Conversion of long and int: strange result and no warning

Question

Why does Java allow this?
long l = Long.MAX_VALUE / 10;
System.out.println(l); // result 922337203685477580
int i = (int)l;
System.out.println(i); // result -858993460The compiler accepts it and the runtime accepts it. Why? Complete nonsense is the result!
The same happens with using a Long object and calling the intValue() method.
Can someone explain it to me?

Answer 1

What do you think of operator overloading?Well, I don't have much influence -:) But this is what Guy Stele, SUN Fellow, say:
Overloaded operators are still a subject of controversy. They are almost indispensable for certain kinds of mathematical work, but people who oppose adding them to the Java language point out, quite rightly, that the feature was badly abused in C++ for nonmathematical purposes, making code much harder to read than necessary. Most Java applications are nonmathematical in nature. One could make a good argument that commercial applications have no need for operator overloading, except that commercial applications do use (or should use) BigDecimal arithmetic, and it would be really nice to be able to use + and - and * and / with BigDecimal numbers. Much the same can be said of so-called "lightweight classes": their greatest value would lie in supporting numerical concepts such as complex numbers and interval arithmetic.
We have an interesting decision to make that is more a political or business question than a technical one: should the Java language be extended to support the needs of mathematical applications? If so, then I would argue strongly for introducing operator overloading and lightweight classes -- I'm pretty sure such facilities would also get used for other purposes. If not, then maybe we should just make + and - and * and / work for the BigInteger and BigDecimal classes as a special case, much the same way that + is already a special case for the String class.