Conversion of byte into string

how can we convert byte into string???
would u plzz help me??

It depends on what relationship you want between byte and string. Is the string the numeric representation or the character value?
byte b = (byte)65;
String s1 = String.valueOf(byte); // gives "65"
String s2 = new String(new byte[]{b}, "ISO-8859-1");  // gives "A"

Similar Messages

  • How to convert byte into string

    can any tell me how to convert byte into string
    when im an debugging thid code in eclipse it shows the result in integer format instead of string but in command prompt it is showing result in string format..........plz help
    package str;
    import java.io.*;
    public class Testfile {
    public static void main(String rags[])
    byte b[]=new byte[100];
    try{
    FileInputStream file=new FileInputStream("abc.txt");
    file.read(b,0,50);
    catch(Exception e)
         System.out.println("Exception is:"+e);
    System.out.println(b);
    String str=new String(b);
    System.out.println(str);
    }

    Namrata.Kakkar wrote:
    errors: count cannot be resolved and Unhandled exception type Unsupported Encoding Exception.
    If i write an integer value instead of "count" then Unhandled exception type Unsupported Encoding Exception error is left.This is elementary. You need to go back to [http://java.sun.com/docs/books/tutorial/|http://java.sun.com/docs/books/tutorial/] .

  • Encoded double byte characters string conversion

    I have double byte encoded strings stored in a properties file. A sample of such string below (I think it is japanese):
    \u30fc\u30af\u306e\u30a2
    I am supposed to read it from file, convert it to actual string and use them on UI. I am not able to figure how to do the conversion -- the string contains text as is, char backslash, char u, and so on. How to convert it to correct text (either using ai::UnicodeString or otherwise)?
    Thanks.

    Where did this file come from? Some kind of Java or Ruby export? I don't think AI has anything in its SDK that would natively read that. You could just parse the string, looking for \u[4 characters]. I believe if you created a QChar and initialized it with the integer value of the four-character hex string, it would properly create the character.

  • Byte to String conversion for encryption and decryption

    Hi Friends ,
    I am trying to encrypt a password string and then decrypt it .
    The thing is i need to convert the encrypted String which is a byte array to a string . While decrypting i need to convert the encrypted string to a Byte .
    I tried using String.getBytes() for converting a string to byte array , but this is giving an exception
    javax.crypto.IllegalBlockSizeException: Input length must be multiple of 8 when decrypting with padded cipherPlease find below my code
    import java.security.Key;
    import javax.crypto.Cipher;
    import javax.crypto.KeyGenerator;
    import sun.misc.BASE64Encoder;
    import sun.misc.BASE64Decoder;
    * @author rajeshreddy
    public class Encrypt
        public static void main(String[] args)
            try
            BASE64Encoder en = new BASE64Encoder();
            BASE64Decoder en1 = new BASE64Decoder();
                String password = "S_@!et";
                KeyGenerator kg = KeyGenerator.getInstance("DESede");
                Key key = kg.generateKey();
                Cipher cipher = Cipher.getInstance("DESede");
                cipher.init(Cipher.ENCRYPT_MODE, key);
                // Encrypt password
                byte[] encrypted = cipher.doFinal(password.getBytes());
                String e = new String(encrypted);
                byte[] toDecrypt  = e.getBytes();
                // Create decryption cipher
                cipher.init(Cipher.DECRYPT_MODE, key);
                byte[] decrypted = cipher.doFinal(toDecrypt);
                // Convert byte[] to String
                String decryptedString = new String(decrypted);
                System.out.println("password: " + password);
                System.out.println("encrypted: " + encrypted);
                System.out.println("decrypted: " + decryptedString);
            } catch (Exception ex)
                ex.printStackTrace();
    }I cab use sun.misc.BASE64Decoder and sun.misc.BASE64Encoder which avoids this error, but this packages are sun proprietery packages so there is a chance of removing these in future releases.
    Please suggest me the best way to tackle this

    1) The "Jakarta Commons Codec" project has Base64 and Hex encoders that are well tested and well regarded. Google is your friend.
    2) Since this is a new project, you should use AES rather than DESede.
    3) The defaults when generating the Cipher object using
    Cipher cipher = Cipher.getInstance("DESede");
                is for ECB block mode with PKCS5 padding. ECB is not a good block mode since it allows some limited forgery though splicing of ciphertext. Use one of the feedback modes such as CBC.
    4) Why are you encrypting passwords rather than just hashing them? While there are situations where encryption rather than hashing is required, it is not the norm and does normally require justification.
    5) Converting encrypted or hashed data to a String is not normally required. What are you doing with that requires this?
    Edited by: sabre150 on Dec 29, 2008 7:44 AM

  • Convery byte[] into a object

    i have a byte[] which I have got from DB. I want to convert it into a object before returning it from a method. There is a wraaper class for byte i.e. Byte. But I am not sure tha how to convert a byte[] into an Object.
    Thanks!!

    georgexu316 wrote:
    corlettk wrote:
    georgexu316 wrote:
    If you know what you are doing, you can perform an implicit conversion by casting the byte.
    byte byteData = new byte();
    Object newObj = (Object) byteData;
    Umm.. Dude, a byte array is-an Object. In Java you don't ever need to explicitly up-cast... but (in order to actually use it as a byte array) you do have to explicitly down-cast it.
    For example:
    package forums;
    class AByteArrayIsAnObject
    public static void main(String[] args) {
    try {
    Object bytes = "Hello World!".getBytes(); // returns a reference to a newly created byte-array-object
    System.out.println( new String((byte[])bytes) );
    } catch (Exception e) {
    e.printStackTrace();
    Well, the person asked to convert it into an Object, maybe he needs it as a object to pass it through another parameter of another method. Even though byte is an extension of Object and you can use all of Object's methods, it wouldn't pass through a parameter of a method that specifies an object.Ummm... Wanna bet?
    package forums;
    class AByteArrayIsAnObjectTest
      public static void main(String[] args) {
        try {
          println(new String((byte[])getBytes("Hello World!")));
        } catch (Exception e) {
          e.printStackTrace();
      private static Object getBytes(String s) {
        return s.getBytes();
      private static void println(Object o) {
        System.out.println(String.valueOf(o));
    }

  • How can I convert an array off byte into an Object ?

    Hi folks...
    I�m developing an application that comunicates a PDA and a computer via Wi-Fi. I�m using a DataStream ( Input and Output ) to receive / send information from / to the computer. Most off the data received from him is in the byte[] type...
    How can I convert an array off byte ( byte[] ) into an Object using MIDP 2.0 / CLDC 1.1 ?
    I found on the web 2 functions that made this... but it uses a ObjectOutputStream and ObjectInputStream classes that is not provided by the J2ME plataform...
    How can I do this ?
    Waiting answers
    Rodrigo Kerkhoff

    There are no ObjectOutputStream and ObjectInputStream classes in CLDC. You must know what you are writing to and reading from the DataStream. You should write the primitives like int, String to the DataOutputstream at one end and read those in exactly the same sequence at the outher end using readInt(), readUTF() methods.

  • What is the efficient way of insert some bytes into a file?

    Hello, everyone:
    If I want to insert some bytes into a file (for example, insert the bytes before all the original content of the file, or append the bytes to a file), and the size of the original file is very big. I am wondering what is the efficient way? Where can I get some sample codes?
    regards,
    George

    Thanks, DrClap.
    I have tried your method and you are correct. I have written a simple program which can be used to insert "Hello World " to the start of a file ("c:\\temp\\input.txt"), and I have verified that it can work. Please help to see whether it is correct and whether it has a more efficient way.
    public class TestDriver {
         public static void main(String[] args) {
              byte[] back_buffer = new byte [1024];
              byte[] write_buffer = new byte [1024];
              System.arraycopy("Hello World".getBytes(), 0, write_buffer, 0, "Hello World".getBytes().length);
              int write_buffer_length = "Hello World ".getBytes().length;
              int count = 0;
              FileInputStream fis = null;
              FileOutputStream fos = null;          
              try {
                   fis = new FileInputStream (new File("c:\\temp\\input.txt"));
                   fos = new FileOutputStream (new File("c:\\temp\\output.txt"));
                   while ((count = fis.read (back_buffer)) >= 0)
                        fos.write(write_buffer, 0, write_buffer_length);
                        System.arraycopy (back_buffer, 0, write_buffer, 0, count);
                        write_buffer_length = count;
                   //write the last block
                   fos.write(write_buffer, 0, write_buffer_length);
                   fis.close();
                   fos.close();
                   //copy content back into original file
                   fis = new FileInputStream (new File("c:\\temp\\output.txt"));
                   fos = new FileOutputStream (new File("c:\\temp\\input.txt"));
                   while ((count = fis.read (back_buffer)) >= 0)
                        fos.write(back_buffer, 0, count);
                   fis.close();
                   fos.close();
                   //remove temporary file
                   File f = new File ("c:\\temp\\output.txt");
                   f.delete();
              } catch (FileNotFoundException e) {
                   // TODO Auto-generated catch block
                   e.printStackTrace();
                   try {
                        fis.close();
                   } catch (IOException e1) {
                        // TODO Auto-generated catch block
                        e1.printStackTrace();
                   try {
                        fos.close();
                   } catch (IOException e2) {
                        // TODO Auto-generated catch block
                        e2.printStackTrace();
              } catch (IOException e) {
                   // TODO Auto-generated catch block
                   e.printStackTrace();
                   try {
                        fis.close();
                   } catch (IOException e1) {
                        // TODO Auto-generated catch block
                        e1.printStackTrace();
                   try {
                        fos.close();
                   } catch (IOException e2) {
                        // TODO Auto-generated catch block
                        e2.printStackTrace();
    }regards,
    George

  • How to convert xslt file into string

    i'm writting a java program to use xslt to transform the xml file. i'm encountering the problem when i try to convert the xslt file into string. i've defined my utility class called 'XmlUtil' to carry out the operation of transform xml file through xslt. but in my main java program i need to convert both xml and xslt file into a string in order to input them in my function argument. my function argument is as follows:
    String htmlString = XmlUtil.applyXsltString(xmlContent, xsltString);
    i've already converted xmlcontent into string by using:
    xmlContent = xmlContentBuffer.toString();
    but i don't know how to convert 'xsltString' now ? i've searched the google for an hour but i cannot find the solution. anyone can help ?
    detail of my souce code is as follow:
    import java.io.*;
    import java.net.*;
    import java.lang.*;
    import java.io.StringReader;
    import java.lang.reflect.Array;
    import java.util.Properties;
    import javax.xml.parsers.DocumentBuilder;
    import javax.xml.parsers.DocumentBuilderFactory;
    import javax.xml.transform.TransformerFactory;
    import javax.xml.transform.sax.SAXResult;
    import javax.xml.transform.sax.SAXSource;
    import javax.xml.transform.sax.SAXTransformerFactory;
    import javax.xml.transform.sax.TransformerHandler;
    import javax.xml.transform.stream.StreamSource;
    import org.apache.xml.serializer.OutputPropertiesFactory;
    import org.apache.xml.serializer.Serializer;
    import org.apache.xml.serializer.SerializerFactory;
    import org.w3c.dom.Document;
    import org.w3c.dom.Node;
    import org.w3c.dom.NodeList;
    import org.xml.sax.InputSource;
    import org.xml.sax.XMLReader;
    import org.xml.sax.helpers.XMLReaderFactory;
    import XmlUtil;
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    public static void download(String address, String localFileName){
    OutputStream out = null;
    URLConnection conn = null;
    InputStream in = null;
    StringBuffer xmlContentBuffer = new StringBuffer();
    String temp = new String();
    String xmlContent;
    try {
    URL url = new URL(address);
    out = new BufferedOutputStream(
    new FileOutputStream(localFileName));
    conn = url.openConnection();
    in = conn.getInputStream();
    byte[] buffer = new byte[1024];
    int numRead;
    long numWritten = 0;
    System.out.println (in.toString ());
    while ((numRead = in.read(buffer)) != -1) {
    out.write(buffer, 0, numRead);
    numWritten += numRead;
    temp = new String(buffer);
    xmlContentBuffer.append(temp);
    System.out.println(localFileName + "\t" + numWritten);
    xmlContent = xmlContentBuffer.toString();
    String htmlString = XmlUtil.applyXsltString(xmlContent, xsltString);
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    try {
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    in.close();
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    out.close();
    } catch (IOException ioe) {
    public static void download(String address) {
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    if (lastSlashIndex >= 0 &&
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    System.err.println("Could not figure out local file name for " + address);
    public static void main(String[] args) {
    for (int i = 0; i < args.length; i++) {
    download(args);
    }

    I don't understand why you need load the XML and XLS files into a String. A Transformer can be constructed from a Source and there is a StreamSouce which can be constructed from an InputStream. The transform() method can take a Source as input and can produce a Result. There is no need to go near a String representation of either the input.

  • How to convert BLOB data into string format.

    Hi,
    I have problem while converting blob data into string format.
    for example,
    Select dbms_lob.substr(c.shape.Get_wkb(),4000,1) from geotable c
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    When i using SQL as i did above,the max length is 4000, but i can get 32K using plsql as below:
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    BEGIN
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    I comfortably convert 32k BLOB field to string.
    My problem is how to convert blob to varchar having size more than 32K.
    Please help me to resolve this,
    Thanx in advance for the support,
    Nilesh

    Nilesh,
    . . . .The result of get_wkb() will not be human readable (all values are encoded into some binary format).
    SELECT utl_raw.cast_to_varchar2(tbl.geometry.get_wkt()) from FeatureTable tbl;
    -- resulting string:
        ☺AW(⌂özßHAA
    Å\(÷. . . .You may also want to have a look at { dbms_lob | http://download.oracle.com/docs/cd/B19306_01/appdev.102/b14258/d_lob.htm#i1015792 } "The DBMS_LOB package provides subprograms to operate on BLOBs, CLOBs, NCLOBs, BFILEs, and temporary LOBs."
    Regards,
    Noel

  • Problems converting byte[] to string

    I use
    byte[] encryptedBytes = cipher.doFinal(bytesToEncrypt);
    String Ciphertext = new String(encryptedBytes);
    and sometimes i get the correct answer ans sometimes no. If yo want the code is in this post:
    http://forum.java.sun.com/thread.jspa?threadID=790137&start=15&tstart=0

    That's because the C language lacks true character and string data types. It only has arrays of bytes. Unfortunately in C bytes are misleadingly called "chars."
    It works if you put ASCII because byte sequences that correspond to ASCII characters can, on most systems, be safely converted to characters and strings. You see, conversions from bytes to characters are done using things called "encoding schemes" or just encodings. If you don't specify an encoding, the system's default is used. The default encoding can be pretty much anything so it's best not to assume much about it.
    You can also use a fixed encoding, like this:String Ciphertext = new String(encryptedBytes, "ISO-8859-1");Just remember that when you convert the string back to bytes you have to use the same encoding again, that isbyte[] cipherBytes = cipherString.getBytes("ISO-8859-1");

  • Converting byte to string

    Im doing a CRC for a txt file.
    So after the CRC calculation i got the 16bit check sum.
    How should i add the 16 bit to the file?
    The file is generated base on various objects. So it would be very good if i could convert the 16 bits into String and then add to the file as part of a text.

    Im suppose to add into the file, the 16 bits as 2 bytes of ASCII.
    Im doing this...
    int firstCRC = crc>>>8;
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    SecCRC : =
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  • How to cram two bytes into a short?

    Hi all,
    I have some byte[] data that I am receiving, and I need to put two bytes into one short (or int, or whatever), as the byte[] will form a two bytes-per-pixel image. I've been working with 8-bit data (this is 12-bits, NOT packed), which is much easier to manipulate.
    I currently have this method to convert a byte[] of 8-bit data into a short (I do this because Java does not support signed types and I need that 8th bit):
    private short[] convertBytesToShorts(byte[] data) {
         short[] convertedData = new short[data.length];
         for (int i = 0; i < data.length; i++) {
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    Furthermore, the two bytes look like this:
    | xxxx xxxx | xxxx 0000 |So the last four bits in the second byte are 0s.
    Any advice is appreciated.
    Message was edited by:
    Djaunl

    I've been working with 8-bit
    data (this is 12-bits, NOT packed), Obviously that is contradictory.
    I currently have this method to convert a byte[] of
    8-bit data into a short (I do this because Java does
    not support signed types and I need that 8th bit):
    Yes it does. The fact that it displays a byte as and integer and the conversion in that process produces a negative display value has nothing at all to do with the bits.
    Is there a way to modify this to place two bytes into
    one short? short s = (short)(((b1 << 8) & 0x0ff) | (b2 & 0x0ff))
    Of course you still have to deal with getting the order correct.
    (You can probably get rid of that first mask but you would need to test that.)

  • Best way to put binary-data into string?

    Hi there!
    What I want to do is to transfer binary data via HTTP/GET so what I have to do is to transfer binary data into a string.
    Currently I do this the follwing way:
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    I know that this way already worked fine, however I now set up my system up again with another linux-distro and now strange things happen.
    e.g. the secData string differs in lenght from run-to-run between 2 and 4 and I don know at all why?
    Transferring the binary-stuff into string-stuff (e.g. short-binary 255 255, String: 65536) is not possible for me because of various reasons.
    The funny thing is that I remeber that this already worked some time ago and I can figure out why it now doesnt...
    Please help!

    First of all thanks a lot for your help!
    Yes, I already think its an encoding problem, but how can I specify the encoding in my application in a portable way. I dont have an idea what to do.
    My applikation should run as applet on many different 1.1+ VMS (msjvm, netscape-1.1.5, ...).
    Thanks again, lg Clemens

  • Format into string 16 bit signed integer

    Is there any format specifier string for "Format into string", whereas the result is an I16 string?
    My problem is when I use "%d" and the input string is 65535, the result string should be "-1".
    Solved!
    Go to Solution.

    Are you trying to get an integer out of an ASCII string (Scan from String) or turn an integer into a string (Format into String).  You title and question seem to contradict each other.
    Assuming you are trying to scan from string, it looks like you need to scan into a U16 and then use a conversion bullet to turn it into an I16.
    There are only two ways to tell somebody thanks: Kudos and Marked Solutions
    Unofficial Forum Rules and Guidelines
    Attachments:
    Scan I16.png ‏11 KB

  • Concat 4 8-bit bytes into 1 32-bit word

    I am just getting started up with LabView. I have an FPGA that is sending a signed (2's Comp) 32 bit vector to the PC serial port in four 8-bit chunks. I am having trouble figuring out how to recombine the four bytes into the original 32-bit word. It is a simple task in any programming language using concatenation but I am really having problems with this.
    Thanks
    Jeremy

    Two ways come to mind immediately.
    1) Go from a string (VISA returns a string from a read) to a byte array then loop and shift each byte the correct amount while OR'ing the result with that from each loop iteration.
    2) Use the join numbers vi to combine multiple bytes into a single 32-bit word.
    I've attached a vi that demonstrates these two solutions.
    Attachments:
    MergeBytesExample.vi ‏28 KB

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