Class paths. Help!!!

Everytime I compile and run my java programs an old class file is ran. How can I stop this.? I reset my pc, move the folder even change the name of the file but nothing works!!!
Help?

You're right, there's no hard and fast rule. I'm speaking from my own experience.
I crusade against a system CLASSPATH because I've seen too many people who were fooled into thinking that their CLASSPATH was 'all set' and couldn't understand why they were having problems.
Tomcat ignores the system CLASSPATH environment variable completely. It's important to understand what Tomcat assumes for CLASSPATH.
I'll bet that it's also true with other J2EE app servers.
Eclipse, JBuilder, and other IDEs ignore the system CLASSPATH environment variable completely. It's important to understand how they want the CLASSPATH to be set.
If you suddenly find yourself developing on a new, unfamiliar system that doesn't have a system CLASSPATH set the way you're used to, what do you do?
Your applications are a lot more portable if you take care of CLASSPATH issues without having an environement variable. It's one less thing you'll have to explain to a user.
Better to know how to set CLASSPATH properly in every situation and do it correctly as needed.
Sorry, I disagree completely. - MOD

Similar Messages

Setting path and class path help

I am a complete beginner who is currently starting a cd based tutorial!I have downloaded jdk1.1.6 which is the nearest developement kit to the one used in the tutorial.I use windows 98.When I try to set my path or class path as instructed in the docs, I cannot find any thing in the autoexec file at all.I have opened using notepad/Run and DOS edit but all three open an empty file.Where will I need to set up the path and class paths.My system must run these from somewhere else perhaps due to an update.

Hi,
Put the following statements in your autoexec.bat.
<homepath> = Path of your JDK folder on the drive. e.g. c:\jdk
SET CLASSPATH=;.;<homepath>\lib\tools.jar; .... continue with other jar files on the same line and seperate the entries by a semicolon.
SET PATH=C:\WINDOWS\;C:\<homepath>\BIN\;
This autoexec.bat must be on c:\. i.e. U can open it in notepad by giving c:\autoexec.bat in the File Open Dialog. It is possible for this file to be empty. Simply add the commands on the last line.
Regards ,
Karan

Help setting Class Path

hi,
I just downloaded and installed JDK 5 update 7 and need help setting the class path. Can someone give me instructions on how to do this in windows XP please.
Cheers

thanks for the replies guys.
I'm still having problems. What I want to be able to do is compile a .java file using the Command Prompt in windows XP.
Currently, when I type javac I get the message:
'javac' is not recognized as an internal or external command, operable program or batch file.I set the classpath to C:\jdk1.5.0_07\bin\ but when I type path in the command prompt this path doesn't appear.
If I change the directory in the command prompt to C:\jdk1.5.0_07\bin\ then type javac it works (I get a list of commands) but I need it to work from within any folder.
Have I set the classpath incorrectly or is it something else?
Thanks

Need help with Class-Path and NCDFE

This isn't a new issue, but I'm getting a variation of a problem a lot of people seem to have had. I was hoping someone out there can help me out.
I have a jar file (imex.jar) sitting in c:\temp\imextest. I also have another jar file, commons-cli-1.0.jar sitting in c:\temp\imextest\lib.
I want to run the jar in a standalone manner. My manifest has the following entries.
Manifest-Version: 1.0
Ant-Version: Apache Ant 1.5.3
Created-By: 1.4.2_01-b06 (Sun Microsystems Inc.)
Main-Class: com.foo.imex.DirectoryImportExport
Class-Path: lib/commons-cli-1.0.jar
I am invoking it using the following command (from c:\temp\imextest)
java -jar imex.jar -i -f c:\matt\RRBus\jiyun.xml -v
I get this result:
Exception in thread "main" java.lang.NoClassDefFoundError: org/apache/commons/cli/ParseException
It seems to me that I have my directory structure and manifest set up correctly, but maybe I don't (as it's not working). Does anyone see what I'm doing wrong here? (the "missing" class is in commons-cli-1.0.jar).
Thanks,
Matt

perhaps jar file needed for parsing is not there in classpath...set it...in the classpath..

Retrieve the class path!! need help

Hi all
I tried to retrieve the class path using the below method:
URL srcUrl = ClassLoader.getSystemResource(fileName)
Since the class path has some space in it, this srcUrl seems to be wrong
the returned value would look like this, "%20" represnts the spaces in the path. So is there a way to avoid this, and to return the path correctly?
D:\PROJECT\ReportDesigner\Run%20report%20designer%20from%20a%20share\
thanks in advance
madumm

File srcDir = new File(srcUrl.getFile());Well you just can't do that, can you? URL.getFile() returns the filename part of the URL, but it's still URL-encoded. You have to convert each %20 to a space, and do a few other possible transformations as well. See java.net.URLDecoder.

Help: manifest class path attribute - OC4J 9.0.3

I have tried everything I can think of. I have even downloaded the developers version of JRun to ensure my code does deploy under the J2EE spec.
Per compleating deployment under JRun, I have migrated back to OC4J and made the approperate modifications to orion-web.xml to include the following entry:
<web-app-class-laoder include-manifest-class-path="true" />
Even with this entry I get the same class not found statements. I am out of ideas.
Anyone got some sugestions?
Info: Ear deployment, static pages deploy under all wars...
Thanks.
Andrew
[email protected]

I have tried everything I can think of. I have even downloaded the developers version of JRun to ensure my code does deploy under the J2EE spec.
Per compleating deployment under JRun, I have migrated back to OC4J and made the approperate modifications to orion-web.xml to include the following entry:
<web-app-class-laoder include-manifest-class-path="true" />
Even with this entry I get the same class not found statements. I am out of ideas.
Anyone got some sugestions?
Info: Ear deployment, static pages deploy under all wars...
Thanks.
Andrew
[email protected]
Hi Andy -
Can you check the attribute and make sure it's the following:
<web web-app-class-loader include-war-manifest-class-path="true"/>
^^^
You have have just typed it in quickly, but I noticed there's a typo in the entry you have above and you are missing the WAR piece of the attribute name.
There's a how-to document on OTN which has an example of this.
http://otn.oracle.com/tech/java/oc4j/htdocs/how-to-servlet-warmanifest.html
cheers
-steve- Hi Steve
Where can I find the zip file I went through the link but doesn't have any link to zip file
Thanks
Ritesh

JBO:33001 bc4j.xcfg file not found in class path

Hi,
I am yet another victim of the age-old error JBO:33001 bc4j.xcfg file not found in class path, When i have my BC4JApp.jar in Tomcat Web-inf/lib directory. All the other jar files and class files in my webserver-application web-inf classes and lib directory works.
But Tomcat server is not able to read this bc4j.xcfg file. I can see in my jar file that this bc4j.xcfg exists and in the specified package directory. still the problem persists. My BC4JApp.jar is perfectly working when i use JDeveloper. but not when i use tomcat4.0 and call a JSP using BC4JApp.jar from browser (My environment is Jdeveloper3.2, Tomcat4.0+IIS in middle tier and oracle 8i as DB, everything on windows2k)
I have gone through almost all the threads possible that relates to this error in this form. None of them have a answer except to say "put the file in classpath". and last reply is "will fix in jDeveloper 9i. So what happens to us who are working in Jdeveloper 3.2?
1. I have this file in my jar file.
2. I also tried creating a seperate directory manually, with the same name as my package under web-inf/classes, web-inf/lib , just under web-inf directory and atlast under approot directory also. I tried having my package directory containing bc4j.xcfg in these folders one at a time and also tried having this directory in all these folders at the same time.
Still no solution.
Itz frustrating that neither proper documentation nor a right url page nor i am aware of available addressing this. page links given in above threads only gives me the wonderful page of ie's "Page cannot be displayed".
Is there a answer to this error and my problem. If this doesn't work, then i have to all the way develop from scratch creating my jsp using JDBC calls and Stored packages etc.
I don't want to give up on this Jdeveloper at this final moment because if this bc4j.xcfg file is found, my application will work perfectly. on these final moments, if this doesn't work, i am frightened to imagine to develop my application in standard way. Atlast, if thatz the option left,we have to do that bcos our production date is close by.
Please can some one in this forum or Jdeveloper help me to solve this problem. I am desperate and very urgent.
Waiting for a reply from Jdev team very much...
( I just posted in the other thread which is pretty old, dated backto May 2001, which was relevant to this error. Just to make sure it is noticed, I am posting it seperately too)
Thanks
Hari(2/3/02)

Hi All,
For those who are following this thread, I got a solution for this error with the help of Jdev Team.
This solution may work, if you have deployed your application in Tomcat4.0.1. This is the environment in which I work and tested.
As you may be aware, Tomcat ignores value in CLASSPATH variable.
To see any files that are existing or newly deployed, it has it own way of detecting it.
Addition information on Tomcat working, you can follow this link,
http://jakarta.apache.org/tomcat/tomcat-4.0-doc/index.html
Coming to point, Tomcat has got five classloaders and each classloader invoked, looks in their related directories for files in following order.
1. /WEB-INF/classes of your web-application
2. /WEB-INF/lib/*.jar of your web application
3. BootStrap classes of your JVM (Tomcat's $JAVA_HOME/jre/lib/ext)
4. System class loader classes($CATALINA_HOME/bin/bootstrap.jar,CATALINA_HOME/lib/tools.jar)
5. $CATALINA_HOME/common/classes
6. $CATALINA_HOME/common/lib/*.jar
7. $CATALINA_HOME//classes
8. $CATALINA_HOME/lib/*.jar
So All your individual application related files should be deployed in your application's WEB-INF/classes or WEB-INF/lib directory accordingly.
If your application files are unpacked, they should be deployed or copied under WEB-INF/classes directory
if the files are within a jar, they should be under WEB-INF/lib directory.
If your Jar-files contains bc4j components, then those jar files should be deployed under WEB-INF/lib directory. Also,do the next step to copy all relavant BC4J runtime libraries under lib directory.
IMPORTANT: Please remember to copy and paste all the required BC4j runtime libraries in the Same WEB-INF/lib directory along with your application jar files. This is the real reason which can solve this JBO:33001 to disappear. It worked for me.
To configure your directory for tag-lib uri's, use web.xml to set the taglib-uri attribute.
Put your web.xml and DataTags.tld in the WEB-INF directory.
Your simple web.xml may look like as follows.
<?xml version="1.0" encoding="ISO-8859-1"?>
<!DOCTYPE web-app
PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
"http://java.sun.com/dtd/web-app_2_3.dtd">
<web-app>
     <taglib>
          <taglib-uri>
               /webapp/DataTags.tld
          </taglib-uri>
          <taglib-location>
               /WEB-INF/DataTags.tld
          </taglib-location>
     </taglib>
</web-app>
You may then modify this web.xml to suit further requirements of your application.
Remember to stop and restart the Tomcat Server (service) by using shutdown and startup scripts after updating any jar files/class files/ JSP or source files deployed in Tomcat.
Sometimes, only this helps even though your context's reloadable attribute is set to true in Tomcat Server's server.xml file.
Hope this above information helps you to solve this error in Tomcat environment. My Sincere thanks once again to Juan and Jdev team for their help and efforts to solve this problem.
Thanks
Hari

How to run a jar file which needs another jar to be in the class path

Hi,
I need to execute a jar, which needs another jar to be in the classpath.
If I run like
java -classpath <jar1 name> -jar <main jar>
It is giving classnotfoundexception, where as the class is available in the <jar1 name>.
so, currently I am doing like this
In the manifest file i have given like
Main-Class: <class name>
Class-Path: <jar name> <jar name2>
then it is running fine. But, if I want to change the jar location again I need to changed the manifest file.
Is there any way to do this? Pls help me.

How about
java -cp jar1.jar;jar2.jar com.acme.MainClass
You won't need to worry about the manifest file after that and you can make a bat files (or .sh file in *nix) for it.

How to set class path for mysql

hai, I have been trying to make a java program read from mysql database. but i don't know how to set the class path for mysql-connector-java-5_1_.0.6-bin. i set the class path in system variable as C:\Program Files\Java\jdk1.5.0_08\jre\lib\ext\mysql-connector-java-5_1_.0.6-bin.
in the command prompt, i compile C:\javac abc.java and run java abc.
when run it come out error java.lang.ClassNotFoundException: com.mysql.jdbc.Driver
i am using Window xp. can anybody help me??? TQ.

hai, I have been trying to make a java program read
from mysql database. but i don't know how to set the
class path for mysql-connector-java-5_1_.0.6-bin. i
set the class path in system variable as C:\Program
Files\Java\jdk1.5.0_08\jre\lib\ext\mysql-connector-jav
a-5_1_.0.6-bin.
in the command prompt, i compile C:\javac abc.java
and run java abc.
when run it come out error
java.lang.ClassNotFoundException:
com.mysql.jdbc.Driver
i am using Window xp. can anybody help me??? TQ.Right click on my computer icon,
Goto properties->advanced->environment variables.
Look for 'classpath' under system variable.
Select it and click edit.
put ';' and path of the mysql connector jar at the end
suppose if u have jar file under d:/driver/mysqlconnector.jar
thn put this value in variable value text box
;d:/driver/mysqlconnector.jar
or simply put ur driver jar file in jre/lib/ext folder
D:\j2sdk1.4.2_03\jre\lib\ext
[Servlet tutorial|http://www.jsptube.com]

Package and class path

for two yrs i am trying to get package right but no result
i am using window 98
i have my jdk in d:\jdk1.2\bin; and this works fine if i do not try to use package;somtimes it works well half way with package!
suppose i want to create a package called rubberband and put classes in it
i created a folder called rubberband in d:\ and then
package rubberband;
import java.awt.*;
public class RubberbandTest extends Frame{}
class RubberbandTestPanel {}
class Colorchoice{}
this is one unit
and there are other classes
package rubberband;
import java.awt.*;
abstract class Rubberband {}
package rubberband;
import java.awt.*;
class RubberbandPanel extends Rubberband {}
and so on
i opened executive.bat and added to class path as follows:
path:d:\rubberband\bin;before the already existing d:\jdk1.2\bin;
then when i come to compile and run the program i have problems
like:class so and so not found
please help please step by step tell me what to do

Another sample might answer your "different location" question.
Suppose program YourProg in package yourPkg located in directory C:\javaprogs needs to access a class file ExtraClass in package extraPkg in directory C:\differentDir.
1) Of course the source file must exist in file
C:\javaprogs\yourPkg\YourProg.java
and
C:\differentDir\extraPkg\ExtraClass.class must exist.
2) Inside the YourProg source, you must import ExtraClass:
import extraPkg.ExtraClass;
3) To compile YourProg, you must include location of extraPkg.ExtraClass in the classpath (or the compiler will complain about the inport line above):
(a -- from C:\javaprogs directory): javac -classpath C:\differentDir yourPkg\YourProg.java
(b -- from any directory): javac -classpath C:\javaprogs;C:\differentDir yourPkg\YourProg.java
4) To run YourProg (assuming it contains a main method), you must include all locations in classpath:
(a -- from C:\javaprogs directory): java -classpath .;C:\differentDir yourPkg.YourProg
(b -- from any directory): java -classpath C:\javaprogs;C:\differentDir yourPkg.YourProg
If you get a NoClassDefFoundError, that means that the java was run without the proper location included in the classpath passed to the -classpath argument. The -classpath argument should be ';'-separated and contain no spaces (so if a long directory name contains space you should enclose in double quotes, as this example:
java -cp "C:\Program Files\somedir;C:\anotherdir" NameOfAClass

Unable to find XML document from class path resource

Hi,
I am trying to learn spring and wrote my first class today. I added all the jar files to the lib folder and created all the classes. When I try to run the client program I get
[INFO] XmlBeanDefinitionReader - Loading XML bean definitions from class path resource [MorningGreeting.xml]
org.springframework.beans.factory.BeanDefinitionStoreException: IOException parsing XML document from class path resource [MorningGreeting.xml]; nested exception is java.io.FileNotFoundException: class path resource [MorningGreeting.xml] cannot be opened because it does not exist
     at org.springframework.beans.factory.xml.XmlBeanDefinitionReader.loadBeanDefinitions(XmlBeanDefinitionReader.java:180)
     at org.springframework.beans.factory.xml.XmlBeanDefinitionReader.loadBeanDefinitions(XmlBeanDefinitionReader.java:148)
     at org.springframework.beans.factory.xml.XmlBeanFactory.<init>(XmlBeanFactory.java:73)
     at org.springframework.beans.factory.xml.XmlBeanFactory.<init>(XmlBeanFactory.java:61)
     at com.training.spring.greetCustomers.EnterTraining.main(EnterTraining.java:22)
Exception in thread "main"
I have my client, interface, XML file all in the same package com.training.spring.greetCustomers. I could not understand what I am doing wrong?? Can you please help me.

congratulations on deciding to learn spring. that's a smart thing to do.
stop assuming that you did it correctly. the xml file is not in the classpath. when you get it there correctly, spring will find it.
you have the source files and xml in that directory, but where do the .class files end up when you run them? does the xml config end up there, too?
remember, the xml config should be in the directory where the root of the package hierarchy begins, not down where the .class files are.
%

Servlet class path

Can anybody tell me what is the exact path to put the servlet class file in
tomcat 4. I was reading a book called more servelet by Marty Hall and its metioned there that i can put them in install_dir/webapps/ROOT/WEB-INF/classes but when i browse to WEB-INF folder there is no folder named classes there.
Please help.

firsly i installed jdk 1.3 on my computer. Then i installed tomcat 4. Then i changed port 8080 in server.xml to 80. Then i set the JAVA_HOME path to point to jdk1.3 folder. Then i setup the class path to D:\Documents and Settings\Ashi\Desktop\tomcat\apache-tomcat-4.1.34\apache-tomcat-4.1.34\common\lib\servlet.jar
Then i downloaded a source file named HelloServlet.java from author's website and compiled it. It compiled successfully. I copied the HelloServlet.class file to the classes directory that you asked me to create. Then i opened my browser and typed http://localhost/servlet/HelloServlet and getting error HTTP Status 404

Not in class path - XSLT Mapping using Stylus studio

Hello,
I am using Stylus studio for XSLT mapping. I have written a JAVA function and when I tried to execute, I am getting an error " ...... not inclasspath".
I have put JAVA file in the classpath as expained in the Stylus studio help documentation.
Can anyone help me on how to place the Java class file in the proper class path and how that java file has to be called from main XML program.
Regards and Thanks in Advance
Arvind

Hello sabarish,
I have tried already as explained in the link you have mentioned. But still not working. In fact i was thinking to zip xsl, class and java files together and upload to XI. But I want to ensure whether i have called the java extension properly from XSL file.
Request you check this:
Java file
package com.eds.ehro.ximapping;
import java.util.Map;
//import com.sap.aii.mapping.api.AbstractTrace;
//import com.sap.aii.mapping.api.StreamTransformationConstants;
import java.util.*;
import java.text.*;
public class Concat_Employee_Sydate_Sytime {
             public static String concat(String empno)
             return empno + "-" + System.currentTimeMillis();
XSL file
<?xml version='1.0' ?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:ns0="http://www.gemsconsult.com/idoctofile/employee"
xmlns:javamap="com.eds.ehro.ximapping.Concat_Employee_Sydate_Sytime">
     <xsl:template match="/">
          <ns1:SetEmployeesDemographics_R xmlns:ns1="urn:EmpDemoVi">
               <ns1:demographics0>
                    <ns2:address xmlns:ns2="urn:com.sap.eds_ehro.besrv.demographics">
                         <ns2:adressLine>
                              <xsl:value-of select="concat(ns0:MT_EMPDETAILS/AddressLine1,ns0:MT_EMPDETAILS/AddressLine2)"/>
                         </ns2:adressLine>
                         <ns2:countyCode>
                              <xsl:value-of select="ns0:MT_EMPDETAILS/Country"/>
                         </ns2:countyCode>
                         <ns2:postalCode>
                              <xsl:value-of select="ns0:MT_EMPDETAILS/Zipcode"/>
                         </ns2:postalCode>
                    </ns2:address>
                    <ns2:clientID xmlns:ns2="urn:com.sap.eds_ehro.besrv.demographics">200</ns2:clientID>
                    <ns2:employeeID xmlns:ns2="urn:com.sap.eds_ehro.besrv.demographics">
                         <xsl:param name="empno">
                              <xsl:value-of select="ns0:MT_EMPDETAILS/EmployeeNo"/>
                         </xsl:param><!xsl:value-of select="ns0:MT_EMPDETAILS/EmployeeNo"/>
                         <xsl:if test="ns0:MT_EMPDETAILS/EmployeeNo">
                              <xsl:value-of select="javamap:concat($empno)"/>
                         </xsl:if>
                    </ns2:employeeID>
                    <ns2:personName xmlns:ns2="urn:com.sap.eds_ehro.besrv.demographics">
                         <ns2:firstName>
                              <xsl:value-of select="ns0:MT_EMPDETAILS/FirstName"/>
                         </ns2:firstName>
                         <ns2:middleName>
                              <xsl:value-of select="ns0:MT_EMPDETAILS/LastName"/>
                         </ns2:middleName>
                    </ns2:personName>
               </ns1:demographics0>
          </ns1:SetEmployeesDemographics_R>
     </xsl:template>
</xsl:stylesheet>

How to set the class path?-

my forlder is :C:\Documents and Settings\india
jdk is in:C:\Program Files\Java\jdk1.5.0_11\bin
can any body can help me to create a classpath for my folder?

An alternative - as stated in reply 2 in your other thread on this topic: http://forum.java.sun.com/thread.jspa?threadID=5170470 - is not to set the CLASSPATH environment variable at all. Use the -classpath switch instead.
As the documentation linked to in that reply points out: "The class search path (more commonly known by the shorter name, "class path") can be set using either the -classpath option when calling a JDK tool (the preferred method) or by setting the CLASSPATH environment variable. The -classpath option is preferred because you can set it individually for each application without affecting other applications and without other applications modifying its value."
As always, the documentation is worth reading; the available command line options worth using.

Stand alone class and the class path

Hi,
I have a simple Java project in Eclipse environment. The project has it's class path,
that contains a jar file that I need to use.
The project runs perfect in the Eclipse.
Now, I need to take the main class out of my project, to function alone in another environment.
My problem is that out of the environment, I don't know how the class should know that classpath.
I moved that jar to the same folder that the class located in, but I don't know how to tell it that the jar is there.
My goal is to run my standalone class from another java class.
I'm afraid that examples in command environment wouldn't help me.
Thanks a lot for any help !

moshi wrote:
I have a simple Java project in Eclipse environment. The project has it's class path,
that contains a jar file that I need to use.Ok, so you have a class that you have written that depends on an external library. Fair enough.
The project runs perfect in the Eclipse.
Now, I need to take the main class out of my project, to function alone in another environment.Maybe (just maybe!) defining what exactly that "other environment" is could help us help you.
My problem is that out of the environment, I don't know how the class should know that classpath.Well, obviously that depends on what that other environment is.
You must have some way to influence that other environments classpath, or you couldn't even get it to call/use your class.
I moved that jar to the same folder that the class located in, but I don't know how to tell it that the jar is there.Now you're just guessing.
My goal is to run my standalone class from another java class. That's simple enough, you probably do it all the time.
I'm afraid that examples in command environment wouldn't help me.And why exactly is that?
Do you realize that you tell us far too little about your problem for us to be able to actually help you?

Applet with class path Problem

Hi all,
I am facing a strange problem: I wrote an applet and sign it tomake it able to access some client resources, my applet is intended to play audio mp3 files, so I need some libs like jmf.jar, if my libs do not exist I recieve them from my web app via URLConnection to servlet.
after libs download completing, I can not instantiate any of libs class because my libs do not exist in the class-path.
I need any suggestion. what can I do?
1 - change the class path - during run time - to point to the current libs location.
or
2 - load the jar libs manually - during run time - and instantiate my classes.
or what?
please include examples.
Thanks
Ahmad Elsafty

PATH and CLASSPATH are different. PATH is an environment variable used by windows to locate programs. CLASSPATH is an environment variable that java uses to find classes.
You need to create a new environment variable. The easiest way to do it in win2k (and to keep it after you reboot) is to do this: right click on "My Computer" and click "Properties" (or go to "System" in the control panel). Click on the "Advanced" tab. Click the "Enviroment Variables..." button. In that window, add a system variable by clicking "New..." in the bottom half. Variable Name: "CLASSPATH" Variable Value: ".;J:\Skribe\Tools\mysql-connector-java-3.0.0-beta\mysql-connector-java-3.0.0-beta-bin.jar;J:\jakarta-log4j-1.2.6\dist\lib\log4j-1.2.6.jar"
You have to make sure that ".;" is the first thing on the line. This tells java to look in the current active directory first for classes it doesn't recognize, then in locations you specify. By default, it just looks in the current directory.
Hope this helps.

Class paths. Help!!!

Similar Messages

Maybe you are looking for