Changing a char-string into decimal

i have a problem:
over my serial connection i just get strings in char but i need decimal numbers!
can you help me!
thx wiesi

What do you mean "a normal number"? This is a number, 97, and it's inside an array. What do you expect this number to be? To extract it from the array you have various options, from using an index array function to using an auto indexed for loop.
If your problem is with using the array, I suggest you read the LabVIEW user manual. Also, try searching this site and google for LabVIEW tutorials. Here is one you can start with. You can also contact your local NI office and join one of their courses.
In addition, I suggest you read the LabVIEW style guide.
Try to take over the world!

Similar Messages

How to change raw char string to 16-bit 2's complement integer?

Hi,
Please see the following raw char sting
óèóóóóþþóèþóóóþóþóóèþóóóóóóóóóþóóóóóèóóóóóþóóþþóóóþóèóóþóèþóèóþóóþóóèþóóóþèóóþóþóþóóóþóóóþóèóþþèþóþó
How could I converter it to 16-bit short signed integer 2's complement?
Thanks,
Ott
Solved!
Go to Solution.

What do you expect for the output? Something like this?
There are only two ways to tell somebody thanks: Kudos and Marked Solutions
Unofficial Forum Rules and Guidelines
Attachments:
To I16 Array.png ‏20 KB

How do I convert a string into a decimal

I've been tryin to convert a string into decimal but I can't get it to work at all. I keep getting an exception.
I've tried all of these:
double myDouble = Double.valueOf(string).doubleValue();
int myint = Interger.parseInt(string);
float myfloat = Float.parseFloat(string);
I can't get anything to work.
That string i'm reading in is an array containing values with decimals. ex: -45.09348
All the above work fine if there is no decimal, but fails when it comes to one.
How do I go about doing this?
Thanks!

This works for me:String s = "-45.6789";
double d = Double.parseDouble(s);
System.out.println(d);Mark

Eliminating ###'s after hex reconversion to char string

This is interesting.
I was originally required to pass a segment to my subroutine. I had to do so using text literals. The   symbol is not recognizable by text literals. Therefore, I had to convert the entire string to hex.
I then passed the hex segment to the subroutine, and reconverted it back to char string.
After this I found a ton of unexpected # symbols in my segment. I tried doing a
REPLACE '###' WITH '' INTO CHARSTRING.
, but unsuccessfully. There is not much documentation on hex_to_char conversion, there are 2 FMs on 46, but I cannot get them to work. If anyone knows how to eliminate these unexpected # symbols please let me know.

DATA: HEXSTRINGER(6000) TYPE 'X'.
DATA: STRINGER(3000) TYPE 'C'.
FIELD-SYMBOLS: <FSHEX>, <RECONVERT2>.
CALL FUNCTION 'ARCHIVE_GET_NEXT_RECORD'
               EXPORTING
                     ARCHIVE_HANDLE       = READ_HANDLE
               IMPORTING
                     RECORD               = ARC_BUFFER-SEGMENT
                     RECORD_STRUCTURE     = ARC_BUFFER-RNAME
           MOVE ARC_BUFFER-SEGMENT TO SEGSTER.
           assign SEGSTER to <fsHEX> type 'X'.
           MOVE <fsHEX> to HEXSTRINGER.
APPEND 'REPORT ZSUBR.' TO CODE.
APPEND 'FORM DYN1 USING HEXSTRINGER.' TO CODE.
APPEND 'DATA: SEGSTER2(3000) TYPE ''C''.' TO CODE.
APPEND 'ASSIGN HEXSTRINGER TO <RECONVERT2> TYPE ''C'' .' TO CODE.
APPEND 'MOVE <RECONVERT2> TO SEGSTER2.' TO CODE.
APPEND 'WRITE:/ SEGSTER2.' TO CODE.
APPEND 'ENDFORM.' TO CODE.
I write out Segster2 and compare it to segster.
I've done some variations of this where after I change the char string to hex string I replace 'C' with '7C' into hexstringer and then re-replace it in the subroutine, and then reconvert it to a char string- but actually I don't think that was a necessary step. I believe I can just convert it to hex, and then reconvert it back to hex in the subroutine.

How can I get an unsigned char string with nulls from a dll into LabVIEW 6i?

The following ethernet packet data is contained in an unsigned char * string returned from my dll (it's formatted on printing):
Received A 230 Packet On Adapter 0x008F0070
Ethernet Dest: 01.E0.BB.00.00.15 Src: 00.E0.BB.00.DD.CC Type: 0x8868
000000: 01 E0 BB 00 00 15 00 E0 : BB 00 DD CC 88 68 48 41 .............hHA
000010: 00 E0 BB 00 DD CC 80 B3 : 00 00 FF FF 00 02 00 01 ................
000020: 01 00 F0 18 FF 7F 7F FF : FF 7F 7F FF FF 7F 7F FF ................etc., etc.
However, when I read this string into LabVIEW 6i, I only get the following:
01E0 BB
Which is the data before the first NULL or 00 information. I found a "Remove Unprintable Chars.vi" but it
just sees more data before the above string, nothing after, as seen here: 5C30 31E0 BB.
Anybody have any suggestions for how to get the rest of the string? Is there something I can do to further reformat my dll? The dll I'm using is already a wrapper around another dll so I have some flexibility, but the bottom line is, the data I want is in the format of an unsigned char *.

Excellent advice, this mostly works so I have some further questions:
I am just reading network traffic off my ethernet card right now, but here is what I get using my C program to test:
000000: 01 E0 BB 00 00 15 00 E0 : BB 00 DD CC 88 68 48 41 .............hHA
000010: 00 E0 BB 00 DD CC 80 B3 : 00 00 FF FF 00 02 00 01 ................
000020: 01 00 38 3C FF 7F 7F 7F : 7F 7F 7F FF FF 7F 7F FF ..8<............
000030: FF 7F 7F FF FF 7F 7F FF : 7F 7F 7F FF FF FF FF FE ................
000040: FE FF FF FF FF 7F 7F 7F : 7F 7E 7E 7F 7F 7E 7E FF .........~~..~~.
000050: 7F 7F 7F 7F FF 7F 7F 7F : 7F 7F 7F FF FF 7F 7E 7F ..............~.
000060: 7F 7F 7E 7F 7F 7E 7F FF : FF 7F FF FF FE FF FF FE ..~..~..........
000070: FF FF FF FF FF 7F 7F FF : FF 7F 7F FF FF FF FF FF ................
000080: FF 7F 7F FF FF 7F 7F FF : FF 7F 7F FF FF 7F 7F FF ................
000090: FF 7F 7F 7F FF 7F 7F 7F : 7F 7F 7F FF FF 7F 7F FF ................
0000A0: FF 7F 7F 7F 7F 7E 7E 7F : 7F 7F FF FF FF FF FF FF .....~~.........
0000B0: FF FF 7F FF FF 7F 7F FF : 7F 7F 7F FF FF 7E 7F FF .............~..
0000C0: FF FF 7F FF FF 7F 7F FF : 7F 7F 7F FF FF 7F 7F FF ................
0000D0: FF 7F 7F FF FF 7F 7F 7F : 7F 7F 7F FF FF FF FF FE ................
0000E0: FE FF FF FF 00 01 : ................
And here is what I get using LabVIEW to call the dll:
0015 00E0 BB00 DDCC 8868 4841 00E0 BB00 DDCC 80B3 0000 FFFF 0002 0001 0100 9600 7F7F 7F7E 7F7F 7F7F 7F7F 7F7F 7F7F 7F00 B405 4300 3300 0000 0000 0000 01E0 BB00 0015 00E0 BB00 DDCC 8868 4841 00E0 BB00 DDCC 80B3 0000 FFFF 0002 0001 0100 9600 7F7F 7F7E 7F7F 7F7F 7F7F 7F7F 7F7F 7F00 F405 1B04 0C04 0000 0000 0000 8000 0000 0000 0000 0800 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000
The first thing I notice is that the first 4 bytes are chopped off, and after about 50 bytes, the data is corrupted until the sequence starts to repeat, but this time it starts with the missing 4 bytes and still corrupts after about 55 bytes.
I am expecting the data in LabVIEW to look very similar to the C data because the network packets I am grabbing are pretty consistant, only a couple bytes will vary between them, not the number I am seeing in LabVIEW.
Another side effect I'm seeing is that I can only run my labVIEW code once, if I try running it again it crashes with failures such as:
memory could not be "read"
For reference, I am opening and closing the network adapter inside the read function of my dll, but the pointer seems like it should be intact...
Attachments:
zListAdapters.vi ‏30 KB
listAdapters.dll ‏201 KB
Reading.dll ‏213 KB

How to store serval char variables into a string variable?

I have serval char variables, but i don't know how to put them together (without using arrays). I am thinking to store these char variables into a string variable but i don't know how to do it. For example,
char letter1 = 'a', letter2 = 'b', letter3 = 'c';
String letters;
then how can i do to make letters = "abc" from using letter1,2,3?
I am just a beginner of Java, if anyone can help me, i will appreciate that very much!!!

String letters=""+leter1+letter2+letter3;is fine and dandy. What it actually compiles to is
String letters = new StringBuffer().append(letter1).append(letter2).append(letter3).toString();Which ofcourse is much more code to write, but still good to know.
So do see the API for java.lang.StringBuffer.
Heikki

How to change elements in ArrayList into String

Greetings,
i like to change elements in arrayList into string.
This is how i declare an ArrayList in a Java file
ArrayList listing = new ArrayList();below is just a simple example of how i insert the string into the arraylist
String concat = "';
concat = concat + "apple";
//Transfer the concat string into arraylist
listing.add(concat);
return listing;
{code}
On my Jsp page, it will receive the ArrayList from the java file. Lets say the Arrayist is pass into my JSP arraylist
This is my JSP arraylist
{code}ArrayList optLists = new ArrayList();{code}
Inside the arraylist element, it holds data eg: *308577;;RS | [CAT 2] Level: Arena, Section: A02* with a pipe between RS and CAT 2.
Now i looping the arraylist
{code}int a = 0;
     for ( a=0; a < optLists.size(); a++)
          String tempString = "";
          String splitTemp = "";
                 String tempString = (String)optLists.get(a);
          splitTemp = tempString.split("|");
          System.out.println("Split String Results: "+ splitTemp);
     {code}}
Heres the error:
*SeatAvailable_jsp.java:560: incompatible types*
    *[javac] found   : java.lang.String[]*
    *[javac] required: java.lang.String*
    *[javac]             splitTemp = tempString.split("|");*
    *[javac]*
What can i do to solve the problem?
Edited by: leeChaolan on May 2, 2008 4:45 AM
Edited by: leeChaolan on May 2, 2008 4:48 AM

paternostro is right, you are returning an array into a string which is wrong
but try this, i haven't tested it though..
nt a = 0;
     for ( a=0; a < optLists.size(); a++)
          String tempString = "";
          String splitTemp = "";
                 String tempString = (String)optLists.get(a);
          String[] splitTemp = tempString.split("|");
          for(String xyz : splitTemp)
               System.out.println("Split String Results: "+ xyz);
     }Edited by: linker on May 2, 2008 1:17 PM
Edited by: linker on May 2, 2008 1:18 PM

How to replace the char values into numeric in my string?

Hi Friends,
I would like to Replace the Charecter values with numeric value in my string.
Exp : first in my string I am having the value like this : 'ABCD1234' ( may be any char and num values ), and I want too get it by '99991234'.
I mean How to replace the char values into numeric in my string?
Thanks,
Sridhar

Hi Sridhar,
I would like to Replace the Charecter values with numeric value in my string.
Exp : first in my string I am having the value like this : 'ABCD1234' ( may be any char and num values ), and I want too get it by '99991234'.
So, if i understand you correctly, you want to replace all characters in a string with 9 as in the above example, irrespective of position of the character, if so try with the below code.
DATA: l_str TYPE string.
l_str = 'ASKHSIUDNSBDKJSDH124312431243124saasdfsf'.
REPLACE ALL OCCURRENCES OF REGEX '\D' IN l_str WITH '9'.
IF sy-subrc EQ 0.
WRITE: l_str. "Result will be 9999999999999999912431243124312499999999
ENDIF.
Regards,
Chen
Edited by: Chen K V on Jun 13, 2011 12:36 PM

How do I convert an 8 bit serial data string I have received (say 01110101) into decimal format??

I am having a hard time finding a function that will help me convert an 8 bit serial data string I have received (say 01110101) into decimal format.

When you have your front panel displayed, you should a whole palette of controls that you can place on the front panel. If the palette is not displayed, thne just right click on your mouse and it should appear. The upper left most set of controls on the palette is Numeric. Go there and select Numeric Indicator to display a numeric output. On the diagram, you can also right click the output 1 and select Create>Indicator. The format string is %b (as in boy) for a binary string. As I said, this should be the value for the format string input. You can right click on the Scan From String and select Edit Scan String. This will bring up a dialog box in which you pick what you want to do (Scan Number) and how you want to do it (Scan Binary Integer
It sounds like you really need to take a course in LabVIEW programming. There are are links here to NI classes and some on-line tutorials.

Convert a String to Decimal Format in European format

Hi Experts,
I am having a string as a context type for a input field, where the user can enter the Price, I need to convert the same into European format "###.###,00", I am using this below code to convert the string to decimal format
User will enter the input as 10 as it needs to be converted into 10,00. Also, 1000 which has to be converted as 1.000,00
String Str1 = wdContext.currentvn_temptable.getVa_TempUnitPrice();
Locale mylocale = Locale.GERMAN;
String pattern="###.###,00";
NumberFormat nf = NumberFormat.getNumberInstance(mylocale);
DecimalFormat df = (DecimalFormat)nf;
df.applyPattern(pattern);
String output = df.format(Str1);
wdComponentAPI.getMessageManager().reportSuccess("Unit Price" + " " + pattern + " " + output);
When I execute the above code, i am getting an error called "Malformed Pattern ###.###,00"
Please let me know, how to convert a String to Quantity in European format
Thanks & Regards,
Palani

Hello!
Try to change your pattern to this one
Locale mylocale = Locale.GERMAN;
String pattern = "#,#00.00";
NumberFormat nf = NumberFormat.getNumberInstance(mylocale);
DecimalFormat df = (DecimalFormat)nf;
df.applyPattern(pattern);
String output = df.format(1111111.222);
Pattern has an influence on number of digits between separators, but you have to use ',' for grouping and '.' for decimal. Character values for separators correspond to your Locale object.
Thanks, Mikhail

Issue with splitting string into multiple lines

Hi Experts,
I have a long string s. I want to split this string into several lines each having 72 characters. For this I have done following programming:
     String s = "For the first time it includes a supplementary report attempting to determine if extreme weather
events can be linked to human-induced climate change. The research team, including members
of the UK Met Office, identified recent episodes of extreme weather then used a computer to
estimate the likelihood of the episode happening in a world without increased CO2." ;
     s = s.replaceAll("[\r\n]+", " ");
     char[] sAr = s.toCharArray();
     AbstractList RecepitsList7 = new Bapitrtext.Bapitrtext_List();;
     int start = 0; // start with
     int i = 72 ;
//     for (int i = 71; i < sAr.length; i++) {
while (i < sAr.length) {
//     {     if (sAr[i] == ' ')
               Bapitrtext Recepits7 = new Bapitrtext();
               Recepits7.setTextid("TEXT");
               Recepits7.setTextline(s.substring(start, i).replaceAll("[\r\n]+", ""));
               RecepitsList7.add(Recepits7);
               start = i+1;
               i += 72;
     input.setText(RecepitsList7);
The output of program is as below:
For the first time it includes a supplementary report attempting to dete
mine if extreme weather events can be linked to human-induced climate
hange. The research team, including members of the UK Met Office, iden
ified recent episodes of extreme weather then used a computer to estim
te the likelihood of the episode happening in a world without increased
Here as we can see last characters are getting deleted by program. For example in first line
determine 'r' is missing in extreme right.
In 3rd line c is missing in extreme left (word change is needed. Program
prints hange.
Also in 3rd line extreme right 't' is missing
Also in 4th line extreme right 'a' is missing
Also the last line is not being printed. In last line "CO2." " should appear.
There are two issues:
1. Why last word of each sentence is not being printed?
2. Why last sentence is not being printed?
I am struggling since last 2 days. Please help. I made all changes like replacing 72 by 71 etc.
By making such changes, I am able to print first line correctly. However under all cases
last character of 2nd line onward is not getting displayed.
Also last line is not getting displayed. I did every thing like using while instead of for loop etc.
Kindly help.
Regards,
Gary
Edited by: 945655 on Jul 10, 2012 11:39 PM

String s = wdContext.currentContextElement().getExpense_Text();
     s = s.replaceAll("[\r\n]+", " ");
     char[] sAr = s.toCharArray();
     AbstractList RecepitsList7 = new Bapitrtext.Bapitrtext_List();;
     int start = 0; // start with
     int i = 72;
while (i < sAr.length) {
               Bapitrtext Recepits7 = new Bapitrtext();
               Recepits7.setTextid("TEXT");
               System.out.println(s.substring(start, i));
               RecepitsList7.add(Recepits7);
               start = i+1;
               i += 72;
     input.setText(RecepitsList7);
Edited by: 945655 on Jul 11, 2012 2:25 AM

Using scan from string to convert a string into a number

I wanted to use scan from string to change a string into a decimal number, but when the string is, for example, 9.14123E-2 it just returns 10. How can I get it to return .00914 or 9.14E-2(as a number not a string). Would there be something easier than scan from string? I'm using labview 5.1. Thank you!

Hello,
May be you can checkout the attached example.
Perkash Mohan Lal
Institute of Semiconductor Technology
Technical University Braunschweig
Attachments:
string_conversion_1.vi ‏44 KB

OR ('|') in regular expressions (e.g. split a String into lines)

Which match gets used when you use OR ('|') to specify multiple possible matches in a regex, and there are multiple matches among the supplied patterns? The first one (in the order written) which matches? Or the one which matches the most characters?
To make this concrete, suppose that you want to split a String into lines, where the line delimiters are the same as the [line terminators used by Java regex|http://java.sun.com/javase/6/docs/api/java/util/regex/Pattern.html#lt] :
     A newline (line feed) character ('\n'),
     A carriage-return character followed immediately by a newline character ("\r\n"),
     A standalone carriage-return character ('\r'),
     A next-line character ('\u0085'),
     A line-separator character ('\u2028'), or
     A paragraph-separator character ('\u2029)
This problem has [been considered before|http://forums.sun.com/thread.jspa?forumID=4&threadID=464846] .
If we ignore the idiotic microsoft two char \r\n sequence, then no problem; the Java code would be:
String[] lines = s.split("[\\n\\r\\u0085\\u2028\\u2029]");How do we add support for \r\n? If we try
String[] lines = s.split("[\\n\\r\\u0085\\u2028\\u2029]|\\r\\n");which pattern of the compound (OR) regex gets used if both match? The
[\\n\\r\\u0085\\u2028\\u2029]or the
\\r\\n?
For instance, if the above code is called when
s = "a\r\nb";and if the first pattern
[\\n\\r\\u0085\\u2028\\u2029]is used for the match when the \r is encountered, then the tokens will be
"a", "", "b"
because there is an empty String between the \r and following \n. On the other hand, if the rule is use the pattern which matches the most characters, then the
\\r\\n
pattern will match that entire \r\n and the tokens will be
"a", "b"
which is what you want.
On my particular box, using jdk 1.6.0_17, if I run this code
String s = "a\r\nb";
String[] lines = s.split("[\\n\\r\\u0085\\u2028\\u2029]|\\r\\n");
System.out.print(lines.length + " lines: ");
for (String line : lines) System.out.print(" \"" + line + "\"");
System.out.println();
if (true) return;the answer that I get is
3 lines: "a" "" "b"So it seems like the first listed pattern is used, if it matches.
Therefore, to get the desired behavior, it seems like I should use
"\\r\\n|[\\n\\r\\u0085\\u2028\\u2029]"instead as the pattern, since that will ensure that the 2 char sequence is first tried for matches. Indeed, if change the above code to use this pattern, it generates the desired output
2 lines: "a" "b"But what has me worried is that I cannot find any documentation concerning this "first pattern of an OR" rule. This means that maybe the Java regex engine could change in the future, which is worrisome.
The only bulletproof way that I know of to do line splitting is the complicated regex
"(?:(?<=\\r)\\n)" + "|" + "(?:\\r(?!\\n))" + "|" + "(?:\\r\\n)" + "|" + "\\u0085" + "|" + "\\u2028" + "|" + "\\u2029"Here, I use negative lookbehind and lookahead in the first two patterns to guarantee that they never match on the end or start of a \r\n, but only on isolated \n and \r chars. Thus, no matter which order the patterns above are applied by the regex engine, it will work correctly. I also used non-capturing groups
(?:X)
to avoid memory wastage (since I am only interested in grouping, and not capturing).
Is the above complicated regex the only reliable way to do line splitting?

bbatman wrote:
Which match gets used when you use OR ('|') to specify multiple possible matches in a regex, and there are multiple matches among the supplied patterns? The first one (in the order written) which matches? Or the one which matches the most characters?
The longest match wins, normally. Except for alternation (or) as can be read from the innocent sentence
The Pattern engine performs traditional NFA-based matching with ordered alternation as occurs in Perl 5.
in the javadocs. More information can be found in Friedl's book, the relevant page of which google books shows at
[http://books.google.de/books?id=GX3w_18-JegC&pg=PA175&lpg=PA175&dq=regular+expression+%22ordered+alternation%22&source=bl&ots=PHqgNmlnM-&sig=OcDjANZKl0VpJY0igVxkQ3LXplg&hl=de&ei=Dcg7S43NIcSi_AbX-83EDQ&sa=X&oi=book_result&ct=result&resnum=1&ved=0CA0Q6AEwAA#v=onepage&q=&f=false|http://books.google.de/books?id=GX3w_18-JegC&pg=PA175&lpg=PA175&dq=regular+expression+%22ordered+alternation%22&source=bl&ots=PHqgNmlnM-&sig=OcDjANZKl0VpJY0igVxkQ3LXplg&hl=de&ei=Dcg7S43NIcSi_AbX-83EDQ&sa=X&oi=book_result&ct=result&resnum=1&ved=0CA0Q6AEwAA#v=onepage&q=&f=false]
If this link does not survive, search google for
regular expression "ordered alternation"
My first hit went right into Friedl's book.
Harald.

Cutting string into peaces

i have to cut string into equal length peaces according to
the length of the first word, and delete spaces between the words to one space like this
( _ = space )
"_ _ _ How__ do__ you__ do__today "
now it returns
How
__d
o__
you
__d
o__
tod
ay_
should be
How
do_
you
do_
tod
ay_
the following code cuts the string into equal length
peaces but it doesn�t cut the spaces between words so
that there is only one space that between the words.
How can i do that????
import java.io.*;
class Cutting{
     public static void main(String []args)throws IOException {
     BufferedReader stdin=new BufferedReader(new InputStreamReader(System.in));
     String str=" How do you do today ";
     String[] cutStr;
     char spr= (' ');
     char rpl= (' ');
     int index=0;
     int offset =0;
     cutStr=cut(str,spr,rpl,stdin);
     for(index=0;index<str.length();index++)
     System.out.println( cutStr[index]);
     //System.out.print("\n" +(cutStr=cut(str, spr, rpl))+"totanoi");
     }//main
static String[] cut(String str, char spr, char rpl,BufferedReader stdin)throws IOException {
str = str.trim();
int wordLen = str.indexOf(spr);
if (wordLen == -1) {
return new String[]{ str};
int words = (int)Math.ceil(str.length() / (double)wordLen);
String[] cutStr = new String[words];
int offset = 0, index = 0;
for (; (offset + wordLen) < str.length(); ++index) {
cutStr[index] = str.substring(offset, (offset + wordLen)).replace(spr, rpl);
offset += wordLen;
cutStr[index] = str.substring(offset, str.length()).replace(spr, rpl);
while (cutStr[index].length() < wordLen) {
cutStr[index] += rpl;
return cutStr;
}//class

use the StringTokenizer class.. very easy to use.. in this case, youd "jump" over all the spaces, and retrieve only the words, do something like:
StringTokenizer st = new StringTokenizer(source, " ");
StringBuffer sb = new StringBuffer();
while (st.hasMoreTokens()) {
String next = st.getNext();
if ( next != null && next.length() >= 1 ) {
sb.append( next + " " ); //add next word, and trailing space.
return sb.toString().trim(); //return source with ONE space between each word
             //trim() called to remove leading/trailing spaces.hope that helps.. i have not tested it, so you might need to change some of the arguments in the StringBuffer/Tokenizer... just look at java docs for info on those two classes and you shouldnt have a problem with this.
good luck!

Can we change data in string object.

Can we change data in string object.

Saw this hack to access the char[]'s in a String in another thread. Beware that the effects of doing this is possible errors, like incorrect hashCode etc.
import java.lang.reflect.*;
public class SharedString {
        public static Constructor stringWrap = null;
        public static String wrap(char[] value, int offset, int length) {
                try {
                        if (stringWrap == null) {
                                stringWrap = String.class.getDeclaredConstructor(new Class[] { Integer.TYPE, Integer.TYPE, char[].class });
                                stringWrap.setAccessible(true);
                        return (String)stringWrap.newInstance(new Object[] { new Integer(offset), new Integer(length), value });
                catch (java.lang.NoSuchMethodException e) {
                        System.err.println ("NoMethod exception caught: " + e);
                catch (java.lang.IllegalAccessException e) {
                        System.err.println ("Access exception caught: " + e);
                catch (java.lang.InstantiationException e) {
                        System.err.println ("Instantiation exception caught: " + e);
                catch (java.lang.reflect.InvocationTargetException e) {
                        System.err.println ("Invocation exception caught: " + e);
                return null;
        public static void main(String[] args) {
                char[] chars = new char[] { 'l', 'e', 'v', 'i', '_', 'h' };
                String test = SharedString.wrap(chars, 0, chars.length);
                System.out.println("String test = " + test);
                chars[0] = 'k';
                chars[1] = 'a';
                chars[2] = 'l';
                chars[3] = 'l';
                chars[4] = 'a';
                chars[5] = 'n';
                System.out.println("String test = " + test);
} Gil

Changing a char-string into decimal

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