Column nightmares

I am trying to create a datasheet that has two sections, each with two columns. The top section has variable column widths, so I can put a wide logo in the left column and a quick bullet list right justified in the right column. The second section is even column widths and is for the datasheet text. I am encountering three problems:
* I need to "feather" the text column, so that the bottom of both columns line up. I used to be able to do this in Framemaker by setting Feathering to ON, in which case Frame would "expand" the space between paragraphs until the last line of each column was pushed to the bottom of that column. Is there a way to do this in AW?
* I keep getting a gap on the right side of the column in the text section. I've tried to set the column width and "space between columns" so that they exactly equal the width of that section (margin to margin) but AW changes my values after I type them. It appears as if the "space between columns" is acting like "space after columns" and is putting the "gap" after both columns, leaving me with a space on the right side of the right column that I can't get rid of.
* I try to set the column and space between widths to exactly what I want but AW changes my values. I double checked that I am entering values that together total the width of the section, but AW is still changing them. This problem is related to the bullet above -- I'm trying to set the column widths and space between to total section width but the values change after I type them.
Help!
I sure miss Framemaker......

Hello
I explained many times the described oddity.
The algorithm used to compute column widths is wrong;
When trying to define to equal columns, it uses
columnWidth = (printable width / 2) - gutter
when it would use
columnWidth = (printable width - gutter) / 2
This is an old bug and, as AppleWorks will certainly no longer evolve we will have to live with it.
Happily, there is a workaround described (for an other purpose) in the help:
Modifying column width and spacing quickly
To quickly modify column width and spacing without using the Section dialog box:
•     Press the Option key while positioning the pointer over a column border so that the pointer changes to this double arrow:
Then drag the column border to a new position.
To quickly change the relative width of two columns without changing their combined width or the space between them, without using the Section dialog box:
•     Press the Option key while positioning the pointer between column borders so that the pointer changes to this double arrow:
Then drag the space between the columns (not the column border) to a new position.
Yvan KOENIG (from FRANCE 13 octobre 2005 10:37:15)

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    added to this report. However, every time I add this column then I get the “No Results”.
       We have tried almost all options including:  tracking the
    table and column to the rpd, making sure the joins are correct. We have even
    tracked this particular column to a single transaction where we can clearly confirm
    that a transaction took place on that date. However when we run it we still get
    the same message.
          We have so many SQL statement to narrow it down, still nothing. When I run this column by itself it brings data, but when I try to run
    with other columns then nothing comes out
    Any idea on how to go about this; just FYI BI Apps isn’t fun
    to work with

    Step1: find the column you are adding in the report ( which column, which presentation folder, which subject area)
    step2: go to RPd, go to the subject area in the presentation layer, find the presentation folder and the column.
    step3: right click on it and say query related - logical column , same way you can query for Physical table.
    step 4: go to physical table and right click and click on Physical model - selected object and direct joins.
    step5: there can be multiple fact/dimensions joined to it. You need to find which fact is participating in the report. so go to presentation layer of the same subject area , find the measure you are adding in report , right click to find physical table.
    step 6: find the join between dimension and fact, check the join condition for data type and data relevence.
    other method is to take the backend SQL and find the fact, dimension and join condition.
    You said the report is not giving any result. so check for Filters in backend query.
    other approach will be to write your own sql to check it results in data. as per the accepted join condition if data dosen't result, the issue can be a join colum data issue. this can be fixed in ETL.
    Mark if the answer is correct.

  • Re: Column is not getting displayed in the BI report

    Hello Gurus,
    I have developed a BI report with more number of parameters.
    Case 1:
    When i run my report , I am able to see data for particular condition but one column doesn't show any thing. All the rows in the column are blank.
    Case 2
    I tried to put the blank column as parameter, The Program works with out displaying that column data.
    I am not sure where it is going wrong. I tried running the code in toad and i am able to see the data.
    I have checked the code, Parameter description, length, Template and data definition.
    Please help.
    Thanks,
    Sreekanth

    Hi ,
    For that column did u changed any alias name in the query...
    check ur template once by loading the xml data...
    check that column form field that matches with the xml tag or not..
    Thanks,
    Ananth

  • Query help: query to return column that represents multiple rows

    I have a table with a name and location column. The same name can occur multiple times with any arbitrary location, i.e. duplicates are allowed.
    I need a query to find all names that occur in both of two separate locations.
    For example,
    bob usa
    bob mexico
    dot mexico
    dot europe
    hal usa
    hal europe
    sal usa
    sal mexico
    The query in question, if given the locations usa and mexico, would return bob and sal.
    Thanks for any help or advice,
    -=beeky

    How about this?
    SELECT  NAME
    FROM    <LOCATIONS_TABLE>
    WHERE   LOCATION IN ('usa','mexico')
    GROUP BY NAME
    HAVING COUNT(DISTINCT LOCATION) >= 2Results:
    SQL> WITH person_locations AS
      2  (
      3          SELECT 'bob' AS NAME, 'USA' AS LOCATION FROM DUAL UNION ALL
      4          SELECT 'bob' AS NAME, 'Mexico' AS LOCATION FROM DUAL UNION ALL
      5          SELECT 'dot' AS NAME, 'Mexico' AS LOCATION FROM DUAL UNION ALL
      6          SELECT 'dot' AS NAME, 'Europe' AS LOCATION FROM DUAL UNION ALL
      7          SELECT 'hal' AS NAME, 'USA' AS LOCATION FROM DUAL UNION ALL
      8          SELECT 'hal' AS NAME, 'Europe' AS LOCATION FROM DUAL UNION ALL
      9          SELECT 'sal' AS NAME, 'USA' AS LOCATION FROM DUAL UNION ALL
    10          SELECT 'sal' AS NAME, 'Mexico' AS LOCATION FROM DUAL
    11  )
    12  SELECT  NAME
    13  FROM    person_locations
    14  WHERE   LOCATION IN ('USA','Mexico')
    15  GROUP BY NAME
    16  HAVING COUNT(DISTINCT LOCATION) >= 2
    17  /
    NAM
    bob
    salHTH!
    Edited by: Centinul on Oct 15, 2009 2:25 PM
    Added sample results.

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