COMMIT_FORM per one DATA BLOCK at a time

Question

Hi,
Please guide for the following:
I have 3 data blocks (tabular) on 3 tables, with three radio buttons on the form. I want to insert records in a table as per the radio button value:
For example
(1) if user has selected rdbtn1 then COMMIT_FORM must insert record in table 1 only.
(2) if user has selected rdbtn2 then COMMIT_FORM must insert record in table 2 only.
(2) if user has selected rdbtn3 then COMMIT_FORM must insert record in table 3 only.
Is it possible with COMMIT_FORM, if so, how, please guide.
Regards.

Answer 1

Here is the fundamental problem. The Commit_Form built-in will save all pending transactions in the entire Forms session. Therefore, in order to save incrementally (one block out of many) you have to use autonomous transactions. In essence you have to create a new session, perform your changes and save the changes outside of the current Forms session. This is typically done using Dynamic SQL. However, you can’t use the EXECUTE_IMMEDIATE Native Dynamic SQL (NDS) command in Forms. You could use FORMS_DDL (which allows you to execute dynamic SQL from Forms) but Forms_DDL issues an implicit COMM IT which will COMMI T the entire Forms Session. Therefore, the best way to accomplish this would be to call a database procedure that uses NDS to perform the needed DML and issue the COMM IT.
The other alternative would be to do what I think "user8937305" is suggesting; depending on the Radio Button selected, you clear the other two data blocks so only the data in the selected data block (radio button) is saved through the FORMS_C OMMIT.
Hope this helps,
Craig B-)
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