Check variable against an array of words

Question

Hi,
I wish to check a variable for a number of words that are in
a array.
Not sure if this is the best way to do it, but this is what i
have.
I have my own counter system that counts every visitor, but
some of these visits are from BOTS, spiders..
So i wish to have a method of searching the HTTP_USER_AGENT
for certain words i put in a array.
What i am after is how i get the words in an array and how i
then get the script to check the HTTP_USER_AGENT for a word in the
array and if so it will not complete the script. (not add to the
counter)
if none of the words are in the HTTP_USER_AGENT then it will
add to the counter.
so something like?
<?
// do array
// check if HTTP_USER_AGENT contains a word from array
if () {
// increase counter if none of the words are in
HTTP_USER_AGENT
include(increase.php);
?>
its the bit between the if () that i have no idea about, any
help would be great.
cheers in advance for your help.
Jason

Answer 1

not very clever wrote:
> this is a bit more about what i am trying to do.
>
> <?
> // do array
> array(1)="something";
> array(2)="something else";
> array(3)=..
> ..
> ..
>
>
> $HTTP_USER_AGENT = contants of the HTTP_USER_AGENT
> // check if HTTP_USER_AGENT contains a word from array
> if (array(x) is in the string $HTTP_USER_AGENT) {
> // increase counter if none of the words are in
HTTP_USER_AGENT
> include(increase.php);
> }
>
> ?>
>
>
$myArray = array('blip','blop','glup',...);
$counter = 0;
foreach($myArray as $mA){
if(preg_match('/'.$mA.'/',$HTTP_USER_AGENT)){
$counter++;
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