Comparing vector to part of a string

I have a file that contains this as the first part of the line:
S1| some other data
S2| some other data
S3| some other data
I have my code like this:
Vector row = new Vector();
while (tokens.hasMoreTokens()) {
row.addElement(tokens.nextToken());
System.out.println("row = " + row.get(0));
try {
if (row.get(0).equals("S")) {
Now, I know that equals will not get the S1, S1, S3, but is there some kind of like statement or wild card that I can use to compare the first element in the file? I need to keep both the S part and the number part, but just want to use the S part in the if statement. Does this make sense? Thanks.
Allyson

You can use the String.regions match method.
If this is needs to be highly modifiable and flexible code you might want to look into the regex library. It is part of 1.4 and is available as an extension to 1.3
P.S. If you are using anything above 1.1 avoid Vector. Use the ArrayList class instead.

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Converting part of the string to a date and subtract with sysdate.

HINT! In order solve this you must know how the pnr is assembled. Study this:
650323-5510, we only need the first six characters. They inform us about when the person (car owner) was born. In this case it is 23 Mars 1965. You have to use several oracle built-in-functions to solve this. Hint! Begin by converting part of the string to a date and subtract with sysdate.
select to_char(to_date(cast(pnr,'YYMMDDMM'))) from car_owner;
please what am i doing wrong. i need the result to be something like this
Hans, Rosenboll, 59,6 years.

Hi.
The main problem here is you have only last two digits of year. That could be the problem in a couple of years from now, when somebody born after 2k would get in to your database. For now if we ignore this problem the right solution would be :
<code>
SELECT months_between(trunc(SYSDATE),
to_date('19' || substr('650323-5510',
1,
6),
'YYYYMMDD')) / 12 years_old
FROM dual
</code>
Suppose you are expecting the age of the car owner as a result above code will give you that. One again notice the '19' I appended.
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Replacing a part of a String with a new String

Hi everybody,
is there a option or a method to replace a part of a String with a String???
I only found the method "replace", but with this method I only can replace a char of the String. I don't need to replace only a char of a String, I have to replace a part of a String.
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str.replace("nice","wonderfull");   // this won't work, because I can't replace a String with the method "replace"
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king regards
IceCube-D

do check java 1.4 api, I think there is a method in it, however for jdk1.3 you can use
private static String replace(String str, String word,String word2) {
     if(str==null || word==null || word2 == null ||
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          return str;
     StringBuffer buff = new StringBuffer(str);
     int lastPosition = 0;
     while(lastPosition>-1) {
          int startIndex = str.indexOf(word,lastPosition);
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          buff.delete(startIndex,startIndex+len);
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          str = buff.toString();
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JAXB unmarshalling error for " " token as part of xsd:string type element

JAXB unmarshalling error for "<" token as part of xsd:string type element
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Hi,
Did you tried to put & lt; (without space) instead of < ?
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Addressing of part of the string in the container

Hello,
in a mail task I would like to print only some characters from a string - e.g. from second to tenth - is it possible to address some part of the string in the container as is usual in abap?
thx,
JJ

Hi,
Yes , it is possible. If you want to show only some part of the string value in mail description you can use normal abap string operations. For example: In Mail description if you want to show only a part variable VALUE. you can just use &VALUE+a(b)&. It will work !!
You can try it out !!
Regards
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Delete part of a string question

Hello I have this String 12a
I need to get a the value 12 of it an make it an int
But the problem is that I don't know what the string is it can be
12
or 12 a
or 12a
It is for people to fill in there house address and this is the number part.
The string is like this String number ="\"12a\"";
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Try this on the command line. Dealing with java.lang.NumberFormatException in cases where the number is too large is left as an exercise.
Harald.
import java.util.regex.*;
* demonstrates use of <code>java.util.regex</code> to check if a
* string starts with digits.
public class bla {
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private bla() {}
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Hello,
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Assign value TO COMPONENT (fieldname) of structure
Thanks.
Regards, Lars.

do you have a set structure name you're dealing with or is that dynamic?
If it's the first scenario and, say, you were dealing with mara and field matnr you could do this:
data l_string.
field-symbols <field> type any.
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How Do I Mirror A Part Of A String?

Dear Programmers,
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There is a Reverse method:
string s = "looks";
s = new string(s.Reverse().ToArray());
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http://stackoverflow.com/questions/228038/best-way-to-reverse-a-string
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https://msdn.microsoft.com/en-us/library/system.string.substring(v=vs.110).aspx
Please remember to mark helpful posts as answer to close your threads and then start a new thread if you have a new question.

Using INSTR to extract part of the string ?

Morning guys and Happy Friday.
I have a situation where I have to pull out part of the string using a select statement.
Here is the string and I have to get the contents between the 2nd and 3rd backslash. So, basically, I have to extract marypoppins. Any ideas ?
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Additionally you can break it all up simply with regular expressions..
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Wrote file afiedt.buf
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Replace part of a string

I want to replace a part of a string value with another in table column(VARCHAR). For example \\server01\data\doc\123.eps with \\server02\data\doc\123.eps . How to replace the server01 part with server02?

Use REPLACE.
Cheers, APC
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2 from dual
3 /
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How to replace part of a String with another String :s ?

Got a String
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What do you mean that it doesn't work? You do know that the method returns the modified string? The actual string that you invoke the method on is not altered.
/Kaj

CS3: grep search to replace part of a string

Can I do a grep search for a string of text but only replace a portion of the string while leaving the remainder intact?
iMac G5, OS 10.5.5

In addition to Eric:
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This restriction does not apply to the 'middle' string, the one you are going to replace anyway -- use whatever GREP you want.

Mysql datetime datatype, from that datetime how can i compar only time part

Hello i have database table in mysql, there is Datetime datatype column, from that datetime how can i compare only time part .....??
Thanks in advance...

Note you can't simply just compare time via equality however.
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Then construct the range.
Then pass the range and, as already mentioned, use specific functions to handle the extraction of the time.

To compare date with another date in string in siebel bip report

Hi,
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This condition is working fine if Date1 have 2014 values but if Date1 cointains 2015 date than the mentioned condition is falling.
Kindly suggest any solutions.
Regards,
Siddhika

This example may help:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
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How can I extract high and low parts of a string that represents a 64bits decimal number?

I want to extract the high and low parts to interpret it and convert to binary code, but such a hugh number (represented by a string) isn't easy to extract from the string directly its high and low parts.

LabVIEW can't handle a 64-bit integer. You will have to store it as two 32-bit integers. If you need exact math on those 64-bit intergers you will have to make up your own routines to handle the carries and what not. If you just need pretty good accuracy, covert both 32-bit integers to double, multiply the upper 32-bit number by 2*32 (also a double) and then add the lower 32-bit number to it.
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Comparing vector to part of a string

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