Convert Unicode to Hex (Big5 hex)
i have a content in MySql as Blob type. The content is a string of unicode. The below string is the content.
82f1570b5a929ad4900f9732002c67008fd16df153d75b9853f87e8f8eab76849ea553ef5091905c62537b9754119ed15e6b592780337abf501f9322002c4ee589e36c7a4ed69ad890544e0051044e8c5343842c7f8e91d1768450b552d9002c800c9ea553ef5df2548c5c0d65b9800159276210597d53cb002e
This is representing a sentence of chinese character. Well, for instance:
82f1 - ying
570b - guo
(ying guo = England country)
My question is, how can i convert 82f1 into Big5 format? Eg: "82f1" will becomes "AD5E".
Anyone has idea to convert it? Thanks
this might be helpful as well
String s = "abcdef";
byte[] bytes;
try {
bytes = s.getBytes("UTF-16BE");
catch (java.io.UnsupportedEncodingException ex) {
for (int i = 0; i < bytes.length; ++i) {
System.out.print
(Integer.toHexString(bytes|0x100).substring(1,3) +
First of all, thank you for replying. This above code showed conversion from char to hex. But my problem is to convert from UTF-16 to Big5. Every 4 digits (82f1) is representing a char in chinese encoding. Therefore, i am looking a way to convert every 4 digits back to Big5 encoding. Do you have any idea of that? :)
Similar Messages
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Converting Char type structure to Hex type structure
Hello ,
In unicode system how to convert char type structure to hex type structure . I am having structures as follows :
DATA: BEGIN OF HEXBYTE,
X TYPE X,
END OF HEXBYTE.
DATA: BEGIN OF CHARBYTE,
C TYPE C,
END OF CHARBYTE.
HEXBYTE-X = CHARFIELD.
CHARBYTE = HEXBYTE.
But error coming is Charbyte and HexByte are not compatible . Plz suggest!!
Thanks ,
KeithHi,
These function modules are:
NLS_STRING_CONVERT_TO_SYS (hex to char)
NLS_SRING_CONVERT_FROM_SYS (char to hex)
Regards,
Nikhil -
Converting byte from dec to hex
Hi All,
I'm having a problem converting byte from decimal to hex - i need the following result:
if entered 127 (dec), the output should be 7f (hex).
The following method fails, of course because of NumberFormatException.
private byte toHexByte(byte signedByte)
int unsignedByte = signedByte;
unsignedByte &= 0xff;
String hexString = Integer.toHexString(unsignedByte);
BigInteger bigInteger = new BigInteger(hexString);
//byte hexByte = Byte.parseByte(hexString);
return bigInteger.byteValue();
}get numberformatexception because a lot of hex digits cannot be transformed into int just like that (ie f is not a digit in decimal) heres some code that i used for a pdp11 assembler IDE... but this is for 16-bit 2s complement in binary/octal/decimal/hex , might be useful for reference as example though
public static String getBase(short i, int base){
String res = (i>=0)? Integer.toString((int)i,base)
: Integer.toString((int)65536+i,base) + " ("+Integer.toString((int)i,base)+")";
StringBuffer pad= new StringBuffer();
for(int x = 0; x < 16 - res.length() ; x++){
pad.append("0");
res = pad.toString() + res;
return res;
} -
Checking and Converting binary, octal, decimal, and hex
Hi,
I have a classroom project which will need to validate that data entered in a text is of a certain type with a keyListener, and then convert that value to the other 3 types.
I know character.isDigit will handle the decimal case, and that I can then use Integer.otString methods to convert to binary, octal, and hex, but what about the other cases?
ThanksOK, this isn't working. If I've already established
that the string entered into, for example, the
integer-only textfield is a valid integer, I should be
able to simply use integer.parseint(s, 2) to convert
it into binary, right?Not exactly. You should be able to use Integer.parseInt(s, 2) to return the result of converting it from binary representation. You appear to think that this affects whatever "s" refers to, which is not the case. Note also, that method returns an int which is the decimal value in question.
When you are thinking of int variables, be careful not to think of them as "decimal" or "binary". They are neither. They are just numbers. "Decimal" and "binary" are text representations of numbers, so those concepts can only be applied to strings.
Integer.parseInt(s, 2);
txtBin.setText(s);So here you want to assume that the input is a string that represents a number in decimal, and you want to find the string that represents the number in binary. Like this:// convert string in decimal representation to number
int dec = Integer.parseInt(s);
// convert int to binary representation as string:
String binary = Integer.toBinaryString(dec);
// write that to the text field
txtBin.setText(binary);You could use a one-liner to do that, but you'll need the "dec" variable to set the other text boxes.
Rembering why I hate OO...All of what I said there is true in just about all computer languages, OO or otherwise.
PC² -
Conversion - ASCII (Alphabet) to Hexa and Hexa to ASCII (Alphabet)
Hi Guys,
Can you please give me the code to change ALPHABET to HEXA and HEXA to ALPHABET in UNICODE system.
1. I want to convert alphabet 'A' to Hexa.
2. Convert Hexa to back in Alphabet (ASCI).
Thanks,
miniNo Response.
-
I am using an event script (AftExportToDat) to create a file to clear data in the target system. When I open the .dat file (in Notepad) it contains characters like 吀䔀䴀倀㬀㈀ 㬀倀 㘀㬀夀吀䐀㬀䠀䔀开䄀唀匀吀刀䄀䰀䤀䄀㬀㰀䔀渀琀椀琀礀 . I believe it is due to the fact that FDM v11.1.1.3 saves files as Unicode. I have tried different formats such as 0,-1,-2, and they are not working. Is there another way to format the file?
Function AppendDataFile(sFilePath1, sFilePath2)
Dim filesys
Dim sBuf
Dim oFile1
Dim oFile2
AppendDataFile = ""
Const ForReading = 1, ForWriting = 2, ForAppending = 8
Set filesys = CreateObject("Scripting.FileSystemObject")
Set oFile1 = filesys.OpenTextFile(sFilePath1, ForAppending, True)
If err > 0 Then AppendDataFile = err.Description
Set oFile2 = filesys.OpenTextFile(sFilePath2, ForReading, False)
If err > 0 Then AppendDataFile = err.Description
Do While Not oFile2.AtEndOfStream
sBuf = oFile2.ReadLine
If UCase(Left(sBuf, 5)) <> "!DATA" Then
oFile1.WriteLine(sBuf)
End If#1
OpenTextFile("c:\testfile.txt", ForAppending,0)
Should open the output file in ASCII.
#2
Looking at your output, it would appear to me the issue is that the source data is coming in as ASCII and it is being interpreted as Unicode. I don't think the file you are writing to is the problem, rather wherever the data is coming in from.
If the situation was reversed (i.e. you started with Unicode and wrote it as ASCII) it would still be readable.
This is a test (in Unicode) would look like T h i s i s a t e s t (in ASCII)
This is a test (in ASCII) would like like a bunch of Japanese characters (in Unicode)
Why?
ASCII characters are represented as one byte while Unicode are represented as two bytes.
T in ASCII is 54 (hex)
T in Unicode is 54 00 (hex)
If you interpret a Unicode data stream as ASCII, each byte in the stream would be treated as its own character. 54 is still T. 00 is a non printable value (null) which would most likely be shown as an empty space.
If you interpret an ASCII data stream as Unicode, you would need to grab two bytes to make one character. Using the example string 'This is a test', the two bytes grabbed would be 54 (T) and 68 (h). The Unicode display character for 5468 is Japanese ..... -
Help with binary to decimal, binary to hex, and hex to ascii or ascii to hex program
I decided to do a program that will do binary to decimal, binary to hex, and hex to ascii for a project related to a java programming course, which only needs to perform features from chapters 1-6 and 8 of Tony Gaddis's book. The functions work fine as their own main programs out side of this combined effort, so can anyone help me determine why I get the following 41 errrors saying: class, interface, or enum expected as well as any other errors that may show up afterwards because I'm stumped. My flowcharts, which have to be revised after discovering that my previous function were logically incorrect after running them in their own main are attached below as the spec sheet.
My code is as follows and I hope you don't mind the commented lines of unused code because I'm not sure where I want things and what I want at the moment:
import java.util.Scanner;
import java.io.*;
import java.lang.*;
public class BintoDectoHextoAscii
public static void main(String[] args)throws IOException
Scanner input = new Scanner(System.in);
System.out.println("Enter a binary number: ");
String binary = input.nextLine(); // store input from user
if (binary == input.nextLine())
//int i= Integer.parseInt(hex,2);
//String hexString = Integer.toHexString(i);
//System.out.println("Hexa decimal: " + hexString);
//int finaldecimalvalue = binaryToDecimal(hexString);
int finaldecimalvalue = binaryToDecimal(hexString);
if (binary != input.nextLine())
String hexInput; // The variable Bin Input declared as the datatype int to store the Binary value
// Create a Scanner object for keyboard input.
//Scanner keyboard = new Scanner(System.in);
// Get the number of binary files.
System.out.print("Enter the Hex value: ");
hexInput = keyboard.nextLine();
System.out.println("Original String: "+ hexInput);
//String hexEquivalent = asciiToHex(demoString);
String hexEquivalent = asciiToHex(hexInput);
//Hex value of original String
System.out.println("Hex String: "+ hexEquivalent);
String asciiEquivalent = hexToASCII(hexEquivalent);
//ASCII value obtained from Hex value
System.out.println("Ascii String: "+ asciiEquivalent);String finalhexOutput = HextoAsciiConverter(hexEquivalent);
if (binary != input.nextLine() && hexInput != keyboard.nextLine())
BufferedReader binInput = new BufferedReader(new InputStreamReader(System.in));
System.out.println("Enter the Binary number:");
String hex = binInput.readLine();
//String finaldecimalvalue = binaryToDecimal(decimal);
//long finalhexvalue = BinaryToHexadecimal(num);
long finalhexvalue = BinaryToHexadecimal();
public static String BinaryToHexadecimal(String hex)
//public static void main(String[] args)throws IOException
//BufferedReader bf= new BufferedReader(new InputStreamReader(System.in));
//System.out.println("Enter the Binary number:");
//String hex = binInput.readLine();
long num = Long.parseLong(hex);
long rem;
while(num > 0)
rem = num % 10;
num = num / 10;
if(rem != 0 && rem != 1)
System.out.println("This is not a binary number.");
System.out.println("Please try once again.");
System.exit(0);
int i= Integer.parseInt(hex,2);
String hexString = Integer.toHexString(i);
System.out.println("Hexa decimal: " + hexString);
return num.tolong();
//int i= Integer.parseInt(hex,2);
//String hexString = Integer.toHexString(i);
//System.out.println("Hexa decimal: " + hexString);
//} // end BintoDectoHextoAsciil
//public static String HexAsciiConverter(String hextInput)
// Get the number of binary files.
//System.out.print("Enter the Hex value: ");
//hexInput = keyboard.nextLine();
//System.out.println("Original String: "+ hexInput);
//String hexEquivalent = asciiToHex(demoString);
//String hexEquivalent = asciiToHex(hexInput);
//Hex value of original String
//System.out.println("Hex String: "+ hexEquivalent);
//String asciiEquivalent = hexToASCII(hexEquivalent);
//ASCII value obtained from Hex value
//System.out.println("Ascii String: "+ asciiEquivalent);
//} // End function
private static String asciiToHex(String asciiValue)
char[] chars = asciiValue.toCharArray();
StringBuffer hex = new StringBuffer();
for (int i = 0; i < chars.length; i++)
hex.append(Integer.toHexString((int) chars[i]));
return hex.toString();
private static String hexToASCII(String hexValue)
StringBuilder output = new StringBuilder("");
for (int i = 0; i < hexValue.length(); i += 2)
String str = hexValue.substring(i, i + 2);
output.append((char) Integer.parseInt(str, 16));
return output.toString();
public static String binaryToDecimal(String binary)
//Scanner input = new Scanner(System.in);
//System.out.println("Enter a binary number: ");
//String binary = input.nextLine(); // store input from user
int[] powers = new int[16]; // contains powers of 2
int powersIndex = 0; // keep track of the index
int decimal = 0; // will contain decimals
boolean isCorrect = true; // flag if incorrect input
// populate the powers array with powers of 2
for(int i = 0; i < powers.length; i++)
powers[i] = (int) Math.pow(2, i);
for(int i = binary.length() - 1; i >= 0; i--)
// if 1 add to decimal to calculate
if(binary.charAt(i) == '1')
decimal = decimal + powers[powersIndex]; // calc the decimal
else if(binary.charAt(i) != '0' & binary.charAt(i) != '1')
isCorrect = false; // flag the wrong input
break; // break from loop due to wrong input
} // end else if
// keeps track of which power we are on
powersIndex++; // counts from zero up to combat the loop counting down to zero
} // end for
if(isCorrect) // print decimal output
System.out.println(binary + " converted to base 10 is: " + decimal);
else // print incorrect input message
System.out.println("Wrong input! It is binary... 0 and 1's like.....!");
return decimal.toint();
} // end function
The errors are as follows:
----jGRASP exec: javac BintoDectoHextoAscii.java
BintoDectoHextoAscii.java:65: error: class, interface, or enum expected
public static String BinaryToHexadecimal(String hex)
^
BintoDectoHextoAscii.java:73: error: class, interface, or enum expected
long rem;
^
BintoDectoHextoAscii.java:74: error: class, interface, or enum expected
while(num > 0)
^
BintoDectoHextoAscii.java:77: error: class, interface, or enum expected
num = num / 10;
^
BintoDectoHextoAscii.java:78: error: class, interface, or enum expected
if(rem != 0 && rem != 1)
^
BintoDectoHextoAscii.java:81: error: class, interface, or enum expected
System.out.println("Please try once again.");
^
BintoDectoHextoAscii.java:83: error: class, interface, or enum expected
System.exit(0);
^
BintoDectoHextoAscii.java:84: error: class, interface, or enum expected
^
BintoDectoHextoAscii.java:87: error: class, interface, or enum expected
String hexString = Integer.toHexString(i);
^
BintoDectoHextoAscii.java:88: error: class, interface, or enum expected
System.out.println("Hexa decimal: " + hexString);
^
BintoDectoHextoAscii.java:90: error: class, interface, or enum expected
return num.tolong();
^
BintoDectoHextoAscii.java:91: error: class, interface, or enum expected
^
BintoDectoHextoAscii.java:124: error: class, interface, or enum expected
StringBuffer hex = new StringBuffer();
^
BintoDectoHextoAscii.java:125: error: class, interface, or enum expected
for (int i = 0; i < chars.length; i++)
^
BintoDectoHextoAscii.java:125: error: class, interface, or enum expected
for (int i = 0; i < chars.length; i++)
^
BintoDectoHextoAscii.java:125: error: class, interface, or enum expected
for (int i = 0; i < chars.length; i++)
^
BintoDectoHextoAscii.java:128: error: class, interface, or enum expected
^
BintoDectoHextoAscii.java:130: error: class, interface, or enum expected
^
BintoDectoHextoAscii.java:135: error: class, interface, or enum expected
for (int i = 0; i < hexValue.length(); i += 2)
^
BintoDectoHextoAscii.java:135: error: class, interface, or enum expected
for (int i = 0; i < hexValue.length(); i += 2)
^
BintoDectoHextoAscii.java:135: error: class, interface, or enum expected
for (int i = 0; i < hexValue.length(); i += 2)
^
BintoDectoHextoAscii.java:138: error: class, interface, or enum expected
output.append((char) Integer.parseInt(str, 16));
^
BintoDectoHextoAscii.java:139: error: class, interface, or enum expected
^
BintoDectoHextoAscii.java:141: error: class, interface, or enum expected
^
BintoDectoHextoAscii.java:144: error: class, interface, or enum expected
public static String binaryToDecimal(String binary)
^
BintoDectoHextoAscii.java:150: error: class, interface, or enum expected
int powersIndex = 0; // keep track of the index
^
BintoDectoHextoAscii.java:151: error: class, interface, or enum expected
int decimal = 0; // will contain decimals
^
BintoDectoHextoAscii.java:152: error: class, interface, or enum expected
boolean isCorrect = true; // flag if incorrect input
^
BintoDectoHextoAscii.java:155: error: class, interface, or enum expected
for(int i = 0; i < powers.length; i++)
^
BintoDectoHextoAscii.java:155: error: class, interface, or enum expected
for(int i = 0; i < powers.length; i++)
^
BintoDectoHextoAscii.java:155: error: class, interface, or enum expected
for(int i = 0; i < powers.length; i++)
^
BintoDectoHextoAscii.java:159: error: class, interface, or enum expected
for(int i = binary.length() - 1; i >= 0; i--)
^
BintoDectoHextoAscii.java:159: error: class, interface, or enum expected
for(int i = binary.length() - 1; i >= 0; i--)
^
BintoDectoHextoAscii.java:159: error: class, interface, or enum expected
for(int i = binary.length() - 1; i >= 0; i--)
^
BintoDectoHextoAscii.java:166: error: class, interface, or enum expected
else if(binary.charAt(i) != '0' & binary.charAt(i) != '1')
^
BintoDectoHextoAscii.java:169: error: class, interface, or enum expected
break; // break from loop due to wrong input
^
BintoDectoHextoAscii.java:170: error: class, interface, or enum expected
} // end else if
^
BintoDectoHextoAscii.java:174: error: class, interface, or enum expected
} // end for
^
BintoDectoHextoAscii.java:180: error: class, interface, or enum expected
else // print incorrect input message
^
BintoDectoHextoAscii.java:185: error: class, interface, or enum expected
return decimal.toint();
^
BintoDectoHextoAscii.java:186: error: class, interface, or enum expected
} // end function
^
41 errors
----jGRASP wedge2: exit code for process is 1.
----jGRASP: operation complete.so can anyone help me determine why I get the following 41 errrors saying: class, interface, or enum expected as well as any other errors that may show up afterwards because I'm stumped.
Yes - YOU CAN!
My code is as follows and I hope you don't mind the commented lines of unused code because I'm not sure where I want things and what I want at the moment:
Excellent! Commenting out code is EXACTLY how you troubleshoot problems like yours.
Comment out sections of code until the problem goes away. Then start adding back ONE SECTION of code at a time until the problem occurs. When it does you have just FOUND the problem.
If you do that you wind up with code that looks like this:
import java.util.Scanner;
import java.io.*;
import java.lang.*;
public class BintoDectoHextoAscii {
public static void main(String[] args)throws IOException {
Scanner input = new Scanner(System.in);
System.out.println("Enter a binary number: ");
String binary = input.nextLine(); // store input from user
public static String BinaryToHexadecimal(String hex) { } // end function
Notice ANYTHING UNUSUAL?
You have a complete CLASS definition followed by a method definition.
Methods have to be INSIDE the class - you can NOT define methods on their own.
Write modular code.
Write EMPTY methods - just the method signature and maybe a RETURN NULL if you need to return something.
Then add calls to those empty methods.
When everything compiles and runs find you can start adding code to the methods ONE METHOD AT A TIME.
Test compile and run after you add the code for each method. -
CRADSDatabase ERROR (5211): There is an error converting Unicode string to or from code page string
Device Blackberry Z10
Sw release 10.2.1.2977
OS Version 10.2.1.3247
The problem is known by Blackberry but they didn't make a little effort to solve this problem and they wonder why nobody buy Blackberry. I come from Android platform and I regret buying Blackberry: call problems(I sent it to service because the people that I was talking with couldn't hear me), jack problems (the headphones does not work; I will send it again to service). This synchronisation problem is "the drop that fills the glass". Please don't buy Blackberry any more.
http://btsc.webapps.blackberry.com/btsc/viewdocument.do?noCount=true&externalId=KB33098&sliceId=2&di...This is a Windows registry issue, if you search the Web using these keywords:
"how to fix craddatabase error 5211" you will find a registry editor that syas it can fix this issue. -
Alogrithm for converting Unicode characters to EBCDIC
I would like to know if there is any algorithm for converting Unicode Characters to EBCDIC.
Awaiting your replys
Thanks in advance,
RaviI would like to know if there is any algorithm for
converting Unicode Characters to EBCDIC.Isn't ECBDIC a 7-bit code like ASCII. Unicode is
16-bit. This means there is no way Unicode can be
mapped on ECBDIC without loss of information. Link to
Unicode,
No. That is like saying that since UTF-8 is 8 bit based then it can't be mapped to UTF-16. But it does.
EBCDIC either directly supports or has versions which support multibyte character sets. A multibyte character set can encode any fixed format sized character set. The basic idea is the same way UTF-8 works.
Multibyte character sets have the added benifit that most of the data in the world is from the ASCII character set and the encodings always support that using only 8 bits. Thus the memory savings over UTF-16 (or UTF-32) are significant. -
Hello,
I'm getting the following error message:
After Effects error: could not convert Unicode characters. (23 :: 46)
I have yet to find an answer that works to resolve this problem. I'm using CS6 on an HP Z220 on Windows 7.
Thanks in advance.So I solved the problem. A little history for this situation: I created a new AE project and while attempting to import a file received the error message: After Effects error: could not convert Unicode characters. (23 :: 46)
I then tried to import a Vanishing Point which broken the spell on the error message and allowed the menu to select a vanishing point to appear. I closed out of that and was then able to import files. -
JZ0I6:An error occured converting UNICODE to the charset used by the server
Hi Friends,
I am using weblogic 8.1 and I developed one MD Bean(Message Distributor Bean). Which takes message from JMS queue and pulish it to JMS Topic. Database is sybase. I was facing this issue.
I am facing following issue:
java.sql.SQLException: JZ006: Caught IOException: java.io.IOException: JZ0I6: An error occured converting UNICODE to the charset used by the server. Error message: java.io.CharConversionException: ?
at com.sybase.jdbc.ErrorMessage.raiseError(Ljava/lang/String;Ljava/lang/String;)V(ErrorMessage.java:???)
at com.sybase.tds.Tds.language(Lcom/sybase/jdbc/ProtocolContext;Ljava/lang/String;Lcom/sybase/jdbc/ParamManager;)V(Tds.java:???)
at com.sybase.jdbc.SybStatement.sendQuery(Ljava/lang/String;Lcom/sybase/jdbc/ParamManager;)Z(SybStatement.java:???)
at com.sybase.jdbc.SybPreparedStatement.sendQuery(Ljava/lang/String;Lcom/sybase/jdbc/ParamManager;)Z(SybPreparedStatement.java:???)
at com.sybase.jdbc.SybStatement.executeUpdate(Ljava/lang/String;Lcom/sybase/jdbc/ParamManager;)I(SybStatement.java:???)
at com.sybase.jdbc.SybPreparedStatement.executeUpdate()I(SybPreparedStatement.java:???)
at weblogic.jdbc.wrapper.PreparedStatement.executeUpdate()I(PreparedStatement.java:115)
at com.lehman.PW.messageMonitor.GASMessageDistributorBean.onMessage(Ljavax/jms/Message;)V(GASMessageDistributorBean.java:343)
at weblogic.ejb20.internal.MDListener.execute(Lweblogic/kernel/ExecuteThread;)V(MDListener.java:370)
at weblogic.ejb20.internal.MDListener.onMessage(Ljavax/jms/Message;)V(MDListener.java:262)
at weblogic.jms.client.JMSSession.onMessage(Ljavax/jms/MessageListener;Lweblogic/jms/common/MessageImpl;)V(JMSSession.java:2678)
at weblogic.jms.client.JMSSession.execute(Lweblogic/kernel/ExecuteThread;)V(JMSSession.java:2598)
at weblogic.kernel.ExecuteThread.execute(Lweblogic/kernel/ExecuteRequest;)V(ExecuteThread.java:219)
at weblogic.kernel.ExecuteThread.run()V(ExecuteThread.java:178)
at java.lang.Thread.startThreadFromVM(Ljava/lang/Thread;)V(Unknown Source)
Please give me the solution.This problem has resolved. I added one line: "CHARSET_CONVERTER_CLASS=com.sybase.jdbc2.utils.PureConverter" into weblogic datasource.
In Internet I got lot's of article but it was worst. There were giving solution on Weblogic 4 or some old version. Generally on internet you will get article:
http://publib.boulder.ibm.com/infocenter/wasinfo/v4r0/index.jsp?topic=/com.ibm.support.was40.doc/html/DB_Connections_Connection_Pooling/swg21066787.html
This article is giving information about weblogic 4.
But We need to solve the issue into weblogic into 8. So in datasource set property: CHARSET_CONVERTER_CLASS=com.sybase.jdbc2.utils.PureConverter. Do not set property: CHARSET_CONVERTER_CLASS=com.sybase.jdbc2.utils.TruncationConverter -
AE error: Could not convert Unicode Characters
Hey guys,
I purchased the Video Copliot Action essentials 2 (720p). Whenever I try to import or drag and drop the pre-keyed clips (quicktime .mov format) into AE, I get the After Effects error: could not convert Unicode Characters (23 ::46) . I found an article online that said to make changes to the text in whatever Im importing, but umm it's a video, not text.
I am using AE cs5.
I can import the clips just fine into Premier Pro and export them oddly enough in Quicktime format just fine, however I lose the transperency "pre-keyed" , that's somehow embedded into the original video, therefore I now have a video of smoke, but with a non removable black background.
Please help! thanks!Hey man i made an account just to reply to this, i had the same error come up while i was importing video files so i had a look around and found that it had something to do with the language/coding not being recognised, so i looked closer into the footage and tried different method of importing the file and later realised that after effects didnt recognise some of the characters in the file path way, the original folder was created using a macbook, windows recognises the language but after effects didnt, so i moved the file to my desktop and tried to import it again and presto it worked fine, you may not have the same problem but i thought just incase you do, you should try moving the file,
if not heres a thread for the error:
http://helpx.adobe.com/after-effects/kb/error-could-convert-unicode-characters.html
hope that could be of some help.
Zai -
" could not convert Unicode characters (23::46) "
I am suddently received an error message: " could not convert Unicode characters (23::46) " on my OS X version 10.9, when I trying to open a template. I have no problem to open the file on my friend's pc tho.. Any suggestion how to fix it greatly appreciated.
Thanks,
Andy,There is some character in the file name or the path name for the file that After Effects doesn't recognize. What is the full path and file name of this project?
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Hello I just created a project in AE CC and wanted to save also a version for CS6.
All went ok but when I tried to open the project in CS6 I received the following error:
"After Effects error: could not convert Unicode characters. (23::46)"
Does anyone know what that means and how to fix it?After Effects CC is much, much better at handling characters that are outside of the character set used by the OS at its current language settings. So, file names and paths (and other strings) that work fine in After Effects CC and later may fail with earlier versions.
For example, if you are running your OS and applications in English and have Chinese characters in your file names, After Effects CS6 and earlier will fail, but After Effects CC and earlier will succeed. -
Converting unicode to cp1251(windows cyrillic)
Hi,
Can someone please let me know how I could programmatically convert unicode string to cp1251.
Thank you.Double post. Other thread with duke dollars:
http://forum.java.sun.com/thread.jspa?threadID=622800
/Kaj
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