may be relaxed in future releases.
Reference Ducumment
Oracle 8.1.7 Manual
NOTE:131557.1

I have done the following code but doesn't
like the statement of - "case(butNext)". What do you mean "doesn't like" -- did you get an error message?
I'm guessing it won't compile because you're trying to switch on a Button.
I tried something
like "g.fillOval(100,50,70,90, BorderLayout.NORTH)"...no that doesn't make sense. You only use BorderLayout.NORTH when you're adding components to a BorderLayout layout manager. An oval is not a component and fillOval isn't adding a component and Graphics is not a Panel or layout manager.
Would appreciate it if someone could tell me how to position
shapes using the graohic method. I think the problem is that you're confusing shapes with components.

Nested CASE expressions in SQL Server 2008 R2

Hi, For some reason when I use the below CASE expression in my SELECT statement I get duplicate records.
CASE WHEN <Condition 1> THEN <Expression 1>
WHEN <Condition 2> THEN <Expression 2>
WHEN <Condition 3> THEN <Expression 3>
WHEN <Condition 4> THEN <Expression 4>
END AS CaseResult
Also tried using coalesce with no luck. How to write a nested CASE expression which would yield just one expression. In case if I have to combine 2 different Expressions for 1 record, Is there a way to merge the 2 Expressions writing CASE
expression something like below.
STUFF ((SELECT ',' + CASE WHEN <Condition 1> THEN <Expression 1>
WHEN <Condition 2> THEN <Expression 2>
WHEN <Condition 3> THEN <Expression 3>
WHEN <Condition 4> THEN <Expression 4>
END
FOR XML PATH(''), ROOT('MyString'), TYPE).value('/MyString[1]','VARCHAR(MAX)'), 1, 1,'') AS CaseResult
--ResultSet
CaseResult
<Expression 1, Expression 2>
I am using SQL Server 2008 R2. Thanks in advance.......
Ione

Hi, For some reason when I use the below CASE expression in my SELECT statement I get duplicate records. Also tried using coalesce with no luck. How to write a nested CASE expression which would yeild just one expression. In case if I have to combine 2 different
Expressions for 1 record, Is there a way to merge the 2 Expressions writing CASE expression something like below in SQL Server 2008 R2.
CASE WHEN <Condition 1> THEN <Expression 1>
WHEN <Condition 2> THEN <Expression 2>
WHEN <Condition 3> THEN <Expression 3>
WHEN <Condition 4> THEN <Expression 4>
END AS CaseResultSTUFF ((SELECT ',' + CASE WHEN <Condition 1> THEN <Expression 1>
WHEN <Condition 2> THEN <Expression 2>
WHEN <Condition 3> THEN <Expression 3>
WHEN <Condition 4> THEN <Expression 4>
END
FOR XML PATH(''), ROOT('MyString'), TYPE).value('/MyString[1]'<span clas
Ione

Case expression error with a select query in the condition

Consider the two query below:
1. The first one use a case expression :
select case when 3 > (select 1 from dual)*2 then 1 else 0 end from dual
2. The equivalent with a decode expression:
select
decode(sign(3-(select 1 from dual)*2),1,1,0) from dual
The first query return an ORA-00905 error but not the second one. It seems that the arithmetic operation (select 1 from dual)*2 cause the error. The folowing query doesn't return this error:
select case when 3 > (select 2 from dual) then 1 else 0 end from dual
I run the test with Oracle 8.1.7.3 Enterprise Edition. Is it a known bug ?
Thomas

ora8174>select case when 3 > (select 1 from dual)*2 then 1 else 0 end from dual;
select case when 3 > (select 1 from dual)*2 then 1 else 0 end from dual
ERROR at line 1:
ORA-00905: missing keyword
ora8174>select case when 3 > cast((select 1 from dual)*2 as number) then 1 else 0 end from dual;
CASEWHEN3>CAST((SELECT1FROMDUAL)*2ASNUMBER)THEN1ELSE0END
                                                       1
1 row selected.
ora8174>select case when 3 > to_number((select 1 from dual)*2) then 1 else 0 end from dual;
CASEWHEN3>TO_NUMBER((SELECT1FROMDUAL)*2)THEN1ELSE0END
                                                    1
1 row selected.
ora8174>@connect
Connected.
ora9204>select case when 3 > (select 1 from dual)*2 then 1 else 0 end from dual;
CASEWHEN3>(SELECT1FROMDUAL)*2THEN1ELSE0END
                                         1
1 row selected.

Qualifying Expression and WHERE CLAUSE Extension

I would like to know the exact difference between 'Qualifying Expression and WHERE CLAUSE Extension'. Since both are meant to contain some CONDITION that would facilitate the Edit Check's success, So I am sometimes a bit confused with these too as to when to use what.
Can someone help Please??

As you can tell from my previous posts (requests!) - I'm a newbie to OC.
From the documentation - it appears that both Qualifying expression and Where Clause work the same way but the way they execute is different.
Qualifying expression is applied after the fetch (key fields and question response data from DCM cursor i.e., after the cursor fetches the data) and Where clause filters before QG fetch.
HTH

How to use CASE stmt in Where clause

Hi,
How to use CASE stmt in WHERE clause?. I need the code. Please send me as early as possible..........

Hi,
1004977 wrote:
Hi,
How to use CASE stmt in WHERE clause?. There's no difference between how a CASE expression is used in a WHERE clause, and how it is used in any other clause. CASE ... END always returns a single scalar value, and it can be used almost anywere a single scalar expression (such as a column, a literal, a single-row function, a + operation, ...) can be used.
CASE expressions aren't needed in WHERE clauses very much. The reason CASE expressions are so useful is that they allow you to do IF-THEN-ELSE logic anywhere in SQL. The WHERE clause already allows you to do IF-THEN-ELSE logic, usually in a more convenient way.
I need the code.So do the peple who want t help you. Post a query where you'd like to use a CASE expression in the WHERE clause. Post CREATE TABLE and INSERT statements for any tables used unless they are commonly available, such as scott.emp). Also, post the results you want from that sample data, and explain how you get those resuts from that data.
See the forum FAQ {message:id=9360002}
Please send me as early as possible..........As mentioned bfore, that's rude. It's also self-defeating. Nobody will refuse to help you because you don't appear pushy enough, but some people will refuse to help you if you appear too pushy.

Oracle:how to use max() function in case expression

how to use max() function in case expression, Please explain with any example

Hope this helps and should be self explanatory
with t as
(select 1 col,100 col2 from dual union
select 2 ,100 from dual union
select 2 ,200 from dual union
select 3,100 from dual union
select 3,200 from dual )
select col, case when max(col2)=100 then 'with 100 range'
when max(col2)=200 then 'with 200 range' end from t group by col

CASE in a WHERE clause : ORA-00905

Hi everyone,
I am trying to use a CASE in a WHERE clause and I got the error ORA-00905: missing keyword. Here is my code :
SELECT id_reserv,
     concat(nom,concat('_',indice)) as nom,
     libelle,
     num_lot,
     resa_keyword1,
     resa_keyword2,
     resa_keyword3,
     resa_keyword4,
     date_creation,
     comm_creation,
     id_util,
     actif,
     id_env_act,
     (SELECT login from utilisateur u where u.id_util=r.id_util) AS nom_util,
     (SELECT nom from environnement e where e.id_env=r.id_env_act) AS nom_env,
     (SELECT count(*) from reserv_comp rc where rc.id_reserv=r.id_reserv) AS nbComp,
     (SELECT count(*) from reserv_modif mc where mc.id_reserv=r.id_reserv) AS nbModif
FROM reservation r
     WHERE r.nom NOT LIKE 'RESERV_LOT_%'
     AND id_util='1'
     AND actif='1'
     AND id_env_act>='-1'
     AND CASE sansdemande
     WHEN true THEN id_reserv not in select id_reserv from demande_livraison where id_env_dep>='-1'
     ELSE id_reserv=id_reserv
     END
     AND nom LIKE '%'
ORDER BY date_creation;
I already looked at the CASE statement and it seems that the syntax is correct, so I'm not sure I can use it in a WHERE clause.
Any help would be nice !
Guich

Hi,
it should be something like this:
AND CASE
WHEN 'false'='true' THEN (select id_reserv from demande_livraison where id_env_dep>='-1')
ELSE id_reserv
     END = id_reserv The subquery should give one row back
But I think it is better to write your query as:
SELECT id_reserv,
     concat(nom,concat('_',indice)) as nom,
     libelle,
     num_lot,
     resa_keyword1,
     resa_keyword2,
     resa_keyword3,
     resa_keyword4,
     date_creation,
     comm_creation,
     id_util,
     actif,
     id_env_act,
     (SELECT login from utilisateur u where u.id_util=r.id_util) AS nom_util,
     (SELECT nom from environnement e where e.id_env=r.id_env_act) AS nom_env,
     (SELECT count(*) from reserv_comp rc where rc.id_reserv=r.id_reserv) AS nbComp,
     (SELECT count(*) from reserv_modif mc where mc.id_reserv=r.id_reserv) AS nbModif
FROM reservation r
     WHERE r.nom NOT LIKE 'RESERV_LOT_%'
     AND id_util='1'
     AND actif='1'
     AND id_env_act>='-1'
     AND
                      ( 'false'='true' and id_reserv not in (select id_reserv from demande_livraison where id_env_dep>='-1')
                      or
                      ( 'true'= 'true' and id_reserv=id_reserv
     AND nom LIKE '%'
ORDER BY date_creation;This coding in SQL something as if a=b then c, else d in the simplest form.
Herald ten Dam
http://htendam.wordpress.com

SQL Loader Control file WHEN clause

LOAD DATA
REPLACE
INTO TABLE IDL_Investments
WHEN average_balance < '100.00'
FIELDS TERMINATED BY X'9'
TRAILING NULLCOLS
Borrower_Id,
Account_No,
customer_No,
cptype_id "GETID(:cptype_id)",
customer_name,
average_balance,
CP_GroupName,
CP_type,
Account_Type,
Instrument_type,
DD_date "TO_DATE(:DD_date, 'dd/mm/yy')",
fac_Maturity_date "TO_DATE(:fac_Maturity_date, 'dd/mm/yy')"
above one is the control file. when i tried to load data i waas getting the following error.
SQL*Loader-350: Syntax error at line 4.
Illegal combination of non-alphanumeric characters
WHEN average_balance < '100.00'
^
instead of '<' symbol if i place an '=' symbol then its workig fine.
So how do I use <, <=, > or >= operators in a WHEN clause of a control file can any one help me?
Thanks in advance.

Thanks for the suggestion but by searching in someother sites i found that
only equality operators ('=', '!=' or '<>') are permited in the WHEN clause expressions of a control file in SQL Loader.
So now i changed my logic.
thanks anyway.

Case Expression in when clause

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