Convert time in miliiseconds to date format

I have a column in my table with datatype number(38,0) , in that column i have values in form of miliseconds since 1970 e.g 1152567973042...
i have a requirement to convert this time in milliseconds to today's date, which i can do as
1152567973042 / 3600 / 24 / 365 == x
1970 + x = today's date
is there a function in oracle supporting this, or i have to customize my requirements and write a function.
Thanks in anticipation

Your function will not work precisely because it does not account for leap years. You should use Oracle date math. If you add a number to an Oracle date datatype, it assumes that the number is in days. Oracle will automatically account for leap years. Try this:
DECLARE
mydate DATE;
milliseconds_since_1970 NUMBER(30,7);
BEGIN
milliseconds_since_1970 := ?;
mydate := TO_DATE( '01-JAN-1970', 'DD-MON-YYYY') + milliseconds_since_1970/(1000*60*60*24);
DBMS_OUTPUT.PUT_LINE('mydate = ' || to_char( mydate, 'DD-MON-YYYY HH24:MI:SS' ) );
END;
This converts your milliseconds (replace ? with the number) to days and then adds the days to January 1, 1970. The result is an Oracle date datatype adjusted for leap years.
Oracle date datatypes have hours, minutes, and seconds. Since these were not specified for 1/1/1970, they default to zero. Since milliseconds_since_1970 has 7 decimal places, it will contain fractional days which Oracle converts to hours, minutes, and seconds.
I'm not sure what format Oracle stores date datatypes in. You have to convert them with a format string every time you use them.
Kevin Tyson

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>
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